I have a command line application that calls a 'netsh' process and changes some IP information. The problem that I have is that every time I call my app in CMD or PowerShell, it starts a new instance of CMD(opens a new CMD window and closes it after it's finished executing)
I would like to know if there is a way to have everything happen in the same window
here is the code that starts a process:
Process p = new Process();
ProcessStartInfo psi = new ProcessStartInfo("netsh", queryStr);
p.StartInfo = psi;
p.Start();
Console.WriteLine("netsh query string is: " + "***" + queryStr + "***");
This is my first question, please don't judge too harshly
I hope I understood your question correctly. You could hide the Shell, while redirecting the ouput. For example,
Process p = new Process();
ProcessStartInfo psi = new ProcessStartInfo("netsh", queryStr);
psi.WindowStyle = ProcessWindowStyle.Hidden;
psi.RedirectStandardOutput = true;
psi.UseShellExecute = false;
p.StartInfo = psi;
p.Start();
var output = p.StandardOutput.ReadToEnd();
ProcessStartInfo.WindowStyle allows to set the state of Window when the process starts. In the current scenario, you could set it to ProcessWindowStyle.Hidden
ProcessStartInfo.UseShellExecute indicates whether to use the OS's Shell. Disabling this would help in redirecting the output.
ProcessStartInfo.RedirectStandardOutput indicates whether the output is written to StandardOutput. By setting it to true, you can redirect the output stream and use the Process.StandardOutput to read the output and display as per application design
Related
I have a C# program that launches a child process and captures its output in a string. This works on most Windows machines (Windows 7 and newer), but when Kaspersky anti-virus is present, Process.StandardOutput.ReadToEnd() returns null. There is no error code or exception. The child process is a trusted console application. The process takes 5 or 6 seconds to run.
The code for launching the child process is as follows:
ProcessStartInfo psi = new ProcessStartInfo();
psi.UseShellExecute = false;
psi.CreateNoWindow = true;
psi.RedirectStandardOutput = true;
psi.RedirectStandardError = true;
psi.WindowStyle = ProcessWindowStyle.Hidden;
psi.FileName = "icao.exe";
psi.Arguments = im_path + "image.jpg";
Process p = new Process();
p.StartInfo = psi;
p.Start();
string output = p.StandardOutput.ReadToEnd();
string error = p.StandardError.ReadToEnd();
MessageBox.Show(error);
p.WaitForExit();
int exitCode = p.ExitCode;
MessageBox.Show(exitCode+"");
Why does output end up being null when Kaspersky is present?
My guess is that Kaspersky's heuristics are seeing that your program wants to execute another exe. Because nothing is telling Kaspersky that this is ok, it flags your program as possible malware, because it wants to interface with other programs that are developed by other companies. If you are able to I would try white listing your program with Kaspersky and see if that solves your issue.
I am working on a project of remotely receiving commands from a server, but I am facing a problem when working with the command prompt locally. Once I get it working locally, then I will move to remote communication.
Problem:
I have to completely hide the console, and client must not see any response when the client is working with the command line but it will show a console for a instance and then hide it.
I had to use c# to send a command to cmd.exe and receive the result back in C#. I have done it in one way by setting the StandardOutput... and input to true.
The commands are not working. For example, D: should change the directory to D and it does, but after that, if we use dir to see the directories in D, it does not show the appropriate directories.
Here is my code:
First Method
Process process = new Process();
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C " + textBoxInputCommand.Text + " >> " + " system";
process.StartInfo = startInfo;
process.Start();
Second Method
ProcessStartInfo procStartInfo = new ProcessStartInfo("cmd", "/c " + textBoxInputCommand.Text);
procStartInfo.WorkingDirectory = #"c:\";
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = true;
procStartInfo.UseShellExecute = false;
Process proc = new Process();
proc.StartInfo = procStartInfo;
proc.Start();
string result = proc.StandardOutput.ReadToEnd();
richTextBoxCommandOutput.Text += result;
I want the program to run as administrator because the exe it generates does not run commands when it runs from the C drive.
Try not to run the commands by passing them to cmd instead write the commands passed by the client to a.bat file execute the .bat. file from your program this will probably hide your command prompt window.
You can also use process.OutputDataRecieved event handler to do anything with the output.
If you want to execute command using administrator rights you can use runascommand. It is equivalent to the sudo command in Linux. Here is a piece of code may be it will help you
var process = new Process();
var startinfo = new ProcessStartInfo(#"c:\users\Shashwat\Desktop\test.bat");
startinfo.RedirectStandardOutput = true;
startinfo.UseShellExecute = false;
process.StartInfo = startinfo;
process.OutputDataRecieved += DoSomething;
process.Start();
process.BeginOutputReadLine();
process.WaitForExit();
//Event Handler
public void DoSomething(object sener, DataReceivedEventArgs args)
{
//Do something
}
Hope it helps you.
You could hide command prompt window by adding this line of code:
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
or do not create it at all
startInfo.CreateNoWindow = true;
Here can be found a few awarding solutions:
Run Command Prompt Commands
I want to run an exe file by my c# code. The exe file is a console application written in c#.
The console application performs some actions which includes writing content in database and writing some files to directory.
The console application (exe file) expects some inputs from user.
