my goal is, to shift an Image an x-amount of pixels to the right. I guess this can be achieved by using WarpAffine. This is at least what my reseach tells me. I used quite a variety of different approaches, like:
CvInvoke.WarpAffine(realImage, transformedImage, transformationMatrix, new Size(realImage.Size);
//or while m is the Mat used to create realImage
transImage.WarpAffine(m,Emgu.CV.CvEnum.Inter.Area,Emgu.CV.CvEnum.Warp.Default,Emgu.CV.CvEnum.BorderType.Default,new Gray());
I get the Exeption:
Exception thrown: 'Emgu.CV.Util.CvException' in Emgu.CV.Platform.NetStandard.dll
[ WARN:0] global E:\bb\cv_x86\build\opencv\modules\videoio\src\cap_msmf.cpp (436) `anonymous-namespace'::SourceReaderCB::~SourceReaderCB terminating async callback
I guess I am using it the wrong way, but there is no suiting example online for me to learn from.
Does anyone has a clean way to explain it to me?
Thank you in advance!
If you are shifting the pixels x amount to the right, I assume that there would be black empty pixels on the left side? If so, you could create an ROI and cut off some pixels on the right, since you are shifting all pixels to the right, and copy the image onto another image.
//The image that you want to shift pixels with
Image<Bgr, byte> inputImage = new Image<Bgr, byte>(1000, 1000);
//The output image
Image<Bgr, byte> image = new Image<Bgr, byte>(990, 1000);
//Create the roi, with 10 pixels cut off from the right side because of the shift
inputImage.ROI = new Rectangle(0, 0, inputImage.Width - 10, inputImage.Height);
inputImage.CopyTo(image);
CvInvoke.ImShow("The Output", image);
CvInvoke.WaitKey(0);
EDIT
Now lets say you want to keep that black stripe on the left side of the image as well. Doing this is very similar to the code above, but only with a few modifications.
//The image that you want to shift pixels with
Image<Bgr, byte> inputImage = new Image<Bgr, byte>(1000, 1000);
//The output image
Image<Bgr, byte> image = new Image<Bgr, byte>(1000, 1000);
//Create the roi, with 10 pixels cut off from the right side because of the shift
inputImage.ROI = new Rectangle(0, 0, inputImage.Width - 10, inputImage.Height);
//The image we want to shift, the same one we created a ROI with,
//has the dimensions 990 X 1000 and the output image has
//dimensions of 1000 x 1000. Unfortunately, in order to paste
//an image onto another image, they need to be the same dimensions.
//How do we do this? We must create an ROI with the output image
//that has the same dimensions as the input image.
image.ROI = new Rectangle(10, 0, image.Width, image.Height);
//Now we can past the image onto the output because the dimensions match
inputImage.CopyTo(image);
//Inorder to make our output seem normal, we must empty the ROI of the output image
image.ROI = Rectangle.Empty;
CvInvoke.ImShow("The Output", image);
CvInvoke.WaitKey(0);
Related
I'am decoding a QR code from an image, since the image is large and have other unwanted graphics I'm drawing an roi around the code and decoding it. Everything works, but when i try to draw a bounding box around the QR code, it is drawn somewhere else. How can I align the rectangle in the same area of the main image?
This is what im getting - The red rectangle is the roi, the green one is the bounding box.
Here is the code :
Image<Gray, byte> Gray_Image = My_Image.Convert<Gray, byte>();
Gray_Image.ROI = Coderect;
Gray_Image._Not();
CvInvoke.cvThreshold(Gray_Image,Gray_Image,50,255.0,Emgu.CV.CvEnum.THRESH.CV_THRESH_BINARY);
Gray_Image.Dilate(5);
StructuringElementEx element = new StructuringElementEx(3, 3, 1, 1, Emgu.CV.CvEnum.CV_ELEMENT_SHAPE.CV_SHAPE_RECT);
CvInvoke.cvMorphologyEx(Gray_Image, Gray_Image, IntPtr.Zero, element, Emgu.CV.CvEnum.CV_MORPH_OP.CV_MOP_CLOSE, 18);
var contour = Gray_Image.FindContours(Emgu.CV.CvEnum.CHAIN_APPROX_METHOD.CV_CHAIN_APPROX_SIMPLE, Emgu.CV.CvEnum.RETR_TYPE.CV_RETR_EXTERNAL);
CvInvoke.cvRectangle(My_Image, new Point(contour.BoundingRectangle.X, contour.BoundingRectangle.Y), new Point(contour.BoundingRectangle.X + contour.BoundingRectangle.Width, contour.BoundingRectangle.Y + contour.BoundingRectangle.Height), new MCvScalar(0, 255, 0), 4, Emgu.CV.CvEnum.LINE_TYPE.EIGHT_CONNECTED, 0);
pictureBox1.Image = My_Image.Bitmap;
I found the solution.
Since I know the (roiX,roiY) of the roi and i also know the (bbX,bbY,bbW,bbH) of the bounding box.
