I'm doing operations on images. Some of these operations require me to create 3 different versions of the pixel data from the image and then later on combine them and do operantions on it.
For regular/small images the code works fine, I simply initialize my image raster data as new int[size].
However for bigger images with a bigger resolution (600, 1200, ...) the new int[size] throws an OutOfMemoryException. Trying to allocate more than 2GB. However I've built it 64bit (not anycpu or 32bit).
To resolve this issue, I've tried to create a MemoryMappedFile in memory itself. This gave me out of resource also. Next I've tried to create a MemoryMappedFile but by first creating a file on disk and then creating a accessor over the complete file.
Still I'm facing the not enough resources with the temporary file on disk and the MemoryMappedFile/ViewAcessor.
Am I doing something wrong in the code below? I thought the MMF and Accessor would handle the virtual memory paging automagically.
mmfPath = Path.GetTempFileName();
// create a file on disk first
using (var fs = File.OpenWrite(mmfPath))
{
var widthBytes = new byte[width * 4];
for (int y = 0; y < height; y++)
{
fs.Write(widthBytes, 0, widthBytes.Length);
}
}
// open the file on disk as a MMF
_RasterData = MemoryMappedFile.CreateFromFile(mmfPath,
FileMode.OpenOrCreate,
Guid.NewGuid().ToString(),
0, // 0 to set te capacity to the size of the file on disk
MemoryMappedFileAccess.ReadWrite);
_RasterDataAccessor = _RasterData.CreateViewAccessor(); // <-- not enough memory resources
Not enough memory resources are available to process this command.
at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath)
at System.IO.MemoryMappedFiles.MemoryMappedView.CreateView(SafeMemoryMappedFileHandle memMappedFileHandle, MemoryMappedFileAccess access, Int64 offset, Int64 size)
at System.IO.MemoryMappedFiles.MemoryMappedFile.CreateViewAccessor(Int64 offset, Int64 size, MemoryMappedFileAccess access)
at System.IO.MemoryMappedFiles.MemoryMappedFile.CreateViewAccessor()
...
In case I can resolve the problem above, I think I will later on run again on the same issue when I need to create a resulting bitmap out of the pixeldata again. (2GB limit).
The goal is working with big images (and temporary copies of its pixeldata for raster/raster operations).
The current issue is that I'm getting Out of memory resources with MemoryMappedFile. Where I thought this would resolve the 2GB limit and that Windows/Framework would handle the virtual memory paging issues.
(.NET Framework 4.8 - 64bit build.)
I'm writing an application where I need to send a file (~600kB) to another unit via a virtual serialport.
When I send it using a terminal application (TeraTerm) it takes less than 10 seconds, but using my program it takes 1-2 minutes.
My code is very simple:
port.WriteTimeout = 30000;
port.ReadTimeout = 5000;
port.WriteBufferSize = 1024 * 1024; // Buffer size larger than file size
...
fs = File.OpenRead(filename);
byte[] filedata = new byte[fs.Length];
fs.Read(filedata, 0, Convert.ToInt32(fs.Length));
...
for (int iter = 0; iter < filedata.Length; iter++) {
port.Write(filedata, iter, 1);
}
Calling port.Write with the entire file length seems to always cause a write timeout for unknown reason, so I'm writing 1 byte at a time.
Solved it, here's the details in case someone else finds this it might give some hints on what's wrong.
I was reading the file wrong, somehow the application used \r\n as newlines when transferring. The file itself is a Intel .hex file which contains checksums which were calculated using \r as newlines.
Checksum errors caused the other device to ACK very slowly, thus making the transfer super slow combined with the PC application now handling checking for checksum errors.
If you have similar errors I recommend using a software snoop to monitor what's actually being sent
I will like to compress a file before sending it through the network. I think the best approach is 7zip because it is free and open source.
How I use 7zip with .net?
I know that 7zip is free and that they have the source code in c# but for some reason it is very slow on c# so I rather call the dll 7z.dll that comes when installing 7zip for performance reasons. So the way I am able to eassily marshal and call the methods in 7z.dll is with the help of the library called sevenzipsharp . For example adding that dll to my project will enable me to do:
// if you installed 7zip 64bit version then make sure you change plataform target
// like on the picture I showed above!
SevenZip.SevenZipCompressor.SetLibraryPath(#"C:\Program Files\7-Zip\7z.dll");
var stream = System.IO.File.OpenRead(#"SomeFileToCompress.txt");
var outputStream = System.IO.File.Create("Output.7z");
SevenZip.SevenZipCompressor compressor = new SevenZip.SevenZipCompressor();
compressor.CompressionMethod = SevenZip.CompressionMethod.Lzma2;
compressor.CompressionLevel = SevenZip.CompressionLevel.Ultra;
compressor.CompressStream(stream, outputStream);
that's how I use 7zip within c#.
