I have a similar case - I receive a DataSet object with data tables willed with data (e. g. customers table ...) from an external module (done by other programmer).
I then save the data set object to an xml using the writeXml method - here is my code
public void Save(string myXmlFilePath)
{
XmlWriterSettings settings = new XmlWriterSettings();
settings.Encoding = System.Text.Encoding.UTF8;
settings.Indent = true;
settings.NewLineHandling = NewLineHandling.None;
using (XmlWriter writer = XmlWriter.Create(myXmlFilePath, settings))
{
ExportObject.WriteXml(writer);
writer.Close();
}
}
I get the standard xml file output structure like this:
<NewDataSet>
<Customers>...</Customers>
<Customers>...</Customers>
<NewDataSet>`
However I want the structure like this
<Customers>
<Customer>...</Customer>
<Customer>...</Customer>
</Customers>`
How can I achieve this?
Specify the desired names to the dataset and the tables within it.
ExportObject.DataSetName = "Customers";
ExportObject.Tables[0].TableName = "Customer";
A work around is to let WriteXml write however it likes and then do an XSD transform to the format you prefer.
Related
there are some records in the recordlist but when I am calling the following method, it is not writing the data to xml. it is just writing .
I am absolutely new to XML. Please help me.
public void SaveRentalRecords()
{
// create the XmlWriterSettings object
XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;
settings.IndentChars = (" ");
// create the XmlWriter object
XmlWriter xmlOut = XmlWriter.Create(path, settings);
// write the start of the document
xmlOut.WriteStartDocument();
xmlOut.WriteStartElement("RentalRecords");
// write each Product object to the xml file
foreach (RecordList record in Records)
{
xmlOut.WriteStartElement("RentalRecord");
xmlOut.WriteElementString("TenantID", record.TenantID);
xmlOut.WriteElementString("TenantName", record.TenantName);
xmlOut.WriteElementString("PropertyID", record.PropertyID);
xmlOut.WriteElementString("PropertyAddress", record.PropertyAddress);
xmlOut.WriteEndElement();
MessageBox.Show(record.TenantID+record.TenantName+record.PropertyID+record.PropertyAddress);
}
// write the end tag for the root element
xmlOut.WriteEndElement();
// close the XmlWriter object
xmlOut.Close();
}
You can try the below approach :
var result = new XElement("RentalRecords", new XElement("RentalRecord", recs.Select(x => new XElement(x.tenantId.ToString(CultureInfo.InvariantCulture), x.tenantName, x.PropertyId.ToString(CultureInfo.InvariantCulture), x.PropertyName))));
result.Save("RentalRecords.xml");
I have a web service to an SSRS server from which I download and serialize reports to XML in C#, and then later save as .rdl files.
I have the possibility to get the all the Data Source's aswell, with
ReportingService2005 rs = new ReportingService2005();
DataSource dataSource = new DataSource();
DataSourceDefinition dataSourceDefinition = rs.GetDataSourceContents(path);
dataSource.Item = dataSourceDefinition;
I want to save the data source objects as .ds or .rds files but I don't know how. Is there a way I can do this using XML serializing or are there any easier methods?
I had the same issue, I used the XML serialize to serialize the DataSource object here is the code snipet:
DataSource ds = new DataSource();
DataSourceDefinition dsDefinition = rs.GetDataSourceContents(item.Path);
ds.Item = dsDefinition;
sOutFile = string.Format(#"{0}{1}.rds", sOutputDir, item.Name);
if (File.Exists(sOutFile))
File.Delete(sOutFile);
SerializeObject(sOutFile, ds); // serializes the dataSource object and save it
here is the SerializeObject method, it serializes and then saves the file in XML format:
private void SerializeObject(string filename, DataSource d)
{
try
{
XmlSerializer serializer =
new XmlSerializer(typeof(DataSource));
// Create an XmlTextWriter using a FileStream.
Stream fs = new FileStream(filename, FileMode.Create);
XmlWriter writer =
new XmlTextWriter(fs, Encoding.Unicode);
// Serialize using the XmlTextWriter.
serializer.Serialize(writer, d);
writer.Close();
}
catch (Exception e) { MessageBox.Show("inside serializeObject Method "+e.Message); }
}
I hope this helps if someone is stuck with this issue
As kyzen suggested in the comment, I used a combination of some custom code and this post from SO Listing all Data Sources and their Dependencies (reports, items, etc) in SQL Server 2008 R2 to get the result I wanted.
I am seeking a help regarding file saving of XML file using XDocument (NOT XMLDocument).
