I want to get the first day and last day of the month where a given date lies in. The date comes from a value in a UI field.
If I'm using a time picker I could say
var maxDay = dtpAttendance.MaxDate.Day;
But I'm trying to get it from a DateTime object. So if I have this...
DateTime dt = DateTime.today;
How to get first day and last day of the month from dt?
DateTime structure stores only one value, not range of values. MinValue and MaxValue are static fields, which hold range of possible values for instances of DateTime structure. These fields are static and do not relate to particular instance of DateTime. They relate to DateTime type itself.
Suggested reading: static (C# Reference)
UPDATE: Getting month range:
DateTime date = ...
var firstDayOfMonth = new DateTime(date.Year, date.Month, 1);
var lastDayOfMonth = firstDayOfMonth.AddMonths(1).AddDays(-1);
UPDATE: From comments (#KarlGjertsen & #SergeyBerezovskiy)
DateTime date = ...
var firstDayOfMonth = new DateTime(date.Year, date.Month, 1);
var lastDayOfMonth = firstDayOfMonth.AddMonths(1).AddSeconds(-1);
//OR
var lastDayOfMonth = firstDayOfMonth.AddMonths(1).AddTicks(-1);
This is more a long comment on #Sergey and #Steffen's answers. Having written similar code myself in the past I decided to check what was most performant while remembering that clarity is important too.
Result
Here is an example test run result for 10 million iterations:
2257 ms for FirstDayOfMonth_AddMethod()
2406 ms for FirstDayOfMonth_NewMethod()
6342 ms for LastDayOfMonth_AddMethod()
4037 ms for LastDayOfMonth_AddMethodWithDaysInMonth()
4160 ms for LastDayOfMonth_NewMethod()
4212 ms for LastDayOfMonth_NewMethodWithReuseOfExtMethod()
2491 ms for LastDayOfMonth_SpecialCase()
Code
I used LINQPad 4 (in C# Program mode) to run the tests with compiler optimization turned on. Here is the tested code factored as Extension methods for clarity and convenience:
public static class DateTimeDayOfMonthExtensions
{
public static DateTime FirstDayOfMonth_AddMethod(this DateTime value)
{
return value.Date.AddDays(1 - value.Day);
}
public static DateTime FirstDayOfMonth_NewMethod(this DateTime value)
{
return new DateTime(value.Year, value.Month, 1);
}
public static DateTime LastDayOfMonth_AddMethod(this DateTime value)
{
return value.FirstDayOfMonth_AddMethod().AddMonths(1).AddDays(-1);
}
public static DateTime LastDayOfMonth_AddMethodWithDaysInMonth(this DateTime value)
{
return value.Date.AddDays(DateTime.DaysInMonth(value.Year, value.Month) - value.Day);
}
public static DateTime LastDayOfMonth_SpecialCase(this DateTime value)
{
return value.AddDays(DateTime.DaysInMonth(value.Year, value.Month) - 1);
}
public static int DaysInMonth(this DateTime value)
{
return DateTime.DaysInMonth(value.Year, value.Month);
}
public static DateTime LastDayOfMonth_NewMethod(this DateTime value)
{
return new DateTime(value.Year, value.Month, DateTime.DaysInMonth(value.Year, value.Month));
}
public static DateTime LastDayOfMonth_NewMethodWithReuseOfExtMethod(this DateTime value)
{
return new DateTime(value.Year, value.Month, value.DaysInMonth());
}
}
void Main()
{
Random rnd = new Random();
DateTime[] sampleData = new DateTime[10000000];
for(int i = 0; i < sampleData.Length; i++) {
sampleData[i] = new DateTime(1970, 1, 1).AddDays(rnd.Next(0, 365 * 50));
}
GC.Collect();
System.Diagnostics.Stopwatch sw = System.Diagnostics.Stopwatch.StartNew();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].FirstDayOfMonth_AddMethod();
}
string.Format("{0} ms for FirstDayOfMonth_AddMethod()", sw.ElapsedMilliseconds).Dump();
GC.Collect();
sw.Restart();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].FirstDayOfMonth_NewMethod();
}
string.Format("{0} ms for FirstDayOfMonth_NewMethod()", sw.ElapsedMilliseconds).Dump();
GC.Collect();
sw.Restart();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].LastDayOfMonth_AddMethod();
}
string.Format("{0} ms for LastDayOfMonth_AddMethod()", sw.ElapsedMilliseconds).Dump();
GC.Collect();
sw.Restart();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].LastDayOfMonth_AddMethodWithDaysInMonth();
}
string.Format("{0} ms for LastDayOfMonth_AddMethodWithDaysInMonth()", sw.ElapsedMilliseconds).Dump();
GC.Collect();
sw.Restart();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].LastDayOfMonth_NewMethod();
}
string.Format("{0} ms for LastDayOfMonth_NewMethod()", sw.ElapsedMilliseconds).Dump();
GC.Collect();
sw.Restart();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].LastDayOfMonth_NewMethodWithReuseOfExtMethod();
}
string.Format("{0} ms for LastDayOfMonth_NewMethodWithReuseOfExtMethod()", sw.ElapsedMilliseconds).Dump();
for(int i = 0; i < sampleData.Length; i++) {
sampleData[i] = sampleData[i].FirstDayOfMonth_AddMethod();
}
GC.Collect();
sw.Restart();
for(int i = 0; i < sampleData.Length; i++) {
DateTime test = sampleData[i].LastDayOfMonth_SpecialCase();
}
string.Format("{0} ms for LastDayOfMonth_SpecialCase()", sw.ElapsedMilliseconds).Dump();
}
Analysis
I was surprised by some of these results.
