We have N number of JSON parameters and class properties as well but
have to remove dynamically the JSON parameters which are not available in class properties while serializing.
If I use [JsonIgnore] it is only removing values, not the entire property; we need to remove the entire property.
Example:
JSON request:
{
"Name":"ABC",
"Age":26,
"Designation":"Er",
"Place":"Pune",
"Gender":"Male"
}
Class:
[Serializable]
public class SampleProperties
{
[JsonProperty("Name")]
public string Name { get; set; }
[JsonProperty("Age")]
public int Age { get; set; }
[JsonProperty("Designation")]
public string Designation { get; set; }
}
Result Expecting :
{
"Name":"ABC",
"Age":26,
"Designation":"Er"
}
the best way to do this is to create an object with 30 fields and deserialize the json string to this object
try somthing like this :
class MyObject
{
public string prop1 {get;set; }
public string prop2 {get;set; }
}
then :
string json = "your json";
MyObject objectWith30Fields = JsonConvert.DeserializeObject<MyObject>(json);
You can set NullValueHandling like the code below that you can see on the documentation of Newtonsoft.Json or in this link as well, in addition, you can use ExpandoObject() as you can see on this link
public class Movie
{
public string Name { get; set; }
public string Description { get; set; }
public string Classification { get; set; }
public string Studio { get; set; }
public DateTime? ReleaseDate { get; set; }
public List<string> ReleaseCountries { get; set; }
}
Movie movie = new Movie();
movie.Name = "Bad Boys III";
movie.Description = "It's no Bad Boys";
string included = JsonConvert.SerializeObject(movie,
Formatting.Indented,
new JsonSerializerSettings { });
// {
// "Name": "Bad Boys III",
// "Description": "It's no Bad Boys",
// "Classification": null,
// "Studio": null,
// "ReleaseDate": null,
// "ReleaseCountries": null
// }
string ignored = JsonConvert.SerializeObject(movie,
Formatting.Indented,
new JsonSerializerSettings { NullValueHandling = NullValueHandling.Ignore });
// {
// "Name": "Bad Boys III",
// "Description": "It's no Bad Boys"
// }
More about ExpandoObject
Related
I'm probably missing something.
I'd like to test behavior when an API call response returns a property of null and I would like to throw an exception when that happens.
I have a Form object as follow
public class Form
{
[Required]
public string Html { get; set; }
public string Json { get; set; }
public string Name { get; set; }
}
I have initialized an object
var myData = new
{
Json = "foo",
};
string jsonData = JsonConvert.SerializeObject(myData);
var response = JsonConvert.DeserializeObject<Form>(File.ReadAllText(jsonPath));
I was expecting to have an exception since the Html property is required and not nullable,
but actually getting the object as
{
Html = null,
Json = foo,
Name = null
}
I have tried to use JsonSerializerSettings as follows but this actually throws an exception only when there is an additional unwanted property and not when there's a missing one.
JsonSerializerSettings config = new JsonSerializerSettings { MissingMemberHandling = MissingMemberHandling.Error, NullValueHandling = NullValueHandling.Include};
var res = JsonConvert.DeserializeObject<Form>(json,config);
You need [JsonProperty(Required = Required.Always)].
public class Form
{
[JsonProperty(Required = Required.Always)]
public string Html { get; set; }
public string Json { get; set; }
public string Name { get; set; }
}
Sample Program
While [Required] attribute is for Data Annotation.
Reference
JsonPropertyAttribute required
I have a requirement where I need a property that is actually a JSON value from a MongoDB collection that needs to be deserialized into a string. This conversion is throwing a "Cannot deserialize a 'String' from a BsonType 'Document'" exception.
I tried implementing a JSON custom converter, but as the value is being treated as a BsonDocument, it is not helping and I am getting the same exception. I also need it in the original format as I need to cast it back into a BsonDocument down the line. I guess I would need a custom Bson serializer/deserializer.
Incoming sample document from MongoDB collection:
{
"name": "Jane Doe",
"dob": {
"month": "Sep",
"day": 09,
"year": 1987
}
}
Type it is expecting for deserialization:
public class Person
{
public string name { get; set; }
public Dob dob { get; set; }
public class Dob
{
public string month { get; set; }
public int day { get; set; }
public int year { get; set; }
}
}
Type I want it to deserialize into:
public class Person
{
public string name { get; set; }
public string dob { get; set; }
}
To summarize, you have a public-facing string property on your model that contains JSON which you would like to internally serialize to MongoDB by deserializing the JSON string to some intermediate DTO, then serializing the DTO itself to Mongo.
