Unhandled Exception inside OnException and inside catch block in Asp.Net - c#

I have a GlobalExceptionFilterAttribute.cs file that I intend to catch unhandled exceptions globally:
public override void OnException (HttpActionExecutedContext actionExecutedContext)
{
// SplunkHelper has bug that creates other exception
SplunkerHelper.LogApplication(actionExecutedContext.Exception);
}
I have two questions:
How to take care the error raised by SplunkerHelper.LogApplication() to avoid crashing the server?
If there are some try catch blocks inside the application like below, would the exception caused by logger be caught in GlobalExceptionFilterAttribute.cs? If not, how to take care of it?
try
{
// do something here
}
catch (Exception ex)
{
// logger is a null, which causes exception
logger.log("error")
throw;
}

Related

Custom exception- Try catch - in c#

it is allowed to use custom exception, where the exception can be thrown like below.
try
{
int foo = int.Parse(token);
}
catch (FormatException ex)
{
//Assuming you added this constructor
throw new ParserException(
$"Failed to read {token} as number.",
FileName,
LineNumber,
ex);
}
But in a normal try catch block, it says , throwing exceptions will clear the stacktrace.
try
{
ForthCall();
}
catch (Exception ex)
{
throw ex;
}
So in custom exception,how it managed to use throw exception, without clear the stacktrace?
There are several ways this can be done.
As mentioned in this link In C#, how can I rethrow InnerException without losing stack trace?, you can use the ExceptionDispatchInfo Class
with code similar to
try
{
task.Wait();
}
catch(AggregateException ex)
{
ExceptionDispatchInfo.Capture(ex.InnerException).Throw();
}
Another way is to have your handler return a boolean, whether the exception was handled or not, so you can use this in your catch clause:
catch (Exception ex) {
if (!HandleException(ex)) {
throw;
}
}
where HandleException is your custom Exception handler. Gotten from this link: How to throw exception without resetting stack trace?
Whenever you use throw with an exception object, it fills in the stack trace at that point. (Compare to Java, which populates stack traces when an exception is constructed.)
If you use throw without an exception object, which you can only do in a catch clause, the caught exception object is re-throw without alteration.

When does the catch arguments get checked in a try/catch block c#

I'm having an issue with a try/catch block, but I can't seem to find out exactly how try/catch works when it's running that I think might have my answer. I have the following try/catch block:
try
{
...
}
catch (MyException e)
{
Log.Error("oh no!");
throw;
}
Now when I run this code I'm getting a System.TypeLoadException: Could not load type SDK.MyException from assembly "SDKSampleLibrary, Version... etc error.
I'm wondering 2 things. First, when does the computer check to see if MyException is there. Is it when it gets to the try or when it gets to the catch? Second, the SDKSampleLibrary.dll is there. How do I tell why it's not seeing it?
If the class MyException gets thrown within the try area, it will get handled inside the catch, See my example below where i throw a new exception which would get handled by the catch statement. However any other kinds of exceptions would not be handled/
try
{
throw(new MyException()); // handled by the catch
throw(new ParseException()); //not handled.
int test = "test" //not handled
}
catch (MyException e)
{
Log.Error("oh no!");
throw;
}
can also catch general exceptions to catch ALL exceptions like:
try
{
throw(new MyException()); // handled by the catch
throw(new ParseException()); //handled.
int test = "test" //handled
}
catch (Exception e)
{
Log.Error("oh no!");
throw;
}
The compiler sees the class since it is blue and does not give compile errors. The problems is happening when you are running the code. I think the problem is in de code that throws the exception which cannot create it. You could try to use the normal Exception type in the catch block and then set a break point.
The problem is not with the try/catch block but rather the problem is the type of exception that you are trying to catch as specified by the exception that your code is throwing. This exception occurs when the runtime tries to load the MyException object. You should make sure that the MyException inherits either from the Exception base class or from any of its children.

Why is the catch block not being triggered?

I am trying to log errors to a file but I can't seem to get the catch block to run when an error occurs. Here is an example of the code:
try
{
cmd.ExecuteNonQuery();
}
catch (MySQLException ex)
{
//run some logging code
}
finally
{
//clean up the resources
}
The problem is when there is an exception, I get the error thrown from the built in webserver that its an unhandled exception. When I debug the code stops at the exception then continues on to the finally block. Can someone point me in the right direction here?
ExecuteNonQuery() throws an exception of type SqlException.
So I'm not sure what MySQLException is, but you need to be catching an SqlException.
Look at this for extra info:
SqlCommand.ExecuteNonQuery Method
SqlException Class.
It seems like the exception thrown is not not of type MySQLException or any exception derived from it. So the catch block never never catches it and the finally block is executed directly!
To check what kind of exception was raised, modify the code to:
try
{
cmd.ExecuteNonQuery();
}
catch (MySQLException ex)
{
//run some logging code
}
catch (Exception ex)
{
// any other exception will be handled here
}
finally
{
//clean up the resources
}
That method can throw different types of exceptions
InvalidCastException
SqlException
IOException
InvalidOperationException
ObjectDisposedException

