I am getting error with deserialization. It says error in xml document.
public T XmlDeserialiseResponseObject<T>(string xml)
{
T returnedXmlClass;
try
{
xml = XmlResponseObjectCleaner(xml);
var doc = new XmlDocument();
doc.LoadXml(xml);
var reader = new XmlNodeReader(doc.DocumentElement);
var ser = new XmlSerializer(typeof(T));
returnedXmlClass = (T)ser.Deserialize(reader);
}
catch (Exception ex)
{
throw ex;
}
return returnedXmlClass;
}
My XML :
<soap:Envelope xmlns:soap='http://schemas.xmlsoap.org/soap/elope/'><soap:Body><GetBenefitStatusFault xmlns:ns2='http://schemas.somesite.co.za/somesite/some/' schemaVersion='1.0'>
<ErrorCode>3513</ErrorCode>
<ErrorMessage>Membership details not valid: Match on initial not found</ErrorMessage>
</GetBenefitStatusFault></soap:Body></soap:Envelope>
XmlResponseObjectCleaner:
private string XmlResponseObjectCleaner(string xml)
{
var sb = new StringBuilder();
sb.Append(xml);
sb.Replace(#"""", "'");
sb.Replace("<env:Envelope xmlns:env='http://schemas.xmlsoap.org/soap/envelope/'>", "");
sb.Replace("</env:Envelope>", "");
sb.Replace("<env:Header/>", "");
sb.Replace("<env:Body>", "");
sb.Replace("ns3:", "");
sb.Replace("ns2:", "");
sb.Replace("</env:Body>", "");
sb.Replace("env", "");
sb.Replace("T00:00:00.000+02:00", "");
sb.Replace("T00:00:00.000Z", "");
return sb.ToString();
}
You could:
load the XML into a DOM and pick out the Body element and parse the OuterXml from there
start at the envelope
Here's an approach for 2:
using System.IO;
using System.Xml.Serialization;
static class P
{
static void Main()
{
const string xml = #"<soap:Envelope xmlns:soap='http://schemas.xmlsoap.org/soap/elope/'><soap:Body><GetBenefitStatusFault xmlns:ns2='http://schemas.somesite.co.za/somesite/some/' schemaVersion='1.0'>
<ErrorCode>3513</ErrorCode>
<ErrorMessage>Membership details not valid: Match on initial not found</ErrorMessage>
</GetBenefitStatusFault></soap:Body></soap:Envelope>";
var obj = XmlDeserialiseResponseObject<GetBenefitBody>(xml);
if (obj.GetBenefitStatusFault is Fault f)
{
System.Console.WriteLine(f.ErrorCode);
System.Console.WriteLine(f.ErrorMessage);
}
}
public static T XmlDeserialiseResponseObject<T>(string xml)
{
var ser = new XmlSerializer(typeof(Envelope<T>));
var obj = (Envelope<T>)ser.Deserialize(new StringReader(xml));
return obj.Body;
}
}
[XmlRoot("Envelope", Namespace = "http://schemas.xmlsoap.org/soap/elope/")]
public class Envelope<T>
{
public T Body { get; set; }
}
public class GetBenefitBody
{
[XmlElement(Namespace = "")]
public Fault GetBenefitStatusFault { get; set; }
}
public class Fault
{
public int ErrorCode { get; set; }
public string ErrorMessage { get; set; }
}
Related
I have a normal list based in model like:
Model:
public class ProjectHistoryModel
{
public int JobNumber { get; set; }
public int DesignKey { get; set; }
public string ProjectName { get; set; }
}
In class I have a list of this model like:
public List<ProjectHistoryModel> ProjectHistoryModel = new List<ProjectHistoryModel>();
Then I save that list into xml file as:
Serialize list:
public static string SerializeObject<T>(this T value)
{
if (value == null)
{
return string.Empty;
}
try
{
var xmlserializer = new XmlSerializer(typeof(T));
var stringWriter = new StringWriter();
using (var writer = XmlWriter.Create(stringWriter))
{
xmlserializer.Serialize(writer, value);
return stringWriter.ToString();
}
}
catch (Exception ex)
{
throw new Exception("An error occurred", ex);
}
}
So I save list just sending it to that method as:
var historyXml = ProjectHistoryModel.SerializeObject();
XML.HistoryProjects = historyXml;
XML.SaveXML();
Now my question is: How can I deserialize this xml and convert to a list again?