Here are a couple of approaches to solving your problem.
Firstly, you could introduce a private DTO-valued property Dob SerializedDOB { get; set; } into your data model, mark that property with [BsonElement("dob")] to force it to be serialized, then modify dob to be a non-serialized surrogate property that serializes from and to the underlying SerializedDOB within its getter and setter. The following code shows this approach:
public class Person
{
public string name { get; set; }
[BsonIgnore]
public string dob
{
get => BsonExtensionMethods.ToJson(SerializedDOB);
set => SerializedDOB = MyBsonExtensionMethods.FromJson<Dob>(value);
}
[BsonElement("dob")]
Dob SerializedDOB { get; set; }
class Dob // The DTO
{
public string month { get; set; }
public int day { get; set; }
public int year { get; set; }
}
}
The advantage of this approach is that, by making the JSON string a surrogate, the setter automatically ensures that it is well-formed.
Demo fiddle #1 here.
Secondly, you could create a custom SerializerBase<string> for dob that maps the string value to and from the DTO Dob during (de)serialization. The following code shows this approach:
public class Person
{
public string name { get; set; }
[BsonSerializer(typeof(JsonStringAsObjectSerializer<Dob>))]
public string dob { get; set; }
class Dob // The DTO
{
public string month { get; set; }
public int day { get; set; }
public int year { get; set; }
}
}
public class JsonStringAsObjectSerializer<TObject> : SerializerBase<string> where TObject : class
{
public override void Serialize(BsonSerializationContext context, BsonSerializationArgs args, string value)
{
if (value == null)
{
var bsonWriter = context.Writer;
bsonWriter.WriteNull();
}
else
{
var obj = MyBsonExtensionMethods.FromJson<TObject>(value);
var serializer = BsonSerializer.LookupSerializer(typeof(TObject));
serializer.Serialize(context, obj);
}
}
public override string Deserialize(BsonDeserializationContext context, BsonDeserializationArgs args)
{
var bsonReader = context.Reader;
var serializer = BsonSerializer.LookupSerializer(typeof(TObject));
var obj = (TObject)serializer.Deserialize(context);
return (obj == null ? null : BsonExtensionMethods.ToJson(obj));
}
}
The advantage of this approach is that JsonStringAsObjectSerializer<TObject> can be reused whenever this requirement arises.
Demo fiddle #2 here.
The following extension method is used with both solutions to deserialize the JSON string to a specified type because, confusingly, BsonExtensionMethods has a ToJson() method but no FromJson() method:
public static partial class MyBsonExtensionMethods
{
// Not sure why but BsonExtensionMethods.cs seems to lack methods for deserializing from JSON, so I added some here.
// See https://github.com/mongodb/mongo-csharp-driver/blob/master/src/MongoDB.Bson/BsonExtensionMethods.cs
public static TNominalType FromJson<TNominalType>(
string json,
JsonReaderSettings readerSettings = null,
IBsonSerializer<TNominalType> serializer = null,
Action<BsonDeserializationContext.Builder> configurator = null)
{
return (TNominalType)FromJson(json, typeof(TNominalType), readerSettings, serializer, configurator);
}
public static object FromJson(
string json,
Type nominalType,
JsonReaderSettings readerSettings = null,
IBsonSerializer serializer = null,
Action<BsonDeserializationContext.Builder> configurator = null)
{
if (nominalType == null || json == null)
throw new ArgumentNullException();
serializer = serializer ?? BsonSerializer.LookupSerializer(nominalType);
if (serializer.ValueType != nominalType)
throw new ArgumentException(string.Format("serializer.ValueType {0} != nominalType {1}.", serializer.GetType().FullName, nominalType.FullName), "serializer");
using (var textReader = new StringReader(json))
using (var reader = new JsonReader(textReader, readerSettings ?? JsonReaderSettings.Defaults))
{
var context = BsonDeserializationContext.CreateRoot(reader, configurator);