Now my question is:
I will like to send a compressed file over the network. I know I could compress it first then send it. The file is 4GB so I will have to wait a long time for it to compress. I will be wasting a lot of space on hard drive. then I will finally be able to send it. I think that is to complicated. I was wondering how it will be possible to send the file meanwhile it is being compressed.
It seems to be a problem with SevenZipSharp:
Have you considered an alternate library - one that doesn't even require 7-Zip to be installed / available?
From the description posted at http://dotnetzip.codeplex.com/ :
creating zip files from stream content, saving to a stream, extracting
to a stream, reading from a stream
Unlike 7-Zip, DotNetZip is designed to work with C# / .Net.
Plenty of examples - including streaming, are available at http://dotnetzip.codeplex.com/wikipage?title=CS-Examples&referringTitle=Examples .
Another option is to use the 7-Zip Command Line Version (7z.exe), and write to/read from standard in/out. This would allow you to use the 7-Zip file format, while also keeping all of the core work in native code (though there likely won't be much of a significant difference).
Looking back at SevenZipSharp:
Since the 0.29 release, streaming is supported.
Looking at http://sevenzipsharp.codeplex.com/SourceControl/changeset/view/59007#364711 :
it seems you'd want this method:
public void CompressStream(Stream inStream, Stream outStream)
Thank you for considering performance here! I think way too many people would do exactly what you're trying to avoid: compress to a temp file, then do something with the temp file.
CompressStream threw an exception. My code is as follows:
public void TestCompress()
{
string fileToCompress = #"C:\Users\gary\Downloads\BD01.DAT";
byte[] inputBytes = File.ReadAllBytes(fileToCompress);
var inputStream = new MemoryStream(inputBytes);
byte[] zipBytes = new byte[38000000]; // this memory size is large enough.
MemoryStream outStream = new MemoryStream(zipBytes);
string compressorEnginePath = #"C:\Engine\7z.dll";
SevenZipCompressor.SetLibraryPath(compressorEnginePath);
compressor = new SevenZip.SevenZipCompressor();
compressor.CompressionLevel = CompressionLevel.Fast;
compressor.CompressionMethod = CompressionMethod.Lzma2;
compressor.CompressStream(inputStream, outputStream);
inputStream.Close();
outputStream.Close();
The exception messages:
Message: Test method Test7zip.UnitTest1.TestCompress threw exception:
SevenZip.SevenZipException: The execution has failed due to the bug in the SevenZipSharp.
Please report about it to http://sevenzipsharp.codeplex.com/WorkItem/List.aspx, post the release number and attach the archive
I get from server images and videos by stream.
Now I'm saving it:
Stream str = client.GetFile(path);
using (var outStream = new FileStream(#"c:\myFile.jpg", FileMode.Create))
{
var buffer = new byte[4096];
int count;
while ((count = str.Read(buffer, 0, buffer.Length)) > 0)
{
outStream.Write(buffer, 0, count);
}
}
I can be jpg, mpg, flv and a lot of other multimedia types (Before I get stream I know what is a extension of this file).
Now I want to not save it , but run direct from stream.
Examples:
I get stream which is mybirthay.avi and I call my method RunFile(stream) and I think this method should works like System.Diagnostics.Process.Start(path), so my stream should be opened by default program in my SO for example allplayer.
I get stream from myfile.jpg and it is opening by irfanview,
etc...
Is it possible ??
If you are set on not saving the stream to the disk, you could use something like Eldos' Callback File System: http://www.eldos.com/cbfs/
Or, use a ramdisk, save your stream there, and shell to that file location.
Windows puts up a wall between processes so they cannot directly access each other's memory without going through privileged debug-like API functions like ReadProcessMemory. This is what keeps the operating system stable and secure. But spells doom for what you are trying to accomplish.
You'll need to use a file. It won't be much slower than direct memory access, the file system cache takes care of that.
Argh, today is the day of stupid problems and me being an idiot.
I have an application which creates a zip file containing some JPEGs from a certain directory. I use this code in order to:
read all files from the directory
append each of them to a ZIP file
using (var outStream = new FileStream("Out2.zip", FileMode.Create))
{
using (var zipStream = new ZipOutputStream(outStream))
{
foreach (string pathname in pathnames)
{
byte[] buffer = File.ReadAllBytes(pathname);
ZipEntry entry = new ZipEntry(Path.GetFileName(pathname));
entry.DateTime = now;
zipStream.PutNextEntry(entry);
zipStream.Write(buffer, 0, buffer.Length);
}
}
}
All works well under Windows, when I open the file e. g. with WinRAR, the files are extracted. But as soon as I try to unzip my archive on Mac OS X, it only creates a .cpgz file. Pretty useless.