I try it something like this but I get stuck:
public static List<string> Load()
{
var xmlList = XML.HistoryProjects;
using (var stream = System.IO.File.OpenRead(FileName))
{
var serializer = new XmlSerializer(xmlList));
return serializer.Deserialize(stream) as [xmlList];
}
}
Regards
You just need to do the same thing in reverse, using a StringReader instead of a writer.
public static T DeserializeObject<T>(this string source)
{
if (string.IsNullOrEmpty(source))
{
return default(T);
}
try
{
var xmlserializer = new XmlSerializer(typeof(T));
var stringReader = new StringReader(source);
using (var reader = XmlReader.Create(stringReader))
{
var result = xmlserializer.Deserialize(reader);
return (T)result;
}
}
catch (Exception ex)
{
throw new Exception("An error occurred", ex);
}
}
Then call it with:
var input = new List<ProjectHistoryModel>();
var serialized = input.SerializeObject();
var output = serialized.DeserializeObject<List<ProjectHistoryModel>>();
Here is a link to a working example on DotNetFiddle.
I have two class : Osoba, test
public class test
{
public string raz { get; set; }
public string dwa { get; set; }
}
public class Osoba
{
public test tehe { get; set; }
}
I also add namespaces to main root and seralize
Osoba ne = new Osoba();
test t1 = new praca2.test();
t1.dwa = "fgfg";
t1.raz = "dfdfdfdf";
ne.tehe = t1;
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("dfs", "http://schemas.microsoft.com/office/infopath/2003/dataFormSolution");
ns.Add("d", "http://schemas.microsoft.com/office/infopath/2009/WSSList/dataFields");
ns.Add("pc", "http://schemas.microsoft.com/office/infopath/2007/PartnerControls");
XmlSerializer xsSubmit = new XmlSerializer(typeof(Osoba));
var xml = #"D:\dupa1.xml";
using (var stream = new FileStream(xml, FileMode.Create))
{
using (XmlWriter writer = XmlWriter.Create(stream))
{
xsSubmit.Serialize(writer, ne,ns);
xml = stream.ToString(); // Your XML
}
}
I get
<?xml version="1.0" encoding="utf-8"?>
<Osoba xmlns:dfs="http://schemas.microsoft.com/office/infopath/2003/dataFormSolution"xmlns:pc="http://schemas.microsoft.com/office/infopath/2007/PartnerControls"xmlns:d="http://schemas.microsoft.com/office/infopath/2009/WSSList/dataFields">
<tehe>
<raz>dfdfdfdf</raz>
<dwa>fgfg</dwa>
</tehe>
</Osoba>
I want add to node namespaces examle:
...
<pc:tehe>
<dfs:raz>dfdfdfdf</dfs:raz>
<dfs:dwa>fgfg</dfs:dwa>
</pc:tehe>
How I can do it?
