I am trying to write a Windows Forms application using C#, however I have never done this before. I have successfully created a login page which takes the user to a home page where 4 buttons are displayed. I am trying to find code to put inside each button that will take the user to a different page.
In windows forms application, you have to call Show method on the Form which you want to show.
Let's say on Button1 click you want to show Form2, then below code will bring Form 2 up on the screen.
private void button1_Click_1(object sender, EventArgs e)
{
Form2 obj = new Form2();
if (obj == null)
{
obj.Parent = this;
}
obj.Show();
this.Hide();
}
You need to create, initialize and show the other forms.
frmSecond frm = new frmSecond();//You should call any other constructor, may be with some parameters
frm.Text ="I wanted to change the title";//Optional: You can change any property value if you need
frm.Show();
If you want to show the form, collect some information from user and return some values then you can use ShowDialog method instead of Show method
if(frm.ShowDialog(this) == DialogResult.OK){
var myVar = frm.ReturnObject;
...
}
You can use below approach for one parent window and new child window.
When you press the button new form opens:
private void button1_Click(object sender, EventArgs e)
{
Form2 frm2 = new Form2();
{
frm2.ShowDialog();
}
}
Related
I'm new to C# and could use some help.
What I have so far is a set of 8 windows forms I have created in C#, these forms have basic things like text boxes, labels, radio buttons, etc. Now that I have completed making all of these forms I want to have one additional form (called the Selector form) I can use to select one of the other 8 forms. At any given time, I want the Selector form to be on top of other windows and it will have 8 radio buttons (or regular buttons, doesn't matter). When one of the buttons is clicked, the current form (not the Selector form) should disappear and a new form should appear. The name of the button will be the name of the new form that appears.
I have seen a few examples and here is the code I have so far:
void Button1Click(object sender, EventArgs e)
{
//this.Hide();
var form1 = new CASII();
form1.Closed += (sender1, args) => this.Close();
form1.Show();
}
void Button2Click(object sender, EventArgs e)
{
// this.Hide();
var form2 = new CCARAdmin();
form2.Closed += (sender1, args) => this.Close();
form2.Show();
//Application.Run(new CCARAdmin());
}
Problem I am having is I don't want to hide the Selector form, which this does, and I don't know how to identify the other form that is open to close it and then open a different form.
From starting the program the logic would be like this:
Show Selector form
When a button is clicked on the Selector form, keep the Selector form on top and show the other form with the name of the button.
When a different button is clicked on the Selector form, close the previous form that was open (not the Selector form) and open the new form corresponding to the name of the button. Keep the Selector form on top.
When the Selector form is close, application stops.
Problem I am having is I don't want to hide the Selector form, which
this does, and I don't know how to identify the other form that is
open to close it and then open a different form.
Set Selector form TopMost to True to make it always on top. Or
you can use BringToFront after opening a new form
to know other forms that are open check this answer. Or you can define each From as a field in the Selector form, and check that.
selectorForm.TopMost = true ( this will help to keep the selector form always on top).
Create a form variable in your selector form to keep the reference of your currently opened form.
Sample code for 1 button click :
Form frm = null;
void Button1Click(object sender, EventArgs e)
{
//this.Hide();
var form1 = new CASII();
if (frm == null)
{
frm = form1;
}
else
{
frm.Close();
}
form1.Show();
this.TopMost = true;
frm = form1;
}
I resolved this by setting TopMost to true and then using the following code under each one of the buttons:
for (int i = Application.OpenForms.Count - 1; i >= 0; i--)
{
if (Application.OpenForms[i].Name != "FormSelector")
Application.OpenForms[i].Close();
}
var form = new TRAC();
if (radioButton9.Checked == true)
{
form.Show();
}
I am making a Windows Forms application. I have a form. I want to open a new form at run time from the original form on a button click. And then close this new form (after 2,3 sec) programatically but from a thread other than gui main thread.
Can anybody guide me how to do it ?
Will the new form affect or hinder the things going on in the original main form ? (if yes than how to stop it ?)
To open from with button click please add the following code in the button event handler
var m = new Form1();
m.Show();
Here Form1 is the name of the form which you want to open.
Also to close the current form, you may use
this.close();
I would do it like this:
var form2 = new Form2();
form2.Show();
and to close current form I would use
this.Hide(); instead of
this.close();
check out this Youtube channel link for easy start-up tutorials you might find it helpful if u are a beginner
This is an old question, but answering for gathering knowledge.
We have an original form with a button to show the new form.
The code for the button click is below
private void button1_Click(object sender, EventArgs e)
{
New_Form new_Form = new New_Form();
new_Form.Show();
}
Now when click is made, New Form is shown. Since, you want to hide after 2 seconds we are adding a onload event to the new form designer
this.Load += new System.EventHandler(this.OnPageLoad);
This OnPageLoad function runs when that form is loaded
In NewForm.cs ,
public partial class New_Form : Form
{
private Timer formClosingTimer;
private void OnPageLoad(object sender, EventArgs e)
{
formClosingTimer = new Timer(); // Creating a new timer
formClosingTimer.Tick += new EventHandler(CloseForm); // Defining tick event to invoke after a time period
formClosingTimer.Interval = 2000; // Time Interval in miliseconds
formClosingTimer.Start(); // Starting a timer
}
private void CloseForm(object sender, EventArgs e)
{
formClosingTimer.Stop(); // Stoping timer. If we dont stop, function will be triggered in regular intervals
this.Close(); // Closing the current form
}
}
In this new form , a timer is used to invoke a method which closes that form.
