I want to show a PictureBox on button click, this should be on first click Show PictureBox, and on next click Hide PictureBox, again on third click show PictureBox and similar on fourth click again hide the PictureBox.
I have tried below code but it stuck after dispose of picture.
public bool i;
private void button1_Click(object sender, EventArgs e)
{
if (!i)
{
m1();
i = true;
}
else
{
m2();
i = false;
}
}
public void m1()
{
pictureBox1.Show();
}
public void m2()
{
pictureBox1.Dispose();
}
You don't need to Dispose your PictureBox. Just set the visibility like this:
private void button1_Click(object sender, EventArgs e)
{
pictureBox1.Visible = !pictureBox1.Visible;
}
pictureBox.Visible = true;
pictureBox.Visible = false;
I assume this is for Winforms? Calling Dispose will destroy the picturebox object in memory so that is why you are having the issue.
Use:
// Show the picture box
pictureBox.Visible = true;
// Hide the picture box
pictureBox.Visible = false;
// Show the picture box
pictureBox.Visible = true;
// Hide the picture box
pictureBox.Visible = false;
Related
I want to add icon inside a button. Here is my code
private void Printbutton_Click(object sender, EventArgs e)
{
// Assign an image to the button.
Printbutton.Image = Image.FromFile("D:\\Downloads\\print.png");
// Align the image and text on the button.
Printbutton.ImageAlign = ContentAlignment.MiddleRight;
Printbutton.TextAlign = ContentAlignment.MiddleLeft;
// Give the button a flat appearance.
Printbutton.FlatStyle = FlatStyle.Flat;
if (SetupThePrinting())
printDocument1.Print();
}
The problem here is that the icon doesn't appear at first , it appears when I click to the button.
What's wrong here ?
you added the icon in printbutton_click event instead defining it in Form initializecomponents
public Form2()
{
InitializeComponent();
// Assign an image to the button.
Printbutton.Image = Image.FromFile("D:\\Downloads\\print.png");
// Align the image and text on the button.
Printbutton.ImageAlign = ContentAlignment.MiddleRight;
Printbutton.TextAlign = ContentAlignment.MiddleLeft;
// Give the button a flat appearance.
Printbutton.FlatStyle = FlatStyle.Flat;
}
private void Printbutton_Click(object sender, EventArgs e)
{
if (SetupThePrinting())
printDocument1.Print();
}
Like this
public Form1()
{
InitializeComponent();
// Assign an image to the button.
button1.Image = Image.FromFile("C:\\Yourfolder");
// Align the image and text on the button.
button1.ImageAlign = ContentAlignment.MiddleRight;
button1.TextAlign = ContentAlignment.MiddleLeft;
// Give the button a flat appearance.
button1.FlatStyle = FlatStyle.Flat;
}
private void button1_Click(object sender, EventArgs e)
{
// Your print code.
}
I think this is a stupid question, but I don't understand what is happening here.
I use this code:
private void pictureBox1_MouseHover(object sender, EventArgs e)
{
pictureBox1.Visible = false;
pictureBox1.BackColor = Color.Black;
}
private void pictureBox1_MouseLeave(object sender, EventArgs e)
{
pictureBox1.Visible = true;
}
The problem is: The picturebox changes color to black if mouse is over picturebox, but the visibility doesn't change. Why?
I think your problem is as soon as you hover the picture it really disappears (that's why you see the back color turn to black, the event is firing). However the picture disappears which lead to situation where your mouse is not on the picture anymore, therefore Mouse_Leave event firing.
You can use MouseEnter event instead of MouseHover and bool field isHover that you can use in attempt to reduce flickering :
public partial class Form1: Form
{
bool isHover = false;
private void pictureBox1_MouseEnter(object sender, EventArgs e)
{
if(isHover) return;
// with MouseHover this control visibility appears to be locked with MouseEnter it is not
pictureBox2.Visible = false;
pictureBox2.BackColor = Color.Black;
}
private void pictureBox1_MouseLeave(object sender, EventArgs e)
{
if(!isHover) return;
isHover = false;
pictureBox2.Visible = true;
}
...
}
I have a pictureBox with an image inside.
I want, when i click on a button the image should hide and click again to show the image.
In the pictureBox, using paint event i am drawing some lines.
So if im doing pictureBox1.Refresh(); it will draw the lines. I want that if i click on a button the image will not display on/off.
pictureBox1 = null; or pictureBox1.Image.Dispose(); doesn't work it's showing me big red x with white background.