I try add class atribute which set namespace
[XmlRoot("Node", Namespace="http://flibble")]
but it bad idea
You're almost there you just need to modify your classes slightly:
public class test
{
[XmlElement(Namespace = "http://schemas.microsoft.com/office/infopath/2003/dataFormSolution")]
public string raz { get; set; }
[XmlElement(Namespace = "http://schemas.microsoft.com/office/infopath/2003/dataFormSolution")]
public string dwa { get; set; }
}
public class Osoba
{
[XmlElement(Namespace = "http://schemas.microsoft.com/office/infopath/2007/PartnerControls")]
public test tehe { get; set; }
}
Sample implementation copied mostly from yours:
class Program
{
static void Main(string[] args)
{
Osoba ne = new Osoba();
test t1 = new test();
t1.dwa = "fgfg";
t1.raz = "dfdfdfdf";
ne.tehe = t1;
XmlSerializer xsSubmit = new XmlSerializer(typeof(Osoba));
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("dfs", "http://schemas.microsoft.com/office/infopath/2003/dataFormSolution");
ns.Add("pc", "http://schemas.microsoft.com/office/infopath/2007/PartnerControls");
var xml = #"D:\dupa1.xml";
using (var stream = new FileStream(xml, FileMode.Create))
{
using (XmlTextWriter writer = new XmlTextWriter(stream, Encoding.UTF8))
{
xsSubmit.Serialize(writer, ne, ns);
}
}
}
}
You will get this XML:
<?xml version="1.0" encoding="utf-8"?>
<Osoba xmlns:dfs="http://schemas.microsoft.com/office/infopath/2003/dataFormSolution" xmlns:pc="http://schemas.microsoft.com/office/infopath/2007/PartnerControls">
<pc:tehe>
<dfs:raz>dfdfdfdf</dfs:raz>
<dfs:dwa>fgfg</dfs:dwa>
</pc:tehe>
</Osoba>
Hth...
Uisng xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication42
{
class Program
{
static void Main(string[] args)
{
string xmlHeader =
"<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
"<Osoba xmlns:dfs=\"http://schemas.microsoft.com/office/infopath/2003/dataFormSolution\"" +
" xmlns:pc=\"http://schemas.microsoft.com/office/infopath/2007/PartnerControls\"" +
" xmlns:d=\"http://schemas.microsoft.com/office/infopath/2009/WSSList/dataFields\">" +
"</Osoba>";
XDocument doc = XDocument.Parse(xmlHeader);
XElement osoba = doc.Root;
XNamespace dfsNs = osoba.GetNamespaceOfPrefix("dfs");
XNamespace pcNs = osoba.GetNamespaceOfPrefix("pc");
osoba.Add(new XElement(pcNs + "tehe", new object[] {
new XElement(dfsNs + "raz", "dfdfdfdf"),
new XElement(dfsNs + "dwa", "fgfg")
}));
}
}
}
I think you are new at C#.I suggest you to study C# basics, design patterns and repository pattern.For your requirement you can use below codes
public class Tehe
{
public string Raz { get; set; }
public string Dwa { get; set; }
}
public class TeheRepository
{
private System.Xml.Linq.XDocument xmlDatas;
public TeheRepository(string filePath)
{
xmlDatas = XDocument.Load(filePath);
}
public IEnumerable<Tehe> FindAll()
{
return xmlDatas.Elements().Elements().Select(tehe =>
{
Tehe t = new Tehe();
t.Dwa = tehe.Elements().ElementAt(1).Value;
t.Raz = tehe.Elements().ElementAt(0).Value;
return t;
});
}
}
I have a Model populated and I wish to serlise to an xml document.
