Develop Reference

C# Error : Unable to insert record in SQL

Please pardon my knowledge on C# as I am very new to it,I am unable to insert a record in SQL and getting the below error while insert image to SQL.
Error :
Object reference not set to an instance of an object.
MemoryStream ms = new MemoryStream();
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
byte[] img = ms.ToArray();
if (img == null)
{
com.Parameters.AddWithValue("#img", null);
}
else
{
com.Parameters.AddWithValue("#img", img);
}
If i select a image and insert it inserts successfully, but if i do not select an image it throws the above error.
Please help!!

Change this:
MemoryStream ms = new MemoryStream();
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
byte[] img = ms.ToArray();
if (img == null)
{
com.Parameters.AddWithValue("#img", null);
}
else
{
com.Parameters.AddWithValue("#img", img);
}
To this
MemoryStream ms = new MemoryStream();
pictureBox1?.Image?.Save(ms, pictureBox1?.Image?.RawFormat);
byte[] img = ms.ToArray();
com.Parameters.AddWithValue("#img", (object)img ?? DBNull.Value);

Try testing that PictureBox1.Image exists before referencing it, like this:
if (pictureBox1.Image != null)
{
MemoryStream ms = new MemoryStream();
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
byte[] img = ms.ToArray();
com.Parameters.AddWithValue("#img", img);
}
else
{
com.Parameters.Add("#img", SqlDbType.VarBinary, 0).Value = DbNull.Value;
}
EDITED to include comment by GarethD

first, you need to make a new condition to check is file selected or not.here are code below:
if pictureBox1.hasfile == true
{
MemoryStream ms = new MemoryStream();
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
byte[] img = ms.ToArray();
if (img == null)
{
com.Parameters.AddWithValue("#img", null);
}
else
{
com.Parameters.AddWithValue("#img", img);
}
}
because you are not selecting any file thats why it throwing exception on runtime

How can I decode a byte array using a JpegBitmapDecoder

I cannot decode images back from their encoded form as a (Jpeg) byte array retrieved from my database to be used as image sources for my WPF application.
The code I am using to encode them as a Jpeg byte array is as follows:
public byte[] bytesFromBitmap(BitmapImage bit)
{
byte[] data;
JpegBitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(bit));
using (MemoryStream ms = new MemoryStream())
{
encoder.Save(ms);
data = ms.ToArray();
}
return data;
}
This is taking my Image taken directly from a webpage and assigned to an Image control like so:
var img = new BitmapImage(new Uri(entity.Image.ImageSrc)); //the entity has been saved in my DB, having been parsed from html
pbImage.Source = img;
This works just fine, I encode the BitmapImage and it saves just fine. But when I retrieve it from the DB and try to display it in another window, I cannot get it to work after trying every example I can see online - all either render nothing, or a black box or a visual mess not at all similar to the image I encoded.
Neither of the following have worked for me:
public BitmapSource GetBMImage(byte[] data)
{
using (var ms = new MemoryStream(data))
{
JpegBitmapDecoder decoder = new JpegBitmapDecoder(ms, BitmapCreateOptions.PreservePixelFormat, BitmapCacheOption.Default);
BitmapSource frame = decoder.Frames[0];
return frame;
}
}
public static BitmapImage ImageFromBytes(byte[] imageData)
{
if (imageData == null)
{
return null;
}
else
{
var image = new BitmapImage();
using (var mem = new MemoryStream())
{
mem.Position = 0;
image.BeginInit();
image.CreateOptions = BitmapCreateOptions.PreservePixelFormat;
image.CacheOption = BitmapCacheOption.OnLoad;
image.UriSource = null;
image.StreamSource = mem;
image.EndInit();
}
image.Freeze();
return image;
}
} //this throws a 'No imaging component suitable to complete this operation was found' exception
Among other uses of memory streams and decoders I just can't get this to work - can anyone help?

