Ok, so im making a program launcher, but the file im trying to run have a random name. Heres my code, it works but when the name changes to something random it will stop working
private void button1_Click(object sender, EventArgs e)
{
Process process = new Process()
{
StartInfo = new ProcessStartInfo(Environment.CurrentDirectory + "/Files/330637421.exe")
{
WindowStyle = ProcessWindowStyle.Normal,
WorkingDirectory = Path.GetDirectoryName(Environment.CurrentDirectory + "/Files/")
}
};
process.Start();
}
Now its working because my file is called 330637421.exe but it will trow an exception because the file will not exist if it changes the name . Btw it is the only exe file on the Files folder. Is there any way to run every exe file on that folder? also keeping the workingdirectory
Here's an example grabbing the first returned file from Directory.GetFiles():
String folder = System.IO.Path.Combine(Environment.CurrentDirectory, "Files");
if (System.IO.Directory.Exists(folder))
{
String executable = System.IO.Directory.GetFiles(folder, "*.exe").FirstOrDefault();
if (executable != null)
{
Process process = new Process()
{
StartInfo = new ProcessStartInfo(executable)
{
WindowStyle = ProcessWindowStyle.Normal,
WorkingDirectory = folder
}
};
process.Start();
}
else
{
MessageBox.Show("No .EXE found in the ../Files Folder!");
}
}
else
{
MessageBox.Show("No ../Files Folder Exists!");
}
You can use GetFiles method to get the file. But you have to be careful if there are multiple files in this path. Then you can use pattern to get the particular file.
You can use the required overloaded method mentioned in the documentation.
I am working with voice records. I need to use an .exe file for convert Wav to .mp3 file. Everything is fine I can execute this exe but I need to do something after when process end with my output .mp3 file. I know my output directory but i cant handle MP3 file before its not created yet. I know maybe I need to use Thread.sleep(); or something like that because I cant catch a file before its not exist.
Here is my code:
string mp3GuidName = Guid.NewGuid().ToString();
var mp3FilePath = WavFilePath.Replace("finalWavFile", mp3GuidName).Replace("wav", "mp3");
var extrasFilePath = HttpContext.Current.Server.MapPath("/").Replace("DevApp.Web", "Extras");
string strArguments = "/c start " + extrasFilePath + "lame.exe --abr 80 -V5 " + WavFilePath + " " + mp3FilePath;
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = strArguments ;
process.StartInfo = startInfo;
process.Start();
var attactment = new Attachment
{
CreatedOn = DateTime.Now,
UpdatedOn = DateTime.Now,
Title = mp3GuidName +".mp3",
Size = _storageProvider.GetFile(mp3FilePath).GetSize(), // here I am trying to get mp3 file but i cant catch it. Because if this wav files size is huge, then convert process is taking time and my mp3 file is not created yet.
FileExtension = _storageProvider.GetFile(mp3FilePath).GetFileType()
};
attactment.MimeType = _storageProvider.GetMimeType(attactment.FileExtension);
attactment.FileUrl = mp3GuidName+".mp3";// file.GetName();
attactment.AttachmentFolderId = folder.Id;
_attachmentRepository.Add(attactment);
I was try to use process.WaitForExit();but I cant solve this problem. I still cant acces to mp3 file.
so how can I catch when the process finish?
Best Regards.
Remove the start command argument from your argument string and you should be able to use process.WaitForExit(); to wait for Lame to finish with encoding:
string strArguments = "/c " + extrasFilePath + "lame.exe --abr 80 -V5 " + WavFilePath + " " + mp3FilePath;
However, you can simplify your code and avoid this dance with cmd.exe altogether by starting lame.exe directly:
string strArguments = "--abr 80 -V5 " + WavFilePath + " " + mp3FilePath;
...
startInfo.FileName = extrasFilePath + "lame.exe";
startInfo.Arguments = strArguments;
...
Below some information about why using the start command argument in your scenario is counterproductive.
Executing console applications such as lame.exe using cmd.exe (or from a console or batch file) normally block cmd.exe (or console/batch file) until the console application exits.
However, using the start command turns this normally blocking execution of a console application into a non-blocking execution. With this argument, the cmd.exe (or console/batch file) will continue execution while the console application is still running. In your particular case it means cmd.exe will exit right after it has started lame.exe (since it has nothing else to execute), effectively sabotaging your attempt to wait for lame.exe to finish.
Edited:
Base on the comments below I have to make it clear that the oroginal solution I recommended does not check if the file is free but it checks only if the file exists!
