I have the following test XML string:
<?xml version="1.0" encoding="UTF-8"?>
<test id="myid">
<b>b1</b>
<a>a2</a>
<a>a1</a>
<b>b2</b>
</test>
which I deserialize using this class:
[XmlRoot(ElementName = "test")]
public class Test
{
[XmlElement(ElementName = "a")]
public List<string> A { get; set; }
[XmlElement(ElementName = "b")]
public List<string> B { get; set; }
[XmlAttribute(AttributeName = "id")]
public string Id { get; set; }
}
If I'm now going to serialize the object the result will be:
<?xml version="1.0" encoding="utf-16"?>
<test xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" id="myid">
<a>a2</a>
<a>a1</a>
<b>b1</b>
<b>b2</b>
</test>
Is there a way to keep the initial sort order?
I guess I can't use [XmlElementAttribute(Order = x)] cause the order shouldn't be hardcoded but identically with the initial xml.
I thought about adding an order property to my lists like that
[XmlRoot(ElementName="a")]
public class A
{
[XmlAttribute(AttributeName="order")]
public string Order { get; set; }
[XmlText]
public string Text { get; set; }
}
[XmlRoot(ElementName="b")]
public class B
{
[XmlAttribute(AttributeName="order")]
public string Order { get; set; }
[XmlText]
public string Text { get; set; }
}
[XmlRoot(ElementName="test")]
public class Test
{
[XmlElement(ElementName="a")]
public List<A> A { get; set; }
[XmlElement(ElementName="b")]
public List<B> B { get; set; }
[XmlAttribute(AttributeName="id")]
public string Id { get; set; }
}
but I don't know how to order by them when serializing.
You can do this with XmlSerializer by using a single collection to capture both the <a> and <b> elements and applying the [XmlElement(Name, Type = typeof(...))] attribute to it multiple times, once for each desired element name. Because you are using a single collection to deserialize both elements, the order is automatically preserved. However, to make this work, XmlSerializer must be able to determine the correct element name when re-serializing. There are two approaches to accomplish this, as documented in Choice Element Binding Support:
If the collection contains polymorphic items, the element name can be mapped to the concrete item type by using the [XmlElementAttribute(String, Type)] constructor. For instance, if you have a sequence of elements that might be strings or integers like so:
<Things>
<string>Hello</string>
<int>999</int>
</Things>
This can be bound to a collection as follows:
public class Things
{
[XmlElement(Type = typeof(string)),
XmlElement(Type = typeof(int))]
public List<object> StringsAndInts { get; set; }
}
If the collection contains only a single type of item, the element name can be encoded in an associated array of enum values, where the enum names correspond to the element names and the array itself is identified via the [XmlChoiceIdentifierAttribute] attribute.
For details, see the documentation examples.
I find option #1 easier to work with than option #2. Using this approach, the following model will deserialize and re-serialize your XML while successfully preserving the order of the <a> and <b> elements:
public abstract class StringElementBase
{
[XmlText]
public string Text { get; set; }
public static implicit operator string(StringElementBase element)
{
return element == null ? null : element.Text;
}
}
public sealed class A : StringElementBase
{
}
public sealed class B : StringElementBase
{
}
[XmlRoot(ElementName = "test")]
public class Test
{
[XmlElement("a", Type = typeof(A))]
[XmlElement("b", Type = typeof(B))]
public List<StringElementBase> Items { get; } = new List<StringElementBase>();
[XmlIgnore]
// For convenience, enumerate through the string values of the items.
public IEnumerable<string> ItemValues { get { return Items.Select(i => (string)i); } }
[XmlAttribute(AttributeName = "id")]
public string Id { get; set; }
}
Working .Net fiddle.
For more examples of using [XmlChoiceIdentifier] to deserialize a sequence of elements with different names to c# objects of the same type, see for instance here or here.
No, basically; XmlSerializer doesn't support that. If you want to use that option you'd need to write it manually with XDocument or XmlDocument or XmlReader.