Although there is not much in it the FirstDayOfMonth_AddMethod was slightly faster than FirstDayOfMonth_NewMethod in most runs of the test. However, I think the latter has a slightly clearer intent and so I have a preference for that.
LastDayOfMonth_AddMethod was a clear loser against LastDayOfMonth_AddMethodWithDaysInMonth, LastDayOfMonth_NewMethod and LastDayOfMonth_NewMethodWithReuseOfExtMethod. Between the fastest three there is nothing much in it and so it comes down to your personal preference. I choose the clarity of LastDayOfMonth_NewMethodWithReuseOfExtMethod with its reuse of another useful extension method. IMHO its intent is clearer and I am willing to accept the small performance cost.
LastDayOfMonth_SpecialCase assumes you are providing the first of the month in the special case where you may have already calculated that date and it uses the add method with DateTime.DaysInMonth to get the result. This is faster than the other versions, as you would expect, but unless you are in a desperate need for speed I don't see the point of having this special case in your arsenal.
Conclusion
Here is an extension method class with my choices and in general agreement with #Steffen I believe:
public static class DateTimeDayOfMonthExtensions
{
public static DateTime FirstDayOfMonth(this DateTime value)
{
return new DateTime(value.Year, value.Month, 1);
}
public static int DaysInMonth(this DateTime value)
{
return DateTime.DaysInMonth(value.Year, value.Month);
}
public static DateTime LastDayOfMonth(this DateTime value)
{
return new DateTime(value.Year, value.Month, value.DaysInMonth());
}
}
If you have got this far, thank you for time! Its been fun :¬). Please comment if you have any other suggestions for these algorithms.
Getting month range with .Net API (just another way):
DateTime date = ...
var firstDayOfMonth = new DateTime(date.Year, date.Month, 1);
var lastDayOfMonth = new DateTime(date.Year, date.Month, DateTime.DaysInMonth(date.Year, date.Month));
"Last day of month" is actually "First day of *next* month, minus 1". So here's what I use, no need for "DaysInMonth" method:
public static DateTime FirstDayOfMonth(this DateTime value)
{
return new DateTime(value.Year, value.Month, 1);
}
public static DateTime LastDayOfMonth(this DateTime value)
{
return value.FirstDayOfMonth()
.AddMonths(1)
.AddMinutes(-1);
}
NOTE:
The reason I use AddMinutes(-1), not AddDays(-1) here is because usually you need these date functions for reporting for some date-period, and when you build a report for a period, the "end date" should actually be something like Oct 31 2015 23:59:59 so your report works correctly - including all the data from last day of month.
I.e. you actually get the "last moment of the month" here. Not Last day.
OK, I'm going to shut up now.
DateTime dCalcDate = DateTime.Now;
dtpFromEffDate.Value = new DateTime(dCalcDate.Year, dCalcDate.Month, 1);
dptToEffDate.Value = new DateTime(dCalcDate.Year, dCalcDate.Month, DateTime.DaysInMonth(dCalcDate.Year, dCalcDate.Month));
Here you can add one month for the first day of current month than delete 1 day from that day.
