How get odd chars from String in C# - c#

I am new to C#. My problem is to take odd chars from a string and get a new string from those odds.
string name = "Filip"; // expected output ="Flp"
I don't want to take, for example,
string result = name.Substring(0, 1) + name.Substring(2, 1) + ... etc.
I need a function for this operation.

Try Linq (you actually want even characters since string is zero-based):
string name = "Filip";
string result = string.Concat(name.Where((c, i) => i % 2 == 0));
In case of good old loop implementation, I suggest building the string with a help of StringBuilder:
StringBuilder sb = new StringBuilder(name.Length / 2 + 1);
for (int i = 0; i < name.Length; i += 2)
sb.Append(name[i]);
string result = sb.ToString();

Related

How can I add a space between every 3 characters counting from the right to the left in a string in C#?

I want to add space between every 3 characters in a string in C#, but count from right to left.
For example :
11222333 -> 11 222 333
Answer by #Jimi from comments (will delete if they post their own)
var YourString = "11222333";
var sb = new StringBuilder(YourString);
for (int i = sb.Length -3; i >= 0; i -= 3)
sb.Insert(i, ' ');
return sb.ToString();
The benefit of this algorithm appears to be that you are working backwards through the string and therefore only moving a certain amount on each run, rather than the whole string.
If you are trying to format a string as a number according to some locale conventions you can use the NumberFormat class to set how you want a number to be formatted as a string
So for example
string input = "11222333";
NumberFormatInfo currentFormat = new NumberFormatInfo();
currentFormat.NumberGroupSeparator = " ";
if(Int32.TryParse(input, NumberStyles.None, currentFormat, out int result))
{
string output = result.ToString("N0", currentFormat);
Console.WriteLine(output); // 11 222 333
}
The following recursive function would do the job:
string space3(string s)
{
int len3 = s.Length - 3;
return (len <= 0) ? s
: (space3(s.Substring(0, len3)) + " " + s.Substring(len3));
}
C# 8.0 introduced string ranges. Ranges allow for a more compact form:
string space3(string s)
{
return (s.Length <= 3) ? s
: (space3(s[..^3]) + " " + s[^3..]);
}
Using Regex.Replace:
string input = "11222333";
string result = Regex.Replace( input, #"\d{3}", #" $0", RegexOptions.RightToLeft );
Demo and detailed explanation of RegEx pattern at regex101.
tl;dr: Match groups of 3 digits from right to left and replace them by space + the 3 digits.
The most efficient algorithm I can come up with is the following:
var sb = new StringBuilder(YourString.Length + YourString.Length / 3 + 1);
if (YourString.Length % 3 > 0)
{
sb.Append(YourString, 0, YourString.Length % 3);
sb.Append(' ');
}
for (var i = YourString.Length % 3; i < YourString.Length; i += 3)
{
sb.Append(YourString, i, 3);
sb.Append(' ');
}
return sb.ToString();
We first assign a StringBuilder of the correct size.
Then we check to see if we need to append the first one or two characters. Then we loop the rest.
dotnetfiddle

How to remove all but the first occurences of a character from a string?

