I am having an issue with the Revit API PrintManager properties, in particular with the PrintToFileName property and the error: Invalid fileName.
What is the proper way to declare what you wish for a printed view to be named when printing to pdf?
My Source (Puts a schedule onto an empty sheet and prints it):
ViewSheet sheet = ViewSheet.Create(Doc, ElementId.InvalidElementId);
Element view = new FilteredElementCollector(Doc)
.OfClass(typeof(ViewSchedule))
.Where(o => o.Name == element) //element is a string from a list of items in a WPF listbox.
.First();
ScheduleSheetInstance.Create(Doc, sheet.Id, view.Id, XYZ.Zero);
ViewSet set = new ViewSet();
set.Insert(sheet);
IList<ElementId> print = new List<ElementId>();
print.Add(sheet.Id);
Uidoc.Selection.SetElementIds(print);
printManager.PrintRange = PrintRange.Select;
ViewSheetSetting viewSheetSetting = printManager.ViewSheetSetting;
viewSheetSetting.CurrentViewSheetSet.Views = set;
printManager.SelectNewPrintDriver("Adobe PDF");
printManager.PrintToFile = true;
printManager.CombinedFile = true;
printManager.PrintToFileName = "TestFileName"; //ERROR HERE
printManager.Apply();
printManager.SubmitPrint(sheet);
Maybe you need to input the full path + name of the file to work.
Update: Found the problem in my formatting thanks to Bogdans post as well as This comment on the Autodesk Revit Api Forum.
Turns out, the PrintToFileName calls for both a path and a filename string. Working snippet is as follows:
string path = #"[same file path here ]";
string currentViewName = view.Name;
printManager.PrintToFileName = path + currentViewName + ".pdf";
printManager.Apply();
Thanks for the response, Bogdan.
Related
Background: I'm trying to write a program to insert an image into a cell of a spreadsheet. LibreOffice recently changed how this is done, and all the samples I could find use the old method which no longer works.
Technically I know that you can't "insert" an image into a cell and that such an image is an overlay on a DrawPage that sits on top of the spreadsheet to "decorate" it.
One of the first steps in doing this (the new way) is to create an XGraphic object which contains the image. The process is to create an XGraphicProvider and call it with MediaProperties that specify the image file URL to be loaded. I have a program that is supposed to do this but the resulting XGraphic is null. The LO SDK gives pretty much no information when you do something wrong; it just doesn't work.
Here is the code I have, with all the headers removed:
// addpic
// add picture to spreadsheet - debug version
class OpenOfficeApp {
[STAThread]
static void Main(string[] args) {
bool lreadonly;
string pqfile;
string pqURL;
string pqpic;
pqfile = "file:///D:/Documents/NSexeye/ODS%20File%20Access/"+
"addpix/addpic.ods";
pqpic = "addpic2";
pqURL = pqpic+".jpg";
lreadonly = false;
Console.WriteLine("Using: "+pqfile);
// get the desktop
XComponentContext XCC = uno.util.Bootstrap.bootstrap();
XMultiComponentFactory XMCF =
(XMultiComponentFactory)XCC.getServiceManager();
XMultiServiceFactory XMSF = (XMultiServiceFactory)XCC.getServiceManager();
XComponentLoader XCL =
(XComponentLoader)XMSF.createInstance("com.sun.star.frame.Desktop");
// open the spreadsheet
PropertyValue[] pPV = new PropertyValue[2];
pPV[0] = new PropertyValue();
pPV[0].Name = "Hidden";
pPV[0].Value = new uno.Any(true);
pPV[1] = new PropertyValue();
pPV[1].Name = "ReadOnly";
if (lreadonly) pPV[1].Value = new uno.Any(true);
else pPV[1].Value = new uno.Any(false);
XComponent XCo = XCL.loadComponentFromURL(pqfile,"_blank",0,pPV);
// create graphic object containing image
object oGP = XMCF.createInstanceWithContext(
"com.sun.star.graphic.GraphicProvider",XCC);
if (oGP == null) {
Console.WriteLine("oGP is null. Aborting.");
return;
}
XGraphicProvider XGP = (XGraphicProvider)oGP;
if (XGP == null) {
Console.WriteLine("XGP is null. Aborting.");
return;
}
pPV = new PropertyValue[1];
pPV[0] = new PropertyValue();
pPV[0].Name = "URL";
pPV[0].Value = new uno.Any(pqURL);
Console.WriteLine("Creating XGraphic containing "+pqURL);
XGraphic XG = XGP.queryGraphic(pPV);
// *** XG is null here
if (XG == null) {
Console.WriteLine("XG is null. Aborting.");
return;
}
// ... lots of stuff to be added here
// save and close the spreadsheet
XModifiable XM = (XModifiable)XCo;
XM.setModified(true);
XStorable XSt = (XStorable)XCo;
XSt.store();
XCloseable XCl = (XCloseable)XCo;
XCl.close(true);
// terminate LibreOffice
// *** I want this to not terminate it if something else is open
XDesktop XD = (XDesktop)XCL;
if (XD != null) XD.terminate();
}
}
I get a null for the XGraphic, in the place indicated in the comments. I don't know if the call to create it is failing, or if one of the earlier steps of the process are incorrect.
