Let's say I have this example JSON:
"Test": {
"KIf42N7OJIke57Dj6dkh": {
"name": "test 1"
},
"xsQMe4WWMu19qdULspve": {
"name": "test 2"
}
}
I want to parse this into an Array of a custom class I have, which will be exampled below:
class Class1 {
public string Name { get; set; }
Class1(string name) {
Name = name;
}
}
How can I parse this using Json.NET's JObject.Parse?
You can achieve your goal with JPath query like this :
var myArray = JObject
.Parse(json)
.SelectTokens("$.Test..name")
.Values<string>()
.Select(s => new Class1(s))
.ToArray();
But probably not the best way to do it.
I personnaly prefere to create classes to represent the json structure and then apply transformations.
void Main()
{
var json = #"{""Test"": {
""KIf42N7OJIke57Dj6dkh"": {
""name"": ""test 1""
},
""xsQMe4WWMu19qdULspve"": {
""name"": ""test 2""
}
}
}";
var root = JsonConvert.DeserializeObject<Root>(json);
var array = root.Test.Select(i => i.Value).ToArray();
array.Dump();
}
public class Root
{
public Dictionary<string, Class1> Test { get; set; }
}
public class Class1
{
public string Name { get; set; }
public Class1(string name)
{
Name = name;
}
}
To begin with, your Json is missing starting/closing braces. The Json needs to have wrapping braces around the Test value.
{
'Test':
{
'KIf42N7OJIke57Dj6dkh': {'name': 'test 1'},
'xsQMe4WWMu19qdULspve': {'name': 'test 2'}
}
}
If you are missing it in the original Json, you could wrap the current input Json as following.
var correctedJson = $"{{{inputJsonString}}}";
If you want to parse the Json Objects to Array of Class1 without creating additional concrete data structures and using JPath Queries, you could use Anonymous Types for the purpose using the DeserializeAnonymousType Method proved by Json.Net. For example,
var sampleObject = new {Test = new Dictionary<string,Class1>()};
var data = JsonConvert.DeserializeAnonymousType(correctedJson,sampleObject);
var result = data.Test.Select(x=>x.Value).ToArray();
You could also achieve it using JPath Query or creating Concrete Data Structures as #Kalten as described in his answer.
Related
I am pretty new to JSON and C# and have created an Azure Function that ties back to Snowflake which requires a very specific type of JSON response. I would like assistance if any in turning a JSON response I'm getting to a slightly different formatted response.
{
"access_token": "access token value here" , "user": "user_val"
}
to looking like
{
"data":
[
[ 0, { "access_token" : "access token value here", "user" : "user_val" } ]
]
}
I need create a nested array with "data" as the parent and a row number response starting at 0.
Using Json.NET:
using System;
using System.Collections.Generic;
using Newtonsoft.Json;
public class Program
{
public static void Main()
{
string json = #"{
""access_token"": ""access token value here"" , ""user"": ""user_val""
}";
Access a = JsonConvert.DeserializeObject<Access>(json);
var accessCollection = new AccessCollection
{
Data = new List<Access> { a }
};
json = JsonConvert.SerializeObject(accessCollection, Formatting.Indented);
Console.WriteLine(json);
}
}
public class Access
{
[JsonProperty("access_token")]
public string AccessToken
{
get;
set;
}
[JsonProperty("user")]
public string User
{
get;
set;
}
}
public class AccessCollection
{
[JsonProperty("data")]
public List<Access> Data
{
get;
set;
}
}
In addition, I consider the inner array is not usual because the data type are int and object. In general, they should be of same type. Because of that, I use a single dimensional array instead.
Please modify the codes according to situation.
.NET Fiddle
"title" : { "newTitle" : "Test"}
"tags" : { "newTags" : ["Tag1", "Tag2"] }
Newtonsoft.Json.Linq;
var json = JObject.Parse(json: json);
var title; // "Test2" in title
List<string> tags; // "TagA", "TagB", "TagC" in tags
json["title"]["newTitle"] = title; // works well
json["tags"]["newTags"] = tags; // not work
I want the JSON result as below:
"title" : { "newTitle" : "Test2"}
"tags" : { "newTags" : ["TagA", "TagB", "TagC"] }
I want to modify some values of JSON. int or string worked well. However, the List or Array does not work.
Please give me a good opinion.
I used a translator. So the writing may be awkward.
