I'm working with C#, using XCOPY. I have method which copies a full directory into another:
public static void ProcessXcopy(string SolutionDirectory, string TargetDirectory)
{
// Use ProcessStartInfo class
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = true;
startInfo.UseShellExecute = false;
//Give the name as Xcopy
startInfo.FileName = "xcopy";
//make the window Hidden
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
//Send the Source and destination as Arguments to the process
startInfo.Arguments = "\"" + SolutionDirectory + "\"" + " " + "\"" + TargetDirectory + "\"" + #" /e /y /I /B";
try
{
// Start the process with the info we specified.
// Call WaitForExit and then the using statement will close.
using (Process exeProcess = Process.Start(startInfo))
{
exeProcess.WaitForExit();
}
}
catch (Exception exp)
{
throw exp;
}
}
That I want to know if there is a way to remove source directory once it is copied to another directory successfully.
If you want to stick .Net Methods, you can use Directory.Delete in the finally statement . The second parameter indicates to remove the Sub Folder/Files. More details here
Directory.Delete(path,true);
you can use robocopy instead of xcopy
robocopy from_folder to_folder files_to_copy /MOVE
xcopy needs .bat script in order to have same functionality with 1 line of robocopy
Ex:
xcopy /D /V %1 %2
if errorlevel 0 (
del /Q %1
exit /B
)
Related
The issue lies with the space between Test & Program. How do I get around this so Process.Start(Info); works as intended. I could change Test Program.exe to TestProgram.exe and this would work perfectly. Ive looked at similar questions but non seem to answer my question. Most mention String Replace or altering the string. I dont want to alter the string but regognise there is a space and process as normal.
Apoligies if this has been asked before but I cant seem to find it so please post the link if this has. Thanks
My code
private string program_name = "Test Program.exe";
ProcessStartInfo Info = new ProcessStartInfo();
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start " + program_name;
Info.WindowStyle = ProcessWindowStyle.Hidden;
Info.CreateNoWindow = true;
Info.FileName = "cmd.exe";
Process.Start(Info);
In your specific example - which seems a little odd, if you don't mind me saying - the program you are executing is part of the argument list and needs to be wrapped in double quotes like so:
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start \"" + program_name + "\"";
Or, just in case program_name is already quoted:
var quoted_name = $"\"{program_name.Trim('"')}\"";
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start " + quoted_name;
If that's really what you're using rather than a contrived example (which is perfectly fine as an example) then it would be simpler to just run the program directly rather than passing it as a commandline to cmd.exe, in which case you don't need the quotes at all:
ProcessStartInfo Info = new ProcessStartInfo();
Info.WindowStyle = ProcessWindowStyle.Hidden;
Info.CreateNoWindow = true;
Info.FileName = program_name; // or program_name.Trim('"')
Process.Start(Info);
Since you're hiding the console window anyway there doesn't seem much point explicitly invoking cmd.exe and having it wait around for the program to complete.
Try this:
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start \"" + program_name + "\"";
I want cmd command in my c# winforms program. I want use command to compress file with 7zip.
In normal cmd i use cd "C:\Program Files(x86)\7-Zip" & 7z.exe a -tzip "C:\xyz\test\txt" "C:\xyz\test\txt" -m0=BZip2 -mx5
string zip = #"/c C:\Program Files(x86)\7-Zip";
string file = #"/c C:\xyz\txt";
string conv = "/c & 7z.exe a -tzip";
string method = "/c -m0=BZip2 -mx5";
System.Diagnostics.ProcessStartInfo proc = new System.Diagnostics.ProcessStartInfo();
proc.FileName = #"C:\windows\system32\cmd.exe";
proc.Arguments = #"/c cd" + zip + conv + file + file + method;
System.Diagnostics.Process.Start(proc);
Doesn't work my code. How can i use this command in my program. I want compress file when i click in button
Something like this:
// File (exe) to start: combination of folder and exe
string fileName = Path.Combine(
// Let's not hardcode "C:\Program Files(x86)" and alike
Environment.GetFolderPath(Environment.SpecialFolder.ProgramFilesX86),
#"7-Zip",
#"7z.exe");
// If desired arguments are
// a -tzip "C:\xyz\test\txt" "C:\xyz\test\txt" -m0=BZip2 -mx5
// we can join them as
string arguments = string.Join(" ",
#"a",
#"-tzip", //TODO: you may want to have these values
#"""C:\xyz\test\txt""", // as variables like file, conv, method etc.
