This question already has answers here:
Why does modal-form disappear completely when minimized?
(5 answers)
Closed 7 years ago.
I have problem with minimizing by program. It has main form and others, which I open by ShowDialog()
Problem is with minimizing these dialog forms. When my friend on Windows7 minimize this dialog, it minimize dialog and main form (dialog isn't in taskbar, I disabled it), but on my Windows7 only dialog is minimized like this
Is here any chance to minimize both forms? I found, that after form is minimized, Resize event is fired, so I made this
private void ShowCode_Resize(object sender, EventArgs e)
{
if (WindowState == FormWindowState.Minimized)
{
main.WindowState = FormWindowState.Minimized;
}
}
but when I click on form in taskbar, main form is showed and dialog is closed, I don't know why?
Is here any chance, to always minimize it to taskbar?
And why on my PC it works this way, and on friend's other way? I don't know that I changed something in Windows settings.
If I understand you correctly - I found a solution after asking a similar question.
Simply add a: Show();
At the end of Form2's event-handler.
See about it here (and in the other answers.)
Related
This question already has answers here:
How to prevent clicks outside the current form?
(2 answers)
Closed 1 year ago.
I am creating an application where I have a Form 1 (Main Form). Inside this main form there is a button that opens up a different and smaller form (Form 2). I don't want to hide Form 1 when showing Form 2 but because of the size of Form 2, the user is able to click Form 1 hiding Form 2 with its size (not hidden like Form2.hide();) however this is something I don't want to do. I want to prohibit the user to click Form 1 if Form 2 is currently open. Is there any event or function I can use to do this? I have seen in it in other applications but I don't even know how to look for it.
In addition to using the ShowDialog method as suggested in question's comments, you can disable the form itself if you want for example the user be able to switch between forms and view or copy some text.
Form.ShowDialog Method: Shows the form as a modal dialog box.
Here is a definition:
Wikipedia: A modal window creates a mode that disables the main window but keeps it visible, with the modal window as a child window in front of it. Users must interact with the modal window before they can return to the parent application. This avoids interrupting the workflow on the main window. Modal windows are sometimes called heavy windows or modal dialogs because they often display a dialog box.
If you don't want to use a modal form, you can initialize the form2 instance like that:
form2.FormClosed += (_s, _e) => this.Enabled = true;
Thus now you can call:
this.Enabled = false;
form2.Show();
You can also check the ShowInTaskBar property of the form2.
Be careful not to add the lambda event handler several times to the same instance: if form2 is just hidden on close, only one FormClosed += is needed, but is required for every instance of a form you want to manage this way.
If you need to disable only certain controls, use them instead of this:
private void SetControlsEnabled(bool state)
{
myControl1.Enabled = state;
myControl2.Enabled = state;
myPanelHavingSomeControls = state; // this changes all inners too
...
}
form2.FormClosed += (_s, _e) => SetControlsEnabled(true);
SetControlsEnabled(false);
form2.Show();
This is the exact use case for a modal form, which disables the parent form and provides visual clues from the OS to tell the user of that relationship. Something along the lines of this will do:
//Code in the event handler that opens the child form
using (Form2 childForm = new Form2())
{
//Put any initialization code here
childForm.ShowDialog(this);
//Any cleanup or using some return value from the form after it closed
}
This question already has an answer here:
Application 'Deactivate' event
(1 answer)
Closed 8 years ago.
I want to create an application that closes one of it's window when the user clicks on another application (or in other words the application loses focus or inactive). All the windows in my application to have the property TopMost = true.
How I can do that?
your help is greatly appreciated.
Edit (Update):
I need when I click on another window in my application, the window is not closed. Only when my application loses focus (the user clicks on another application), the window will be closed.
Check out the Deactivate event, or override OnDeactivate:
protected override void OnDeactivate(EventArgs e)
{
Close();
}
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
(C#) How to detect when a windows form is being minimized
First of all my code:
private void Form1_Load(object sender, EventArgs e)
{
this.MinimumSizeChanged += new EventHandler(Form1_MinimumSizeChanged);
}
void Form1_MinimumSizeChanged(object sender, EventArgs e)
{
MessageBox.Show("1");
}
so, my program idea is, when the program get minized i will do a system tray, but this event never happnd. how can i know when the user do a minize screen(minize the program).
i have tryed everything. any ideas?
MinimumSizeChanged has nothing to do with the form getting minimized. MinimumSizeChanged has to deal with when the MinimumSize properties of the form are changed.
You want to check the Resize event of the form.
In order to minimize to the system tray, add a NotifyIcon control to your form. Now, override the OnResize method and check if your WindowState property is set to FormWindowState.Minimized. If it is, Hide() your forms and show your notify icon. Make sure to set the Icon property of the NotifyIcon as well. Now just reverse the process for the case when the form is restored.
I am using Visual Studio 2010, C# .NET 4.0. I have 3 forms: Form1, Form2, Form3.
In Form1 I have a button to open Form2:
private void button1_Click(object sender, EventArgs e)
{
Form2 f = new Form2();
f.Show();
}
In Form2 I have a private Form3 variable always pointing to the same Form3:
private Form3 f = new Form3();
And a button to open it as a dialog:
private void button1_Click(object sender, EventArgs e)
{
f.ShowDialog();
}
In Form3 I just have a button to hide the form:
private void button1_Click(object sender, EventArgs e)
{
this.Hide();
}
The problem is that having the situation that Form2 is in front of Form1, and Form3 in front of Form2, when I click the button of Form3 to hide it, it not only hides itself but sends Form1 to the back of all of the other Windows.