So I rather recommend the following:
private bool IsBusy(FileInfo file)
{
FileStream stream = null;
try
{
stream = file.Open(FileMode.Open, FileAccess.Read, FileShare.None);
}
catch ()
{
return true;
}
finally
{
if (stream != null)
stream.Close();
}
return false;
}
the usage will be:
while(IsBusy(fileinfo))
{
//just wait
}
ORIGINAL:
You can use a while loop to find out when the file is ready:
while(!File.Exists(mp3FileName))
{
//just wait
}
// add the attachment here
I have a C# GUI allowing a user to select a file and then run this against objdump, outputting the content to the GUI.
However, I am having problems when the user selects a file where the path contains spaces, it causes the command line execution to break.
I had a look around Stackoverflow and there seem to be all these hacks for Windows scripting because paths with spaces aren't easy to solve. However, as I am passing the file name programatically I cannot do this/is there an easier way?
This is my code:
private void button1_Click(object sender, EventArgs e)
{
DialogResult result = openFileDialog1.ShowDialog();
if (result == DialogResult.OK){
dataGridView1.Rows.Clear();
dataGridView1.Refresh();
string filename = openFileDialog1.FileName; //May contain spaces
try
{
var proc = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = "dumpbin.exe",
Arguments = "/DISASM " + filename, // Causing this to fail
UseShellExecute = false,
RedirectStandardOutput = true,
CreateNoWindow = true
}
};
proc.Start();
You need to wrap the filename with double quotes, just like you normally would from command line.
Try this:
Arguments = "/DISASM \"" + filename + "\"",
Try to put quotes around the path
pSInfo.Argument = #"""c:\test cases\testfile.csv""";
or if you prefer
pSInfo.Argument = "\"c:\\test cases\\testfile.csv\"";
Use quotes around the filename:
Arguments = $"/DISASM \"{filename}\"",
Is there any way to run command prompt commands from within a C# application? If so how would I do the following:
copy /b Image1.jpg + Archive.rar Image2.jpg
This basically embeds an RAR file within JPG image. I was just wondering if there was a way to do this automatically in C#.
this is all you have to do run shell commands from C#
string strCmdText;
strCmdText= "/C copy /b Image1.jpg + Archive.rar Image2.jpg";
System.Diagnostics.Process.Start("CMD.exe",strCmdText);
EDIT:
This is to hide the cmd window.
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C copy /b Image1.jpg + Archive.rar Image2.jpg";
process.StartInfo = startInfo;
process.Start();
EDIT 2:
It is important that the argument begins with /C, otherwise it won't work. As #scott-ferguson said: /C carries out the command specified by the string and then terminates.
Tried RameshVel's solution but I could not pass arguments in my console application. If anyone experiences the same problem here is a solution:
using System.Diagnostics;
Process cmd = new Process();
cmd.StartInfo.FileName = "cmd.exe";
cmd.StartInfo.RedirectStandardInput = true;
cmd.StartInfo.RedirectStandardOutput = true;
cmd.StartInfo.CreateNoWindow = true;
cmd.StartInfo.UseShellExecute = false;
cmd.Start();
cmd.StandardInput.WriteLine("echo Oscar");
cmd.StandardInput.Flush();
cmd.StandardInput.Close();
cmd.WaitForExit();
Console.WriteLine(cmd.StandardOutput.ReadToEnd());
var proc1 = new ProcessStartInfo();
string anyCommand;
proc1.UseShellExecute = true;
proc1.WorkingDirectory = #"C:\Windows\System32";
proc1.FileName = #"C:\Windows\System32\cmd.exe";
proc1.Verb = "runas";
proc1.Arguments = "/c "+anyCommand;
proc1.WindowStyle = ProcessWindowStyle.Hidden;
Process.Start(proc1);
None of the above answers helped for some reason, it seems like they sweep errors under the rug and make troubleshooting one's command difficult. So I ended up going with something like this, maybe it will help someone else:
var proc = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = #"C:\Program Files\Microsoft Visual Studio 14.0\Common7\IDE\tf.exe",
Arguments = "checkout AndroidManifest.xml",
UseShellExecute = false,
RedirectStandardOutput = true,
CreateNoWindow = true,
WorkingDirectory = #"C:\MyAndroidApp\"
}
};
proc.Start();
Though technically this doesn't directly answer question posed, it does answer the question of how to do what the original poster wanted to do: combine files. If anything, this is a post to help newbies understand what Instance Hunter and Konstantin are talking about.