return serializer.Deserialize(context);
}
}
}
I have this json string:
[
{
"id":"EORDERING_GRE017",
"name":"DELIMITER",
"value":"|"
},
{
"id":"EORDERING_GRE017",
"name":"ENABLED",
"value":"Y"
},
{
"id":"EORDERING_GRE017",
"name":"EXTERNALERRORRECIPIENT",
"value":"jaymie#moo.co.uk; matt#moo.co.uk"
},
{
"id":"EORDERING_GRE017",
"name":"FILETYPE",
"value":"delimited"
},
{
"id":"EORDERING_GRE017",
"name":"INTERNALERRORRECIPIENT",
"value":"jaymie#moo.co.uk; matt#moo.co.uk"
},
{
"id":"EORDERING_GRE017",
"name":"USESOWNBRANCHCODES",
"value":"True"
},
{
"id":"EORDERING_GRE017",
"name":"USESOWNSKUS",
"value":"True"
}
]
And I would like to turn that json into my class, which looks like this:
public class Settings
{
public bool Enabled { get; set; }
public string FileType { get; set; }
public string Delimiter { get; set; }
public string OrderFileSuffix { get; set; }
public string ResultFileSuffix { get; set; }
public bool UseOwnBranchCodes { get; set; }
public bool UseOwnProductCodes { get; set; }
public string InternalContacts { get; set; }
public string ExternalContacts { get; set; }
}
But I am unsure which is the best way to do this. Can someone give me a hand? :)
You could create a NameValue object:
public class NameValuePair
{
public string Name { get; set; }
public string Value { get; set; }
}
And deserialize the json array to List and convert it to Dictionary:
var dict = JsonConvert.DeserializeObject<List<NameValuePair>>(json).ToDictionary(x => x.Name, x => x.Value);
Then create a custom converter class with a method that accepts this dictionary and returns a Settings object:
public class SettingsConverter
{
public Settings Convert(IDictionary<string, string> data)
{
return new Settings
{
Enabled = data["ENABLED"].Equals("Y", StringComparison.Ordinal),
...
};
}
}
The JSON is an array of objects that would fit this class:
public class Setting
{
public string Id { get; set; }
public string Name { get; set; }
public string Value { get; set; }
}
So deserialize into that:
var settingList = JsonConvert.DeserializeObject<Setting[]>(jsonString);
But then you want to map specific settings to specific properties of that Settings class. You could do that by trying to find the particular setting for each property in the list of settings:
var settingsObject = new Settings
{
FileType = settingList.FirstOrDefault(s => s.Name == "FILETYPE")?.Value,
Delimiter = settingList.FirstOrDefault(s => s.Name == "DELIMITER")?.Value,
// ...
}
You'll have to manually map the properties. If you don't want that, you could write a custom serializer, but that'll quickly become a maintenance nightmare.
For those out there that may need some more help with the JSON Class Configuration, try: http://json2csharp.com/#
An excellent way of Auto Generating the Classes!
Or even easier, in VS, Goto:
Edit -> Paste Special -> Paste as JSON Classes
I am trying to do the following inside a Dictionary<string,string>
{
"name": "Bob Barker",
"devName": "InformationServices",
"ReturnedData": [{
"level_heading": "blah1",
"DeliverBestMedicalValue": "blah2",
"level_question": "blah3"
}]
}
I can add the name and devName just fine but I am unsure on how to go about adding the ReturnedData part of the array to the list so that it will return as the layout above?
Example code I am using:
febRecords.RootObject febRecordsData = JsonConvert.DeserializeObject<febRecords.RootObject>(serverResponse);
Dictionary<string,string> febFormData = new Dictionary<string,string>();
febFormData.Add("name", data.firstname.ToString());
febFormData.Add("devName", febData["Data"]["DevisionName"].ToString());
febFormData.Add("ReturnedData", ???); //<-this is where I am stuck
return Ok(JsonConvert.SerializeObject(febFormData, Newtonsoft.Json.Formatting.Indented));
As you see, febFormData.Add("ReturnedData", ???); is the spot where I am stuck and dont really know what to do in order to get the dictionary to output the correct JSON format like I want.