#"""C:\xyz\test\txt""",
#"-m0=BZip2",
#"-mx5");
ProcessStartInfo procInfo = new ProcessStartInfo() {
FileName = fileName, // We want to start fileName
Arguments = arguments, // With arguments
}
// Process is IDisposable, do not forget to Dispose HProcess handle
using (var process = Process.Start(procInfo)) {
// It's fire and forget implementation, if you want to wait for results
// add process.WaitForExit();
// process.WaitForExit(); // uncomment, if you want to pause
}
You seem to have made a mistake with your arguments.
Your current command line will be:
C:\windows\system32\cmd.exe /c cd/c C:\Program Files(x86)\7-Zip/c & 7z.exe a -tzip/c C:\xyz\txt/c C:\xyz\txt/c -m0=BZip2 -mx5
The spurious /c everywhere is not going to help and neither are the lack of spaces.
I'm guessing what you meant to run was these two commands in succession:
cd C:\Program Files(x86)\7-Zip
7z.exe a -tzip C:\xyz\txt C:\xyz\txt -m0=BZip2 -mx5
Which means you should change your code to:
string zip = #" C:\Program Files(x86)\7-Zip";
string file = #" C:\xyz\txt";
string conv = " & 7z.exe a -tzip";
string method = " -m0=BZip2 -mx5";
This will produce:
C:\windows\system32\cmd.exe /c cd C:\Program Files(x86)\7-Zip & 7z.exe a -tzip C:\xyz\txt C:\xyz\txt -m0=BZip2 -mx5
The command I'm trying to execute is
"C:\Program Files (x86)\MyAPP\solr-6.2.0\bin\solr" start -f -c -z "10.195.42.93:2181,10.195.42.92:2181" -h 10.195.42.92
And this works just fine on the command Line.
I'm trying to execute this as C# process.
NOTE: Below code works fine if i remove the quotes surrounding IPList
var IPList="10.195.42.93:2181,10.195.42.92:2181";
var hostIP="10.195.42.92"
string command = #"/c ""C:\Program Files (x86)\MyApp\solr-6.2.0\bin\solr"" start -f -c -z """ + IPList + #""" -h " + hostIP;
Process process = new Process();
log.Info("Starting " + command);
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = command;
process.StartInfo = startInfo;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.UseShellExecute = false;
process.StartInfo.CreateNoWindow = true;
process.OutputDataReceived += (s, e) => log.Info(e.Data);
process.ErrorDataReceived += (s, e) => log.Info(e.Data);
process.Start();
process.BeginOutputReadLine();
process.BeginErrorReadLine();
This throws error :
'C:\Program' is not recognized as an internal or external command,...
I have looked at the similar issue posted Here and tried the /s option but no heed.
What am i missing here ?
As the error says, it is trying to execute C:\Program which basically means something is wrong with the way you are escaping quotes. May be try to escape " using - \"
You're asking cmd.exe to run the command C:\Program Files (x86)\MyApp\solr-6.2.0\bin\solr. It will not run "C:\Program Files (x86)\MyApp\solr-6.2.0\bin\solr" because the quotes are consumed by the invocation of cmd.exe.
I do not know the proper way to fix this. You probably need to add escaped quotes somehow.
Enclosing the command with "(quotes) after /c solves the issue.