This is the method I use to combine files (in this case a jpg and a zip). Note that I create a buffer that gets filled with the content of the zip file (in small chunks rather than in one big read operation), and then the buffer gets written to the back of the jpg file until the end of the zip file is reached:
private void CombineFiles(string jpgFileName, string zipFileName)
{
using (Stream original = new FileStream(jpgFileName, FileMode.Append))
{
using (Stream extra = new FileStream(zipFileName, FileMode.Open, FileAccess.Read))
{
var buffer = new byte[32 * 1024];
int blockSize;
while ((blockSize = extra.Read(buffer, 0, buffer.Length)) > 0)
{
original.Write(buffer, 0, blockSize);
}
}
}
}
if you want to run the command in async mode - and print the results. you can you this class:
public static class ExecuteCmd
{
/// <summary>
/// Executes a shell command synchronously.
/// </summary>
/// <param name="command">string command</param>
/// <returns>string, as output of the command.</returns>
public static void ExecuteCommandSync(object command)
{
try
{
// create the ProcessStartInfo using "cmd" as the program to be run, and "/c " as the parameters.
// Incidentally, /c tells cmd that we want it to execute the command that follows, and then exit.
System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd", "/c " + command);
// The following commands are needed to redirect the standard output.
//This means that it will be redirected to the Process.StandardOutput StreamReader.
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
// Do not create the black window.
procStartInfo.CreateNoWindow = true;
// Now we create a process, assign its ProcessStartInfo and start it
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
// Get the output into a string
string result = proc.StandardOutput.ReadToEnd();
// Display the command output.
Console.WriteLine(result);
}
catch (Exception objException)
{
// Log the exception
Console.WriteLine("ExecuteCommandSync failed" + objException.Message);
}
}
/// <summary>
/// Execute the command Asynchronously.
/// </summary>
/// <param name="command">string command.</param>
public static void ExecuteCommandAsync(string command)
{
try
{
//Asynchronously start the Thread to process the Execute command request.
Thread objThread = new Thread(new ParameterizedThreadStart(ExecuteCommandSync));
//Make the thread as background thread.
objThread.IsBackground = true;
//Set the Priority of the thread.
objThread.Priority = ThreadPriority.AboveNormal;
//Start the thread.
objThread.Start(command);
}
catch (ThreadStartException )
{
// Log the exception
}
catch (ThreadAbortException )
{
// Log the exception
}
catch (Exception )
{
// Log the exception
}
}
}
if you want to keep the cmd window open or want to use it in winform/wpf then use it like this
string strCmdText;
//For Testing
strCmdText= "/K ipconfig";
System.Diagnostics.Process.Start("CMD.exe",strCmdText);
/K
Will keep the cmd window open
Yes, there is (see link in Matt Hamilton's comment), but it would be easier and better to use .NET's IO classes. You can use File.ReadAllBytes to read the files and then File.WriteAllBytes to write the "embedded" version.
with a reference to Microsoft.VisualBasic
Interaction.Shell("copy /b Image1.jpg + Archive.rar Image2.jpg", AppWinStyle.Hide);
This can also be done by P/Invoking the C standard library's system function.
using System.Runtime.InteropServices;
[DllImport("msvcrt.dll")]
public static extern int system(string format);
system("copy Test.txt Test2.txt");
Output:
1 file(s) copied.
Here is little simple and less code version. It will hide the console window too-
System.Diagnostics.Process process = new System.Diagnostics.Process();
process.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
process.StartInfo.FileName = "cmd.exe";
process.StartInfo.Arguments = "/C copy /b Image1.jpg + Archive.rar Image2.jpg";
process.Start();
I have the following method, which I use to run the command prompt commands from C#
In first parameter pass the command you want to run
public static string RunCommand(string arguments, bool readOutput)
{
var output = string.Empty;
try
{
var startInfo = new ProcessStartInfo
{
Verb = "runas",
FileName = "cmd.exe",
Arguments = "/C "+arguments,
WindowStyle = ProcessWindowStyle.Hidden,
UseShellExecute = false,
CreateNoWindow = true,
RedirectStandardOutput = true,
RedirectStandardError = false
};
var proc = Process.Start(startInfo);
if (readOutput)
{
output = proc.StandardOutput.ReadToEnd();
}
proc.WaitForExit(60000);
return output;
}
catch (Exception)
{
return output;
}
}
You can achieve this by using the following method (as mentioned in other answers):
strCmdText = "'/C some command";
Process.Start("CMD.exe", strCmdText);
When I tried the methods listed above I found that my custom command did not work using the syntax of some of the answers above.
