Parse string date (EEST included) but it fails - c#

I am trying to parse a string into a DateTime, but it fails and shows an exception. The code is provided below:
static void Main(string[] args)
{
string dt = "Wed Sep 05 00:00:00 EEST 2012";
string Fm = "EEE MMM dd HH:mm:ss zzz yyyy";
DateTime dateTime;
dateTime = DateTime.ParseExact(dt, Fm, CultureInfo.InvariantCulture);
Console.WriteLine(dateTime.Date);
}
This is the exception:
Unhandled Exception: System.FormatException: String was not recognized as a valid DateTime.
at System.DateTime.ParseExact(String s, String format, IFormatProvider provider)
at DateParser.Program.Main(String[] args) in C:\Users\AhmedSaeed\source\repos\DateParser\DateParser\Program.cs:line 17

string dt = "Wed Sep 05 00:00:00 EEST 2012";
Although a real timezone, "EEST" does not match the zzz format (in length) and this may be an issue.
Additionally, as apomene said, EEE is not a valid format string.

DateTime structure does not keep time zone information. It just have date and time values which is based a long called Ticks. That's why there is no custom date and time format string that matches that abbreviation. The zzz format specifier is for the signed offset of the local operating system's time zone from UTC and it is not meaninful to use it with DateTime parsing as stated on the documentation.
If you wanna parse an abbreviation in your string, you have to escape it as a string literal. Other than this, there is no way to parse it. On the other hand, timezone abbreviations are not even unique. For example, CST can mean Central Standard Time, China Standard Time or Cuba Standard Time.
Also there is no EEE custom date format specifier. Abbreviated day names matches with ddd format specifier instead.
string dt = "Wed Sep 05 00:00:00 EEST 2012";
string Fm = "ddd MMM dd HH:mm:ss 'EEST' yyyy";
DateTime dateTime = DateTime.ParseExact(dt, Fm, CultureInfo.InvariantCulture);
Console.WriteLine(dateTime.Date);
Here a demonstration.

Related

String was not recognized as a valid DateTime while converting from Arab Standard Time to datetime

I want to convert String into DateTime. Everything is correct but don't know why I am getting this error;
String was not recognized as a valid DateTime
string dtf = hdnFromDate.Value;
(While debugging I can see dtf value is Sun Dec 13 2020 00:00:00 GMT+0300 (Arab Standard Time)) and I am trying to convert into DateTime But no success
I am converting in this way
DateTime date = DateTime.ParseExact(dtf, "dd/MM/yyyy", null);
I also try like this
DateTime dt= DateTime.ParseExact(dtf,
"ddd MMM dd yyyy HH:mm:ss 'GMT'K '(Arab Standard Time)'",
CultureInfo.InvariantCulture);
Where I am doing wrong?
Reference to DateTime.ParseExact Method
Converts the specified string representation of a date and time to its
DateTime equivalent. The format of the string representation must
match a specified format exactly or an exception is thrown.
So your datetime string should like this otherwise you will get exception
Mon Dec 14 2020 14:42:46 GMT+08:00 (Arab Standard Time)
or
Mon Dec 14 2020 14:42:46 GMT+0800 (Arab Standard Time)
You can try this to get what kind of string you need
Console.WriteLine(
DateTime.Now.ToString("ddd MMM dd yyyy HH: mm:ss 'GMT'K '(Arab Standard Time)'",
CultureInfo.InvariantCulture)
);
If your string have whitespace li
Mon Dec 14 2020 14: 42:46 GMT+08:00 (Arab Standard Time)
Yoo can try
Console.WriteLine(
DateTime.Now.ToString("ddd MMM dd yyyy HH: mm:ss 'GMT'K '(Arab Standard Time)'",
CultureInfo.InvariantCulture,
DateTimeStyles.AllowWhiteSpaces)
);

How to Convert long string to DateTime?