So I have a xml file that does not have indentation (in fact it is 1 line). When I read this to XDocument using XDocument.Parse (after reading and storing string using StreamReader), the resulting XDocument is indented.
Alright, I thought it will be fine as long as if I can save it back to the file without indentation. However, even though I have
XmlWriterSettings writerSettings = new XmlWriterSettings();
writerSettings.NewLineOnAttributes = false;
writerSettings.NewLineHandling = NewLineHandling.None;
writerSettings.Indent = false;
and pass that in when I create XmlWriter
using (var writer = XmlWriter.Create(u.ToFileSystemPath(), settings))
{
xd.Save(writer);
}
The resulting XML file still has indentation. When I am debugging on Visual studio, I noticed that the writer is a class XmlWellFormedWriter. Does this have something to do with my result? Any help would be appreciated.
Thank you.
SaveOptions are available on Save() as well as ToString().
string xmlstring =
#"<Top>
<First>1</First>
<Second>Dude</Second>
<Third>Now</Third>
</Top>";
XDocument doc = XDocument.Parse(xmlstring);
doc.Save(#"C:\temp\noIndet.xml", SaveOptions.DisableFormatting);
// string noIndent = doc.ToString(SaveOptions.DisableFormatting);
Output:
I would like to perform object serialization to only one branch in an existing XML file. While reading by using:
RiskConfiguration AnObject;
XmlSerializer Xml_Serializer = new XmlSerializer(typeof(RiskConfiguration));
XmlTextReader XmlReader = new XmlTextReader(#"d:\Projects\RiskService\WCFRiskService\Web.config");
XmlReader.ReadToDescendant("RiskConfiguration");
try
{
AnObject = (RiskConfiguration)Xml_Serializer.Deserialize(XmlReader);
AnObject.Databases.Database[0].name = "NewName";
}
finally
{
XmlReader.Close();
}
It is possible, I do not know how to edit the object again performed it can save the file without erasing other existing elements in an XML file. Can anyone help me?
I found a way to display the desired item serialization. How do I go now instead of the paste to the original element in XML?
StringWriter wr = new StringWriter();
XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;
settings.OmitXmlDeclaration = true;
settings.Encoding = System.Text.Encoding.Default;
using (XmlWriter writer = XmlWriter.Create(wr, settings))
{
XmlSerializerNamespaces emptyNamespace = new XmlSerializerNamespaces();
emptyNamespace.Add(String.Empty, String.Empty);
Xml_Serializer.Serialize(writer, AnObject, emptyNamespace);
MessageBox.Show(wr.ToString());
}
First of all, you should stop using new XmlTextReader(). That has been deprecated since .NET 2.0. Use XmlReader.Create() instead.
Second, XML is not a random-access medium. You can't move forward and backwards, writing into the middle of the file. It's a text-based file.
If you need to "modify" the file, then you'll need to write a new version of the file. You could read from the original file, up to the point where you need to deserialize, writing the nodes out to a new version of the file. You could then deserialize from the original file, modify the objects, and serialize out to the new version. You could then continue reading from the original and writing the nodes out to the new version.
I'm trying to create an XML with multiple root elements. I can't change that because that is the way I'm supposed to send the XML to the server. This is the error I get when I try to run the code:
System.InvalidOperationException: This operation would create an incorrectly structured document.
Is there a way to overwrite this error and have it so that it ignores this?
Alright so let me explain this better:
Here is what I have
XmlDocument doc = new XmlDocument();
doc.LoadXml(_application_data);
Now that creates the XML document and I can add a fake root element to it so that it works. However, I need to get rid of that and convert it into a DocumentElement object.
How would I go about doing that?
Specify Fragment when creating XmlWriter as shown here
XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.ConformanceLevel = ConformanceLevel.Fragment;
settings.CloseOutput = false;
// Create the XmlWriter object and write some content.
MemoryStream strm = new MemoryStream();
using (XmlWriter writer = XmlWriter.Create(strm, settings))
{
writer.WriteElementString("orderID", "1-456-ab");
writer.WriteElementString("orderID", "2-36-00a");
writer.Flush();
}
If it has multiple root elements, it's not XML. If it resembles XML in other ways, you could place everything under a root element, then when you send the string to the server, you just combine the serialized child elements of this root element, or as #Austin points out, use an inner XML method if available.
just create an XML with single root then get it's content as XML text.
you are talking about XML fragment anyways, since good xml has only one root.
this is sample to help you started:
var xml = new XmlDocument();
var root = xml.CreateElement("root");
root.AppendChild(xml.CreateElement("a"));
root.AppendChild(xml.CreateElement("b"));
Console.WriteLine(root.InnerXml); // outputs "<a /><b />"