Assume your JSON data has defined object template, you can create a class based on your JSON data. With Newtonsoft.Json, you deserialize your JSON into an object and next update the object's properties value.
Note: When access object's inner properties for example Title.NewTitle and Tags.NewTags, you may need to add some null checking for preventing NullReferenceException.
1st solution: Convert to strongly-typed object
public static void Main()
{
var json = "{\"title\" : { \"newTitle\" : \"Test\"}, \"tags\" : { \"newTags\" : [\"Tag1\", \"Tag2\"] }}";
var inputObj = JsonConvert.DeserializeObject<JsonInput>(json);
inputObj.Title.NewTitle = "Test2";
inputObj.Tags.NewTags = new List<string> {"TagA", "TagB", "TagC"};
Console.WriteLine(JsonConvert.SerializeObject(inputObj));
}
public class JsonInput
{
public Title Title {get;set;}
public Tags Tags {get;set;}
}
public class Title
{
public string NewTitle {get;set;}
}
public class Tags
{
public List<string> NewTags {get;set;}
}
1st solution Code snippets and Output
2nd solution: With dynamic
To update array, you need parse your List<string> to JArray type
public static void Main()
{
var json = "{\"title\" : { \"newTitle\" : \"Test\"}, \"tags\" : { \"newTags\" : [\"Tag1\", \"Tag2\"] }}";
var title = "Test2"; // "Test2" in title
List<string> tags = new List<string> {"TagA", "TagB", "TagC"}; // "TagA", "TagB", "TagC" in tags
dynamic root = JObject.Parse(json);
JObject titleObj = (JObject)root["title"];
titleObj["newTitle"] = title;
JObject tagsObj = (JObject)root["tags"];
tagsObj["newTags"] = JArray.FromObject(tags);
Console.WriteLine(root);
}
2nd solution Code snippets and Output
try this
var jsonObject=JObject.Parse(json);
var newTitle = "Test2";
List<string> newTags = new List<string> { "TagA", "TagB", "TagC"};
jsonObject["title"]["newTitle"]= newTitle;
jsonObject["tags"]["newTags"]= JArray.FromObject(newTags);
result
{
"title": {
"newTitle": "Test2"
},
"tags": {
"newTags": [
"TagA",
"TagB",
"TagC"
]
}
}
I have a simple class with a property of type object, which can contain JSON built from different sources
public class SimpleClass
{
public string Id { get; set; }
public object JSONData { get; set; }
}
I'm using FluentAssertions object graph comparison but this isn't working
private void Verify(SimpleClass actualOutput, SimpleClass expectedOutput)
{
actualOutput.Should().BeEquivalentTo(expectedOutput);
}
Depending on the source of the objects, I'm seeing messages like these
Expected member JSONData to be a
System.Collections.Generic.IDictionary`2[System.String,Newtonsoft.Json.Linq.JToken], but found a
System.Text.Json.JsonElement.
Expected member JSONData to be
System.String, but found
System.Text.Json.JsonElement.
The objects are equal when I convert them to strings
private void Verify(SimpleClass actualOutput, SimpleClass expectedOutput)
{
actualOutput.JSONData.ToString().Should().Be(expectedOutput.JSONData.ToString());
}
I don't want to compare individual properties like that, because I need to compare a collection of SimpleClass instances. Is there any way to make this work using object graph comparison? Can I configure FluentAssertions to do the string conversion during comparison?
[Fact]
public void CompareJson()
{
var jsonText = #"{
""Element1"": 123,
""Element2"": ""text""
}";
var x1 = new SimpleClass { Id = "X", JSONData = jsonText };
var x2 = new SimpleClass { Id = "X", JSONData = JsonConvert.DeserializeObject(x1.JSONData.ToString()) };
x1.Should().BeEquivalentTo(
x2,
o => o.Using<object>(ctx => ctx.Subject.ToString().Should().Be(ctx.Expectation.ToString())).When(
info => info.SelectedMemberPath.EndsWith(nameof(SimpleClass.JSONData))));
}
I need to deserialize this weird JSON (image below). I've seen some deserialization hints using Dictionary<>, etc. but the problem is that "parameters" contains different data, then previous keys.
Can I somehow get it to work using JsonSerializer deserializator without doing foreach loops and other suspicious implementations? I do need data from "data" in my application.