I have a date string in the following format:
var dateString = Fri Jun 26 2020 00:00:00 GMT+0100 (British Summer Time)
How can I convert this to a DateTime in C# such as 26/06/2020 00:00:00
I have tried:
DateTime.Parse(dateString);
And:
DateTime.ParseExact(dateString);
And I get:
System.FormatException: 'String was not recognized as a valid DateTime.'
You can accomplish this by using DateTime.ParseExact and providing a custom date time format. However, this will only work if you first modify the input string to be able to fit the custom date and time format strings that are included in .net.
CultureInfo provider = CultureInfo.InvariantCulture;
var input = "Fri Jun 26 2020 00:00:00 GMT+0100 (British Summer Time)";
// set up a regex that will match the text starting with GMT, and extract just the timezone offset
// (the description of the timezone is irrelevant here)
var r = new Regex(#"GMT([+-]\d\d\d\d) \([\w\s]*\)");
// this will remove the extra text: "Fri Jun 26 2020 00:00:00 +0100"
// now we can match it in our format string
var s = r.Replace(input, "$1");
var f = "ddd MMM dd yyyy hh:mm:ss zzz"; // matches the s variable
var d = DateTime.ParseExact(s, f, provider); // you now have parsed your date
This will include the timezone offset in the DateTime object. If you just want it to be set to "26/06/2020 00:00:00" and to ignore the datetime offset, then just change the regex replace above to replace with String.Empty instead of $1.
This will solve your problem.
var dateString = "Fri Jun 26 2020 00:00:00 GMT + 0100(British Summer Time)"; Console.WriteLine(DateTime.Parse(dateString.Substring(4, 11)));
Hello so what you can do is you can take advantage of "datetime" class and just write this:
DateTime.Now.ToString("MM/dd/yyyy HH:mm");
edit: sorry i forgot to supply the link haha
https://www.c-sharpcorner.com/blogs/date-and-time-format-in-c-sharp-programming1

Convert string to datetime UTC

I have this string "Sun Aug 02 2015 00:15:47 GMT+0000 (UTC)"
I created this much of the datetime format "ddd MMM dd yyyy HH:mm:ss"
Now im not sure what to do with the ending part of that datetime string.
Im not sure if the string I have is a standard format for UTC that can be easily converted or if its a custom format.
Nonetheless, I want to turn that string datetime into a datetime object.
string str = "Sun Aug 02 2015 00:15:47 GMT+0000 (UTC)";
var dt = DateTime.ParseExact(str, "ddd MMM dd yyyy HH:mm:ss \"GMT\"zzzz \"(UTC)\"", CultureInfo.InvariantCulture);
I would consider one of these two approaches:
string str = "Sun Aug 02 2015 00:15:47 GMT+00:00 (UTC)";
str = str.Substring(0, str.IndexOf('(') - 1);
DateTime dt = DateTime.ParseExact(str, "ddd MMM dd yyyy HH:mm:ss 'GMT'K",
CultureInfo.InvariantCulture, DateTimeStyles.AdjustToUniversal);
or
string str = "Sun Aug 02 2015 00:15:47 GMT+00:00 (UTC)";
str = str.Substring(0, str.IndexOf('(') - 1);
DateTimeOffset dto = DateTimeOffset.ParseExact(str, "ddd MMM dd yyyy HH:mm:ss 'GMT'K",
CultureInfo.InvariantCulture);
In either example, we assume that the part in parenthesis is irrelevant. This may be important if your input can vary with different time zones.
In the first example, we assume that you want the output to always be a UTC based DateTime. The input offset could vary, but the output will always be adjusted to Coordinated Universal Time, and will have DateTimKind.Utc.
In the second example, we assume that you want the output to match exactly what was provided in the input. To do this, the output needs to be a DateTimeOffset type. Otherwise, you wouldn't be able to track offsets that didn't exactly match UTC or your own local time zone.
I prefer the second option. If you need a DateTime, you can always get one by calling the .DateTime, .UtcDateTime, or .LocalDateTime properties of the resulting DateTimeOffset.

How can I convert this string to date?