Exception.Data and Exception Handling Questions

I have a couple questions about exceptions.
1) when you hit a catch block, swallowing means what exactly? I thought it was always rethrow or the existing exceptions is passed up to the next catch block.
2) If you add Exception.Data values to an excepction, I notice I have to do another throw; to grab that data futher up in another catch block later. Why?
Swallowing an exception means catching it and not doing anything useful with it. A common thing you might see is this:
try
{
DoSomeOperationThatMightThrow();
}
catch (Exception ex) // don't do this!
{
// exception swallowed
}
You usually don't want to catch a base Exception at all, it's better to catch and handle specific Exception types, and ideally you should only catch exception types that you can do something useful with at the level of code you're in. This can be tricky in complex applications, because you might be handling different errors at different levels in the code. The highest level of code might just catch serious/fatal exceptions, and lower levels might catch exceptions that can be dealt with with some error handling logic.
If you do catch an exception and need to rethrow it, do this:
try
{
DoSomething();
}
catch (SomeException ex)
{
HandleError(...);
// rethrow the exception you caught
throw;
// Or wrap the exception in another type that can be handled higher up.
// Set ex as the InnerException on the new one you're throwing, so it
// can be viewed at a higher level.
//throw new HigherLevelException(ex);
// Don't do this, it will reset the StackTrace on ex,
// which makes it harder to track down the root issue
//throw ex;
}
Swallowing an exception normally means having a handling block for the exception, but not doing anything in the block. For example:
try { 3/0; } catch DivideByZeroException { //ignore } //Note: I know this really wont' compile because the compiler is smart enough to not let you divide by a const of 0.
You have to rethrow because the first handler for an exception is the only one that will execute.
If you want the exception to bubble up you either don't handle it or you rethrow it. By the way, it's important to note that in .NET by just saying "throw" you'll preserve the stack trace. If you "throw Exception" you'll lose your stack trace.
Ok, you can handle the exception up to call stack you can do some thing like this:
public class A
{
public void methodA()
{
try
{
}
catch(Exception e)
{
throw new Exception("Some description", e);
}
}
}
public class B
{
public void methodB()
{
try
{
A a = new A();
a.methodA();
}
catch(Exception e)
{
//...here you get exceptions
}
}
}

The mystery of the twin exceptions

Here's an interesting question. I have a system that attempts to run some initialization code. If it fails, we call the deinitializer to clean everything up.
Because we call the deinitializer in exception handling, we run the risk that both initialize and deinitialize will fail, and hypothetically, it now seems that we have to throw two exceptions.
It seems pretty unlikely that we will, though. So what happens and what should the code do here?
try { /* init code here */ }
catch (Exception ex)
{
try
{
_DeinitializeEngine();
}
catch (Exception ex2)
{
throw new OCRException("Engine failed to initialize; ALSO failed to deinitialize engine!", ex2);
}
finally
{
throw new OCRException("Engine failed to initialize; failed to initialize license!", ex);
}
}
You shouldn't throw in the Finally block. Instead, use the InnerException to add information in the throw.
Update
What you have to do is to catch and rethrow with the "history" of exception, this is done with InnerException. You can edit it when bulding a new exception. This is a code snippet I just wrote to illustrate the idea that I explain in all the comments below.
static void Main(string[] args)
{
try
{
principalMethod();
}
catch (Exception e)
{
Console.WriteLine("Test : " + e.Message);
}
Console.Read();
}
public static void principalMethod()
{
try
{
throw new Exception("Primary");
}
catch (Exception ex1)
{
try
{
methodThatCanCrash();
}
catch
{
throw new Exception("Cannot deinitialize", ex1);
}
}
}
private static void methodThatCanCrash()
{
throw new NotImplementedException();
}
No need to use double throw with finalize. If you put a break point at the Console.WriteLine(...). You will notice that you have all the exception trace.
If your clean up code is failing and you cannot leave the application in a clean and known state I would let the exception go unhandled (or catch it with the UnhandledException event to log it) then close the application.
Because if you can't handle the first exception, what point is there in catching the second exception?
If I understand your problem correctly, here's what I would have done:
try { /* init code here */ }
catch (Exception ex)
{
// Passing original exception as inner exception
Exception ocrex = new OCRException("Engine failed to initialize", ex);
try
{
_DeinitializeEngine();
}
catch (Exception ex2)
{
// Passing initialization failure as inner exception
ocrex = new OCRException("Failed to deinitialize engine!", ocrex);
}
throw ocrex;
}
You have two possible exception conditions: one in which the first method failed, and one in which both methods failed.
You're already defining your own exception class. So create another (or extend the first) with a RelatedException or PriorException property. When you throw the exception in the second case, save a reference to the first exception in this property.
It's up to the exception handler that catches this exception to figure out what to do with the second exception.

Categories

Resources