Related
I am working on deserializing the following XML document into a C# class:
<Station>
<station_id>KMSP</station_id>
<wmo_id>72658</wmo_id>
<latitude>44.88</latitude>
<longitude>-93.23</longitude>
<elevation_m>255.0</elevation_m>
<site>MINNEAPOLIS</site>
<state>MN</state>
<country>US</country>
<site_type>
<METAR />
<TAF />
</site_type>
</Station>
This is the class that it is being deserialized into:
public class Station
{
[XmlElement(ElementName ="station_id")]
public string StationId { get; set; }
[XmlElement(ElementName = "wmo_id")]
public string WmoId { get; set; }
[XmlElement(ElementName ="latitude")]
public double Latitude { get; set; }
[XmlElement(ElementName = "longtitude")]
public double Longtitude { get; set; }
[XmlElement(ElementName="site")]
public string Site { get; set; }
[XmlElement(ElementName ="state")]
public string State { get; set; }
[XmlElement(ElementName ="country")]
public string Country { get; set; }
[XmlElement(ElementName = "site_type")]
public string[] SiteType { get; set; }
}
Everything seems to be deserializng correctly, except for the <site_type> tag. The contents of this tag will vary from Station to Station, but will always contain one or more items of a specific value - essentially from an enum. These tags are always self closing and do not ever contain attributes. They are strictly in the <METAR /> format. When I attempt to deserialize this XML, I get a ReadElementContentAs() error, and I am 99% sure it's that tag that is causing the issue. Would anyone happen to know where I went wrong on this, or have any advice on how to deserialize that kind of element?
Thank you!
Taking your comment on this answer into account
For clarifcation, these type tags in the SiteType will never contain any data like the other tags. If the tag is present, it means that this weather station produces that type of report (METAR, TAF, SIGMENTS, etc)
That SiteType isn't an array of strings, but an array of types, with a different one per report type. All share the same base class.
public abstract class SiteType
{ }
public class Metar : SiteType
{ }
public class Taf : SiteType
{ }
That SiteType property then looks like below
[XmlArray(ElementName = "site_type")]
[XmlArrayItem(typeof(Metar), ElementName ="METAR")]
[XmlArrayItem(typeof(Taf), ElementName = "TAF")]
public SiteType[] SiteType { get; set; }
To check whether a certain report type is supported for a station, you check for the presence of the corresponding type within that SiteType array.
var hasMetar = p.SiteType.Any(o => o.GetType() == typeof(Metar));
You can declare a property as follows:
[XmlAnyElement(Name = "site_type")]
public XmlElement SiteType { get; set; }
After deserialization, there will be a collection of nodes in the property.
foreach(XmlNode node in station.SiteType.ChildNodes)
Console.WriteLine(node.Name);
I want to serialize the following class
[Serializable]
public class Model{
[XmlElement("ElementName")]
public string Name { get; set; }
[XmlElement("Number")]
public int Number { get; set; }
}
And I will get the following result:
<Model>
<ElementName>testData</ElementName>
<Number>5</Number>
</Model>
Is there any way xml document to look like that with the property type:
<Model>
<ElementName><string>testData</string></ElementName>
<Number><int>5</int></Number>
</Model>
The only way I can think to get that output with XmlSerializer would be to change the model to include those layers:
public class XmlInt32
{
[XmlElement("int")]
public int Value {get;set;}
// not shown... maybe some implicit operators?
}
public class XmlString
{
[XmlElement("string")]
public string Value {get;set;}
// not shown... maybe some implicit operators?
}
public class Model
{
[XmlElement("ElementName")]
public XmlString Name { get; set; }
public XmlInt32 Number { get; set; }
}
Note, however, that this layout looks pretty unusual and atypical; frankly, I would expect the version in the top example in the question, not the bottom one. If you want to formally define the types of each element, that's usually done in a schema (xsd), not in the payload (xml).
I am having problems deserializing XML to an object with a list. The deserialize runs without error but the Resources list is empty, and I know there is one resource returned in the XML. It seems like it is just not being deserialised properly.
