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asp.net check image resolution and save in DB

asp.net core MVC - framework net6.0
I have a page in which i upload an image and save it to the db.
the file i'm getting from the view is IFormFile.
I want to be able to check the resolution (width and height) of the photo before saving in DB.
Can it be done with IFormFile?
here is the controller that handles the file :
public JsonResult Submit(IFormFile PhotoFile)
{
int success = 0;
string excep = "";
try
{
if (PhotoFile.Length > 0)
{
using (var ms = new MemoryStream())
{
PhotoFile.CopyTo(ms);
var fileBytes = ms.ToArray();
}
}
ApplicationUser appUser =
_unitOfWork.ApplicationUser.GetAll().Where(a => a.UserName == User.Identity.Name).FirstOrDefault();
if (appUser != null)
{
FileUpload fileUpload = new FileUpload()
{
file = PhotoFile,
CompanyId = appUser.CompanyId
};
SaveFile(fileUpload);
}
excep = "success";
success = 1;
return Json(new { excep, success });
}
catch (Exception ex)
{
excep = "fail";
success = 0;
return Json(new { excep, success });
}
}
public string SaveFile(FileUpload fileObj)
{
Company company = _unitOfWork.Company.GetAll().
Where(a => a.Id == fileObj.CompanyId).FirstOrDefault();
if(company != null && fileObj.file.Length > 0)
{
using (var ms = new MemoryStream())
{
fileObj.file.CopyTo(ms);
var fileBytes = ms.ToArray();
company.PhotoAd = fileBytes;
_unitOfWork.Company.Update(company);
_unitOfWork.Save();
return "Saved";
}
}
return "Failed";
}

As far as I know this isn't possible with just IFormFile and you need System.Drawing.Common.
So first you need to convert it like:
using var image = Image.FromStream(PhotoFile.OpenReadStream());
Then you can simply get the height/width with image.height and image.width

Get size of uploading file C# MVC

I'am trying create some validation for file size. My code:
[HttpPost]
public ActionResult Index(FotoModel model)
{
TryUpdateModel(model);
if (ModelState.IsValid)
{
if (model != null && model.File != null)
{
var fileName = Path.GetFileName(model.File.FileName);
var fileExtension = Path.GetExtension(fileName);
long fileSize = new FileInfo(fileName).Length;
fileName = "file" + fileExtension;
var path = Path.Combine(Server.MapPath("~/Content/Images"), fileName);
if (fileSize < 55000)
{
model.File.SaveAs(path);
model.link = fileName.ToString();
}
else
{
ViewData["Size"] = "Akceptowane pliki: jpg, jpeg, png o maksymalnym rozmiarze 50 KB";
}
return View(model);
}
}
return View(model);
}
And in this line:
long fileSize = new FileInfo(fileName).Length;
I'am receiving error: "File cannot be found". Do You know how can I resolved this ?

In Asp.Net MVC we have to use HttpPostedFileBase for Uploaded files as shown below :-
public ActionResult Index(FotoModel model, HttpPostedFileBase file)
{
if (file != null)
{
int byteCount = file.ContentLength; // <---Your file Size or Length
.............
.............
}
}

What you are looking is a ContentLength
public ActionResult Index(FotoModel model)
{
if (model != null && model.File != null)
{
var fileSize = model.File.ContentLength;
}
}

Read single cell values from httppostedfilebase Excel File

I have an Excelfile that the client send to server as httppostedfilebase and I need to know how I can read values from this file.
[HttpPost]
public ActionResult ShowExcelFile(GetExcel model)
{
var file = model.Files[0];
FileInfo info = new FileInfo(file.FileName);
var fileName = Path.GetFullPath(file.FileName);
if (file != null && file.ContentLength > 0)
{
using (ExcelPackage package = new ExcelPackage(info))
{
//Read some cell value, how?
}
}
return View("ShowExcelFile");
}
My model:
public class GetExcel
{
public List<HttpPostedFileBase> Files { get; set; }
public GetExcel()
{
Files = new List<HttpPostedFileBase>();
}
}
My view:
#using (Html.BeginForm("ShowExcelFile", "ShowExcel", FormMethod.Post, new { enctype = "multipart/form-data" }))
{
#Html.TextBoxFor(m => m.Files, new { type = "file", name = "Files" })<br />
<input type="submit" value="Upload file" />
}
I really don't now how to do this, I have tried Excel Data Reader but it can't read formula values. I just wan't to read a cell value from this excelfile send from the client

Lets put this inside your controller action u will get the file:
[AcceptVerbs(HttpVerbs.Post)]
public JsonResult ShowExcelFile()
{
// For getting the file that is Uploadeded.
HttpPostedFileBase fileUpload = Request.Files["Files"];
byte[] data;
using (Stream inputStream = fileUpload.InputStream)
{
MemoryStream memoryStream = inputStream as MemoryStream;
if (memoryStream == null)
{
memoryStream = new MemoryStream();
inputStream.CopyTo(memoryStream);
data = memoryStream.ToArray();
return Json(data, JsonRequestBehavior.AllowGet);
}
}
return Json(new { }, JsonRequestBehavior.AllowGet);
}

As far as I understand you use EPPlus library. To get the value you need to write smth like that
public void Upload(HttpPostedFileBase file)
{
package.Load(file.InputStream);
var worksheet = package.Workbook.Worksheets.First();
var cellValue = worksheet.Cells[rowIndex, columnIndex].Value;
var formulaValue = worksheet.Cells[rowIndex, columnIndex].Formula;
}

