Develop Reference

Form.ShowDialog Methode

I have created a software, which save some Information in an Excel File. The software has two possibilities:
To select the folder and then the software will create an Excel File with random name and there will save the data , or
To select an existed Excel File which is created from the user and there will save the data.
How to create a ONE ShowDialog to ask the user do you want to choose the folder or the file?!
Code that I have used to choose a Folder:
using (var fbd = new FolderBrowserDialog())
{
DialogResult result = fbd.ShowDialog();
if (result == DialogResult.OK && !string.IsNullOrWhiteSpace(fbd.SelectedPath))
{
textBox3.Text = fbd.SelectedPath;
}
}
Code that I have used to choose a File:
OpenFileDialog excelFilename = new OpenFileDialog();
if (excelFilename.ShowDialog() == DialogResult.OK)
{
textBox3.Text = excelFilename.FileName;
}

Maybe something like this?:
MessageBoxResult result = MessageBox.Show("Ask user what he wants to do", "", MessageBoxButton.YesNo);
string path = null;
//MessageBoxResult.Yes means File, .No means Folder
if (result == MessageBoxResult.Yes)
{
//File-Picker
OpenFileDialog filePicker = new OpenFileDialog()
{
FileName = "Excel File",
DefaultExt = ".xls",
Filter = "Excel Document | *.xls"
};
if (filePicker.ShowDialog() == true)
{
path = filePicker.FileName;
}
}
else if (result == MessageBoxResult.No)
{
//Folder-Picker
CommonOpenFileDialog folderPicker = new CommonOpenFileDialog()
{
IsFolderPicker = true,
Multiselect = false
};
path = Path.Combine(folderPicker.FileName, DateTime.Now.ToString("yyyy-MM-ddTHH-mm-ss"));
//Create file in folder
File.Create(path);
}
if (path != null)
{
// Do something with path (file user selected/program created)
}
Make sure you have the using System.Windows, using Microsoft.Win32; and using System.IO; using's at the beginning of your program.
You also have to add the WindowsAPICodePack library to your project to use the folder-picker. You can do that with the NuGet manager. Here's the link to the library: WindowsAPICodePack - 1.1.1

Saving txt file going to wrong location

I'm trying to save a text file log to a specific location from my Windows Form project. I set the InitialDirectory to Path.GetFullPath(filePath) where I pass in filePath which is set as a simple path of "C:\MyWork\EventLogs\"
The log saves on Exit of the program (when a user closes or hits an Exit button), but it still saves in the Project\bin\Debug folder of my project.
Any ideas would be great. Thanks!
try
{
DateTime today = DateTime.Now;
string todayDate = today.ToString("yyyy-MM-dd_HHmm");
string fileName = (todayDate + "_EventLog" + ".txt").Trim();
string filePath = #"C:\MyWork\EventLogs\";
DirectoryInfo di = Directory.CreateDirectory(filePath);
SaveFileDialog sn = new SaveFileDialog
{
FileName = fileName,
AddExtension = true,
CheckPathExists = true,
Filter = "Text (*.txt)|*.txt",
OverwritePrompt = true,
InitialDirectory = Path.GetFullPath(filePath)
};
sn.RestoreDirectory = true;
StreamWriter SaveFile = new StreamWriter(fileName);
foreach (var item in EventLog)
{
SaveFile.WriteLine(item);
}
SaveFile.Close();
}
catch (Exception x)
{
MessageBox.Show(x.ToString());
}

You don't show the save dialog or use its FileName property in your current code, instead you refer to the initial fileName when saving.
So what you need to do is something like this instead:
if (sn.ShowDialog() == DialogResult.OK)
{
using (StreamWriter SaveFile = new StreamWriter(sn.FileName))
{
foreach (var item in EventLog)
{
SaveFile.WriteLine(item);
}
}
}
This will display the save dialog and assuming that the user clicks on OK the FileName of the save dialog should be the full path of where the user wants to save to.

You must show the Save Dialog for it to return the value you are expecting.

Create a (text) file using FolderBrowserDialog

I created a notepad, however i want to save the file using the FolderBrowserDialog. Now i can't save the file because of this error: An unhandled exception of type 'System.NotSupportedException' occurred in mscorlib.dll
Additional information: The specified path is not supported.
this is the code i enterd:
private void Create_button_Click(object sender, EventArgs e)
{
DialogResult dialogResult = MessageBox.Show("Are you sure to make the file", "Sure?", MessageBoxButtons.YesNo, MessageBoxIcon.Question);
if (dialogResult == DialogResult.Yes)
{
FolderBrowserDialog openfiledalog1 = new FolderBrowserDialog();
if (openfiledalog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
string[] files = Directory.GetFiles(openfiledalog1.SelectedPath);
StreamWriter File = new StreamWriter(files + "." + groupBox3);
File.Write(textBox4);
}
}
else if (dialogResult == DialogResult.No)
{
}
}
can somebody help me?

a few things here to cause problems:
string[] files = Directory.GetFiles(openfiledalog1.SelectedPath);
Here you read the existing files in that directory. I thought you wanted to create a file? IN that case you provide a destination path, e.g.
var dest=Path.Combine(openfileDialog1.SelectedPath,"myfile.txt");
The following especially will not work:
StreamWriter File = new StreamWriter(files + "." + groupBox3);
You are passing a string array here. You need to pass a string as argument, not an array. See above. Also you try to name it like (which?) existing file + an extension determined by some groupBox3?
Writing the file, assuming that textBox4 contains the contents to be written, needs to be specified via the .Text property:
File.Write(textBox4.Text);
Please be specific as to which control or variable contains the desired output filename, which the contents, and what groupBox3 is supposed to provide.
Edit:
RadioButton suffix = groupBox3.Controls.OfType<RadioButton>().FirstOrDefault(n => n.Checked);
if (suffix == null)
MessageBox.Show("Please select a valid extension first");
else
{
var extension = suffix.Text;
FolderBrowserDialog openfiledalog1 = new FolderBrowserDialog();
if (openfiledalog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
var dest = Path.Combine(openfiledalog1.SelectedPath, "NewFile." + extension);
using (StreamWriter File = new StreamWriter(dest, false))
{
File.Write(textBox4.Text);
}
}
}

