I just want to replace a portion of a string only if matches the given text.
My use case is as follows:
var text = "<wd:response><wd:response-data></wd:response-data></wd:response >";
string result = text.Replace("wd:response", "response");
/*
* expecting the below text
<response><wd:response-data></wd:response-data></response>
*
*/
I followed the following answers:
Way to have String.Replace only hit "whole words"
Regular expression for exact match of a string
But I failed to achieve what I want.
Please share your thoughts/solutions.
Sample on
https://dotnetfiddle.net/pMkO8Q
In general, you should really be parsing and manipulating XML as XML, using functions that know how XML works and what's legal in the language. Regex and other naive text manipulation will often lead you into trouble.
That said, for a very simple solution to this specific problem, you can do this with two replaces:
var text = "<wd:response><wd:response-data></wd:response-data></wd:response >";
text.Replace("wd:response>", "response>").Replace("wd:response ", "response ")
(Note the spaces at the end of the parameters to the second replace.)
Alternatively use a regex similar to "wd:response\s*>"
The easiest way to achieve your result as per your .net fiddle is use the replace as below.
string result = text.Replace("wd:response>", "response>");
But proper way to achieve this is parsing using XML
You can capture the string wd-response in a capturing group and replace using Regex.Replace using the MatchEvaluator like this.
Regex explanation - <[/]?(wd:response)[\s+]?>
Match < literally
Match / optionally hence the ?
Match the string wd:response and place it in a capturing group enclosed with ()
Match one or more optional whitespace [\s+]?
Match > literally
public class Program
{
public static void Main(string[] args)
{
string text = "<wd:response><wd:response-data></wd:response-data></wd:response >";
string replacePattern = "response";
string pattern = #"<[/]?(wd:response)[\s+]?>";
string replacedPattern = Regex.Replace(text, pattern, match =>
{
// Extract the first group
Group group = match.Groups[1];
// Replace the group value with the replacePattern
return string.Format("{0}{1}{2}", match.Value.Substring(0, group.Index - match.Index), replacePattern, match.Value.Substring(group.Index - match.Index + group.Length));
});
Console.WriteLine(replacedPattern);
}
}
Outputting:
<response><wd:response-data></wd:response-data></response >
Related
I've got the following value:
--> Some comment
CREATE VIEW ABC
AS SELECT
Z.NUMBER AS ID,
Z.LANGUAGE AS LNG,
SUBSTR(Z.VALUE_01,01,02) AS RUN_NUMB,
SUBSTR(Z.TXT_VALUE_01,01,79) AS TXT
FROM
MYTABLE Z
WHERE ID = '0033'
AND LNG = 'DE'
I want a regular expression, where I can pass the value (or a part of the value) before the AS and I'll receive the AS-Value, e.g.
Z.NUMBER --> I'll receive ID
Z.LANGUAGE --> I'll receive LNG
Z.VALUE_01 --> I'll receive RUN_NUMB
Z.TXT_VALUE_01 --> I'll receive TXT
Currently I have something like this:
(?<=Z.NUMBER\sAS).+?(?=(,|FROM))
...but this doesn't work for my SUBSTR values
Edit: I'm using C# to execute the Regex:
string expr = #"--> Some comment ....."; //so the long text
string columnExprValue = "Z.LANGUAGE";
string asValue = Regex.Match(expr, #"(?<=" + columnExprValue + #"\sAS).+?(?=(,|FROM))")?.Value.Replace("AS", "").Trim() ?? ""; //Workaround to remove AS, because I don't know how to remove it in Regex
This should work, but the implementation is "naive" in sense that it always expects correct valid parameters that do really exists, you can add necessary checks needed.