There are a few prolems with the how the controller and view are implemented . For example, your ActionResult expects List<HttpPostedFileBase>, but the view is posting HttpPostedFileBase.
However, beyond that, inside using of package, try:
ExcelWorksheet worksheet = package.Workbook.Worksheets[1];
worksheet.Select(new ExcelAddress("A1")); //there is more than one way to set this
string cellVal = (string)worksheet.SelectedRange.Value;

pass img to controller in Razor

I'm working on an ASP.net MVC4 application and I want to send an Image that I have on my view to the controller through a form
Here is my View
#using (Html.BeginForm("Index", "Home", FormMethod.Post, new { #enctype = "multipart/form-data" }))
{
<img src="img/annonceBrute.JPG" width ="60" height="60" name ="imageFile" />
#Html.TextArea("resultText")
<input type="submit" style="margin-left:40px;cursor:pointer;" id="l" value="Envoyer"/>
}
And in my controller I have a code that works with uploaded image but I want to use an image that already exists in my view. Here is the code of the controller
public ActionResult Index(HttpPostedFileBase imageFile)
{
var db = new Bd_scanitEntities();
IEnumerable<SelectListItem> items = db.JournalSet
.Select(c => new SelectListItem
{
Value = c.Id.ToString(),
Text = c.label
});
ViewBag.IdJournal1 = items;
//Conversion
if (imageFile!= null && imageFile.ContentLength > 0)
{
// for now just fail hard if there's any error however in a propper app I would expect a full demo.
using (var engine = new TesseractEngine(Server.MapPath(#"./tessdata"), "eng", EngineMode.Default))
{
// have to load Pix via a bitmap since Pix doesn't support loading a stream.
using (var image = new System.Drawing.Bitmap(imageFile.InputStream))
{
using (var pix = PixConverter.ToPix(image))
{
using (var page = engine.Process(pix))
{
//meanConfidenceLabel.InnerText = String.Format("{0:P}", page.GetMeanConfidence());
//ViewBag.meanConfidenceLabel = String.Format("{0:P}", page.GetMeanConfidence());
ViewBag.resultText = page.GetText();
}
}
}
}
}
return View();
}
My problem is that I don't know which type I should use in the index argument in order to get the image from the view .

You can't send image to controller this way, if you only need the path of the image on controller, use hidden field:
<input type="hidden" name="image" value="img/annonceBrute.JPG"/>
if you want the whole image to be posted on server, you need to use input type file you can't post a html display tag to server using form, in form only input fields are posted on server.
in controller action you can read file like this:
public ActionResult MyAction(FormCollection form)
{
string filePath = Server.MapPath(form["image"].ToString());
byte[] buffer; //file bytes
FileStream fileStream = new FileStream(filePath, FileMode.Open, FileAccess.Read);
try
{
int length = (int)fileStream.Length; // get file length
buffer = new byte[length]; // create buffer
int count; // actual number of bytes read
int sum = 0; // total number of bytes read
// read until Read method returns 0 (end of the stream has been reached)
while ((count = fileStream.Read(buffer, sum, length - sum)) > 0)
sum += count; // sum is a buffer offset for next reading
}
finally
{
fileStream.Close();
}
return View();
}

As it looks that you wants to upload image from view and Get HttpPostedFileBase in controller so use input file tag
<input id="image1" name="image1" type="file" />
in Controller action you should get HttpPosted file like this
if (Request.Files.Count > 0)
{
if (Request.Files["image1"].ContentLength > 0)
{
HttpPostedFileBase pf = Request.Files["image1"]
}
}
Now you can save this HttpPostedFileBase or what ever is your requirement

C# (Asp.net MVC 2) Display image from byte[] in View

I need to save picture in my datebase of asp.net mvc application. I created a field in a table MimeType (nvarchar[50]) and ImageData for save the picture in byte[]. I use ado.net. I save the image in a table like this:
private DBAppl db = new DBAppl();
public void CreateNewCar(newcar Car, HttpPostedFileBase image)
{
if (image != null)
{
Car.mimetype = image.ContentType;
Car.ImageData = new byte[image.ContentLength];
image.InputStream.Read(Car.ImageData, 0, image.ContentLength);
}
db.AddTonewcars(Car);
db.SaveChanges();
}
Picture normal saved in table. Then I walt to display my image in View. I create method in controller
public FileContentResult GetImage(int newcarid)
{
DBAppl db = new DBAppl();
newcar car = (from p in db.newcars
where p.newcarid == newcarid
select p).First();
return File(car.ImageData, car.mimetype.Trim());
}
In view I inserted this code:
<% if (Model.ImageData == null)
{ %>
None
<% }
else
{ %>
<img src="<%= Url.Action("GetImage", "Cars", new { Model.newcarid }) %>" alt="<%: Model.description %>" /> <% } %>
But the picture is not loaded, only alt. Help, what I done wrong? I try to use link in sourse code of html-page but a read that picture have error. I looked in mozilla "Information about the page" and see that page have my picture (778 kb) but it is 0px x 0px.

Try to set headers before returning file
HttpContext.Response.AddHeader("Content-Length"("Content-Type", "image/jpeg"));
or however you are accessing your headers.
use image/jpeg for jpg files
google for other extensions and file tpes.

I solved the problem this way:
public FileContentResult GetImage(int newcarid)
{
DBAppl db = new DBAppl();
newcar car = (from p in db.newcars
where p.newcarid == newcarid
select p).First();
return File(car.ImageData**.ToArray()**, car.mimetype.Trim());
}
In class:
public void CreateNewCar(newcar Car, HttpPostedFileBase image)
{
**var car = new newcar();**
if (image != null)
{
car.name = Car.name;
car.date = DateTime.Now;
car.color = Car.color;
car.picmimetype = image.ContentType;
int length = image.ContentLength;
byte[] buffer = new byte[length];
image.InputStream.Read(buffer, 0, length);
car.ImageData = buffer;
}
db.AddTonewcars(car);
db.SaveChanges();