A normal .zip file created manually with the same files on Windows is extracted without any problems on Windows and Mac OS X.
I found the above code on the Internet, so I am not absolutely sure if the whole thing is correct. I wonder if it is needed to use zipStream.Write() in order to write directly to the stream?
got the exact same problem today. I tried implementing the CRC stuff as proposed but it didn't help.
I finaly found the solution on this page: http://community.sharpdevelop.net/forums/p/7957/23476.aspx#23476
As a result, I just had to add this line in my code:
oZIPStream.UseZip64 = UseZip64.Off;
And the file opens up as it should on MacOS X :-)
Cheers
fred
I don't know for sure, because I am not very familiar with either SharpZipLib or OSX , but I still might have some useful insight for you.
I've spent some time wading through the zip spec, and actually I wrote DotNetZip, which is a zip library for .NET, unrelated to SharpZipLib.
Currently on the user forums for DotNetZip, there's a discussion going on about zip files generated by DotNetZip that cannot be read on OSX. One of the people using the library is having a problem that seems similar to what you are seeing. Except I have no idea what a .cpgxz file is.
We tracked it down, a little. At this point the most promising theory is that OSX does not like "bit 3" in the "general purpose bitfield" in the header of each zip entry.
Bit 3 is not new. PKWare added bit 3 to the spec 17 years ago. It was intended to support streaming generation of archives, in the way that SharpZipLib works. DotNetZip also has a way to produce a zipfile as it is streamed out, and it will also set bit-3 in the zip file if used in this way, although normally DotNetZip will produce a zipfile with bit-3 unset in it.
From what we can tell, when bit 3 is set, the OSX zip reader (whatever it is - like I said I'm not familiar with OSX) chokes on the zip file. The same zip contents produced without bit 3, allows the zip file to be opened. Actually it's not as simple as just flipping one bit - the presence of the bit signals the presence of other metadata. So I am using "bit 3" as a shorthand for all that.
So the theory is that bit 3 causes the problem. I haven't tested this myself. There's been some impedance mismatch on the communication with the person who has the OSX machine - so it is unresolved as yet.
But, if this theory holds, it would explain your situation: that WinRar and any Windows machine can open the file, but OSX cannot.
On the DotNetZip forums, we had a discussion about what to do about the problem. As near as I can tell, the OSX zip reader is broken, and cannot handle bit 3, so the workaround is to produce a zip file with bit 3 unset. I don't know if SharpZipLib can be convinced to do that.
I do know that if you use DotNetZip, and use the normal ZipFile class, and save to a seekable stream (like a filesystem file), you will get a zip that does not have bit 3 set. If the theory is correct, it should open with no problem on the Mac, every time. This is the result the DotNetZip user has reported. It's just one result so not generalizable yet, but it looks plausible.
example code for your scenario:
using (ZipFile zip = new ZipFile()
{
zip.AddFiles(pathnames);
zip.Save("Out2.zip");
}
Just for the curious, in DotNetZip you will get bit 3 set if you use the ZipFile class and save it to a nonseekable stream (like ASPNET's Response.OutputStream) or if you use the ZipOutputStream class in DotNetZip, which always writes forward only (no seeking back).
I think SharpZipLib's ZipOutputStream is also always "forward only."
So, I searched for a few more examples on how to use SharpZipLib and I finally got it to work on Windows and os x. Basically I added the "Crc32" of the file to the zip archive. No idea what this is though.
Here is the code that worked for me:
using (var outStream = new FileStream("Out3.zip", FileMode.Create))
{
using (var zipStream = new ZipOutputStream(outStream))
{
Crc32 crc = new Crc32();
foreach (string pathname in pathnames)
{
byte[] buffer = File.ReadAllBytes(pathname);
ZipEntry entry = new ZipEntry(Path.GetFileName(pathname));
entry.DateTime = now;
entry.Size = buffer.Length;
crc.Reset();
crc.Update(buffer);
entry.Crc = crc.Value;
zipStream.PutNextEntry(entry);
zipStream.Write(buffer, 0, buffer.Length);
}
zipStream.Finish();
// I dont think this is required at all
zipStream.Flush();
zipStream.Close();
}
}
Explanation from cheeso:
CRC is Cyclic Redundancy Check - it's a checksum on the entry data. Normally the header for each entry in a zip file contains a bunch of metadata, including some things that cannot be known until all the entry data has been streamed - CRC, Uncompressed size, and compressed size. When generating a zipfile through a streamed output, the zip spec allows setting a bit (bit 3) to specify that these three data fields will immediately follow the entry data.