Converting image to base64

I have the following code to convert image to base64:
private void btnSave_Click(object sender, RoutedEventArgs e)
{
StreamResourceInfo sri = null;
Uri uri = new Uri("Checked.png", UriKind.Relative);
sri = Application.GetResourceStream(uri);
BitmapImage bitmap = new BitmapImage();
bitmap.SetSource(sri.Stream);
WriteableBitmap wb = new WriteableBitmap(bitmap);
MemoryStream ms = new MemoryStream();
wb.SaveJpeg(ms, bitmap.PixelWidth, bitmap.PixelHeight, 0, 100);
byte[] imageBytes = ms.ToArray();
base64 = System.Convert.ToBase64String(imageBytes);
}
And the following code to get Bitmap image form base 64:
public static BitmapImage base64image(string base64string)
{
byte[] fileBytes = Convert.FromBase64String(base64string);
using (MemoryStream ms = new MemoryStream(fileBytes, 0, fileBytes.Length))
{
ms.Write(fileBytes, 0, fileBytes.Length);
BitmapImage bitmapImage = new BitmapImage();
bitmapImage.SetSource(ms);
return bitmapImage;
}
}
So when i convert and deconvert it is blank.
I know that deconverter works, because, when i give him exact string:
string base64="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";
Which is my Checked.png converted in online converter. It decompreses perfectly.
And this is my base64, which i get by converting:
"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"
My problem is that string which i get as base64 from my code - is incorrect *What i did wrong?*

What about trying:
public static BitmapImage base64image(string base64string)
{
byte[] fileBytes = Convert.FromBase64String(base64string);
using (MemoryStream ms = new MemoryStream(fileBytes))
{
Image streamImage = Image.FromStream(ms);
context.Response.ContentType = "image/jpeg";
streamImage.Save(context.Response.OutputStream, ImageFormat.Jpeg);
return streamImage;
}
}
I agree with Alexei that your code for reading the image in does look a little strange. I've recently written some code for a similar task that I was doing which might point you in the right direction:
string fileContent = null;
/* Check the file actually has some content to display to the user */
if (uploadFile != null && uploadFile.ContentLength > 0)
{
byte[] fileBytes = new byte[uploadFile.ContentLength];
int byteCount = uploadFile.InputStream.Read(fileBytes, 0, (int)uploadFile.ContentLength);
if (byteCount > 0)
{
fileContent = CreateBase64Image(fileBytes);
}
}
private string CreateBase64Image(byte[] fileBytes)
{
Image streamImage;
/* Ensure we've streamed the document out correctly before we commit to the conversion */
using (MemoryStream ms = new MemoryStream(fileBytes))
{
/* Create a new image, saved as a scaled version of the original */
streamImage = ScaleImage(Image.FromStream(ms));
}
using (MemoryStream ms = new MemoryStream())
{
/* Convert this image back to a base64 string */
streamImage.Save(ms, System.Drawing.Imaging.ImageFormat.Png);
return Convert.ToBase64String(ms.ToArray());
}
}

not an answer: more of a long comment ... OP states that decoding code works perfectly fine, also it looks suspicios. Also code assumed to be verified to work on PNG images, but saving code explicitly produces valid JPG with SaveJpeg call...
Your code that creates stream for reading looks strange - you create stream over existing byte array, than write the same bytes into that stream, and that pass that stream without seeking back to 0 to some method.
Potential fix (assuming BitampImage can accept JPG stream):
don't call Write at all as stream already have the bytes you want
set ms.Position = 0 after writing to the stream.
Note: I'm not sure if it is OK to dispose stream that is a source for BitmapImage, you may need to remove using too.

showing image in gridview from byte array

I have a following problem:
I am using c# and .aspx pages. On .aspx page i have a GridView. I set a GridView datasource to be:
GridView1.DataSource = PictureInfo.PictureInfoList;
My "PictureInfo" class looks like this:
public class PictureInfo
{
public static List<PictureInfo> PictureInfoList = new List<PictureInfo>();
public string PictureDescription { get; set; }
public byte[] Picture { get; set; }
}
Is it possible and how to show a picture which is in "byte[] Picture" in a GridView? Or which way it is possible? I'm saving data in this way before i send it to a database. And i would like to show it in a GridView before i send it to a database. As you can see I'm a beginner but i would be very happy if i could make this work. My head hearts already from reading some solutions online, none helped until now.
thank you very much

I suggest you a solution for: Converting byte[] to Bitmap (may it will be useful for you):
public BitmapSource ByteArrayToBitmap(byte[] byteArray) {
BitmapSource res;
try {
using (var stream = new MemoryStream(byteArray)) {
using (var bmp = new Bitmap(stream)) {
res = ToBitmap(bmp);
}
}
} catch {
res = null;
}
return res;
}
public BitmapSource ToBitmap(Bitmap bitmap) {
using (var stream = new MemoryStream()) {
bitmap.Save(stream, ImageFormat.Bmp);
stream.Position = 0;
var result = new BitmapImage();
result.BeginInit();
result.CacheOption = BitmapCacheOption.OnLoad;
result.StreamSource = stream;
result.EndInit();
result.Freeze();
return result;
}
}
Next, you should adapt, and include the Bitmap in your GridView.