My goal here, in addition to getting my program working, is to create a sample program showing how to add an image to a Calc spreadsheet cell, and to manipulate such images. There are a fair number of people asking questions about this and none of the examples I've found will work. I think a good working sample will be of value.
I've spent a lot of time searching for information and code samples for this, with nothing that helps. I've tried to find ways to verify the validity of the XGraphicProvider interface with no luck. I've run out of things to try.
I'm hoping someone who knows about the LibreOffice SDK can take a look and maybe see what I'm doing wrong.
Update: I figured out what I was doing wrong: I was passing a bare filename in the "URL" property to XGraphicProvider. It has to be the same format (starting with "file:///") as the spreadsheet's file name specification.
Now I'm stuck with another property problem. The XGraphic has to be specified as a parameter to the GraphicObjectShape's Graphic property, but the setPropertyValue() function requires that it be a uno.Any type. I can't figure out how to specify an interface name like XGraphic as a uno.Any.
Here is the piece of code that won't compile, complaining that it can't convert an XGraphic to a uno.Any, in the first setPropertyValue call:
// set image XGraphic
XPropertySet XPS = (XPropertySet)XS;
XPS.setPropertyValue("Graphic",XG);
XPS.setPropertyValue("Name",new uno.Any(pqpic));
XG is an XGraphic type. Using "new uno.Any(XG)" doesn't work either, giving a similar compiler error.
After trying unsuccessfully for a few hours to get the latest LO SDK up and running, let me offer some untested ideas.
First of all, here is some working Basic code, no doubt similar to what you're translating from. The important line is oShape.Graphic = oProvider.queryGraphic(Props()).
oDoc = ThisComponent
oSheet = oDoc.CurrentController.ActiveSheet
pqURL = "file:///C:/Users/JimK/Desktop/addpic.jpg"
oProvider = createUnoService("com.sun.star.graphic.GraphicProvider")
oShape = oDoc.createInstance("com.sun.star.drawing.GraphicObjectShape")
Dim Props(0) as new com.sun.star.beans.PropertyValue
Props(0).Name= "URL"
Props(0).Value = pqURL
oShape.Graphic = oProvider.queryGraphic(Props())
oCell = oSheet.getCellByPosition(5,5)
oShape.Name = oCell.AbsoluteName + "##" + Props(0).Value
oShape.Anchor = oCell
oSheet.DrawPage.add(oShape)
'Resize
w = oShape.Graphic.Size.Width
h = oShape.Graphic.Size.Height
wcl = oCell.Size.Width
hcl = oCell.Size.Height
If w<>0 and h<>0 then
oCell.String=""
Dim Size as new com.sun.star.awt.Size
Size.Width = wcl
Size.Height = h*wcl/w
If Size.Height > hcl then
Size.Width = hcl*w/h
Size.Height = hcl
Endif
oShape.setSize(Size)
oShape.setPosition(oCell.Position)
erase oShape
Else
oShape.dispose()
Endif
Now, how to translate this to C#? It looks like you may need to explicitly specify the type. In the SDK example, there are calls like this.