I am using the following code to deserialize
var ser = new XmlSerializer(typeof(SearchResult));
var test = result.Content.ReadAsStringAsync();
var t = (SearchResult)ser.Deserialize(result.Content.ReadAsStreamAsync().Result);
The variable "test" on line 2 of the code above is equal to
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<ns3:searchResult total="1" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ns3="ers.ise.cisco.com">
<resources>
<resource id="76a4b0f2-64e2-11e6-9f15-00505688a404" name="5555884552">
<link rel="self" href="https://servername123:9060/ers/config/guestuser/76a4b0f2-64e2-11e6-9f15-00505688a404" type="application/xml"/>
</resource>
</resources>
</ns3:searchResult>
So I would expect to get one ExistingWifiAccountDto in the Resources list. But I don't. It is empty. What am I doing wrong?
The classes for object mapping are below
[XmlRoot(ElementName = "searchResult", Namespace = "ers.ise.cisco.com")]
public class SearchResult
{
public SearchResult()
{
Resources = new List<ExistingWifiAccountDto>();
}
[XmlArray("resources")]
[XmlArrayItem("resource", typeof(ExistingWifiAccountDto))]
public List<ExistingWifiAccountDto> Resources { get; set; }
}
public class ExistingWifiAccountDto
{
public ExistingWifiAccountDto()
{
}
[XmlAttribute("id")]
public string Id { get; set; }
[XmlAttribute("name")]
public string Name { get; set; }
[XmlElement("link")]
public LinkDto Link { get; set; }
}
public class LinkDto
{
public LinkDto()
{
}
[XmlAttribute("rel")]
public string Rel { get; set; }
[XmlAttribute("href")]
public string Href { get; set; }
[XmlAttribute("type")]
public string Type { get; set; }
}
You'll have to set the namespace to an empty string for the "resources" array since it is not inherited in you situation. This should then flow down to child elements.
Try changing
[XmlArray("resources")]
to
[XmlArray("resources", Namespace = "")]
This will cause it to deserialize correctly, alternatively, you could also set each node from "resources" down with the Form attribute:
Form = XmlSchemaForm.Unqualified
Cheers
I need to sandwich an element inside of another element. Is it possible to serialize XML like this?
http://pastebin.com/7qDE7Ses
Here is my class
[XmlRoot(ElementName = "SalesOrderMod")]
public partial class SalesOrderMod
{
[XmlElementAttribute(Order = 1)]
public string TxnID { get; set; }
[XmlElementAttribute(Order = 2)]
public string EditSequence { get; set; }
[XmlElementAttribute(Order = 3)]
public string ShipDate { get; set; }
[XmlElementAttribute(Order = 4)]
public ListRef ShipMethodRef = new ListRef();
public bool ShouldSerializeShipMethodRef()
{
return !(String.IsNullOrEmpty(ShipMethodRef.FullName));
}
[XmlElementAttribute(Order = 5)]
public string Other { get; set; }
[XmlElementAttribute(Order = 6, ElementName = "SalesOrderLineMod")]
public List<LineMod> SalesOrderLineMod = new List<LineMod>();
[XmlElementAttribute(Order = 7, ElementName = "SalesOrderLineGroupMod")]
public List<LineMod> SalesOrderLineGroupMod = new List<LineMod>();
}
You originally indicated you would like to serialize a series of elements inside an XML document like so:
<SalesOrderLineRet>
</SalesOrderLineRet>
<SalesOrderLineGroupRet>
</SalesOrderLineGroupRet>
<SalesOrderLineRet>
</SalesOrderLineRet>
You can if the types that correspond to SalesOrderLineRet and SalesOrderLineGroupRet have some common base type T, and they are stored in a List<T>. For instance, the following class definitions:
public abstract class SalesOrderLineRetBase
{
}
public class SalesOrderLineRet : SalesOrderLineRetBase
{
}
public class SalesOrderLineGroupRet : SalesOrderLineRetBase
{
}
public class RootObject
{
[XmlElement(typeof(SalesOrderLineRetBase))]
[XmlElement(typeof(SalesOrderLineRet))]
[XmlElement(typeof(SalesOrderLineGroupRet))]
public List<SalesOrderLineRetBase> SalesOrders { get; set; }
}
Will, when serialized, produce the following XML:
<RootObject>
<SalesOrderLineRet />
<SalesOrderLineGroupRet />
</RootObject>
Using [XmlElement(typeof(T))] tells XmlSerializer that the list should be serialized without an outer container element, and that items of type T can be expected to be found in the list. You must apply [XmlElement(typeof(T))] once for each type T that will be stored in the list.