I have a string of text and want to ensure that it contains at most one single occurrence of a specific character (,). Therefore I want to keep the first one, but simply remove all further occurrences of that character.
How could I do this the most elegant way using C#?
This works, but not the most elegant for sure :-)
string a = "12,34,56,789";
int pos = 1 + a.IndexOf(',');
return a.Substring(0, pos) + a.Substring(pos).Replace(",", string.Empty);
You could use a counter variable and a StringBuilder to create the new string efficiently:
var sb = new StringBuilder(text.Length);
int maxCount = 1;
int currentCount = 0;
char specialChar = ',';
foreach(char c in text)
if(c != specialChar || ++currentCount <= maxCount)
sb.Append(c);
text = sb.ToString();
This approach is not the shortest but it's efficient and you can specify the char-count to keep.
Here's a more "elegant" way using LINQ:
int commasFound = 0; int maxCommas = 1;
text = new string(text.Where(c => c != ',' || ++commasFound <= maxCommas).ToArray());
I don't like it because it requires to modify a variable from a query, so it's causing a side-effect.
Regular expressions are elegant, right?
Regex.Replace("Eats, shoots, and leaves.", #"(?<=,.*),", "");
This replaces every comma, as long as there is a comma before it, with nothing.
(Actually, it's probably not elegant - it may only be one line of code, but it may also be O(n^2)...)
If you don't deal with large strings and you reaaaaaaly like Linq oneliners:
public static string KeepFirstOccurence (this string #string, char #char)
{
var index = #string.IndexOf(#char);
return String.Concat(String.Concat(#string.TakeWhile(x => #string.IndexOf(x) < index + 1)), String.Concat(#string.SkipWhile(x=>#string.IndexOf(x) < index)).Replace(#char.ToString(), ""));
}
You could write a function like the following one that would split the string into two sections based on the location of what you were searching (via the String.Split() method) for and it would only remove matches from the second section (using String.Replace()) :
public static string RemoveAllButFirst(string s, string stuffToRemove)
{
// Check if the stuff to replace exists and if not, return the original string
var locationOfStuff = s.IndexOf(stuffToRemove);
if (locationOfStuff < 0)
{
return s;
}
// Calculate where to pull the first string from and then replace the rest of the string
var splitLocation = locationOfStuff + stuffToRemove.Length;
return s.Substring(0, splitLocation) + (s.Substring(splitLocation)).Replace(stuffToRemove,"");
}
You could simply call it by using :
var output = RemoveAllButFirst(input,",");
A prettier approach might actually involve building an extension method that handled this a bit more cleanly :
public static class StringExtensions
{
public static string RemoveAllButFirst(this string s, string stuffToRemove)
{
// Check if the stuff to replace exists and if not, return the
// original string
var locationOfStuff = s.IndexOf(stuffToRemove);
if (locationOfStuff < 0)
{
return s;
}
// Calculate where to pull the first string from and then replace the rest of the string
var splitLocation = locationOfStuff + stuffToRemove.Length;
return s.Substring(0, splitLocation) + (s.Substring(splitLocation)).Replace(stuffToRemove,"");
}
}
which would be called via :
var output = input.RemoveAllButFirst(",");
You can see a working example of it here.
static string KeepFirstOccurance(this string str, char c)
{
int charposition = str.IndexOf(c);
return str.Substring(0, charposition + 1) +
str.Substring(charposition, str.Length - charposition)
.Replace(c, ' ').Trim();
}
Pretty short with Linq; split string into chars, keep distinct set and join back to a string.
text = string.Join("", text.Select(c => c).Distinct());

Alternatively upper- and lowercase words in a string

I use Visual Studio 2010 ver.
I have array strings [] = { "eat and go"};
I display it with foreach
I wanna convert strings like this : EAT and GO
Here my code:
Console.Write( myString.First().ToString().ToUpper() + String.Join("",myString].Skip(1)).ToLower()+ "\n");
But the output is : Eat and go . :D lol
Could you help me? I would appreciate it. Thanks
While .ToUpper() will convert a string to its upper case equivalent, calling .First() on a string object actually returns the first element of the string (since it's effectively a char[] under the hood). First() is actually exposed as a LINQ extension method and works on any collection type.
As with many string handling functions, there are a number of ways to handle it, and this is my approach. Obviously you'll need to validate value to ensure it's being given a long enough string.
using System.Text;
public string CapitalizeFirstAndLast(string value)
{
string[] words = value.Split(' '); // break into individual words
StringBuilder result = new StringBuilder();
// Add the first word capitalized
result.Append(words[0].ToUpper());
// Add everything else
for (int i = 1; i < words.Length - 1; i++)
result.Append(words[i]);
// Add the last word capitalized
result.Append(words[words.Length - 1].ToUpper());
return result.ToString();
}
If it's always gonna be a 3 words string, the you can simply do it like this:
string[] mystring = {"eat and go", "fast and slow"};
foreach (var s in mystring)
{
string[] toUpperLower = s.Split(' ');
Console.Write(toUpperLower.First().ToUpper() + " " + toUpperLower[1].ToLower() +" " + toUpperLower.Last().ToUpper());
}
If you want to continuously alternate, you can do the following:
private static string alternateCase( string phrase )
{
String[] words = phrase.split(" ");
StringBuilder builder = new StringBuilder();
//create a flag that keeps track of the case change
book upperToggle = true;
//loops through the words
for(into i = 0; i < words.length; i++)
{
if(upperToggle)
//converts to upper if flag is true
words[i] = words[i].ToUpper();
else
//converts to lower if flag is false
words[i] = words[i].ToLower();
upperToggle = !upperToggle;
//adds the words to the string builder
builder.append(words[i]);
}
//returns the new string
return builder.ToString();
}
Quickie using ScriptCS:
scriptcs (ctrl-c to exit)
> var input = "Eat and go";
> var words = input.Split(' ');
> var result = string.Join(" ", words.Select((s, i) => i % 2 == 0 ? s.ToUpperInvariant() : s.ToLowerInvariant()));
> result
"EAT and GO"