Due to naming conventions I have to over ride the class names for my XML document,
This is my Model(s):
[Serializable]
[XmlRoot("preferences")]
public class PreferencesModel
{
[XmlIgnore]
public string MessageToUser { get; set; }
[XmlElement(ElementName = "sectiondivider")]
public List<SectionDivider> SectionDivider { get; set; }
}
[Serializable]
[XmlRoot(ElementName = "sectiondivider")]
public class SectionDivider
{
[XmlAttribute("name")]
public string Name { get; set; }
[XmlElement("preference")]
public List<PreferenceModel> PreferenceModel { get; set; }
}
[Serializable]
[XmlRoot("preference")]
public class PreferenceModel
{
[XmlAttribute("type")]
public string Type { get; set; }
public string Name { get; set; }
[XmlAttribute("value")]
public string Value { get; set; }
[XmlElement("options")]
public List<Option> Options { get; set; }
}
this is how I serialize:
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(ObjectToXmlString(obj, includeNameSpace, includeStartDocument, rootAttribute));
return xDoc;
public static string ObjectToXmlString(Object obj, bool includeNameSpace, bool includeStartDocument, XmlRootAttribute rootAttribute)
{
SpecialXmlWriter stWriter = null;
XmlSerializer xmlSerializer = default(XmlSerializer);
string buffer = null;
try
{
if (rootAttribute == null)
{
xmlSerializer = new XmlSerializer(obj.GetType());
}
else
{
xmlSerializer = new XmlSerializer(obj.GetType(), rootAttribute);
}
MemoryStream memStream = new MemoryStream();
StringWriter writer = new StringWriter();
stWriter = new SpecialXmlWriter(memStream, new UTF8Encoding(false), includeStartDocument);
if (!includeNameSpace)
{
System.Xml.Serialization.XmlSerializerNamespaces xs = new XmlSerializerNamespaces();
//To remove namespace and any other inline
//information tag
xs.Add("", "");
xmlSerializer.Serialize(stWriter, obj, xs);
}
else
{
xmlSerializer.Serialize(stWriter, obj);
}
buffer = Encoding.UTF8.GetString(memStream.ToArray());
}
catch (Exception e)
{
string msg = e.Message;
throw;
}
finally
{
if (stWriter != null)
stWriter.Close();
}
return buffer;
}
I call it like this:
XmlDocument preferencesxml = Codec.ObjectToXml(m.SectionDivider,false,
false, new XmlRootAttribute("preferences"));
My m value is:
and my resulting XML is this:
XmlRootAttribute, as the name suggests, only applies to the root element of the XML being serialised.
You need to use XmlTypeAttribute in this context:
[XmlType("sectiondivider")]`
public class SectionDivider
{
//...
}
As an aside, the [Serializable] attribute is not relevant to XmlSerializer - it can be removed unless you need it for some other purpose.
private void Form1_FormClosing(object sender, FormClosingEventArgs e) //Save On Form Closing
{
XmlDocument xDoc = new XmlDocument();
xDoc.Load(path + "\\Address Book - Me \\settings.xml");
XmlNode xNode = xDoc.SelectSingleNode("People");
xNode.RemoveAll();
foreach (Person pe in people)
{
XmlNode xTop = xDoc.CreateElement("People");
XmlNode xName = xDoc.CreateElement("Name");
XmlNode xLastName = xDoc.CreateElement("LastName");
XmlNode xStreet = xDoc.CreateElement("Address");
XmlNode xPhone = xDoc.CreateElement("Phone");
XmlNode xEmail = xDoc.CreateElement("Email");
XmlNode xDate = xDoc.CreateElement("Birth");
XmlNode xCity = xDoc.CreateElement("City");
XmlNode xState = xDoc.CreateElement("State");
XmlNode xCountry = xDoc.CreateElement("Country");
XmlNode xDetails = xDoc.CreateElement("Detail");
xName.InnerText = pe.Name;
xLastName.InnerText = pe.LastName;
xStreet.InnerText = pe.StreetAdress;
xPhone.InnerText = pe.Phone;
xEmail.InnerText = pe.Email;
xDate.InnerText = pe.Date.ToFileTime().ToString();
xCity.InnerText = pe.City;
xState.InnerText = pe.State;
xCountry.InnerText = pe.Country;
xDetails.InnerText = pe.Details;
xTop.AppendChild(xName);//adding a new node
xTop.AppendChild(xLastName);
xTop.AppendChild(xStreet);
xTop.AppendChild(xPhone);
xTop.AppendChild(xEmail);
xTop.AppendChild(xDate);
xTop.AppendChild(xCity);
xTop.AppendChild(xState);
xTop.AppendChild(xCountry);
xTop.AppendChild(xDetails);
xDoc.DocumentElement.AppendChild(xTop);
}
xDoc.Save(path + "\\Address Book - Me \\settings.xml");//
I'm trying to make an agenta that saves information and reload them after I restart my app. But when I closed my program nothing works and that's it:
Xml An unhandled exception of type 'System.Xml.XmlException' occurred in System.Xml.dll and Additional information: Root element is missing.