I found out more complex commands need to be encapsulated in quotes to work:
string strCmdText;
strCmdText = "'/C cd " + path + " && composer update && composer install -o'";
Process.Start("CMD.exe", strCmdText);
you can use simply write the code in a .bat format extension ,the code of the batch file :
c:/ copy /b Image1.jpg + Archive.rar Image2.jpg
use this c# code :
Process.Start("file_name.bat")
You can use RunProcessAsTask pacakge and run your process async and easily like this:
var processResults = await ProcessEx.RunAsync("git.exe", "pull");
//get process result
foreach (var output in processResults.StandardOutput)
{
Console.WriteLine("Output line: " + output);
}
This may be a bit of a read so im sorry in advance. And this is my tried and tested way of doing this, there may be a simpler way but this is from me throwing code at a wall and seeing what stuck
If it can be done with a batch file then the maybe over complicated work around is have c# write a .bat file and run it. If you want user input you could place the input into a variable and have c# write it into the file. it will take trial and error with this way because its like controlling a puppet with another puppet.
here is an example, In this case the function is for a push button in windows forum app that clears the print queue.
using System.IO;
using System;
public static void ClearPrintQueue()
{
//this is the path the document or in our case batch file will be placed
string docPath =
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
//this is the path process.start usues
string path1 = docPath + "\\Test.bat";
// these are the batch commands
// remember its "", the comma separates the lines
string[] lines =
{
"#echo off",
"net stop spooler",
"del %systemroot%\\System32\\spool\\Printers\\* /Q",
"net start spooler",
//this deletes the file
"del \"%~f0\"" //do not put a comma on the last line
};
//this writes the string to the file
using (StreamWriter outputFile = new StreamWriter(Path.Combine(docPath, "test.bat")))
{
//This writes the file line by line
foreach (string line in lines)
outputFile.WriteLine(line);
}
System.Diagnostics.Process.Start(path1);
}
IF you want user input then you could try something like this.
This is for setting the computer IP as static but asking the user what the IP, gateway, and dns server is.
you will need this for it to work
public static void SetIPStatic()
{
//These open pop up boxes which ask for user input
string STATIC = Microsoft.VisualBasic.Interaction.InputBox("Whats the static IP?", "", "", 100, 100);
string SUBNET = Microsoft.VisualBasic.Interaction.InputBox("Whats the Subnet?(Press enter for default)", "255.255.255.0", "", 100, 100);
string DEFAULTGATEWAY = Microsoft.VisualBasic.Interaction.InputBox("Whats the Default gateway?", "", "", 100, 100);
string DNS = Microsoft.VisualBasic.Interaction.InputBox("Whats the DNS server IP?(Input required, 8.8.4.4 has already been set as secondary)", "", "", 100, 100);
//this is the path the document or in our case batch file will be placed
string docPath =
Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
//this is the path process.start usues
string path1 = docPath + "\\Test.bat";
// these are the batch commands
// remember its "", the comma separates the lines
string[] lines =
{
"SETLOCAL EnableDelayedExpansion",
"SET adapterName=",
"FOR /F \"tokens=* delims=:\" %%a IN ('IPCONFIG ^| FIND /I \"ETHERNET ADAPTER\"') DO (",
"SET adapterName=%%a",
"REM Removes \"Ethernet adapter\" from the front of the adapter name",
"SET adapterName=!adapterName:~17!",
"REM Removes the colon from the end of the adapter name",
"SET adapterName=!adapterName:~0,-1!",
//the variables that were set before are used here
"netsh interface ipv4 set address name=\"!adapterName!\" static " + STATIC + " " + STATIC + " " + DEFAULTGATEWAY,
"netsh interface ipv4 set dns name=\"!adapterName!\" static " + DNS + " primary",
"netsh interface ipv4 add dns name=\"!adapterName!\" 8.8.4.4 index=2",
")",
"ipconfig /flushdns",
"ipconfig /registerdns",
":EOF",
"DEL \"%~f0\"",
""
};
//this writes the string to the file
using (StreamWriter outputFile = new StreamWriter(Path.Combine(docPath, "test.bat")))
{
//This writes the file line by line
foreach (string line in lines)
outputFile.WriteLine(line);
}
System.Diagnostics.Process.Start(path1);
}
Like I said. It may be a little overcomplicated but it never fails unless I write the batch commands wrong.