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C# Count decimal places without considering the trailing zeros [closed]

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For a given decimal with precision of 8 like 0.00010000, I would like to get the decimal places without the trailing zeros.
All methods that I tested returned 8, and in this case should be 4.

You can use string value=decimalValue.ToString("0.########") this will convert the value into a string and show up to 8 decimal places, without trailing zeros. Eg. 1.05000000 - > 1.05, 1.00000001->1.00000001. Then value.Split('.').ToList().ElementAt(1).Length

string output = Regex.Replace("0.00010000", #"[0]*$", "");

decimal someDecimal = 0.00010000000m;
Console.WriteLine(someDecimal.ToString().TrimEnd('0'));

Left-pad a floating point number without losing trailing zeros after decimal point [closed]

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I am attempting to write out to a fixed format text file and am having some trouble formatting the numbers properly. It needs to be padded with leading zeros and an implied decimal.
Example:
43.80
The output would need to be:
0000004380
So far, I have attempted to convert the double to a string, replace the decimal, and then pad with "0".
((amount.ToString()).Replace(".","")).PadLeft(10, '0')
The problem with this is when the number ends with zeros. The above example comes out as:
0000000438
Any suggestions?

decimal value = 34.80M;
int intVal = (int)(value * 100);
return intVal.ToString("0000000000");

You could try:
((string.Format("{0:0.00}", amount)).Replace(".","")).PadLeft(10, '0')
That way you don't lose the 2nd decimal place when the value is 0.

You can pass a .ToString() format string in as described in this article:
https://msdn.microsoft.com/en-us/library/dwhawy9k(v=vs.110).aspx
Does the incoming value always have two decimal places? If so, you could multiply by 100 to get rid of the decimal, and then to .ToString("D10")
(Int)(43.80 * 100).ToString("D10")

This should do the job : $"{(int)(amount * 100):D010}"

Should the currecy textbox in winforms gets rounding done all the time? [closed]

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i have standard windows textbox that is formatted for currency but there is minor issue, when the user enter a value like 19999.9999999, this get rounded to 20000.00. If the user enters the value as 19999.99 this value will not get rounded. In the big industry, what is the correct way to format this number?
I need this to be rounded without harming the property value!

How about Math.Round.
try like this
decimal dValue = Math.Round(19999.999999M, 3);
Take a look at the msdn for complete reference of Math.Round() method.

Number to String (Always 2 decimal Place) [closed]

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I want to show a double value to label (C#) with 2 decimal places no matters that value like 13 or 13.5 or 13.505
Its always show 13.00

You can pass the format in to the to string method
eg:
ToString("0.00"); //2dp Number
ToString("n2"); // 2dp Number
ToString("c2"); // 2dp currency
http://msdn.microsoft.com/en-us/library/dwhawy9k.aspx
To change, for example, 13.505 to 13.00 you'd also want to run it through Math.Floor or use one of the other suggested methods for rounding down.
Math.Floor(value)
http://msdn.microsoft.com/en-us/library/e0b5f0xb.aspx
If, on the other hand, you want to change 13.505 to 13.50 you'd want to run it through Math.Truncate.
Math.Truncate(Value)
http://msdn.microsoft.com/en-us/library/7d101hyf(v=vs.110).aspx
So to tie that together:
Double testValue = 13.505;
Double testValueTruncated = Math.Truncate(100 * testValue) / 100;
string withDecimalPlaces = testValueTruncated.ToString("0.00");
withDecimalPlaces will now have the value "13.50"

try this method
double i=12.22222; //first variable
double j=1.2545; //second variable
double h=i*j; // multiple first and second
string s=h.ToString("0.00"); // convert to string and proper format
this methed return
s="15.33"

C# Convert To Decimal String Value like 0.33 [closed]

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How to convert this string to decimal 0.55 exactly.
Decimal.parse("0,55")
I need to get exact value excluding leading zeroes.

This should fix your problem (if I understand the problem, that is):
var number = decimal.Parse("0,55".Replace(',', '.'), CultureInfo.InvariantCulture);
EDIT
Not every culture uses the point (.) symbol as the decimal separator. If you don't specify a format provider, the framework defaults to the current culture. I'm guessing that in this particular case, the decimal.Parse() method was interpreting "0,55" as decimal 55.0.