I am retrieving data from an iSeries where there is a separate date and time fields. I want to join them into a DateTime field in my C# project. I don't see a way to add just a time to a DateTime field. How would you suggest accomplishing this?
You can do this quite easily:
DateTime dateOnly;
DateTime timeOnly;
...
DateTime combined = dateOnly.Date.Add(timeOnly.TimeOfDay);
TimeOfDay returns a TimeSpan, which you then add to the date.
Edit (thanks to commenters below) - to be safe, use dateOnly.Date to ensure the date part only.
How are they being stored? Assuming that the date portion is being stored as a DateTime of midnight of the day in question and the time is a TimeSpan, you can just add them.
DateTime date = ...;
TimeSpan time = ...;
DateTime result = date + time;
You could easily construct a TimeSpan from your "time" field.
Once you have that, just do:
TimeSpan time = GetTimeFieldData();
dateField = dateField.Add(time);
Datetime date = new DateTime(Date1.Year, Date1.Month, Date1.Day, Time1.Hour, Time1.Minute, Time1.Second);
You can add a TimeSpan to a DateTime and write something like this.
// inside consuming function
ISeriesObject obj = getMyObject();
DateTime dt = getDate(obj) + getTime(obj);
private DateTime getDate(ISeriesObject obj)
{
//return a DateTime
}
private TimeSpan getTime(ISeriesObject obj)
{
//return a TimeSpan
}
My answer addresses joining two objects of DateOnly and TimeOnly in .NET 6:
DateOnly orderDate = ...
TimeOnly orderTime = ...
DateTime orderDateTime = orderDate.ToDateTime(orderTime);
This should do:
var output = date.Date + time.TimeOfDay;
or
var output = new DateTime(date.Year, date.Month, date.Day,
time.Hour, time.Minute, time.Second);
suppose that both variable date and time are both of Type DateTime
Note that adding the time to the date is not your biggest problem here. As #Reed Copsey mentioned, you just create a DateTime from the date and then .Add the time.
However, you need to make sure that the iSeries date and time (a Unix time most probably) are in the same representation as the .Net representation. Thus, you most probably need to convert it by adding it to a Jan 1, 1970 DateTime as well.
Cant you simply format the date part and time part as separate strings, then join them together? Then you can parse the string back to a DateTime object
Related
I have a function which is already compact, i wanted to know if there was better (like a DateTime functionality already included).
Currently i use this:
DateTime today = DateTime.Now;
DateTime tomorrow = new DateTime(today.Year, today.Month, today.Day, 0, 0, 0).AddDays(1);
double remaining = (tomorrow - today).TotalMilliseconds;
Thank for reading.
You can simplify the tomorrow value by just doing this and taking the benefit of DateTime.Today:
DateTime tomorrow = DateTime.Today.AddDays(1);
So your code will be easy to read:
DateTime today = DateTime.Now;
DateTime tomorrow = DateTime.Today.AddDays(1);
double remaining = (tomorrow - today).TotalMilliseconds;
You can create extension for DateTime
public static class DateExtensions
{
public static double GetNextDayRemainingMs(this DateTime dateTime)
{
return (dateTime.AddDays(1).Date - dateTime).TotalMilliseconds;
}
}
Usage
DateTime.Now.GetNextDayRemainingMs();
You can try following code
(DateTime.Today.AddDays(1)-DateTime.Now).TotalMilliseconds
Instead of defining instance for tomorrow variable you can use .AddDate(1).Date property
.AddDate(1) will add one day to DateTime.Now and .Date property
will give you only date and sets time to 00.
DateTime today = DateTime.Now;
double remaining = (today.AddDate(1).Date - today).TotalMilliseconds;
Or (Elegant way)
You can use Today property of DateTime.
An object that is set to today's date, with the time component set to
00:00:00.
double remaining = (DateTime.Today.AddDays(1)-DateTime.Now).TotalMilliseconds
I have a calendar and a textbox that contains a time of day. I want to create a datetime that is the combination of the two. I know I can do it by looking at the hours and mintues and then adding these to the calendar DateTime, but this seems rather messy.
Is there a better way?
You can use the DateTime.Add() method to add the time to the date.