Like it first asks , 'Do you want to reset database ?' y for yes and n for no.
again if user makes a choice then application again asks , 'do you want to reset files ?'
y for yes and n for no.
If user makes some choice the console application starts to get executed.
Now I want to run this exe console application by my c# code. I am trying like this
string strExePath = "exe path";
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = strExePath;
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
using (Process exeProcess = Process.Start(startInfo))
{
exeProcess.WaitForExit();
}
I want to know how can I provide user inputs to the console application by my c# code?
Please help me out in this. Thanks in advance.
You can redirect input and output streams from your exe file.
See redirectstandardoutput
and redirectstandardinput for examples.
For reading:
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "Write500Lines.exe";
p.Start();
// Do not wait for the child process to exit before
// reading to the end of its redirected stream.
// p.WaitForExit();
// Read the output stream first and then wait.
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
For writing:
...
myProcess.StartInfo.RedirectStandardInput = true;
myProcess.Start();
StreamWriter myStreamWriter = myProcess.StandardInput;
myStreamWriter.WriteLine("y");
...
myStreamWriter.Close();
ProcessStartInfo has a constructor that you can pass arguments to:
public ProcessStartInfo(string fileName, string arguments);
Alternatively, you can set it on it's property:
ProcessStartInfo p = new ProcessStartInfo();
p.Arguments = "some argument";
Here is a sample of how to pass arguments to the *.exe file:
Process p = new Process();
// Redirect the error stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.FileName = #"\filepath.exe";
p.StartInfo.Arguments = "{insert arguments here}";
p.Start();
error += (p.StandardError.ReadToEnd());
p.WaitForExit();
I am having trouble executing an external console application using Process.Start
Process p = new Process();
p.StartInfo.WorkingDirectory = "dump";
p.StartInfo.FileName = "test.exe";
p.StartInfo.Arguments = s;
p.Start();
When the argument that p generates executes, the external application crashes, although if I copy the exact same argument in a command line window it runs fine.
So my question instead how would I create a new instance of a command window and then add the command test.exe + s to run?
So effectively I am launching cmd and then adding my arguments on to it
If you want to run test.exe prm1 prm2 via cmd, use cmd.exe /c test.exe prm1 prm2. Though I don't really understand what this has to do with the crashes. Sounds like your problem is with test.exe - find out what's causing it to crash, and that will help you fix your C# code so that you don't need the cmd.
One of the places I would examine is the working directory. When you set it to "dump", are you sure the current directory is what you expect? Try using a full path first. It's possible that test.exe happens to be in the system path so it gets executed, but its working directory is not what it expects, and this causes it to crash.
try this:
ProcessStartInfo processToRunInfo = new ProcessStartInfo();
processToRunInfo.Arguments = "Arguments");
processToRunInfo.CreateNoWindow = true;
processToRunInfo.WorkingDirectory = "C:\\yourDir\\";
processToRunInfo.FileName = "test.exe";
//processToRunInfo.CreateNoWindow = true;
//processToRunInfo.WindowStyle = ProcessWindowStyle.Hidden;
Process process = new Process();
process.StartInfo = processToRunInfo;
process.Start();
Process p = new Process();
p.StartInfo.WorkingDirectory = "/full/path/to/dump";
p.StartInfo.FileName = "/full/path/to/test.exe";
p.StartInfo.Arguments = s; // will call 'text.exe s'
p.Start();
Take a look at MSDN.
You need to Create an instance of the StartInfo class and user Start() such as
ProcessStartInfo startInfo = new ProcessStartInfo("IExplore.exe");
startInfo.WindowStyle = ProcessWindowStyle.Minimized;
Process.Start(startInfo);
startInfo.Arguments = "www.example.com";
Process.Start(startInfo);
Try it!
Rewriting your code would look something like this:
ProcessStartInfo startInfo = new ProcessStartInfo("test.exe");
startInfo.WindowStyle = ProcessWindowStyle.Minimized;
startInfo.WorkingDirectory = "dump";
startInfo.Arguments = "s";
Process.Start(startInfo);
I've some troubles with running processes and passing args to them.
I know how to run process with some args
ProcessStartInfo psi = new ProcessStartInfo("cmd.exe", "/c something");
Process p = Process.Start(psi)
The problem is that after script is executed process is terminated. That's why there is "/c"
But I'm running multiple scripts and I would like to run them in one process ("cmd.exe") not to start new process every time.
Is there some solutions for it ?
I hope somebody understand what I'm talking about ;)
I recommend you utilize a batch file to script the execution of your executables and call your batch file instead. Or, you can do this -
Process p = new Process();
ProcessStartInfo info = new ProcessStartInfo();
info.FileName = "cmd.exe";
info.RedirectStandardInput = true;
info.UseShellExecute = false;
p.StartInfo = info;
p.Start();
using (StreamWriter sw = new StreamWriter(p.StandardInput))
{
if (sw.BaseStream.CanWrite)
{
sw.WriteLine("mysql -u root -p");
sw.WriteLine("mypassword");
sw.WriteLine("use mydb;");
}
}
It sounds like you ought to investigate redirecting the standard input - be sure to also set psi.UseShellExecute to false. You'll probably also want to redirect standard output, so you can have some way of knowing what your child process is doing.
Read more about redirection here.