Add separator to string at every N characters?

I have a string which contains binary digits. How to separate string after each 8 digit?
Suppose the string is:
string x = "111111110000000011111111000000001111111100000000";
I want to add a separator like ,(comma) after each 8 character.
output should be :
"11111111,00000000,11111111,00000000,11111111,00000000,"
Then I want to send it to a list<> last 8 char 1st then the previous 8 chars(excepting ,) and so on.
How can I do this?
Regex.Replace(myString, ".{8}", "$0,");
If you want an array of eight-character strings, then the following is probably easier:
Regex.Split(myString, "(?<=^(.{8})+)");
which will split the string only at points where a multiple of eight characters precede it.
Try this:
var s = "111111110000000011111111000000001111111100000000";
var list = Enumerable
.Range(0, s.Length/8)
.Select(i => s.Substring(i*8, 8));
var res = string.Join(",", list);
There's another Regex approach:
var str = "111111110000000011111111000000001111111100000000";
# for .NET 4
var res = String.Join(",",Regex.Matches(str, #"\d{8}").Cast<Match>());
# for .NET 3.5
var res = String.Join(",", Regex.Matches(str, #"\d{8}")
.OfType<Match>()
.Select(m => m.Value).ToArray());
...or old school:
public static List<string> splitter(string in, out string csv)
{
if (in.length % 8 != 0) throw new ArgumentException("in");
var lst = new List<string>(in/8);
for (int i=0; i < in.length / 8; i++) lst.Add(in.Substring(i*8,8));
csv = string.Join(",", lst); //This we want in input order (I believe)
lst.Reverse(); //As we want list in reverse order (I believe)
return lst;
}
Ugly but less garbage:
private string InsertStrings(string s, int insertEvery, char insert)
{
char[] ins = s.ToCharArray();
int length = s.Length + (s.Length / insertEvery);
if (ins.Length % insertEvery == 0)
{
length--;
}
var outs = new char[length];
long di = 0;
long si = 0;
while (si < s.Length - insertEvery)
{
Array.Copy(ins, si, outs, di, insertEvery);
si += insertEvery;
di += insertEvery;
outs[di] = insert;
di ++;
}
Array.Copy(ins, si, outs, di, ins.Length - si);
return new string(outs);
}
String overload:
private string InsertStrings(string s, int insertEvery, string insert)
{
char[] ins = s.ToCharArray();
char[] inserts = insert.ToCharArray();
int insertLength = inserts.Length;
int length = s.Length + (s.Length / insertEvery) * insert.Length;
if (ins.Length % insertEvery == 0)
{
length -= insert.Length;
}
var outs = new char[length];
long di = 0;
long si = 0;
while (si < s.Length - insertEvery)
{
Array.Copy(ins, si, outs, di, insertEvery);
si += insertEvery;
di += insertEvery;
Array.Copy(inserts, 0, outs, di, insertLength);
di += insertLength;
}
Array.Copy(ins, si, outs, di, ins.Length - si);
return new string(outs);
}
If I understand your last requirement correctly (it's not clear to me if you need the intermediate comma-delimited string or not), you could do this:
var enumerable = "111111110000000011111111000000001111111100000000".Batch(8).Reverse();
By utilizing morelinq.
Here my two little cents too. An implementation using StringBuilder:
public static string AddChunkSeparator (string str, int chunk_len, char separator)
{
if (str == null || str.Length < chunk_len) {
return str;
}
StringBuilder builder = new StringBuilder();
for (var index = 0; index < str.Length; index += chunk_len) {
builder.Append(str, index, chunk_len);
builder.Append(separator);
}
return builder.ToString();
}
You can call it like this:
string data = "111111110000000011111111000000001111111100000000";
string output = AddChunkSeparator(data, 8, ',');
One way using LINQ:
string data = "111111110000000011111111000000001111111100000000";
const int separateOnLength = 8;
string separated = new string(
data.Select((x,i) => i > 0 && i % separateOnLength == 0 ? new [] { ',', x } : new [] { x })
.SelectMany(x => x)
.ToArray()
);
I did it using Pattern & Matcher as following way:
fun addAnyCharacter(input: String, insertion: String, interval: Int): String {
val pattern = Pattern.compile("(.{$interval})", Pattern.DOTALL)
val matcher = pattern.matcher(input)
return matcher.replaceAll("$1$insertion")
}
Where:
input indicates Input string. Check results section.
insertion indicates Insert string between those characters. For example comma (,), start(*), hash(#).
interval indicates at which interval you want to add insertion character.
input indicates Input string. Check results section. Check results section; here I've added insertion at every 4th character.
Results:
I/P: 1234XXXXXXXX5678 O/P: 1234 XXXX XXXX 5678
I/P: 1234567812345678 O/P: 1234 5678 1234 5678
I/P: ABCDEFGHIJKLMNOP O/P: ABCD EFGH IJKL MNOP
Hope this helps.
As of .Net 6, you can simply use the IEnumerable.Chunk method (Which splits elements of a sequence into chunks) then reconcatenate the chunks using String.Join.
var text = "...";
string.Join(',', text.Chunk(size: 6).Select(x => new string(x)));
This is much faster without copying array (this version inserts space every 3 digits but you can adjust it to your needs)
public string GetString(double valueField)
{
char[] ins = valueField.ToString().ToCharArray();
int length = ins.Length + (ins.Length / 3);
if (ins.Length % 3 == 0)
{
length--;
}
char[] outs = new char[length];
int i = length - 1;
int j = ins.Length - 1;
int k = 0;
do
{
if (k == 3)
{
outs[i--] = ' ';
k = 0;
}
else
{
outs[i--] = ins[j--];
k++;
}
}
while (i >= 0);
return new string(outs);
}
For every 1 character, you could do this one-liner:
string.Join(".", "1234".ToArray()) //result: 1.2.3.4
If you intend to create your own function to acheive this without using regex or pattern matching methods, you can create a simple function like this:
String formatString(String key, String seperator, int afterEvery){
String formattedKey = "";
for(int i=0; i<key.length(); i++){
formattedKey += key.substring(i,i+1);
if((i+1)%afterEvery==0)
formattedKey += seperator;
}
if(formattedKey.endsWith("-"))
formattedKey = formattedKey.substring(0,formattedKey.length()-1);
return formattedKey;
}
Calling the mothod like this
formatString("ABCDEFGHIJKLMNOPQRST", "-", 4)
Would result in the return string as this
ABCD-EFGH-IJKL-MNOP-QRST
A little late to the party, but here's a simplified LINQ expression to break an input string x into groups of n separated by another string sep:
string sep = ",";
int n = 8;
string result = String.Join(sep, x.InSetsOf(n).Select(g => new String(g.ToArray())));
A quick rundown of what's happening here:
x is being treated as an IEnumerable<char>, which is where the InSetsOf extension method comes in.
InSetsOf(n) groups characters into an IEnumerable of IEnumerable -- each entry in the outer grouping contains an inner group of n characters.
Inside the Select method, each group of n characters is turned back into a string by using the String() constructor that takes an array of chars.
The result of Select is now an IEnumerable<string>, which is passed into String.Join to interleave the sep string, just like any other example.
I am more than late with my answer but you can use this one:
static string PutLineBreak(string str, int split)
{
for (int a = 1; a <= str.Length; a++)
{
if (a % split == 0)
str = str.Insert(a, "\n");
}
return str;
}