This only happens when there is a window of another program (such as Windows Explorer) in the background of Form1. It seems like a bug. What do you think?
Yes, this cannot work properly by design. A dialog disables all of the windows that your program displays. So that it is modal. When you hide the dialog, there are no windows left that can get the focus. Windows is forced to find another window to give the focus to. That will be a window owned by another application. Your own windows will now hide behind it.
There are more side effects, the dialog will also close. Necessary because otherwise the user can never get back to your program anymore since all windows are disabled. This is all unsurprising behavior. Bug would be a strong word, but it would of course work better if it first re-enabled all windows before closing the dialog. But closing the dialog is already undesirable behavior.
Don't call Hide() for a dialog. Just set the DialogResult property to DialogResult.Cancel to achieve the exact same effect, minus the focus problem. You do have to reset it back to None if you want to display the dialog again. That's a real bug.
By the documentation. Form.Close method doesn't dispose forms shown by Form.ShowDialog method. Quote:
The two conditions when a form is not disposed on Close is when (1) it is part of a multiple-document interface (MDI) application, and the form is not visible; and (2) you have displayed the form using ShowDialog. In these cases, you will need to call Dispose manually to mark all of the form's controls for garbage collection.
So, maybe there are ways to return focus to your application (e.g. via Windows API). But it is much more convenient to call Form.Close manually on dialog windows.
I have a problem with modality of the forms under C#.NET. Let's say I have main form #0 (see the image below). This form represents main application form, where user can perform various operations. However, from time to time, there is a need to open additional non-modal form to perform additional main application functionality supporting tasks. Let's say this is form #1 in the image. On this #1 form there might be opened few additional modal forms on top of each other (#2 form in the image), and at the end, there is a progress dialog showing a long operation progress and status, which might take from few minutes up to few hours. The problem is that the main form #0 is not responsive until you close all modal forms (#2 in the image). I need that the main form #0 would be operational in this situation. However, if you open a non-modal form in form #2, you can operate with both modal #2 form and newly created non modal form. I need the same behavior between the main form #0 and form #1 with all its child forms. Is it possible? Or am I doing something wrong? Maybe there is some kind of workaround, I really would not like to change all ShowDialog calls to Show...
Image http://img225.imageshack.us/img225/1075/modalnonmodalproblem.png
Modal forms do exactly what "modal" means, they disable all other windows in the app. That's rather important, your program is in a somewhat perilous state. You've got a chunk of code that is waiting for the dialog to close. Really Bad Things could happen if those other windows were not disabled. Like the user could start the modal dialog again, now your code is nested twice. Or she could close the owner window of the dialog, now it suddenly disappears.
These are the exact kind of problems you'd run into if you call Application.DoEvents() inside a loop. Which is one way to get a form to behave modal without disabling other windows. For example:
Form2 mDialog;
private void button1_Click(object sender, EventArgs e) {
mDialog = new Form2();
mDialog.FormClosed += (o, ea) => mDialog = null;
mDialog.Show(this);
while (mDialog != null) Application.DoEvents();
}
This is dangerous.
It is certainly best to use modal forms the way they were designed to stay out of trouble. If you don't want a modal form then simply don't make it modal, use the Show() method. Subscribe to its FormClosing event to know that it is about to close:
private void button1_Click(object sender, EventArgs e) {
var frm = new Form2();
frm.FormClosing += new FormClosingEventHandler(frm_FormClosing);
frm.Show();
}
void frm_FormClosing(object sender, FormClosingEventArgs e) {
var frm = sender as Form2;
// Do something with <frm>
//...
}
The first thing that comes to mind would be something like this. You could disable form 1 when you launch form 2 and then have form 1 handle the closed event of the second form to re-enable itself. You would NOT open modal 2 using show dialog.
Now keep in mind, from a user perspective this is going to be quite cumbersome, you might look at doing a MDI application to get all windows inside of a single container.
Your main form will not be responsive until any modal dialogs that are in the same process space are closed. There is not work around for that.
It looks to me like you could use an MDI application setting the Form #0 IsMdiContainer property to true.
Then, you could do something alike:
public partial class Form0 {
public Form0 {
InitializeComponent();
this.IsMdiContainer = true; // This will allow the Form #0 to be responsive while other forms are opened.
}
private void button1_Click(object sender, EventArgs e) {
Form1 newForm1 = new Form1();
newForm1.Parent = this;
newForm1.Show();
}
}
Using the ShowDialog() as you stated in your question will make all of the forms Modal = true.
By definition, a modal form is:
When a form is displayed modally, no input (keyboard or mouse click) can occur except to objects on the modal form. The program must hide or close a modal form (usually in response to some user action) before input to another form can occur. Forms that are displayed modally are typically used as dialog boxes in an application.
You can use this property [(Modal)] to determine whether a form that you have obtained from a method or property has been displayed modally.
So, a modal form shall be used only when you require immediate assistance/interaction from the user. Using modal forms otherwise makes believe that you're perhaps running into a wrong direction.
If you do not want your main form to be an MDI container, then perhaps using multithreading is one solution through a simple BackgroundWorker class is the key to what you want to achieve. Thus, it looks to me like a design smell...
What is it you want to do, apart of making your main form responsive, etc.
What is it you have to do?
Explaining what you have to do, we might be able to guide you altogether into the right, or at least perhaps better, direction.
Actually the answer is very simple. Try
newForm.showDialog();
This will open a new form, while the parent one is inaccessible.