So the regex I'm going to use is this .*Z\.VALUE_01.*\s+AS\s+(?<Alias>[^,\s]*), where "Z\.VALUE_01" I will do as parameter. See regex tester - https://regex101.com/r/UJi8pY/1
The idea here is that in Group named "Alias" we should have the exact thing you are looking for
Then C# code will look like this:
public static string GetAlias(string input, string column)
{
var regexPart = column.Replace(".","\\.");
return Regex.Match(input, $".*{regexPart}.*\\s+AS\\s+(?<Alias>[^,\\s]*)").Groups["Alias"].ToString();
}
public static void Main()
{
string val = #"--> Some comment
CREATE VIEW ABC
AS SELECT
Z.NUMBER AS ID,
Z.LANGUAGE AS LNG,
SUBSTR(Z.VALUE_01,01,02) AS RUN_NUMB,
SUBSTR(Z.TXT_VALUE_01,01,79) AS TXT
FROM
MYTABLE Z
WHERE ID = '0033'
AND LNG = 'DE'";
Console.WriteLine(GetAlias(val, "Z.NUMBER"));
Console.WriteLine(GetAlias(val, "Z.LANGUAGE "));
Console.WriteLine(GetAlias(val, "Z.VALUE_01"));
Console.WriteLine(GetAlias(val, "Z.TXT_VALUE_01"));
}
.NET Fiddle - https://dotnetfiddle.net/Z9kd8h
Good suggestion in another answer from #the-fourth-bird to use Regex.Escape instead of column.Replace(".","\\."), so all regex symbols would be escaped
Getting the values with a regex from sql can be very brittle, this pattern is based on the example data.
To get the values only you might use lookarounds:
(?<=\bZ\.(?:LANGUAGE|NUMBER|(?:TXT_)?VALUE_01)\b.*?\sAS\s+)[^\s,]+(?=,|\s+FROM\b)
Explanation
(?<= Lookbehind assertion
\b A word boundary
Z\. Match Z.
(?:LANGUAGE|NUMBER|(?:TXT_)?VALUE_01)\b Match any of the alternatives followed by a word boundary (Or just match a single string like Z\.LANGUAGE)
.*? Match optional characters, as few as possible
\sAS\s+ Match AS between whitespace chars
) Close the lookbehind
[^\s,]+ Match 1+ non whitspace chars except for a comma
(?=,|\s+FROM\b) Positive lookahead, assert either , or FROM to the right
See a .NET regex demo.
Or a capture group variant:
\bZ\.(?:LANGUAGE|NUMBER|(?:TXT_)?VALUE_01)\b.*?\sAS\s+([^\s,])+(?:,|\s+FROM\b)
See another .NET regex demo.
If you want to make the pattern dynamic, you can make use of Regex.Escape to escape the meta characters like the dot to match it literally, or else it would match any character.
For example:
string input = #"--> Some comment
CREATE VIEW ABC
AS SELECT
Z.NUMBER AS ID,
Z.LANGUAGE AS LNG,
SUBSTR(Z.VALUE_01,01,02) AS RUN_NUMB,
SUBSTR(Z.TXT_VALUE_01,01,79) AS TXT
FROM
MYTABLE Z
WHERE ID = '0033'
AND LNG = 'DE'";
string columnExprValue = Regex.Escape("Z.LANGUAGE");
string pattern = #"(?<=\b" + columnExprValue + #"\b.*?\sAS\s+)[^\s,]+(?=,|\s+FROM\b)";
string asValue = Regex.Match(input, pattern)?.Value ?? "";
Console.WriteLine(asValue);
Output
LNG
Check this :
/^ \h*+ (?:substr[(])?(?: Z.TXT_VALUE_01 )(?:,[^,]+,[^,]+[)])? \h* AS \h+ (\w+) \v* [,]? \v* $/gmxi
i have the following sample cases :
1) "Sample"
2) "[10,25]"
I want to form a(only one) regular expression pattern, to which the above examples are passed returns me "Sample" and "10,25".
Note: Input strings do not include Quotes.
I came up with the following expression (?<=\[)(.*?)(?=\]), this satisfies the second case and retreives me only "10,25" but when the first case is matched it returns me blank. I want "Sample" to be returned? can anyone help me.
C#.
here you go, a small regex using a positive lookbehind, sometime these are very handy
Regex
(?<=^|\[)([\w,]+)
Test string
Sample
[10,25]
Result
MATCH 1
[0-6] Sample
MATCH 2
[8-13] 10,25
try at regex101.com
if " is included in your original string, use this regex, this will look for " mark as well, you may choose to remove ^| from lookup if " mark is always included or you may choose to leave it as it is if your text has combination of with and without " marks
Regex
(?<=^|\[|\")([\w,]+)
try at regex101.com
As far as I can tell, the below regex should help:
Regex regex = new Regex(#"^\w+|[[](\w)+\,(\w)+[]]$");
This will match multiple words, or 2 words (alphanumeric) separated by commas and inside square brackets.