DateTime date = DateTime.Now;
TimeSpan time = new TimeSpan(36, 0, 0, 0);
DateTime combined = date.Add(time);
Console.WriteLine("{0:dddd}", combined);
You can also create your timespan by parsing a String, if that is what you need to do.
Alternatively, you could look at using other controls. You didn't mention if you are using winforms, wpf or asp.net, but there are various date and time picker controls that support selection of both date and time.
If you are using two DateTime objects, one to store the date the other the time, you could do the following:
var date = new DateTime(2016,6,28);
var time = new DateTime(1,1,1,13,13,13);
var combinedDateTime = date.AddTicks(time.TimeOfDay.Ticks);
An example of this can be found here
Depending on how you format (and validate!) the date entered in the textbox, you can do this:
TimeSpan time;
if (TimeSpan.TryParse(textboxTime.Text, out time))
{
// calendarDate is the DateTime value of the calendar control
calendarDate = calendarDate.Add(time);
}
else
{
// notify user about wrong date format
}
Note that TimeSpan.TryParse expects the string to be in the 'hh:mm' format (optional seconds).
Using https://github.com/FluentDateTime/FluentDateTime
DateTime dateTime = DateTime.Now;
DateTime combined = dateTime + 36.Hours();
Console.WriteLine(combined);
DateTime newDateTime = dtReceived.Value.Date.Add(TimeSpan.Parse(dtReceivedTime.Value.ToShortTimeString()));
Combine both. The Date-Time-Picker does support picking time, too.
You just have to change the Format-Property and maybe the CustomFormat-Property.
Hi I currently have a TimePicker. It returns an object TimeSpan.
What I need to do is to set a DateTimeOffset that is equal to current date plus the TimeSpan from the TimePicker.
How can I actually get the current DateTimeOffset.now that doesn't have a Time on it, only the Date so that I can add the offset to it.
Thanks
As in DateTime object you have a Date property, it returns date part without time (it means time is 00:00:00).
DateTime today = DateTimeOffset.Now.Date;
DateTime result = today + yourTimeSpan;
With this solution will lost Offset information (because Date is a DateTime). To keep it you just need to subtract time part:
DateTimeOffset now = DateTimeOffset.Now;
DateTimeOffset result = now - now.Time + yourTimeSpan;
Or with constructor:
DateTimeOffset now = DateTimeOffset.Now;
DateTimeOffset result = new DateTimeOffset(now.Date + yourTimeSpan, now.Offset);
Can you not just .Date it?
var a = DateTimeOffset.Now.Date;
try using:
DateTime.Today
instead of Now.
If I have a timestamp in the form: yyyy-mm-dd hh:mm:ss:mmm
How can I just extract the date from the timestamp?
For instance, if a timestamp reads: "2010-05-18 08:36:52:236" what is the best way to just get 2010-05-18 from it.
What I'm trying to do is isolate the date portion of the timestamp, define a custom time for it to create a new time stamp. Is there a more efficient way to define the time of the timestamp without first taking out the date, and then adding a new time?
DateTime.Parse("2010-05-18 08:36:52:236").ToString("yyyy-MM-dd");
You should use the DateTime type:
DateTime original = DateTime.Parse(str);
DateTime modified = original.Date + new TimeSpan(13, 15, 00);
string str = modified.ToString("yyyy-MM-dd HH:mm:ss:fff");
Your format is non-standard, so you'll need to call ParseExact instead of Parse:
DateTime original = DateTime.ParseExact(str, "yyyy-MM-dd HH:mm:ss:fff", CultureInfo.InvariantCulture);
You could use substring:
"2010-05-18 08:36:52:236".Substring(0, 10);
Or use ParseExact:
DateTime.ParseExact("2010-05-18 08:36:52:236",
"yyyy-MM-dd HH:mm:ss:fff",
CultureInfo.InvariantCulture)
.ToString("yyyy-MM-dd");
DateTime date;
if (DateTime.TryParse(dateString, out date))
{
date = date.Date; // Get's the date-only component.
// Do something cool.
}
else
{
// Flip out because you didn't get a real date.