By adding the X of roi and X of bounding box i got the X of the location, similarly for Y.
I simply had to do the following :
cvInvoke.cvRectangle(My_Image, new Point(roiX+bbX, roiY+bbY), new Point((roiX+bbX)+bbW,(roiY+bbY)+bbH), new McvScalar(0,255,0), Line_Type.Eight_Connected,0);
I have several small images and I want them to have exactly 100x100 pixel without scaling. To archieve that, I'm creating a white 100x100 image and copy the small image into those.
My code:
/*Small image*/
Emgu.CV.Mat Char = new Emgu.CV.Mat();
/*...fill small Image with stuff...*/
/*Create black Image (don't know how to create a White Image)*/
FinalChar = Emgu.CV.Mat.Zeros(100, 100, Emgu.CV.CvEnum.DepthType.Cv8U, 1);
/*Invert Image to become white*/
Emgu.CV.CvInvoke.BitwiseNot(FinalChar, FinalChar);
/*Copy small Image to large Image starting at row 5 and column 5*/
Char.CopyTo(FinalChar.Row(5).Col(5)); /*This is NOT working... Image 'Finalchar' is still White.*/
Please don't tell me about this post: OpenCV draw an image over another image
I don't know, but rowRange and colRange is not part of Emgu.CV.
Here is a small, not working example you can copy to try out:
/*Create small black image*/
Emgu.CV.Mat Small = Emgu.CV.Mat.Zeros(10, 10, Emgu.CV.CvEnum.DepthType.Cv8U, 1);
/*Create large white image*/
Emgu.CV.Mat Large = Emgu.CV.Mat.Zeros(20, 20, Emgu.CV.CvEnum.DepthType.Cv8U, 1);
Emgu.CV.CvInvoke.BitwiseNot(Large, Large);
/*Copy small, black image to large white image at 5,5 - the large image should
now contain a black rect in its center*/
Small.CopyTo(Large.Row(5).Col(5));
Emgu.CV.CvInvoke.NamedWindow("Output", Emgu.CV.CvEnum.NamedWindowType.AutoSize);
Emgu.CV.CvInvoke.Imshow("Output", Large);
Emgu.CV.CvInvoke.WaitKey();
return;
Ok, the example "Putting a smaller Image within a larger Image" is not correct - it just adds the Image. So it will work, if your base Image is black. But if your Image is White (R=G=B=255) and you add any value, it will Clip to 255.
But that is working for me:
public static Emgu.CV.Mat EnterAtCenter(int Size = 100)
{
/*Create Mat and Image large, white*/
Emgu.CV.Mat Large = Emgu.CV.Mat.Zeros(Size, Size, Emgu.CV.CvEnum.DepthType.Cv8U, 1);
Emgu.CV.CvInvoke.BitwiseNot(Large, Large);
Emgu.CV.Image<Emgu.CV.Structure.Gray, Byte> ImageLarge = new Emgu.CV.Image<Emgu.CV.Structure.Gray, byte>(Large.Bitmap);
/*Create Mat and Image small, black*/
Emgu.CV.Mat Small = Emgu.CV.Mat.Zeros(10, 10, Emgu.CV.CvEnum.DepthType.Cv8U, 1);
Emgu.CV.Image<Emgu.CV.Structure.Gray, Byte> ImageSmall = new Emgu.CV.Image<Emgu.CV.Structure.Gray, byte>(Small.Bitmap);
/*Copy small Image to large Image at 5,5*/
ImageLarge.ROI = new System.Drawing.Rectangle(5, 5, Small.Width, Small.Height);
ImageSmall.CopyTo(ImageLarge);
ImageLarge.ROI = System.Drawing.Rectangle.Empty;
return ImageLarge.Mat;
}
I need to use the floodFill function of EMGUCV in C#.
I managed to use it like this:
Image<Gray, Byte> img = new Image<Gray, byte>(this.B);
img.Save("orig.png");
int height = img.Rows;
int width = img.Cols;
Point s = new Point( 227, 295);
int tol = 8;
Mat outputMask = new Mat(height + 2, width + 2, Emgu.CV.CvEnum.DepthType.Cv8U, 1);
Rectangle dummyRect = new Rectangle();
CvInvoke.FloodFill(img,
outputMask,
s,
new MCvScalar(255, 0, 0),
out dummyRect,
new MCvScalar(tol), new MCvScalar(tol),
Emgu.CV.CvEnum.Connectivity.EightConnected);
//Emgu.CV.CvEnum.FloodFillType.MaskOnly);
img.Save("imgModif.png");
Console.Write("End");
However the output I get in img (or in outputMask) when I use it does not make any sense at all. Some white rectangular areas. I am expecting the results of a "photoshop like" magic wand. ANy idea of what is wrong? Moreover, even though I specify (255,0,0) as the fill color, the result is white in img. (B is a preloaded Bitmap image)
I am trying to do the same as this:
http://www.andrew-seaford.co.uk/flood-fill-opencv/
except I work with a grayscale image initially.