Here's some of my code:
using var client = new WebClient();
var json = client.DownloadString(GetJsonString());
var invoicesData = JsonSerializer.Deserialize<JsonMyData>(json, options);
If using Newtonsoft is necessary I might start using it.
With Newtonsoft you can parse and access arbitrary JSON documents, even ones that can't reasonably be deserialized into a .NET object. So something like:
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System;
namespace ConsoleApp35
{
class Program
{
static void Main(string[] args)
{
var json = #"
{
""myData"" :
{
""0"" : { ""data"": { ""A"":1,""B"":2} },
""1"" : { ""data"": { ""A"":1,""B"":2} },
""2"" : { ""data"": { ""A"":1,""B"":2} },
""3"" : { ""data"": { ""A"":1,""B"":2} },
""parameters"" : { ""p"":""a""}
},
""status"":{ }
}";
var foo = JObject.Parse(json);
var a = foo["myData"]["1"]["data"];
Console.WriteLine(a);
Console.WriteLine("Hit any key to continue");
Console.ReadKey();
}
}
}
I think you should really consider using Newtonsoft.Json instead of default JsonDeserializer, it is much easier to use in such situations.
If you are interested in processing this without foreach loops and wanting to access the data in a list format, I would suggest using Dictionary for this. When you use dictionary, you can use Objects as values that would compensate for differences in numbers (0, 1, 2, ..) and words (parameters).
// Classes to Deserialize data we need.
public class MyObject
{
[JsonProperty("data")]
public Data Data { get; set; }
}
public class Data
{
public int A { get; set; }
public int B { get; set; }
}
Usage in Main
// Read in the JSON
var myData = JsonConvert.DeserializeObject<dynamic>(jsonString)["myData"];
// Convert To Dictionary
Dictionary<string, dynamic> dataAsObjects = myData.ToObject<Dictionary<string, dynamic>>();
string searchFor = "3";
dataAsObjects.TryGetValue(searchFor, out dynamic obj);
if (obj != null)
{
// Conversion to int and matching against searchFor is to ensure its a number.
int.TryParse(searchFor, out int result);
if (result == 0 && result.ToString().Equals(searchFor))
{
MyObject myObject = obj.ToObject<MyObject>();
Console.WriteLine($"A:{myObject.Data.A} - B:{myObject.Data.B}");
}
else if (result == 8 && result.ToString().Equals(searchFor))
{
// I am not clear on whats your parameters class look like.
MyParameters myParams = obj.ToObject<MyParameters>();
}
}
Output
A:1 - B:2
With this method you can either access the numbers or the parameters element.
How can I deserialize a string in C# that only have values and no name. It looks like this: The problem is that this stream of string does not have name and uses array.
{
"result": {
"14400": [
[
1502985600,
262.18,
262.18,
257,
257,
1096.0131
],
[
1503000000,
257,
261.33,
254.8,
257,
1130.5897
]
],
"14405": [
[
1503014400,
258.03,
261.5,
257.01,
257.01,
520.7805
],
[
1503028800,
258,
260.98,
252.4,
259.56,
298.5658
],
]
]
}
}
Just create a class like
public class Root
{
public Dictionary<int,List<List<double>>> Result { get; set; }
}
and deserialize as
var res = JsonConvert.DeserializeObject<Root>(json);
I see it's an array, you could create a method to parse the class out of given JArray.
The Jason data
public void methpod()
{
string json ="Your jason value "
var factory = new Factory();
var suggest = factory.Create(json);
Console.WriteLine(suggest);
}
Make a class as suggested :
public class Factory
{
public Evan Create(string json)
{
var array = JArray.Parse(json);
string search = array[0].ToString();
string[] terms = array[1].ToArray().Select(item => item.ToString()).ToArray();
return new Evan{Search = search, Terms = terms};
}
}
and another
public class Evan
{
public string Search { get; set; }
public IEnumerable<string> Terms { get; set; }
public override string ToString()
{
return string.Format("Search={0},Terms=[{1}]",
Search, string.Join(",", Terms));
}
}
Tip
If you have JSON that you want to deserialize, and you don't have the class to deserialize it into, Visual Studio 2019 can automatically generate the class you need:
Copy the JSON that you need to deserialize.
Create a class file and delete the template code.
Choose Edit > Paste Special > Paste JSON as Classes.
The result is a class that you can use for your deserialization target