DateTime now = DateTime.Now;
var startDate = new DateTime(now.Year, now.Month, 1);
var endDate = startDate.AddMonths(1).AddDays(-1);
If you only care about the date
var firstDay = new DateTime(date.Year, date.Month, 1, 0, 0, 0, date.Kind);
var lastDay = new DateTime(date.Year, date.Month, 1, 0, 0, 0, date.Kind).AddMonths(1).AddDays(-1);
If you want to preserve time
var firstDay = new DateTime(date.Year, date.Month, 1, date.Hour, date.Minute, date.Second, date.Kind);
var lastDay = new DateTime(date.Year, date.Month, 1, date.Hour, date.Minute, date.Second, date.Kind).AddMonths(1).AddDays(-1);
Try this one:
string strDate = DateTime.Now.ToString("MM/01/yyyy");
The accepted answer here does not take into account the Kind of the DateTime instance. For example if your original DateTime instance was a UTC Kind then by making a new DateTime instance you will be making an Unknown Kind instance which will then be treated as local time based on server settings. Therefore the more proper way to get the first and last date of the month would be this:
var now = DateTime.UtcNow;
var first = now.Date.AddDays(-(now.Date.Day - 1));
var last = first.AddMonths(1).AddTicks(-1);
This way the original Kind of the DateTime instance is preserved.
I used this in my script(works for me) but I needed a full date without the need of trimming it to only the date and no time.
public DateTime GetLastDayOfTheMonth()
{
int daysFromNow = DateTime.DaysInMonth(DateTime.Now.Year, DateTime.Now.Month) - (int)DateTime.Now.Day;
return DateTime.Now.AddDays(daysFromNow);
}
For Persian culture
PersianCalendar pc = new PersianCalendar();
var today = pc.GetDayOfMonth(DateTime.Now);
var firstDayOfMonth = pc.GetDayOfMonth(DateTime.Now.AddDays(-(today-1)));
var lastDayOfMonth = pc.GetDayOfMonth(DateTime.Now.AddMonths(1).AddDays(-today));
Console.WriteLine("First day "+ firstDayOfMonth);
Console.WriteLine("Last day " + lastDayOfMonth);
You can do it
DateTime dt = DateTime.Now;
DateTime firstDayOfMonth = new DateTime(dt.Year, date.Month, 1);
DateTime lastDayOfMonth = firstDayOfMonth.AddMonths(1).AddDays(-1);
Give this a try. It basically calculates the number of days that has passed on DateTime.Now, then subtracts one from that and uses the new value to find the first of the current month. From there it uses that DateTime and uses .AddMonths(-1) to get the first of the previous month.
Getting the last day of last month does basically the same thing except it adds one to number of days in the month and subtracts that value from DateTime.Now.AddDays, giving you the last day of the previous month.
int NumberofDays = DateTime.Now.Day;
int FirstDay = NumberofDays - 1;
int LastDay = NumberofDays + 1;
DateTime FirstofThisMonth = DateTime.Now.AddDays(-FirstDay);
DateTime LastDayOfLastMonth = DateTime.Now.AddDays(-LastDay);
DateTime CheckLastMonth = FirstofThisMonth.AddMonths(-1);
You can try this for get current month first day;
DateTime.Now.AddDays(-(DateTime.Now.Day-1))
and assign it a value.
Like this:
dateEndEdit.EditValue = DateTime.Now;
dateStartEdit.EditValue = DateTime.Now.AddDays(-(DateTime.Now.Day-1));
Create an instance of DateTime class
DateTime dateTime = DateTime.Now;
If you want to get the last day of the month you can do this
int lastDayOfMonth = DateTime.DaysInMonth(caducidadPuntos.Year, caducidadPuntos.Month);
If you want to get the first day of the month, you can do this
DateTime firstDayMonth = new DateTime(dateTime.Year, dateTime.Month, 1);
We had the requirement of being able to get the start and end of a given dates month, including times, inclusively. We ended up utilizing the aforementioned solutions, huge thanks to everyone here, and combined it into a util class to be able to get the start and end for a given month and year number combination up to the last millisecond. Including what we moved forward with in the event it helps someone else.