Please help me.
From comment: the exception was thrown here: xDoc.Load(path + "\\Address Book - Me \\settings.xml");
Delete your folder with .xml file. Then made a new .xml file with this.
XmlTextWriter xW = new XmlTextWriter(YourPath, YourEncoding);
xW.WriteStartElement(Your Tag);
xW.WriteEndElement();
xW.Close();
The simplest way would be to use XmlSerialization as in the example below.
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;
namespace ConsoleApplication1
{
public class Program
{
static void Main(string[] args)
{
var settings = new Settings();
settings.People.Add(new Person { Name = "Name", LastName = "LastName", City="City", Country="Country", Date="11/11/11", Details="Details", Email="Email", Phone="Phone", State="State", Street="Steet" });
settings.Save("c:\\test.xml");
settings = Settings.TryLoad("c:\\test.xml");
}
[Serializable]
public class Settings
{
public Settings()
{
}
public List<Person> People
{
get { return people; }
set { people = value; }
}
List<Person> people = new List<Person>();
public void Save(string path)
{
XmlSerializer xs = new XmlSerializer(typeof(Settings));
using (var sw = new StreamWriter(File.Open(path, FileMode.OpenOrCreate)))
{
xs.Serialize(sw, this);
}
}
public static Settings TryLoad(string path)
{
Settings settings = null;
XmlSerializer xs = new XmlSerializer(typeof(Settings));
using (var sw = new StreamReader(File.OpenRead(path)))
{
try
{
settings = xs.Deserialize(sw) as Settings;
}
catch (Exception)
{
// skip
}
}
return settings;
}
}
[Serializable]
public class Person
{
public Person()
{
}
public string Name { get; set; }
public string LastName { get; set; }
public string Street { get; set; }
public string Phone { get; set; }
public string Email { get; set; }
public string Date { get; set; }
public string City { get; set; }
public string State { get; set; }
public string Country { get; set; }
public string Details { get; set; }
}
}
}
I have to two simple serialize/desirialize methods,
Mapping:
[System.Runtime.Serialization.DataContract(Namespace = "", Name = "PARAMS")]
public sealed class CourseListRequest {
[DataMember(Name = "STUDENTID")]
public int StudentId { get; set; }
[DataMember(Name = "YEAR")]
public string Year { get; set; }
[DataMember(Name = "REQUESTTYPE")]
public int RequestType { get; set; }
}
public static string Serialize<T>(this T value) {
if (value == null) throw new ArgumentNullException("value");
try {
var dcs = new DataContractSerializer(typeof (T));
string xml;
using (var ms = new MemoryStream()) {
dcs.WriteObject(ms, value);
xml = Encoding.UTF8.GetString(ms.ToArray());
}
return xml;
}
catch (Exception e) {
throw;
}
}
public static T Deserialize<T>(this string xml) where T : class {
if (string.IsNullOrEmpty(xml)) {
return default(T);
}
try {
var dcs = new DataContractSerializer(typeof (T));
using (var ms = new MemoryStream(Encoding.UTF8.GetBytes(xml))) {
ms.Position = 0;
return dcs.ReadObject(ms) as T;
}
}
catch (Exception e) {
throw;
}
}
result:
<PARAMS xmlns:i="http://www.w3.org/2001/XMLSchema-instance"><REQUESTTYPE>36</REQUESTTYPE><STUDENTID>0</STUDENTID><YEAR>תשע</YEAR></PARAMS>
How to remove xmlns:i="http://www.w3.org/2001/XMLSchema-instance" ?? On serializing
Switch to using XmlSerializer
System.Xml.Serialization.XmlSerializer
This will generate plain XML with no namespaces