To hide it:
pictureBox.Visible = false;
To hide/show it in a click event:
void SomeButton_Click(Object sender, EventArgs e)
{
pictureBox.Visible = !pictureBox.Visible;
}
For toggling the image in your PictureBox you can create a 1 pixel bitmap and assign it to the picture box when you want hide your image, then assign your image back again. I am a little unclear of what the second part of your question is asking, any drawing in the picturebox's Paint Event will remain unless you exclude it in the Paint Event based on some Condition. If you want to draw a line in the box an toggle it on/off from a button see my second example.
i.e.
public partial class Form1 : Form
{
Bitmap nullBitmap = new Bitmap(1, 1); // create a 1 pixel bitmap
Bitmap myImage = new Bitmap("Load your Image Here"); // Load your image
bool showImage; // boolean variable so we know what image is assigned
public Form1()
{
InitializeComponent();
pictureBox1.Image = myImage;
showImage = true;
}
private void button1_Click(object sender, EventArgs e)
{
if (showImage)
{
pictureBox1.Image = nullBitmap;
showImage = false;
}
else
{
pictureBox1.Image = myImage;
showImage = true;
}
}
}
Second Example
public partial class Form1 : Form
{
bool showLines;
public Form1()
{
InitializeComponent();
showLines = true;
}
private void button1_Click(object sender, EventArgs e)
{
if (showLines)
{
showLines = false;
pictureBox1.Invalidate();
}
else
{
showLines = true;
pictureBox1.Invalidate();
}
}
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
if(showLines)
e.Graphics.DrawLine(Pens.Purple, 0, 0, 100, 100);
}
}
picturebox1.BackgroundImage = null
I'm trying to make a "checkbox" that has a custom check image. I need it to toggle between checked and unchecked when the user clicks the picturebox. I've tried the following code, and the first click shows the checked image fine, however a second click does nothing. Any ideas?
private void pictureBox7_Click(object sender, EventArgs e)
{
if (pictureBox7.Image == Image.FromFile(checkedImg))
{
pictureBox7.Image = Image.FromFile(uncheckedImg);
}
else
{
pictureBox7.Image = Image.FromFile(checkedImg);
}
}
Your if statement is wrong as it is unlikely to return true because you are comparing instances of the Image class which you recreate every time. You could modify it like this:
private bool _pbChecked = false;
private void pictureBox7_Click(object sender, EventArgs e)
{
var pictureBox = (PictureBox)sender;
string imgPath = _pbChecked ? uncheckedImg : checkedImg;
pictureBox.Image = Image.FromFile(imgPath);
_pbChecked = !_pbChecked;
}
I have a Winforms app in C# that calls calls a method asynchronously and uses a callback.
I would like to display an animated gif to let the end user know that work is being done.
I would like to have the animated gif hover over the center of the form.
How can I do this?
Update:
Thanks. I guess the step I was missing was to use a Picture Box to hold the gif.
The following seems to be doing the trick of showing the gif and like jmatthews3865 said below I can just set the visible property of the PictureBox to false to hide it.
private ShowAnimatedGif()
{
PictureBox pb = new PictureBox();
this.Controls.Add(pb);
pb.Left = (this.Width / 2) - (pb.Width / 2);
pb.Top = (this.Height / 2) - (pb.Height / 2);
pb.Image = Resources.AnimatedGifHere;
pb.Visible = true;
}
in your form, simply include the image with it's visible property set to false.
from the event which calls the long running async process (button1_click etc.), set the images visibility property to true. event fires, image appears, async process runs and your ui thread should still be responsive.
in your callback event set the images visible property to false to indicate that the process is complete.
Need some code to give an exact answer, but this is fairly trivial, insert the gif before you make the asynchronous call, then remove it in the callback.
This is the answer. I'm using LoadingCircle which is an animated gif component.
public partial class Form1 : Form
{
public delegate void ProcessAnimation(bool show);
ProcessAnimation pa;
public Form1()
{
InitializeComponent();
pa = this.ShowAnimation;
}
private void button2_Click(object sender, EventArgs e)
{
Thread tr = new Thread(FlushToServer);
tr.Start();
}
private void ShowAnimation(bool show)
{
if (show)
{
loadingCircle1.Visible = true;
loadingCircle2.Active = true;
}
else
{
loadingCircle1.Visible = false;
loadingCircle1.Active = false;
}
}
private void FlushToServer()
{
this.Invoke(this.pa,true);
//your long running process
System.Threading.Thread.Sleep(5000);
this.Invoke(this.pa,false);
}
}
i modify the above code a bit and it will not throw error "c# invoke or begininvoke cannot be called on a control until the window handle has been created."
namespace AnimateUI
{
public partial class Form1 : Form
{
public delegate void ProcessAnimation(bool show);
ProcessAnimation pa;
public Form1()
{
InitializeComponent();
pa = this.ShowAnimation;
pictureBox1.Visible = false;
}
private void ShowAnimation(bool show)
{
if (show)
{
pictureBox1.Visible = true;
}
else
{
pictureBox1.Visible = false;
}
}
private void button1_Click(object sender, EventArgs e)
{
Thread tr = new Thread(StartTask);
tr.Start();
}
private void StartTask()
{
if (!this.IsHandleCreated)
this.CreateControl();
this.Invoke(this.pa, true);
System.Threading.Thread.Sleep(15000);
this.Invoke(this.pa, false);
}
}
}