on your handler.ashx
public void ProcessRequest(HttpContext context)
{
context.Response.ContentType = "image/jpeg";
string ImageID=request["ID"];
//byte[] ImageByte=pictureInfo.Picture;//local imageByte
byte[] ImageByte=getImage(ImageId);//image byte from any other sour,e.g database
Stream strm = new MemoryStream(ImageByte));
long length = strm.Length;
byte[] buffer = new byte[length];
int byteSeq = strm.Read(buffer, 0, 2048);
while (byteSeq > 0)
{
context.Response.OutputStream.Write(buffer, 0, byteSeq);
byteSeq = strm.Read(buffer, 0, 2048);
}
}
now set image url for your asp:image inside your gridview as follows
Image1.ImageUrl = "somthing.ashx?ID="+userImageID;
i hope you have unique id for your image to be visible. I hope you have all set now. Comments and query are well comed.
retrieve image byte from database
public byte[] GetImage(string ImageId)
{ byte[] img = null;
DataTable dt = new DataTable();
SqlCommand cmd = new SqlCommand();
cmd.CommandType = CommandType.StoredProcedure;
cmd.CommandText = "SlikaHendler";
cmd.Parameters.AddWithValue("#Id", ImageId);
cmd.Connection = yourConnection();
SqlDataReader dr = null;
dr = cmd.ExecuteReader();
if (dr.Read())
{
img = (byte[])dr[0];
}
dr.Close();
return img;//returns array of byte
}

I know pictures are recorded as binaries to databases. In this aspect, your problem turns to a "converting binary to byte".
If you can reach your picture info as binary data, you can convert it as taking 3 digits for 1 byte, and convert & show as bytes.
http://en.wikipedia.org/wiki/ASCII

Image.FromStream() method returns Invalid Argument exception

I am capturing images from a smart camera imager and receiving the byte array from the camera through socket programming (.NET application is the client, camera is the server).
The problem is that i get System.InvalidArgument exception at runtime.
private Image byteArrayToImage(byte[] byteArray)
{
if(byteArray != null)
{
MemoryStream ms = new MemoryStream(byteArray);
return Image.FromStream(ms, false, false);
/*last argument is supposed to turn Image data validation off*/
}
return null;
}
I have searched this problem in many forums and tried the suggestions given by many experts but nothing helped.
I dont think there is any problem with the byte array as such because When i feed the same byte array into my VC++ MFC client application, i get the image. But this doesn't somehow work in C#.NET.
Can anyone help me ?
P.S :
Other methods i've tried to accomplish the same task are:
1.
private Image byteArrayToImage(byte[] byteArray)
{
if(byteArray != null)
{
MemoryStream ms = new MemoryStream();
ms.Write(byteArray, 0, byteArray.Length);
ms.Position = 0;
return Image.FromStream(ms, false, false);
}
return null;
}
2.
private Image byteArrayToImage(byte[] byteArray)
{
if(byteArray != null)
{
TypeConverter tc = TypeDescriptor.GetConverter(typeof(Bitmap));
Bitmap b = (Bitmap)tc.ConvertFrom(byteArray);
return b;
}
return null;
}
None of the above methods worked. Kindly help.

Image.FromStream() expects a stream that contains ONLY one image!
It resets the stream.Position to 0. I've you have a stream that contains multiple images or other stuff, you have to read your image data into a byte array and to initialize a MemoryStream with that:
Image.FromStream(new MemoryStream(myImageByteArray));
The MemoryStream has to remain open as long as the image is in use.
I've learned that the hard way, too.