The util:
public class DateUtil
{
public static (DateTime startOfMonth, DateTime endOfMonth) GetStartAndEndOfMonth(int month, int year)
{
DateTime startOfMonth = GetStartOfMonth(month, year);
DateTime endOfMonth = GetEndOfMonth(month, year);
return (startOfMonth, endOfMonth);
}
public static DateTime GetStartOfMonth(int month, int year)
{
return new DateTime(year, month, 1).Date;
}
public static DateTime GetEndOfMonth(int month, int year)
{
return new DateTime(year, month, 1).Date.AddMonths(1).AddMilliseconds(-1);
}
}
Usage:
(DateTime startOfMonth, DateTime endOfMonth) = DateUtil.GetStartAndEndOfMonth(2, 2021); // February, 2021
easy way to do it
Begin = new DateTime(DateTime.Now.Year, DateTime.Now.Month,1).ToShortDateString();
End = new DataFim.Text = new DateTime(DateTime.Now.Year, DateTime.Now.Month, DateTime.DaysInMonth(DateTime.Now.Year, DateTime.Now.Month)).ToShortDateString();
DateTime dCalcDate = DateTime.Now;
var startDate = new DateTime(Convert.ToInt32(Year), Convert.ToInt32(Month), 1);
var endDate = new DateTime(Convert.ToInt32(Year), Convert.ToInt32(Month), DateTime.DaysInMonth((Convert.ToInt32(Year)), Convert.ToInt32(Month)));
I have to add 15 minutes to the current time and set it to a DateTime object in C#. If my current time is say 11:50 PM, and 15 minutes is added, the hour part becomes 24 and is causing the following error: "Hour, Minute, and Second parameters describe an un-representable DateTime."
public static DateTime NewTime(this DateTime dateTime)
{
int hour = dateTime.Hour;
int minute = dateTime.Minute;
if (minute > 0)
{
minute = dateTime.Minute + (15);
if (minute >= 60)
{
hour = hour + 1;
minute = 0;
}
}
return new DateTime(dateTime.Year, dateTime.Month,
dateTime.Day, hour, minute, 0);
}
Thanks
Your logic does not make sense, you are only adding minutes if the minutes are greater than 0 so what happens if they are 0?
To add time use the methods built into the type definition, no need to reinvent the wheel. Example:
public static DateTime Add15Minutes(this DateTime dateTime)
{
return dateTime.AddMinutes(15);
}
You are checking for an overflow on the minute attribute, but not the hour attribute. You could check for an overflow on the hour attribute like this:
public static DateTime NewTime(this DateTime dateTime)
{
int hour = dateTime.Hour;
int minute = dateTime.Minute;
var day = dateTime.Day;
if (minute > 0)
{
minute = dateTime.Minute + (15);
if (minute >= 60)
{
hour = hour + 1;
minute = 0;
}
}
if (hour > 24) {
day += 1;
}
return new DateTime(dateTime.Year, dateTime.Month,
day, hour, minute, 0);
}
However, you will also run into problems with the overflow of days in a month, which is even more complicated to handle. Instead, just use the built in Add function:
public static DateTime NewTime(this DateTime dateTime)
{
return new dateTime.AddMinutes(15);
}
I think you are overthinking this maybe? DateTime already provides many support methods and this will probably do what you need without the need to create an extension method:
var myValue = new DateTime(2017,3,14,23,50,0);
var result = myValue.AddMinutes(15);
I am trying to create an if statement based on the dropdown created below. That determines whether the Time from is before or after Time To. According to the results, show validation.
For Example: Time From 4:00 and Time To 4:30. Should be acceptable.
However if Time From 4:00 and Time To 3:30. This should not be acceptable.
Any ideas?
private void BindTime()
{
// Set the start time (00:00 means 12:00 AM)
DateTime StartTime = DateTime.ParseExact("00:00", "HH:mm", null);
// Set the end time (23:55 means 11:55 PM)
DateTime EndTime = DateTime.ParseExact("23:55", "HH:mm", null);
//Set 15 minutes interval
TimeSpan Interval = new TimeSpan(0, 15, 0);
//To set 1 hour interval
//TimeSpan Interval = new TimeSpan(1, 0, 0);
ddlTimeFrom.Items.Clear();
ddlTimeTo.Items.Clear();
while (StartTime <= EndTime)
{
ddlTimeFrom.Items.Add(StartTime.ToShortTimeString());
ddlTimeTo.Items.Add(StartTime.ToShortTimeString());
StartTime = StartTime.Add(Interval);
}
ddlTimeFrom.Items.Insert(0, new ListItem(" Select ", "0"));
ddlTimeTo.Items.Insert(0, new ListItem(" Select ", "0"));
}
When you want to validate, use this function:
private bool IsSelectionValid()
{
DateTime fromTime;
DateTime toTime;
if(!DateTime.TryParse(ddlTimeFrom.SelectedValue, out fromTime) ||
!DateTime.TryParse(ddlTimeTo.SelectedValue, out toTime))
{
return false;
}
return fromTime < toTime;
}
IsSelectionValid would give return false if fromTime is not less than toTime.