(You can use List<object> if the types in the list have no other more derived base type, however I don't recommend that. I would instead recommending grouping the possible types of list entry under a specific base type.)
If you would prefer your list to be serialized with an outer container element, you can use [XmlArray] and [XmlArrayItem(typeof(T))]:
public abstract class SalesOrderLineRetBase
{
}
public class SalesOrderLineRet : SalesOrderLineRetBase
{
}
public class SalesOrderLineGroupRet : SalesOrderLineRetBase
{
}
public class RootObject
{
[XmlArray("SalesOrders")]
[XmlArrayItem(typeof(SalesOrderLineRetBase))]
[XmlArrayItem(typeof(SalesOrderLineRet))]
[XmlArrayItem(typeof(SalesOrderLineGroupRet))]
public List<SalesOrderLineRetBase> SalesOrders { get; set; }
}
Which produces the following XML:
<RootObject>
<SalesOrders>
<SalesOrderLineRet />
<SalesOrderLineGroupRet />
</SalesOrders>
</RootObject>
You must apply [XmlArrayItem(typeof(T))] for each type T that will be stored in the list.
(Since you don't include the relevant classes and XML in your question, I'm not sure which one you might want.)
My XML:
<result>
<document version="2.1.0">
<response type="currency">
<currency>
<code>AMD</code>
<price>85.1366</price>
</currency>
</response>
<response type="currency">
<currency>
<code>AUD</code>
<price>31.1207</price>
</currency>
</response>
</document>
</result>
My Class:
public class CurrencyData
{
public string Code { get; set; }
public string Price { get; set; }
}
My deserializer calling:
RestClient.ExecuteAsync<List<CurrencyData>>...
If i renamed class CurrencyData to Currency then all will been done right. But I want to keep this class name.
Ok, I think I got it,
You can try RestClient.ExecuteAsync<Result>()
[XmlRoot("result")]
public class Result
{
[XmlElement("document")]
public Document Document { get; set; }
}
public class Document
{
[XmlElement("response")]
public Response[] Responses { get; set; }
[XmlAttribute("version")]
public string Version { get; set; }
}
public class Response
{
[XmlElement("currency")]
public CurrencyData Currency { get; set; }
[XmlAttribute("type")]
public string Type { get; set; }
}
public class CurrencyData
{
[XmlElement("code")]
public string Code { get; set; }
[XmlElement("price")]
public decimal Price { get; set; }
}
I had to add a few XmlElement attribute to override the casing without having to name classes and properties in lowercase. but you can drop them if you can change the xml to match the casing
Answer of kay.one is perfect! It works with a any remarks:
public List<Response> Responses { get; set; }
works
public Response[] Responses { get; set; }
don`t works
And
[XmlElement("AnyValue")]
it is from System.Xml.Serialization namespace and don`t work.
Feel free to just delete them.
In this example annotation attributes and properties has same names and serializer understands.
But right annotation attributes are from RestSharp.Deserializers namespace
[DeserializeAs(Name="AnyXmlValue")]
public string AnyModelValue { get; set; }
How to manage deserialization of RestSharp
Then change the xml tag to CurrencyData. Here is the documentation about the xml deserializer: https://github.com/restsharp/RestSharp/wiki/Deserialization
I'm not sure why Kay.one's answer is accepted, it doesn't answer the question.
Per my comment, the default RestSharp deserializer doesn't check for the DeserializeAs attribute when deserializing a list. I'm not sure if that's intentional or a mistake as the author doesn't seem to be very available.
Anyways it's a simple fix.
private object HandleListDerivative(object x, XElement root, string propName, Type type)
{
Type t;
if (type.IsGenericType)
{
t = type.GetGenericArguments()[0];
}
else
{
t = type.BaseType.GetGenericArguments()[0];
}
var list = (IList)Activator.CreateInstance(type);
var elements = root.Descendants(t.Name.AsNamespaced(Namespace));
var name = t.Name;
//add the following
var attribute = t.GetAttribute<DeserializeAsAttribute>();
if (attribute != null)
name = attribute.Name;