Maybe the image is embedded in an OLE field and you have to consider the 88 bytes OLE header plus payload:
byteBlobData = (Byte[]) reader.GetValue(0);
stream = new MemoryStream(byteBlobData, 88, byteBlobData.Length - 88);
img = Image.FromStream(stream);

I'm guessing that something is going wrong when receiving the file from the server. Perhaps you're only getting part of the file before trying to convert it to an Image? Are you sure it's the exact same byte array you're feeding the C++ application?
Try saving the stream to a file and see what you get. You might be able to uncover some clues there.
You can also add a breakpoint and manually compare some of the bytes in the byte array to what they're supposed to be (if you know that).
Edit: It looks like there's nothing wrong with receiving the data. The problem is that it's in raw format (not a format that Image.FromStream understands). The Bitmap(Int32, Int32, Int32, PixelFormat, IntPtr) constructor may be of use here. Or, you can create the blank bitmap and blt it manually from the raw data.

I've had this problem when doing this:
MemoryStream stream = new MemoryStream();
screenshot.Save(stream, ImageFormat.Png);
byte[] bytes = new byte[stream.Length];
stream.Save(bytes, 0, steam.Length);
With the last 2 lines being the problem. I fixed it by doing this:
MemoryStream stream = new MemoryStream();
screenshot.Save(stream, ImageFormat.Png);
byte[] bytes = stream.ToArray();
And then this worked:
MemoryStream stream = new MemoryStream(bytes);
var newImage = System.Drawing.Image.FromStream(stream);
stream.Dispose();

System.InvalidArgument means The stream does not have a valid image format, i.e. an image type that is not supported.

Try this:
public Image byteArrayToImage(byte[] item)
{
Image img=Image.FromStream(new MemoryStream(item));
img.Save(Response.OutputStream, ImageFormat.Gif);
return img;
}
Hope it helps!

I've had the same problem in the past and it was caused by a leak within the windows GDI libraries, which is what 'Bitmap' uses. If this happening all the time for you then its probably unrelated, however.

this code is working
string query="SELECT * from gym_member where Registration_No ='" + textBox9.Text + "'";
command = new SqlCommand(query,con);
ad = new SqlDataAdapter(command);
DataTable dt = new DataTable();
ad.Fill(dt);
textBox1.Text = dt.Rows[0][1].ToString();
textBox2.Text = dt.Rows[0][2].ToString();
byte[] img = (byte[])dt.Rows[0][18];
MemoryStream ms = new MemoryStream(img);
pictureBox1.Image = Image.FromStream(ms);
ms.Dispose();

Try to use something similar to what is described here https://social.msdn.microsoft.com/Forums/vstudio/en-US/de9ee1c9-16d3-4422-a99f-e863041e4c1d/reading-raw-rgba-data-into-a-bitmap
Image ImageFromRawBgraArray(
byte[] arr,
int charWidth, int charHeight,
int widthInChars,
PixelFormat pixelFormat)
{
var output = new Bitmap(width, height, pixelFormat);
var rect = new Rectangle(0, 0, width, height);
var bmpData = output.LockBits(rect, ImageLockMode.ReadWrite, output.PixelFormat);
// Row-by-row copy
var arrRowLength = width * Image.GetPixelFormatSize(output.PixelFormat) / 8;
var ptr = bmpData.Scan0;
for (var i = 0; i < height; i++)
{
Marshal.Copy(arr, i * arrRowLength, ptr, arrRowLength);
ptr += bmpData.Stride;
}
output.UnlockBits(bmpData);
return output;
}

After load from DataBase byteArray has more byte than one image. In my case it was 82.
MemoryStream ms = new MemoryStream();
ms.Write(byteArray, 82, byteArray.Length - 82);
Image image = Image.FromStream(ms);
And for save in the DB I insert 82 byte to begin stream. Properties.Resources.ImgForDB - it is binary file that contain those 82 byte. (I get it next path - Load Image from DB to MemoryStream and save to binary file first 82 byte. You can take it here - https://yadi.sk/d/bFVQk_tdEXUd-A)
MemoryStream temp = new MemoryStream();
MemoryStream ms = new MemoryStream();
OleDbCommand cmd;
if (path != "")
{
Image.FromFile(path).Save(temp, System.Drawing.Imaging.ImageFormat.Bmp);
ms.Write(Properties.Resources.ImgForDB, 0, Properties.Resources.ImgForDB.Length);
ms.Write(temp.ToArray(), 0, temp.ToArray().Length);
cmd = new OleDbCommand("insert into Someone (first, Second, Third) values (#a,#b,#c)", connP);
cmd.Parameters.AddWithValue("#a", fio);
cmd.Parameters.AddWithValue("#b", post);
cmd.Parameters.AddWithValue("#c", ms.ToArray());
cmd.ExecuteNonQuery();