THis is what i get if I set the tol=255 (which should fill the whole image in white, if this function was really behaving like a magic wand):
Lena tol=255
This ''rectangle'' that can be seen does not make sense, even worse, you can see some white pixels going out of this rectangle region (on Lena's hat)... so it does not even seem to be a sort of rectangular constraint. Also a few pixels in the "pseudo rectangle" are not white... I would be curious if someone could test this function on their system with a lena image.
I'm very new to Emgucv, so need a little help?
The code below is mainly taken from various places from Google. It will take a jpg file (which has a green background) and allow, from a separate form to change the values of h1 and h2 settings so as to create (reveal) a mask.
Now what I want to be able to do with this mask is to turn it transparent.
At the moment it will just display a black background around a person (for example), and then saves to file.
I need to know how to turn the black background transparent, if this is the correct way to approach this?
Thanks in advance.
What I have so far is in C# :
imgInput = new Image<Bgr, byte>(FileName);
Image<Hsv, Byte> hsvimg = imgInput.Convert<Hsv, Byte>();
//extract the hue and value channels
Image<Gray, Byte>[] channels = hsvimg.Split(); // split into components
Image<Gray, Byte> imghue = channels[0]; // hsv, so channels[0] is hue.
Image<Gray, Byte> imgval = channels[2]; // hsv, so channels[2] is value.
//filter out all but "the color you want"...seems to be 0 to 128 (64, 72) ?
Image<Gray, Byte> huefilter = imghue.InRange(new Gray(h1), new Gray(h2));
// TURN IT TRANSPARENT somewhere around here?
pictureBox2.Image = imgInput.Copy(mask).Bitmap;
imgInput.Copy(mask).Save("changedImage.png");
I am not sure I really understand what you are trying to do. But a mask is a binary object. A mask is usually black for what you do not want and white for what you do. As far as I know, there is no transparent mask, as to me that makes no sense. Masks are used to extract parts of an image by masking out the rest.
Maybe you could elaborate on what it is you want to do?
Doug
I think I may have the solution I was looking for. I found some code on stackoverflow which I've tweaked a little :
public Image<Bgra, Byte> MakeTransparent(Image<Bgr, Byte> image, double r1, double r2)
{
Mat imageMat = image.Mat;
Mat finalMat = new Mat(imageMat.Rows, imageMat.Cols, DepthType.Cv8U, 4);
Mat tmp = new Mat(imageMat.Rows, imageMat.Cols, DepthType.Cv8U, 1);
Mat alpha = new Mat(imageMat.Rows, imageMat.Cols, DepthType.Cv8U, 1);
CvInvoke.CvtColor(imageMat, tmp, ColorConversion.Bgr2Gray);
CvInvoke.Threshold(tmp, alpha, (int)r1, (int)r2, ThresholdType.Binary);
VectorOfMat rgb = new VectorOfMat(3);
CvInvoke.Split(imageMat, rgb);
Mat[] rgba = { rgb[0], rgb[1], rgb[2], alpha };
VectorOfMat vector = new VectorOfMat(rgba);
CvInvoke.Merge(vector, finalMat);
return finalMat.ToImage<Bgra, Byte>();
}
I'm now looking at adding SmoothGaussian to the mask to create a kind on blend, where the two images are layered, rather than a sharp cut-out.
I have a windows forms application and i want to count number of objects from a medical images. For instance
I used an algorithm which can take the contours of every object from the image.
private void findContoursToolStripMenuItem_Click(object sender, EventArgs e)
{
Image<Gray, byte> imgOutput = imgInput.Convert<Gray, byte>().ThresholdBinary(new Gray(100), new Gray(255));
Emgu.CV.Util.VectorOfVectorOfPoint contours = new Emgu.CV.Util.VectorOfVectorOfPoint();
Mat hier = new Mat();
Image<Gray, byte> imgout = new Image<Gray, byte>(imgInput.Width, imgInput.Height, new Gray(100));
CvInvoke.FindContours(imgOutput, contours, hier, Emgu.CV.CvEnum.RetrType.External, Emgu.CV.CvEnum.ChainApproxMethod.ChainApproxSimple);
CvInvoke.DrawContours(imgout, contours, -1, new MCvScalar(123, 0, 0));
pictureBox2.Image = imgout.Bitmap;
}
But I can't find out the number of cells from the image. Any advice or algorithm I have to use ?
I search within EMGU documentation but I don't find any function which does somethink like I want.
Any advice or answer will be rewarded.
If you consider that is too broad, I don't want the implemented algorithm. I just need some ideas or a suggestion of algorithm i have to use.
It probably a bit basic and brute force, but how about selecting a random point on the image that is close to the green colour, then effectively search for 'matching' colours (with a tolerance for the same colour. As you visit each pixel, colour it black so you don't look at it again and count how many pixels you have coloured in. Each time you select a pixel, make sure it's not black. Once you can't find any more points, if the number of black pixels is greater than a tolerance (so you only find 'big' polygons), then count it in the number of cells.