How to give custom made locations for downloading the file

I just wanted to know how can i give a custom made default location for grabbing the files.
I have uploaded a file to the local database and i have binded the file to the gird also. When i press download its showing an error called "the file is not found in location"
If i copy the particular uploaded files to the specified location i can download it easily.
So i just need to know how can i give a default location so that i can upload and downlaod the file from the same exact location.
snapshot of error: https://imageshack.com/i/ewTrmAI2j
Edited the same below code with custom made folder path. But i dont know why the file is always being asked from bin/debug/ folder. WHy its happening like this. IS there any way i can make changes to this folder.. other than bin/debug/ folder
Codes:
private void DownloadAttachment(DataGridViewCell dgvCell)
{
string fileName = Convert.ToString(dgvCell.Value);
//Return if the cell is empty
if (fileName == string.Empty)
return;
FileInfo fileInfo = new FileInfo(fileName);
string fileExtension = fileInfo.Extension;
byte[] byteData = File.ReadAllBytes(fileInfo.FullName); - - - - <<<<< ERROR HERE
//show save as dialog
using (SaveFileDialog saveFileDialog1 = new SaveFileDialog())
{
//Set Save dialog properties
saveFileDialog1.Filter = "Files (*" + fileExtension + ")|*" + fileExtension;
saveFileDialog1.Title = "Save File as";
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.FileName = fileName;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
string s = cncInfoDataGridView.Rows[dgvCell.RowIndex].Cells[1].Value.ToString();
File.WriteAllBytes(saveFileDialog1.FileName, byteData);
byteData = System.Text.Encoding.ASCII.GetBytes(s);
}
}
}

The FileInfo() constructor only works with a full file path. It sounds like you are trying to use the constructor with just a file name, at which point it fails when you try to read the file because its not a valid path. There are a couple possibilities for dealing with this:
Create your own MyFileInfo() class inheriting from FileInfo() and add a constructor that appends your specific path to the filename.
Simply append the path in-line in your code as:
var myPath = #"c:\folder\stuff\";
FileInfo fileInfo = new FileInfo(myPath + fileName);
Normally the path would be setup as a setting in your app.config so you could change it easily if needed.

I found the answer
codes for the binding file path to the gridview and download the file using the file path
private void UploadAttachment(DataGridViewCell dgvCell)
{
using (OpenFileDialog fileDialog = new OpenFileDialog())
{
//Set File dialog properties
fileDialog.CheckFileExists = true;
fileDialog.CheckPathExists = true;
fileDialog.Filter = "All Files|*.*";
fileDialog.Title = "Select a file";
fileDialog.Multiselect = true;
if (fileDialog.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
string strfilename = fileDialog.FileName;
cncInfoDataGridView.Rows[dgvCell.RowIndex].Cells[1].Value = strfilename;
}
}
}
/// <summary>
/// Download Attachment from the provided DataGridViewCell
/// </summary>
/// <param name="dgvCell"></param>
private void DownloadAttachment(DataGridViewCell dgvCell)
{
string fileName = Convert.ToString(dgvCell.Value);
if (!string.IsNullOrEmpty(fileName))
{
byte[] objData;
FileInfo fileInfo = new FileInfo(fileName);
string fileExtension = fileInfo.Extension;
//show save as dialog
using (SaveFileDialog saveFileDialog1 = new SaveFileDialog())
{
//Set Save dialog properties
saveFileDialog1.Filter = "Files (*" + fileExtension + ")|*" + fileExtension;
saveFileDialog1.Title = "Save File as";
saveFileDialog1.CheckPathExists = true;
saveFileDialog1.FileName = fileName;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
string s = cncInfoDataGridView.Rows[dgvCell.RowIndex].Cells[1].Value.ToString();
objData = File.ReadAllBytes(s);
File.WriteAllBytes(saveFileDialog1.FileName, objData);
}
}
}
}
}

Selection of a folder path with C#

I have a WPF application in which i have this method:
public static string getFile(List<string> extensions)
{
Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog();
string ext = "files (", filter = "";
foreach (string s in extensions)
{
ext += s + ",";
filter += "*." + s + ";";
}
ext += ")";
dlg.Filter =ext+"|"+ filter;
Nullable<bool> result = dlg.ShowDialog();
if (result == true)
{
return dlg.FileName;
}
else return null;
}
I need to add another simple method which returns a folder path in which i will save new file.
How can i do this?
What is the best way to do it?

SaveFileDialog is what you need. From MSDN link:
// Configure save file dialog box
Microsoft.Win32.SaveFileDialog dlg = new Microsoft.Win32.SaveFileDialog();
dlg.FileName = "Document"; // Default file name
dlg.DefaultExt = ".text"; // Default file extension
dlg.Filter = "Text documents (.txt)|*.txt"; // Filter files by extension
// Show save file dialog box
Nullable<bool> result = dlg.ShowDialog();
// Process save file dialog box results
if (result == true)
{
// Save document
string filename = dlg.FileName;
}

I'd suggest having a look at the free Ookii Dialogs for WPF. I've used it on commercial projects in the past and it's always worked really well. Native support for WPF obviously but also has a lot of options for customization and provides more consistency across different versions of Windows.