Here is the new form which automatically closes after 2 seconds, we will be able operate on both the forms where no interference between those two forms.
For your knowledge,
form.close() will free the memory and we can never interact with that form again
form.hide() will just hide the form, where the code part can still run
For more details about timer refer this link, https://learn.microsoft.com/en-us/dotnet/api/system.timers.timer?view=netframework-4.7.2
You just need to use Dispatcher to perform graphical operation from a thread other then UI thread. I don't think that this will affect behavior of the main form. This may help you :
Accessing UI Control from BackgroundWorker Thread
This might also help:
void ButtQuitClick(object sender, EventArgs e)
{
QuitWin form = new QuitWin();
form.Show();
}
Change ButtQuit to your button name and also change QuitWin to the name of the form that you made.
When the button is clicked it will open another window, you will need to make another form and a button on your main form for it to work.
private void btnchangerate_Click(object sender, EventArgs e)
{
this.Hide(); //current form will hide
Form1 fm = new Form1(); //another form will open
fm.Show();
}
on click btn current form will hide and new form will open
What is the best way to close a form and get to another form.
At present I have a Main Form and then two forms:
I want to know how to close one form and open another form efficiently.The two times I did it had a slight different outcome:
The main form in my application is just the introduction which will load some Company Logo and show a progress bar which will then take it to a log-in form, where in I have a log-in button, from where the actual application will open.
I have some questions.In the Main Form I have added this code:
private void Form1_Load(object sender, EventArgs e)
{
int i;
for (i = 0; i <= 100; i++)
{
progressBar.Value = i;
label1.Text = "Please wait while Refresh loads up...";
}
}
private void progressTimer_Tick(object sender, EventArgs e)
{
this.Close();
}
private void MainForm_Deactivate(object sender, EventArgs e)
{
Form form = new FirstForm();
form.ShowDialog(this);
}
1) This works fine, just that the new form that opens up is at the task bar and is not in the center of the screen(as I have set it's property).How do I fix this?
In the First Form I have added this code:
private void loginButton_Click(object sender, EventArgs e)
{
using( ERPQueries eq = new ERPQueries())
{
int? count = eq.CheckEmployee(userTextBox.Text,passwordTextBox.Text);
if (count == 1)
{
//testLabel.Text = "Ok";
this.Close();
Form form = new SecondForm();
form.ShowDialog(this);
}
else
{
testLabel.Text = "Invalid username or password!";
}
}
}
2) Here the next Form pops up in the center of the screen.I want to know how is it different from the first case, as I have used showDialog() in both the cases?
3) Also in the first case my Main Form Disappears, whereas in the second case the First Form is still visible in the background and disappears only after closing the SecondForm.
I'm sure I'm doing a lot of mistakes, my code is flawed.Please help.This is the first time I'm making an application with multiple forms.
Edit:
When I use Show() instead of ShowDialog() I don't see the new form.Am I missing something?
I tried this.Dispose() instead of this.Close().In the first case it works fine.In the second case, it disposes all the forms.
try:
form.Show();
not
form.ShowDialog(this);
which is what makes it modal.
ShowDialog() is blocking call, so if in one Form's deactivate event you call ShowDialog() of another, your parent form will not yet finish it deactivating.
Like a suggesion I can give you create a collection/stack of forms you want to manage and give control over it to a FormManager class, where you implement whatever logic you want and can call either ShowDialog() or Show(). In other words bring out forms Show/Hide management out forms itself.
Regards.
I am learning windows forms and can create a one form with textboxes and stuff, but I was wondering how can I change the form upon let's say clicking a button?, so for instance my initial form has a textbox and a button, if the button is clicked I want to show a form with a dropdown and a button. SO the question should be:
1) How do I change the form upon clicking a button but without creating a new instance of the form.
2) If I wanted, how can I add a form when the button is clicked showing the same drop down and button as a pop up form?
In reality I would like to know both cases, changing the form via using the same form and via popping a new form on top.
Should the questions not be clear, I am willing to further explain
Thank you
I'm assuming you already know how to add controls in the form designer and how to implement event handlers.
Question 1
private void button1_Click(object sender, EventArgs e)
{
if (comboBox1.Visible)
{
comboBox1.Visible = false;
textBox1.Visible = true;
}
else
{
comboBox1.Visible = true;
textBox1.Visible = false;
}
}
The button click handler simply toggles the visibility of the two controls.
Question 2
private void button2_Click(object sender, EventArgs e)
{
Form1 form = new Form1();
form.ShowDialog();
}
This time the button handler instantiates a new form an then shows it as a modal dialog. Call Show() if you don't want to show modally.
In C sharp win forms,
not using MDI, m creating multiple forms
i wish to hide the previous form while loading a new form on a button's click
i write the following code to achieve the purpose but the previous form still remains visible, kindly help!!
here's the code...
private void btnEmployee_Click(object sender, EventArgs e)
{
Form f3 = new EmployeeLogIn();
f3.Show();
Form id = new Login();
id.Hide();
}
You're hiding a newly-created form. You need to get the reference to the previous form by either passing it into the current form, or using a static property.
EDIT: actually I think this is what you wanted to do:
private void btnEmployee_Click(object sender, EventArgs e)
{
Form f3 = new EmployeeLogIn();
f3.Show();
this.Hide();
}
Your code will only continue when the form is loaded, so when the f3.Show() statement is finished.
Consider showing the f3 form in a new thread.