Format string with dashes

I have a compressed string value I'm extracting from an import file. I need to format this into a parcel number, which is formatted as follows: ##-##-##-###-###. So therefore, the string "410151000640" should become "41-01-51-000-640". I can do this with the following code:
String.Format("{0:##-##-##-###-###}", Convert.ToInt64("410151000640"));
However, The string may not be all numbers; it could have a letter or two in there, and thus the conversion to the int will fail. Is there a way to do this on a string so every character, regardless of if it is a number or letter, will fit into the format correctly?
Regex.Replace("410151000640", #"^(.{2})(.{2})(.{2})(.{3})(.{3})$", "$1-$2-$3-$4-$5");
Or the slightly shorter version
Regex.Replace("410151000640", #"^(..)(..)(..)(...)(...)$", "$1-$2-$3-$4-$5");
I would approach this by having your own formatting method, as long as you know that the "Parcel Number" always conforms to a specific rule.
public static string FormatParcelNumber(string input)
{
if(input.length != 12)
throw new FormatException("Invalid parcel number. Must be 12 characters");
return String.Format("{0}-{1}-{2}-{3}-{4}",
input.Substring(0,2),
input.Substring(2,2),
input.Substring(4,2),
input.Substring(6,3),
input.Substring(9,3));
}
This should work in your case:
string value = "410151000640";
for( int i = 2; i < value.Length; i+=3){
value = value.Insert( i, "-");
}
Now value contains the string with dashes inserted.
EDIT
I just now saw that you didn't have dashes between every second number all the way, to this will require a small tweak (and makes it a bit more clumsy also I'm afraid)
string value = "410151000640";
for( int i = 2; i < value.Length-1; i+=3){
if( value.Count( c => c == '-') >= 3) i++;
value = value.Insert( i, "-");
}
If its part of UI you can use MaskedTextProvider in System.ComponentModel
MaskedTextProvider prov = new MaskedTextProvider("aa-aa-aa-aaa-aaa");
prov.Set("41x151000a40");
string result = prov.ToDisplayString();
Here is a simple extension method with some utility:
public static string WithMask(this string s, string mask)
{
var slen = Math.Min(s.Length, mask.Length);
var charArray = new char[mask.Length];
var sPos = s.Length - 1;
for (var i = mask.Length - 1; i >= 0 && sPos >= 0;)
if (mask[i] == '#') charArray[i--] = s[sPos--];
else
charArray[i] = mask[i--];
return new string(charArray);
}
Use it as follows:
var s = "276000017812008";
var mask = "###-##-##-##-###-###";
var dashedS = s.WithMask(mask);
You can use it with any string and any character other than # in the mask will be inserted. The mask will work from right to left. You can tweak it to go the other way if you want.
Have fun.
If i understodd you correctly youre looking for a function that removes all letters from a string, aren't you?
I have created this on the fly, maybe you can convert it into c# if it's what you're looking for:
Dim str As String = "410151000vb640"
str = String.Format("{0:##-##-##-###-###}", Convert.ToInt64(MakeNumber(str)))
Public Function MakeNumber(ByVal stringInt As String) As String
Dim sb As New System.Text.StringBuilder
For i As Int32 = 0 To stringInt.Length - 1
If Char.IsDigit(stringInt(i)) Then
sb.Append(stringInt(i))
End If
Next
Return sb.ToString
End Function

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