One Java example:
// String input = "Sample";
String input = "[10,25]";
String text = "[^,\\[\\]]+";
Pattern pMod = Pattern.compile("(" + text + ")|(?>\\[(" + text + "," + text + ")\\])");
Matcher mMod = pMod.matcher(input);
while (mMod.find()) {
if(mMod.group(1) != null) {
System.out.println(mMod.group(1));
}
if(mMod.group(2)!=null) {
System.out.println(mMod.group(2));
}
}
if input is "[hello&bye,25|35]", then the output is hello&bye,25|35
In C#, I have a string comes from a file in this format:
Type="Data"><Path.Style><Style
or maybe
Type="Program"><Rectangle.Style><Style
,etc. Now I want to only extract the Data or Program part of the Type element. For that, I used the following code:
string output;
var pair = inputKeyValue.Split('=');
if (pair[0] == "Type")
{
output = pair[1].Trim('"');
}
But it gives me this result:
output=Data><Path.Style><Style
What I want is:
output=Data
How to do that?
This code example takes an input string, splits by double quotes, and takes only the first 2 items, then joins them together to create your final string.
string input = "Type=\"Data\"><Path.Style><Style";
var parts = input
.Split('"')
.Take(2);
string output = string.Join("", parts); //note: .net 4 or higher
This will make output have the value:
Type=Data
If you only want output to be "Data", then do
var parts = input
.Split('"')
.Skip(1)
.Take(1);
or
var output = input
.Split('"')[1];
What you can do is use a very simple regular express to parse out the bits that you want, in your case you want something that looks like this and then grab the two groups that interest you:
(Type)="(\w+)"
Which would return in groups 1 and 2 the values Type and the non-space characters contained between the double-quotes.
Instead of doing many split, why don't you just use Regex :
output = Regex.Match(pair[1].Trim('"'), "\"(\w*)\"").Value;
Maybe I missed something, but what about this:
var str = "Type=\"Program\"><Rectangle.Style><Style";
var splitted = str.Split('"');
var type = splitted[1]; // IE Data or Progam
But you will need some error handling as well.
How about a regex?
var regex = new Regex("(?<=^Type=\").*?(?=\")");
var output = regex.Match(input).Value;
Explaination of regex
(?<=^Type=\") This a prefix match. Its not included in the result but will only match
if the string starts with Type="
.*? Non greedy match. Match as many characters as you can until
(?=\") This is a suffix match. It's not included in the result but will only match if the next character is "
Given your specified format:
Type="Program"><Rectangle.Style><Style
It seems logical to me to include the quote mark (") when splitting the strings... then you just have to detect the end quote mark and subtract the contents. You can use LinQ to do this:
string code = "Type=\"Program\"><Rectangle.Style><Style";
string[] parts = code.Split(new string[] { "=\"" }, StringSplitOptions.None);
string[] wantedParts = parts.Where(p => p.Contains("\"")).
Select(p => p.Substring(0, p.IndexOf("\""))).ToArray();
I am trying to extract all of the text (shown as xxxx) in the follow pattern:
Session["xxxx"]
using c#
This may be Request.Querystring["xxxx"] so I am trying to build the expression dynamically. When I do so, I get all sorts of problems about unescaped charecters or no matches :(
an example might be:
string patternstart = "Session[";
string patternend = "]";
string regexexpr = #"\\" + patternstart + #"(.*?)\\" + patternend ;
string sText = "Text to be searched containing Session[\"xxxx\"] the result would be xxxx";
MatchCollection matches = Regex.Matches(sText, #regexexpr);
Can anyone help with this as I am stumped (as I always seem to be with RegEx :) )
With some little modifications to your code.
string patternstart = Regex.Escape("Session[");
string patternend = Regex.Escape("]");
string regexexpr = patternstart + #"(.*?)" + patternend;
The pattern you construct in your example looks something like this:
\\Session[(.*?)\\]
There are a couple of problems with this. First it assumes the string starts with a literal backslash, second, it wraps the entire (.*?) in a character class, that means it will match any single open parenthesis, period, asterisk, question mark, close parenthesis or backslash. You'd need to escape the the brackets in your pattern, if you want to match a literal [.