xFieldProp.setPropertyValue(
"Orientation",
new uno.Any(
typeof (unoidl.com.sun.star.sheet.DataPilotFieldOrientation),
unoidl.com.sun.star.sheet.DataPilotFieldOrientation.DATA ) );
So in your case, something like this:
XPS.setPropertyValue(
"Graphic"
new uno.Any(
typeof(unoidl.com.sun.star.graphic.XGraphic),
XG));
Alternatively, follow the suggestion here: set GraphicURL, which should load the image and set Graphic for you.
I've been trying to create a smart form definition from another application. The app successfully creates the smart form, but I'm unable to get the FieldList, DisplayXSLT or Schema fields to populate.
This leaves me with a blank smart form definition (less that ideal).
Here's the code I have to perform the action. Any ideas?
// form is a simple POCO with values copied from an existing SmartForm Definition
var config = new SmartFormConfigurationData();
config.SmartformTitle = form.Name;
config.SmartformDescription = form.Description;
config.XmlSchema = form.Schema;
config.PackageDisplayXslt = form.Xslt;
config.FieldList = form.FieldList;
config.Type = EkEnumeration.XmlConfigType.Content;
var api = new SmartFormConfigurationManager(ApiAccessMode.Admin);
api.RequestInformation.ServicesPath = this.EktronServiceHost;
api.RequestInformation.AuthenticationToken = this.GetAdminAuthToken();
api.Add(config);
Update:
I heard back from Ektron Support on this issue. It's not so much a "bug" per-se... It's more a case of this API class looking very similar to the ContentManager but not behaving like it. I expected that since it looked so similar to ContentManager and many of the other classes, I would be able to call Add() and it would just magically work. It turns out the solution is a little more complicated.
Adding a smartform is a two-step process: first Add(), then Update().
The Add method doesn't set all of the fields and in fact passes in NULL for a few of the parameters on the stored procedure that creates the entry in xml_collection_tbl.
The real fun comes in step 2. Basically, you start with the SmartForm's HTML -- the stuff you see when you're in the "Data Design" view for editing the smart form definition and you click that <> button ("HTML") at the bottom of the editor. You run that through a whole bunch of XSLTs that are burried in the WorkArea folder to construct the missing fields, and then you call update. Here's the code that worked for me:
var sfManager = new SmartFormConfigurationManager();
var data = sfManager.GetItem(12);
if (data == null) return;
var sfcData = new SmartFormConfigurationData();
sfcData.Type = EkEnumeration.XmlConfigType.Content;
sfcData.SmartformTitle = "SmartForm12 copy";
sfcData.SmartformDescription = "SmartForm12 copy";
sfcData.XmlSchema = "";
sfcData.PackageDisplayXslt = data.PackageDisplayXslt;
sfcData.FieldList = data.FieldList;
sfcData = sfManager.Add(sfcData);
Response.Write("SmartForm added with id: " + sfcData.Id);
var design = System.IO.File.ReadAllText(Server.MapPath("~/NewsArticleSmartForm.html"));
var contentApi = new ContentAPI();
var schema = contentApi.TransformXsltPackage(design, Server.MapPath("~/WorkArea/ContentDesigner/DesignToSchema.xslt"), true);
var fieldList = contentApi.TransformXsltPackage(design, Server.MapPath("~/WorkArea/ContentDesigner/DesignToFieldList.xslt"), true);
var viewEntryXslt = contentApi.TransformXsltPackage(design, Server.MapPath("~/WorkArea/ContentDesigner/DesignToEntryXSLT.xslt"), true);
var xsltArgs = new XsltArgumentList();
xsltArgs.AddParam("srcPath", "", "/WorkArea/ContentDesigner/");
var viewXsltSource = string.Concat("<root>", design, "<ektdesignpackage_list>", fieldList, "</ektdesignpackage_list></root>");