Example :
"/c ""c:\prog files\xyz\solr" start -c -z "blah,blah,blah" -h
IP "
Basically the command that is getting executed is
> cmd.exe /c "C:\Program Files (x86)\MyAPP\solr-6.2.0\bin\solr" start -f -c -z "10.195.42.93:2181,10.195.42.92:2181" -h 10.195.42.92
This command fails, and this has nothing to do with c# process api or .net.
Previously somebody has asked how to run a command line command in C# from visual studio and the beneath was the answer.
I tried the same intended to call a tool called cccc which can run on command line. But when I run the beneath code I do not get any results and nothing shows wrong.
Stating generally how can we run the same commands from C# as it was in command line and get the same results. Say I call a program (it could be any program that is able to run on command line, for instance, cccc, ccm, and so on) on command line and get some results. How to call the command line and give the arguments so it will call in its turn the cccc or whatever and do the same thing as it was without C#.
string strCmdText;
strCmdText = "/C d: cd D:\\Exercises\\npp52\\PowerEditor\\src && dir /s /b | cccc - --outdir=d:\\myfolder";
System.Diagnostics.Process.Start("CMD.exe", strCmdText);
Add 'pause' to the end of your command:
string strCmdText;
strCmdText = "/C d: cd D:\\Exercises\\npp52\\PowerEditor\\src && dir /s /b | cccc - --outdir=d:\\myfolder & pause";
System.Diagnostics.Process.Start("CMD.exe", strCmdText);
or redirect console standard output to a stream.
Here need more magic with OutputDataReceived handler
void Main()
{
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.FileName="cmd.exe";
proc.StartInfo.Arguments = "/c ping 127.0.0.1";
proc.StartInfo.UseShellExecute = false;
proc.OutputDataReceived += new DataReceivedEventHandler(SortOutputHandler);
proc.StartInfo.RedirectStandardOutput = true;
proc.Start();
proc.BeginOutputReadLine();
proc.WaitForExit();
proc.Close();
}
private void SortOutputHandler(object sendingProcess,
DataReceivedEventArgs outLine)
{
if (!String.IsNullOrEmpty(outLine.Data))
{
// Do what You need with out
Console.WriteLine(outLine.Data);
}
}
Instead of trying to put everything inside a string you could take advantage of the ProcessStartInfo class to better define your arguments
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "CMD.EXE";
psi.WorkingDirectory = "D:\\Exercises\\npp52\\PowerEditor\\src ";
psi.Arguments = "/C dir /s /b | cccc - --outdir=d:\\myfolder"";
psi.WindowStyle = ProcessWindowStyle.Normal;
Process.Start(psi);
Also with the command window open you could see if there are syntax errors in your command
Another problem is that you are not using RedirectStandardOutput, so output is discarded. Take a look at this answer.
I got this program written in C# WinForms.
im using system.diagnostic to create a CMD process.
with that cmd i want some arguments but they are not present or working :S
dont know why ?!
NOTE: im not sure how to use more than 1 argument, correct me if im wrong :D
im trying to replicate the "copy /b %filename% lpt1" command....
here is my code:
public void OutputBtn_Process_Click(object sender, EventArgs e)
{
foreach (FileInfo fi in listBox1.Items)
{
Process process1 = new Process();
process1.StartInfo.UseShellExecute = false;
process1.StartInfo.Arguments = "copy /b myfile.txt test.txt";
//process1.StartInfo.LoadUserProfile = true;
process1.StartInfo.FileName = "cmd.exe";
process1.StartInfo.WorkingDirectory = Path.GetDirectoryName(fi.FullName);
process1.Start();
}
}
string strCmdText;
strCmdText= "/C copy /b myfile.txt test.txt";
System.Diagnostics.Process.Start("CMD.exe",strCmdText);
Try this
process1.StartInfo.Arguments = "/C \"copy /b myfile.txt LPT1:\"";
The documentation on Windows 7 command-line tool cmd.exe