}
Get the .Date member on the DateTime
DateTime date = DateTime.Now;
DateTime midnightDate = date.Date;
use it like this:
var x = DateTime.Now.Date; //will give you midnight today
x.AddDays(1).AddTicks(-1); //use these method calls to modify the date to whats needed.
The best (and fastest) way to do this is to convert the date to an integer as the time part is stored in the decimal part.
Try this:
select convert(datetime,convert(int, #yourdate))
So you convert it to an integer and then back to a data and voila, time part is gone.
Of course subtracting this result from the original value will give you the time part only.
I use this to convert DateTime value into Date and then I add 00:00:00 and 23:59:59 to make sure whole day is taken into consideration when counting stuff. I'm pretty sure it's wrong way of doing things. What would be the right way?
DateTime varObliczOd = DateTime.Parse(dateTimeWycenaPortfelaObliczDataOd.Value.ToShortDateString() + " 00:00:00");
DateTime varObliczDo = DateTime.Parse(dateTimeWycenaPortfelaObliczDataDo.Value.ToShortDateString() + " 23:59:59");
if dateTimeWycenaPortfelaObliczDataOd is of type DateTime, You can use:
dateTimeWycenaPortfelaObliczDataOd.Date
to get the date part only (time will be 00:00:00...).
If you want to get the very last tick of the date, you can use:
dateTimeWycenaPortfelaObliczDataOd.Date.AddDays(1).AddTicks(-1)
but you really better work with the next date (.AddDays(1)).
In any case, there is no need to convert to string and back to DateTime.
DateTime objects have a Date property which might be what you need.
You can use the following properties / methods on a DateTime object to get your values :
DateTime varObliczOd = dateTimeWycenaPortfelaObliczDataOd.Date;
DateTime varObliczDo = dateTimeWycenaPortfelaObliczDataOd.AddDayes(1).AddTicks(-1);
It would help to know why you're needing it, but this would work.
DateTime varObliczOd = dateTimeWycenaPortfelaObliczDataOd.Date;
DateTime varObliczDo = varObliczOd.AddDays(1).AddSeconds(-1);
Using the Date attribute and then manipulating them directly to create the required time component - no need to bother with parsing and conversion.
You could use the Date property of the DateTime object to accomplish what you need.
DateTime varObliczOd = dateTimeWycenaPortfelaObliczDataOd.Value.Date;
DateTime varObliczDo = dateTimeWycenaPortfelaObliczDataDo.Value.Date.AddDays(1);
If you really want it to end at 23:59:59 you can do:
DateTime varObliczDo = dateTimeWycenaPortfelaObliczDataDo.Value.Date.AddDays(1).AddSeconds(-1);
Will set varObliczDo to be your ending date with no time plus one day (at midnight). So if dateTimeWycenaPortfelaObliczDataDo was 2010-03-05 16:12:12 it would now be 2010-03-06 00:00:00.
Something like this maybe? I've typed this out of my head, there are probably some mistakes in the code.
DateTime varObliczOd = dateTimeWycenaPortfelaObliczDataOd.AddSeconds(-dateTimeWycenaPortfelaObliczDataOd.Seconds).AddMinutes(-dateTimeWycenaPortfelaObliczDataOd.Minutes).AddHours(-dateTimeWycenaPortfelaObliczDataOd.Hours);
DateTime varObliczDo = new DateTime(dateTimeWycenaPortfelaObliczDataDo.Year, dateTimeWycenaPortfelaObliczDataDo.Month, dateTimeWycenaPortfelaObliczDataDoDay, 23, 59, 59);
DateTime newDate = new DateTime( oldDate.Year, oldDate.Month, oldDate.Day, 23, 59,59 )
DateTime newDate = new DateTime( oldDate.Year, oldDate.Month, oldDate.Day, 0, 0, 0 )
You could work with TimeSpan:
DateTime varObliczOd = dateTimeWycenaPortfelaObliczDataOd - new TimeSpan(dateTimeWycenaPortfelaObliczDataOd.Hours, dateTimeWycenaPortfelaObliczDataOd.Minutes, dateTimeWycenaPortfelaObliczDataOd.Seconds);
Like that you avoid at least the parsing, which can fail depending on the local culture settings.