var viewXslt = contentApi.XSLTransform(viewXsltSource, Server.MapPath("~/WorkArea/ContentDesigner/DesignToViewXSLT.xslt"), true, false, xsltArgs, false);
var initialDocument = contentApi.TransformXsltPackage(design, Server.MapPath("~/WorkArea/ContentDesigner/PresentationToData.xslt"), true);
var sbPackage = new StringBuilder("<ektdesignpackage_forms><ektdesignpackage_form><ektdesignpackage_designs><ektdesignpackage_design>");
sbPackage.Append(design);
sbPackage.Append("</ektdesignpackage_design></ektdesignpackage_designs><ektdesignpackage_schemas><ektdesignpackage_schema>");
sbPackage.Append(schema);
sbPackage.Append("</ektdesignpackage_schema></ektdesignpackage_schemas><ektdesignpackage_lists><ektdesignpackage_list>");
sbPackage.Append(fieldList);
sbPackage.Append("</ektdesignpackage_list></ektdesignpackage_lists><ektdesignpackage_views><ektdesignpackage_view>");
sbPackage.Append(viewEntryXslt);
sbPackage.Append("</ektdesignpackage_view><ektdesignpackage_view>");
sbPackage.Append(viewXslt);
sbPackage.Append("</ektdesignpackage_view></ektdesignpackage_views><ektdesignpackage_initialDocuments><ektdesignpackage_initialDocument>");
sbPackage.Append(initialDocument);
sbPackage.Append("</ektdesignpackage_initialDocument></ektdesignpackage_initialDocuments></ektdesignpackage_form></ektdesignpackage_forms>");
sfcData.PackageXslt = sbPackage.ToString();
sfcData.FieldList = fieldList;
var baseFilename = "SmartForm" + sfcData.Id;
var schemaFilename = "/" + baseFilename + "Schema.xsd";
var xsltFilename = "/" + baseFilename + "Xslt.xslt";
sfcData.XmlSchema = schemaFilename; // The file will be prefixed with /XmlFiles
var unPackDisplayXslt = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><xsl:stylesheet version=\"1.0\" xmlns:xsl=\"http://www.w3.org/1999/XSL/Transform\"><xsl:output method=\"xml\" version=\"1.0\" encoding=\"UTF-8\" indent=\"yes\"/><xsl:template match=\"/\"><xsl:choose><xsl:when test=\"ektdesignpackage_forms/ektdesignpackage_form[1]/ektdesignpackage_views/ektdesignpackage_view[2]\"><xsl:copy-of select=\"ektdesignpackage_forms/ektdesignpackage_form[1]/ektdesignpackage_views/ektdesignpackage_view[2]/node()\"/></xsl:when><xsl:otherwise><xsl:copy-of select=\"ektdesignpackage_forms/ektdesignpackage_form[1]/ektdesignpackage_views/ektdesignpackage_view[1]/node()\"/></xsl:otherwise></xsl:choose></xsl:template></xsl:stylesheet>";
var displayXslt = contentApi.TransformXsltPackage(sbPackage.ToString(), unPackDisplayXslt, false);
System.IO.File.WriteAllText(Server.MapPath("~/XmlFiles" + xsltFilename), displayXslt);
sfcData.Xslt1 = xsltFilename; // The file will be prefixed with /XmlFiles
sfcData.DefaultXslt = 1;
sfManager.Update(sfcData);
I extracted the HTML for my existing smart form and saved in the root of my site as NewsArticleSmartForm.html. Here's what my file looked like:
<p>Author: <input type="text" name="Author" id="Author" ektdesignns_caption="Author" ektdesignns_name="Author" title="Author" ektdesignns_indexed="false" ektdesignns_nodetype="element" size="24" class="design_textfield" /></p>
<p> </p>
<p>Article Summary: <textarea name="Summary" id="Summary" ektdesignns_caption="Summary" ektdesignns_name="Summary" title="Summary" ektdesignns_indexed="false" ektdesignns_nodetype="element" cols="40" rows="3" class="design_textfield"></textarea>
</p>
<p> </p>
<p>Article Body:</p>
<p> </p>
<ektdesignns_richarea id="Body" name="Body" ektdesignns_caption="Body" ektdesignns_name="Body" title="Body" ektdesignns_indexed="false" ektdesignns_nodetype="element"> </ektdesignns_richarea>
<p> </p>
Good luck!