Im making a post from a view and getting it in a actionresult as a string.
The value I get is:
Tue Feb 18 2014 00:00:00 GMT-0300 (Hora oficial do Brasil)
Using DateTime.Parse throws an exception:
String was not recognized as a valid DateTime.
What makes this string invalid, and how can I successfully convert it to a DateTime?
DateTime.Parse throws exception for this string because it does not have a standart date/time format.
If your GMT-0300 (Hora oficial do Brasil) is stable in your string, you can use;
var s = "Tue Feb 18 2014 00:00:00 GMT-0300 (Hora oficial do Brasil)";
var date = DateTime.ParseExact(s,
"ddd MMM dd yyyy HH:mm:ss 'GMT'K '(Hora oficial do Brasil)'",
CultureInfo.InvariantCulture);
Console.WriteLine(date);
Output will be;
2/18/2014 12:00:00 AM
Here is a demonstration.
I don't think there is a way to parse your (Hora oficial do Brasil) part except using string delimiter.
Take a look at;
The "K" Custom Format Specifier
I don't know why K specifier doesn't work on Ideone actually. I have to put -0300 part also as a string delimiter for generating example. It can be an issue with DateTimeKind enumeration but I'm not sure..
The string is invalid because of the 'GMT' and the '(Hora oficial do Brasil)' parts.
Simply put: the parser is unable to determine what is part of a date time and what is not.
By using format strings you will be able to parse the string into the DateTime format.
see: MSDN: Custom Date and Time Format Strings
in your case this format string will work: "ddd MMM dd yyyy hh:mm:ss 'GMT'K '(Hora oficial do Brasil)'".
You can use it like this:
string input = "Tue Feb 18 2014 00:00:00 GMT-0300 (Hora official do Brasil)";
string[] format = { "ddd MMM dd yyyy hh:mm:ss 'GMT'K '(Hora official do Brasil)'" };
DateTime date;
if (DateTime.TryParseExact(input, format, CultureInfo.InvariantCulture, DateTimeStyles.None, out date))
{
//Yepee the input was parsed correct
}
else
{
//system was unable to parse the string
}
Or like this if error handling is not nessesary:
string input = "Tue Feb 18 2014 00:00:00 GMT-0300 (Hora official do Brasil)";
string format = "ddd MMM dd yyyy hh:mm:ss 'GMT'K '(Hora official do Brasil)'";
DateTime date = DateTime.ParseExact(input, format, CultureInfo.InvariantCulture);

Converting string to DateTime [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Date time format from string?
Does anyone know how I could convert the following string to a DateTime value in C# ?
"Thu Nov 15 2012 00:00:00 GMT+0300 (E. Africa Standard Time)"
If you only have strings ending with "GMT+0300 (E. Africa Standard Time)", you can try:
string dateString = "Thu Nov 15 2012 00:00:00 GMT+0300 (E. Africa Standard Time)";
DateTime date = DateTime.ParseExact(dateString, "ddd MMM dd yyyy HH:mm:ss 'GMT+0300 (E. Africa Standard Time)'", System.Globalization.CultureInfo.InvariantCulture);
The meanings of the specifiers are as follows:
"ddd" The abbreviated name of the day of the week.
"MMM" The abbreviated name of the month.
"dd" The day of the month, from 01 through 31.
"yyyy" The year as a four-digit number.
"HH" The hour, using a 24-hour clock from 00 to 23.
"mm" The minute, from 00 through 59.
"ss" The second, from 00 through 59.
":" The time separator.
"string", 'string' Literal string delimiter.
You can find out more about different format specifiers in the MSDN article named Custom Date and Time Format Strings
Moreover, if you want to parse "GMT+0300 (E. Africa Standard Time)" part too, I think you should implement a way to parse them yourself. I don't think there's a specifier for that.
First of all, you should Africa Standart Time culture info use for yours';
CultureInfo( "af-ZA", false );
But your string is really complex for converting to DateTime. For me it looks imposible to convert to DateTime perfectly. But we can some rehabilitation in your string. For example, if your string was like this; "11/15/2012 00:00:00" you can convert it like this;
using System;
using System.Globalization;
namespace Programs
{
public class Program
{
public static void Main(string[] args)
{
string str = "11/15/2012 00:00:00";
DateTime dt = DateTime.ParseExact(str, "MM/dd/yyyy hh:mm:ss", new CultureInfo("af-ZA"));
Console.WriteLine(dt.ToString());
}
}
}
Custom Date and Time Format Strings
DateTime.ParseExact Method
Try this:
DateTime date = DateTime.Parse(yourDateTimeString);
There is no way to handle (E. Africa Standard Time).
Assuming that UTC=GMT you can also get the time zone part, just remove not important parts of your string
string t = Regex.Replace("Thu Nov 15 2012 00:00:00 GMT+0300 (E. Africa Standard Time)", "([(].+?[)])", "");
t= t.Replace("GMT", "").Trim();
DateTime a = DateTime.ParseExact(t, "ddd MMM dd yyyy HH:mm:ss zzzz", System.Globalization.CultureInfo.InvariantCulture);

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