Any help would be great!
update
Would this be how the class needs to look?
public class theOutput
{
public string name { get; set; }
public string devName { get; set; }
public List<string> ReturnedData { get; set; }
}
As suggested by #Panagiotis Kanavos you'd really be better off having .NET entity to match your JSON data. For example:
// propertyname attributes can be ignored if property names
// match the json data property names 1:1
[JsonObject]
public class MyClass
{
public MyClass()
{
ReturnedData = new List<ReturnedData>();
}
[JsonProperty(PropertyName = "name")]
public string Name { get; set; }
[JsonProperty(PropertyName = "devName")]
public string DevName { get; set; }
[JsonProperty(PropertyName = "ReturnedData")]
public List<ReturnedData> ReturnedData { get; set; }
}
[JsonObject]
public class ReturnedData
{
[JsonProperty(PropertyName = "level_heading")]
public string LevelHeading { get; set; }
[JsonProperty(PropertyName = "DeliverBestMedicalValue")]
public string DeliverBestMedicalValue { get; set; }
[JsonProperty(PropertyName = "level_question")]
public string LevelQuestion { get; set; }
}
This would make conversion to/from JSON that much easier.
[TestMethod]
public void TestSome()
{
string json = #"{
""name"": ""Bob Barker"",
""devName"": ""InformationServices"",
""ReturnedData"": [{
""level_heading"": ""blah1"",
""DeliverBestMedicalValue"": ""blah2"",
""level_question"": ""blah3""
}]
}";
var obj = JsonConvert.DeserializeObject<MyClass>(json);
Assert.IsTrue(JToken.DeepEquals(JObject.Parse(json), JObject.FromObject(obj)));
}
You can always generate stubs from you JSON data using e.g. http://json2csharp.com/
Here "live" .NET fiddle, too https://dotnetfiddle.net/9ACddp
After a deserialization I save the content in an object:
var obj = JsonConvert.DeserializeObject<dynamic>(responseText);
so I execute a loop for populate a DataGrid
foreach(var item in obj)
{
MainWindow.AppWindow.Squadre_DataGrid.Items.Add(new Teams.Club_Information
{
code = item.code,
name = item.name,
shortName = item.shortName,
squadMarketValue = item.squadMarketValue
});
}
The problem's that inside the foreach the compiler show Runtime Binder Exception.
Why happean this?
Some more details:
Class structure
public class Self
{
public string href { get; set; }
}
public class Fixtures
{
public string href { get; set; }
}
public class Players
{
public string href { get; set; }
}
public class Links
{
public Self self { get; set; }
public Fixtures fixtures { get; set; }
public Players players { get; set; }
}
public class RootObject
{
public Links _links { get; set; }
public string name { get; set; }
public string code { get; set; }
public string shortName { get; set; }
public string squadMarketValue { get; set; }
public string crestUrl { get; set; }
}
JSON structure:
{
"_links": {
"self": { "href": "http://api.football-data.org/alpha/teams/19" },
"fixtures": { "href": "http://api.football-data.org/alpha/teams/19/fixtures" },
"players": { "href": "http://api.football-data.org/alpha/teams/19/players" }
},
"name": "Eintracht Frankfurt",
"code": "SGE",
"shortName": "Eintr. Frankfurt",
"squadMarketValue": "75.475.000 ?",
"crestUrl": "http://upload.wikimedia.org/wikipedia/commons/0/04/Eintracht_Frankfurt_Logo.svg"
}
The object you are deserializing does not contain a property named code. So the line code = item.code causes an exception at runtime, because the Json.Net object behind the dynamic does not contain a value named code.
This means that the Json that you are parsing does not contain a property named code. Or else it only sometimes contains a property named code. In that case you'll have to either parse it is a JObject and check if the property exists or create an type do deserialize it into.'
Edit
Based on the Json that you posted along with the class structure it looks like you should just be deserializing directly into a RootObject class:
var obj = JsonConvert.DeserializeObject<RootObject>(responseText);
Or in any case you can still deserialize into a dynamic but you need to get rid of the foreach since you don't have a collection of RootObject
var obj = JsonConvert.DeserializeObject<dynamic>(responseText);
MainWindow.AppWindow.Squadre_DataGrid.Items.Add(new Teams.Club_Information
{
code = obj.code,
name = obj.name,
shortName = obj.shortName,
squadMarketValue = obj.squadMarketValue
});
Where you went wrong was the foreach. Since obj is dynamic there is no compiler error and the Json.Net JObject that is returned supports iteraction. But the that gives you back each of the property values, (e.g. _links, name, etc) on at a time, not the object that you are interested in.