Original Answer:
Creating a copy of a SmartForm configuration should be fairly straight-forward. The SmartFormConfigurationData object has a Clone() method on it which makes it really easy to create a copy of an existing SmartForm. I say "should be" because it doesn't work.
I had an answer all typed out ready to post; I tried some code and it appeared to work. The new smartform was listed in the workarea, but when I clicked on that new smartform to view its details, I realized something was wrong.
I tried the following code:
var sfManager = new SmartFormConfigurationManager();
var config = sfManager.GetItem(7);
if (config == null) return;
var newSmartForm = config.Clone();
newSmartForm.SmartformTitle += " copy";
sfManager.Add(newSmartForm);
Here are the details from the original smartform:
And here's what the new smartform looked like -- the one I created with the frameworkAPI:
I did find one API method that successfully created a copy of an existing smartform:
var sfApi = new Ektron.Cms.ContentAPI();
var newId = sfApi.ReplicateXmlConfiguration(7, "copied sf title");
The problem with that method is that the smartform must exist on your system and you can only change the title. So, I went digging into the database to see what was happening. It turns out that after calling this ReplicateXmlConfiguration() method, the two database records are identical (except for the expected LastUpdated type of fields).
After calling the frameworkAPI's Update() method (same holds true when calling Add()), the "updated" record is clearly different.
I think we've got a genuine bug here. This happens both in v8.7 sp2 and v9.0 sp1. I've opened a case with Ektron support, and I'll update my answer as I hear back. They have always been very responsive when I've dealt with them in the past.
We have a series of internal reports that we update regularly from our internal databases. We built an application in C# that uploads these reports to a Google Site. Everything works fine, except that the name of the file shown to the final user in the File Cabinet does not include the original spaces nor the extension separator (.)
For example, Stock per warehouse.pdf is shown as : Stockperwarehousepdf
Below is a simplified version of the code.
private AtomEntry UploadAttachment(string filename, AtomEntry parent, string title, string description)
{
SiteEntry entry = new SiteEntry();
AtomCategory category = new AtomCategory(SitesService.ATTACHMENT_TERM, SitesService.KIND_SCHEME);
category.Label = "attachment";
entry.Categories.Add(category);
AtomLink parentLink = new AtomLink(AtomLink.ATOM_TYPE, SitesService.PARENT_REL);
parentLink.HRef = parent.SelfUri;
entry.Links.Add(parentLink);
entry.MediaSource = new MediaFileSource(filename, MediaFileSource.GetContentTypeForFileName(filename));
entry.Content.Type = MediaFileSource.GetContentTypeForFileName(filename);
entry.Title.Text= title;
entry.Summary.Text = description;
AtomEntry newEntry = null;
newEntry = service.Insert(new Uri(makeFeedUri("content")), entry);
}
The key line is where the MediaFileSource object is created. Any idea of what we are missing? I've tried all sort of changes :(
entry.Title.Text = entry.MediaSource.Name;
is missing
I am trying to figure out how to write a Hyperlink inside a cell using EPPlus instead of the cell containing the link text. I need it to be recognized as a link and be clickable.
Any help is appreciated.
This is the other way to do:
var cell = sheet.Cells["A1"];
cell.Hyperlink = new Uri("http://www.google.com");
cell.Value = "Click me!";
I have tested. It works fine.
The below code worked fine with me.
string FileRootPath = "http://www.google.com";
_Worksheet.Cells[intCellNumber, 1].Formula = "HYPERLINK(\"" + FileRootPath + "\",\"" + DisplayText + "\")";
I hope this would help you.
Happy coding!!