If you use ZipOutputStream, normally as you write the entry data, it is compressed and a CRC is calculated, and the 3 data fields are written immediately after the file data.
What you've done is streamed the data twice - the first time implicitly as you calculate the CRC on the file before writing it. If my theory is correct, the what is happening is this: When you provide the CRC to the zipStream before writing the file data, this allows the CRC to appear in its normal place in the entry header, which keeps OSX happy. I'm not sure what happens to the other two quantities (compressed and uncompressed size).
I had exactly the same problem, my mistake was (and in your example code as well) that I didn't supply the file lenght for each entry.
Example code:
...
ZipEntry entry = new ZipEntry(Path.GetFileName(pathname));
entry.DateTime = now;
var fileInfo = new FileInfo(pathname)
entry.size = fileInfo.lenght;
...
I was separating the folder names with a backslash... when I changed this to a forward slash it worked!
What's going on with the .cpgz file is that Archive Utility is being launched by a file with a .zip extension. Archive Utility examines the file and thinks it isn't compressed, so it's compressing it. For some bizarre reason, .cpgz (CPIO archiving + gzip compression) is the default. You can set a different default in Archive Utility's Preferences.
If you do indeed discover this is a problem with OS X's zip decoder, please file a bug. You can also try using the ditto command-line tool to unpack it; you may get a better error message. Of course, OS X also ships unzip, the Info-ZIP utility, but I'd expect that to work.
I agree with Cheeso's answer however if the Input file size is greater than 2GB then byte[] buffer = File.ReadAllBytes(pathname); will throw an IO exception.
So i modified Cheeso code and it works like a charm for all the files.
.
long maxDataToBuffer = 104857600;//100MB
using (var outStream = new FileStream("Out3.zip", FileMode.Create))
{
using (var zipStream = new ZipOutputStream(outStream))
{
Crc32 crc = new Crc32();
foreach (string pathname in pathnames)
{
tempBuffLength = maxDataToBuffer;
FileStream fs = System.IO.File.OpenRead(pathname);
ZipEntry entry = new ZipEntry(Path.GetFileName(pathname));
entry.DateTime = now;
entry.Size = buffer.Length;
crc.Reset();
long totalBuffLength = 0;
if (fs.Length <= tempBuffLength) tempBuffLength = fs.Length;
byte[] buffer = null;
while (totalBuffLength < fs.Length)
{
if ((fs.Length - totalBuffLength) <= tempBuffLength)
tempBuffLength = (fs.Length - totalBuffLength);
totalBuffLength += tempBuffLength;
buffer = new byte[tempBuffLength];
fs.Read(buffer, 0, buffer.Length);
crc.Update(buffer, 0, buffer.Length);
buffer = null;
}
entry.Crc = crc.Value;
zipStream.PutNextEntry(entry);
tempBuffLength = maxDataToBuffer;
fs = System.IO.File.OpenRead(pathname);
totalBuffLength = 0;
if (fs.Length <= tempBuffLength) tempBuffLength = fs.Length;
buffer = null;
while (totalBuffLength < fs.Length)
{
if ((fs.Length - totalBuffLength) <= tempBuffLength)
tempBuffLength = (fs.Length - totalBuffLength);
totalBuffLength += tempBuffLength;
buffer = new byte[tempBuffLength];
fs.Read(buffer, 0, buffer.Length);
zipStream.Write(buffer, 0, buffer.Length);
buffer = null;
}
fs.Close();
}
zipStream.Finish();
// I dont think this is required at all
zipStream.Flush();
zipStream.Close();
}
}
I had a similar problem but on Windows 7. I updated to the as of this writing latest version of ICSharpZipLib 0.86.0.518. From then on I could no longer decompress any ZIP archives created with the code that was working so far.
There error messages were different depending on the tool I tried to extract with:
Unknown compression method.
Compressed size in local header does not match that of central directory header in new zip file.
What did the trick was to remove the CRC calculation as mentioned here: http://community.sharpdevelop.net/forums/t/8630.aspx
So I removed the line that is:
entry.Crc = crc.Value
And from then on I could again unzip the ZIP archives with any third party tool. I hope this helps someone.
There are two things:
Ensure your underlying output stream is seekable, or SharpZipLib won't be able to back up and fill in any ZipEntry fields that you omitted (size, crc, compressed size, ...). As a result, SharpZipLib will force "bit 3" to be enabled. The background has been explained pretty well in previous answers.
Fill in ZipEntry.Size, or explicitly set stream.UseZip64 = UseZip64.Off. The default is to conservatively assume the stream could be very large. Unzipping then requires "pk 4.5" support.
I encountered weird behavior when archive is empty (no entries inside it) it can not be opened on MAC - generates cpgz only. The idea was to put a dummy .txt file in it in case when no files for archiving.