You could use a pattern like this:
Session\[(.*?)]
For example:
string regexexpr = #"Session\[(.*?)]";
string sText = "Text to be searched containing Session[\"xxxx\"] the result would be xxxx";
MatchCollection matches = Regex.Matches(sText, #regexexpr);
Console.WriteLine(matches[0].Groups[1].Value); // "xxxx"
The characters [ and ] have a special meaning with regular expressions - they define a group where one of the contained characters must match. To work around this, simply 'escape' them with a leading \ character:
string patternstart = "Session\[";
string patternend = "\]";
An example "final string" could then be:
Session\["(.*)"\]
However, you could easily write your RegEx to handle Session, Querystring, etc automatically if you require (without also matching every other array you throw at it), and avoid having to build up the string in the first place:
(Querystring|Session|Form)\["(.*)"\]
and then take the second match.
I have a problem dealing with the # symbol in Regex, I am trying to remove #sometext
from a text string can't seem to find anywhere where it uses the # as a literal. I have tried myself but doesn't remove the word from the string. Any ideas?
public string removeAtSymbol(string input)
{
Regex findWords = new Regex(______);//Find the words like "#text"
Regex[] removeWords;
string test = input;
MatchCollection all = findWords.Matches(test);
removeWords = new Regex[all.Count];
int index = 0;
string[] values = new string[all.Count];
YesOutputBox.Text = " you got here";
foreach (Match m in all) //List all the words
{
values[index] = m.Value.Trim();
index++;
YesOutputBox.Text = YesOutputBox.Text + " " + m.Value;
}
for (int i = 0; i < removeWords.Length; i++)
{
removeWords[i] = new Regex(" " + values[i]);
// If the words appears more than one time
if (removeWords[i].Matches(test).Count > 1)
{
removeWords[i] = new Regex(" " + values[i] + " ");
test = removeWords[i].Replace(test, " "); //Remove the first word.
}
}
return test;
}
You can remove all occurences of "#sometext" from string test via the method
Regex.Replace(test, "#sometext", "")
or for any word starting with "#" you can use
Regex.Replace(test, "#\\w+", "")
If you need specifically a separate word (i.e. nothing like #comp within tom#comp.com) you may preceed the regex with a special word boundary (\b does not work here):
Regex.Replace(test, "(^|\\W)#\\w+", "")
You can use:
^\s#([A-Za-z0-9_]+)
as the regex to recognize Twitter usernames.
Regex to remove #something from this string: I want to remove #something from this string.
var regex = new Regex("#\\w*");
string result = regex.Replace(stringWithAt, "");
Is that what you are looking for?
I've had good luck applying this pattern:
\B#\w+
This will match any string starting with an # character that contains alphanumeric characters, plus some linking punctuation like the underscore character, if it does not occur on a boundary between alphanumeric and non-alphanumeric characters.
The result of executing this code:
string result = Regex.Replace(
#"#This1 #That2_thing this2#3that #the5Others #alpha#beta#gamma",
#"\B#\w+",
#"redacted");
is the following string:
redacted redacted this2#3that redacted redacted#beta#gamma
If this question is Twitter-specific, then Twitter provides an open source library that helps capture Twitter-specific entities like links, mentions and hashtags. This java file contains the code defining the regular expressions that Twitter uses, and this yml file contains test strings and expected outcomes of many unit tests that exercise the regular expressions in the Twitter library.
Twitter's mention-matching pattern (extracted from their library, modified to remove unnecessary capture groups, and edited to make sense in the context of a replacement) is shown below. The match should be performed in a case-insensitive manner.
(^|[^a-z0-9_])[#\uFF20][a-z0-9_]{1,20}
Here is an example which reproduces the results of the first replacement in my answer:
string result = Regex.Replace(
#"#This1 #That2_thing this2#3that #the5Others #alpha#beta#gamma",
#"(^|[^a-z0-9_])[#\uFF20][a-z0-9_]{1,20}",
#"$1redacted",
RegexOptions.IgnoreCase);
Note the need to include the substitution $1 since the first capture group can't be directly converted into an atomic zero-width assertion.