There's a few ways to go about it:
To use URI, then set a human readable name:
var cell = sheet.Cells["A1"];
cell.Hyperlink = new Uri("https://www.google.com");
cell.Value = "Click me!";
To use ExcelHyperLink and set a human readable name using object initializer :
var cell = sheet.Cells["A1"];
cell.Hyperlink = new ExcelHyperLink("https://www.google.com") { Display = "Click me!" };
To use =Hyperlink() formula:
var cell = sheet.Cells["A1"];
cell.Formula = string.Format("HYPERLINK({0},{1})", "https://www.google.com", "Click me!");
cell.Calculate();
Based on provided answers and documentation I was able to create an extension method that also deals with proper hyperlink formatting. It creates a named style, if needed, and use that style for all subsequent hyperlinks:
public static void WriteHyperlink(this ExcelRange cell, string text, string url, bool excelHyperlink = false, bool underline = true)
{
if (string.IsNullOrWhiteSpace(text))
return;
// trying to reuse hyperlink style if defined
var workBook = cell.Worksheet.Workbook;
string actualStyleName = underline ? HyperLinkStyleName : HyperLinkNoUnderlineStyleName;
var hyperlinkStyle = workBook.Styles.NamedStyles.FirstOrDefault(s => s.Name == actualStyleName);
if (hyperlinkStyle == null)
{
var namedStyle = workBook.Styles.CreateNamedStyle(actualStyleName);
namedStyle.Style.Font.UnderLine = underline;
namedStyle.Style.Font.Color.SetColor(Color.Blue);
}
if (excelHyperlink)
cell.Hyperlink = new ExcelHyperLink(url) { Display = text };
else
{
cell.Hyperlink = new Uri(url);
cell.Value = text;
cell.StyleName = actualStyleName;
}
}
Without the styling, the hyperlink will look just as regular text, if cell.Hyperlink = new Uri(url); is used without explicit styling (although the cursor will properly indicate that the text is actually a hyperlink text).
I don't know EPPlus, but in VBA (and I guess C# would use the same principle) you would use the following code:
Sub Test()
' place value into cell
ActiveSheet.[A1] = 13
' create link and set its range property
ActiveSheet.Hyperlinks.Add ActiveSheet.[A1], "http://www.google.at"
' use cell in a calculation
ActiveSheet.[A2].Formula = "=A1+2"
End Sub
Hyperlinks are objects having a range property, so while your cell value can be changed by overtyping, the link will remain. Edit the cell by a long mouse click
Hope this helps - good luck MikeD
If you are using EPPlus and want to create a link to another sheet within the same document, then this is the proper way to do this:
var link = "Another Excel Sheet"; //Maximum length is 31 symbols
using (var excel = new ExcelPackage())
{
var ws = excel.Workbook.Worksheets.Add("Test");
ws.Cells[row, col].Hyperlink =
new ExcelHyperLink((char)39 + link + (char)39 + "!A1",
"Name of another excel sheet could be more then 31 symbols");
}
This is the proper way to create a link to another sheet within Excel document. Having using formula with HYPERLINK function, if a file is downloaded to the client, latest Excel version will raise security warnings.
I have looked over other posts here on the same subject and searched Google but I am extremely new to C# NET and at a loss. I am trying to parse this XML...
<whmcsapi version="4.1.2">
<action>getstaffonline</action>
<result>success</result>
<totalresults>1</totalresults>
<staffonline>
<staff>
<adminusername>Admin</adminusername>
<logintime>2010-03-03 18:29:12</logintime>
<ipaddress>127.0.0.1</ipaddress>
<lastvisit>2010-03-03 18:30:43</lastvisit>
</staff>
</staffonline>
</whmcsapi>
using this code..
XDocument doc = XDocument.Parse(strResponse);
var StaffMembers = doc.Descendants("staff").Select(staff => new
{
Name = staff.Element("adminusername").Value,
LoginTime = staff.Element("logintime").Value,
IPAddress = staff.Element("ipaddress").Value,
LastVisit = staff.Element("lastvisit").Value,
}).ToList();
label1.Text = doc.Element("totalresults").Value;
foreach (var staff in StaffMembers)
{
listBox1.Items.Add(staff.Name);
}
I have printed out the contents of strResponse and the XML is definitely there. However, when I click this button, nothing is added to the listBox1 or the label1 so I something is wrong.
Add Root here to start navigating from the root element (whmcsapi):
string label1_Text = doc.Root.Element("totalresults").Value;