This is my front end, in my case, I would like to add all the total hours of time in and time out of all my rows in my datagridview. My datagridview fields are id, employee code, date, timein and timeout.
Here is my back end, in here I computed the the late, the total hours, the day difference and the night difference. Is it possible to display on my textboxes the total hours, the late, the day diff and night based on the data on my datagridview. Sorry for my english, clarify my questions with yours.
string timeIn = datagridAttendance.CurrentRow.Cells["timeIn"].Value.ToString();
string timeOut = datagridAttendance.CurrentRow.Cells["timeOut"].Value.ToString();
DateTime tIn = Convert.ToDateTime(timeIn);
DateTime tOut = Convert.ToDateTime(timeOut);
TimeSpan span = tOut - tIn;
txtTotalHours.Text = Convert.ToString(span);
DateTime start = Convert.ToDateTime(txtStart.Text);
txtMe.Text = tIn.ToShortTimeString();
DateTime inTime = Convert.ToDateTime(txtMe.Text);
if (inTime > start)
{
TimeSpan late = inTime - start;
txtLate.Text = Convert.ToString(late);
}
else
{
txtLate.Text = "Not Late";
}
TimeSpan passLength = new TimeSpan(0, 0, 0, 1);
TimeSpan nightTime = new TimeSpan();
while (tIn < tOut)
{
tIn = tIn.Add(passLength);
if (tIn.Hour < 6 || tIn.Hour == 23)
{
nightTime = nightTime.Add(passLength);
}
}
txtNightDif.Text = Convert.ToString(nightTime);
TimeSpan day = span - nightTime;
txtDayDif.Text = Convert.ToString(day);
Your code will look like below with the arrays timein[] timeout[] being the values in each row of DataGridView
DateTime[] timein = { DateTime.Parse("1:00"), DateTime.Parse("3:00"), DateTime.Parse("5:00"), DateTime.Parse("7:00") };
DateTime[] timeout = { DateTime.Parse("2:00"), DateTime.Parse("4:00"), DateTime.Parse("6:00"), DateTime.Parse("8:00") };
TimeSpan totalTime = new TimeSpan();
for (int i = 0; i < timein.Count(); i++)
{
totalTime += timeout[i] - timein[i];
}
You can do this in your database, and then return the sum of timespans as a column. That would be better and far easier.
I have my start date as 05/03/2012 and duration is 200 days now I would like to get the end date excluding sundays. So that my end date should be 05/02/2013.. Can some one help me
Try this for me:
var startDate = new DateTime(2012, 5, 3);
var sundaysOverDuration = 200 / 7;
var actualDuration = 200 + sundaysOverDuration;
var newDate = startDate.AddDays(actualDuration);
I also honestly have to admit that this link is flat out elegant surrounding how it handles a lot of the exceptions that exist when doing these types of calculations. I'm not sure you need something that complex, but it's worth letting you know. I'm going to inline the code just to ensure it's preserved if the link is ever broken.
public static double GetBusinessDays(DateTime startD, DateTime endD)
{
double calcBusinessDays =
1 + ((endD-startD).TotalDays * 6 -
(startD.DayOfWeek-endD.DayOfWeek) * 2) / 7;
if ((int)startD.DayOfWeek == 0) calcBusinessDays --;
return calcBusinessDays;
}
public static DateTime AddWorkDaysToStartDate(DateTime startD, double businessDays)
{
int DoW = (int)startD.DayOfWeek;
double temp = businessDays + DoW + 1;
if (DoW != 0) temp --;
DateTime calcendD = startD.AddDays(
Math.Floor(temp / 6)*2-DoW + temp
- 2* Convert.ToInt32(temp % 6 == 0)) ;
}
Finally, based on your question it doesn't appear you need to handle holidays, but if you do the solution is much more complex and would need to be database driven, so just keep that in mind.
You can use the CalendarDateAdd class from the Time Period Library for .NET:
// ----------------------------------------------------------------------
public void AddDaysSample()
{
CalendarDateAdd calendarDateAdd = new CalendarDateAdd();
calendarDateAdd.AddWorkingWeekDays();
calendarDateAdd.WeekDays.Add( DayOfWeek.Saturday );
DateTime start = new DateTime( 2012, 5, 3 );
TimeSpan duration = new TimeSpan( 200, 0, 0, 0 );
DateTime? end = calendarDateAdd.Add( start, duration );
Console.WriteLine( "AddDaysSample : {0:d} + {1} days = {2:d}", start, duration.Days, end );
} // AddDaysSample