This question already has answers here:
How to remove decimal part from a number in C#
(8 answers)
Closed 2 years ago.
I have some variable length decimal numbers for ex:
1.123,
1.1234,
12.12345,
I need only the first 4 decimals. I can't use Math.Round() because I do not want rounded numbers, I just want to trim it and keep only first 4, like 1.1234, or 22.1234. Is there a way to accomplish this?
Thank you.
Multiply by 10000, store as integer to get rid off any remaining decimals. Divide by 10000.
var result = number.ToString("n4");
check Standard numeric format strings
Related
This question already has answers here:
String Format Numbers Thousands 123K, Millions 123M, Billions 123B
(3 answers)
Closed 5 years ago.
i have decimals and want to display them as "thousand €" but without any positions after the decimal point.
For instance 56000.45 should be displayed as 56 T €.
I have tried several ways and read about using the "," for division, and have tried adding it to this expression: {0:N0} T € but without success.
Could anyone point me in the right direction please?
Thanks in advance!
You could try
decimal currency = (56000.45 - (decimal) 56000.45 % 1000) /1000;
d will now equal 56.00, you can use
Math.Round(currency)
to get the value 56
This question already has answers here:
How do I display a decimal value to 2 decimal places?
(19 answers)
Closed 5 years ago.
so I have the following problem I'm trying to output 2 numbers after the decimal comma but it doesn't output it with 2 numbers only when I have zero or more than one zero at the end of the number.
Console.WriteLine(Math.Round(s * 0.07, 2));
here's how I did it.
You might want:
Console.WriteLine($"{s:N2}");
This question already has answers here:
How to limit a decimal number? [duplicate]
(6 answers)
Closed 6 years ago.
So,
I got example number: 0.00857382942837523 which length is 18, but I would like to remove from the end example 9 numbers. Thing is, that number is different every time, so I can't "predict" numbers what are going to be at the end.
//My question was marked to duplicate, but it can't be solved like that. Mine has 0.00, if I would do math.round it would give up 0...
You need Math.Truncate
decimal d= 0.00857382942837523m;
d= Math.Truncate(d * 1000000000m) / 1000000000m;
Console.WriteLine(d); // 0.008573829
This question already has answers here:
Formatting a double to two decimal places
(8 answers)
Closed 6 years ago.
I have a small question regarding Math.Round function.
I need the string "12.123456" to be rounded at 4 decimals. I used:
Math.Round(Convert.ToDouble(pData), 4).ToString()
where pData is defined as string, but the values are decimal with 7 decimals.
My problem is that I expected to get every time the exact 4 decimals, but for some values it gives me only 2 (eg. 12.12 instead of 12.1200).
How can I change in order to always get the needed 4 decimals?
Regards,
You should use format strings instead:
pDate.ToString("0.0000")
or
pDate.ToString("n4")
This question already has answers here:
Display Float as String with at Least 1 Decimal Place
(4 answers)
Closed 7 years ago.
From the following two - double precision - numbers:
123456
0.0003232
I need to get (at least one decimal place) ...
123456.0 (one decimal place added)
0.0003232 (same as above)
... and never scientific notation, like E+000. The more close result from standard string.Format() is string.Format("{0:F1}", myDoubleVal) but in the second case the decimals are lost.
What else can I try?
Thanks.
Try the below
string.Format("{0:0.0###########}",myval);
Thanks