Develop Reference

using OfficeOpenXml - Print cell.Value as Number

I am having some Cell values printed as Taxt (String) and i want them to be printed as Number, as this values are used in a Sum Formula.
The values came from an operation that i do with a library (OSISoft AF SDK) and are printed in my Excel as Strings.
ExcelRange cell = excelSheet.Cells[startRow, startCol + i + y];
cell.Value = valueAsString;
Just in case someone is using AF SDK as me getting data from PI Systems my code is actually something like this...
//point is a PIPoint.
cell.Value = point.RecordedValue(startDate.LocalTime.AddHours(i), OSIsoft.AF.Data.AFRetrievalMode.AtOrBefore);

Just parsing the value to double (or int) will be okey.
cell.Value = Double.Parse(cell.Value.ToString());
You can also set a Format to the number, but it is not necessary:
cell.Style.Numberformat.Format = "0.00";
All formats available:
https://stackoverflow.com/a/40214134/6574873

EPPlus number format

I have an Excel sheet generated with Epplus, I am experiencing some pain points and I wish to be directed by someone who have solved a similar challenge.
I need to apply number formatting to a double value and I want to present it in Excel like this.
8 → 8.0
12 → 12.0
14.54 → 14.5
0 → 0.0
Here is my code
ws.Cells[row, col].Style.Numberformat.Format = "##0.0";
The final Excel file always append E+0 to the end of this format and therefore presents the final values like this instead.
8 → 8.0E+0
12 → 12.0E+0
14.54 → 14.5E+0
0 → 000.0E+0
When I check in the format cells of the generated Excel sheet, I see that my format appears as ##0.0E+2 instead of ##0.0 that I applied.
What may be wrong?

Here are some number format options for EPPlus:
//integer (not really needed unless you need to round numbers, Excel will use default cell properties)
ws.Cells["A1:A25"].Style.Numberformat.Format = "0";
//integer without displaying the number 0 in the cell
ws.Cells["A1:A25"].Style.Numberformat.Format = "#";
//number with 1 decimal place
ws.Cells["A1:A25"].Style.Numberformat.Format = "0.0";
//number with 2 decimal places
ws.Cells["A1:A25"].Style.Numberformat.Format = "0.00";
//number with 2 decimal places and thousand separator
ws.Cells["A1:A25"].Style.Numberformat.Format = "#,##0.00";
//number with 2 decimal places and thousand separator and money symbol
ws.Cells["A1:A25"].Style.Numberformat.Format = "€#,##0.00";
//percentage (1 = 100%, 0.01 = 1%)
ws.Cells["A1:A25"].Style.Numberformat.Format = "0%";
//accounting number format
ws.Cells["A1:A25"].Style.Numberformat.Format = "_-$* #,##0.00_-;-$* #,##0.00_-;_-$* \"-\"??_-;_-#_-";
Don't change the decimal and thousand separators to your own
localization. Excel will do that for you.
By request some DateTime formatting options.
//default DateTime pattern
worksheet.Cells["A1:A25"].Style.Numberformat.Format = DateTimeFormatInfo.CurrentInfo.ShortDatePattern;
//custom DateTime pattern
worksheet.Cells["A1:A25"].Style.Numberformat.Format = "dd-MM-yyyy HH:mm";

Addition to Accepted Answer, because value Accept Object you must pass Number to Value For Example if your input is in string :
var input = "5";
ws.Cells["A1:A25"].Value = double.Parse(input);

Another addition to the accepted answer: you can use nullable values and the formatting all looks good BUT it ends up being a string in Excel and you can't SUM, AVG etc.
So make sure you use the actual Value of the nullable.

And if you want to format a specific column like column "B" to number format you can do it this way-
using (var package = new ExcelPackage())
{
var worksheet = package.Workbook.Worksheets.Add("SHEET1");
worksheet.Cells["A1"].LoadFromDataTable(dataTable, PrintHeaders: true);
for (var col = 1; col < dataTable.Columns.Count + 1; col++)
{
if (col == 2)//col number 2 is equivalent to column B
{
worksheet.Column(col).Style.Numberformat.Format = "#";//apply the number formatting you need
}
worksheet.Column(col).AutoFit();
}
return File(package.GetAsByteArray(), XlsxContentType, "report.xlsx");//downloads file
}

I solved it as follows, so I just load the model and change as per my model if it is int ordatetime
var li = typeof(Model)
.GetProperties()
.ToArray();
using (var package = new ExcelPackage(stream))
{
var workSheet = package.Workbook.Worksheets.Add("Sheet1");
var i = 0;
foreach (var c in li)
{
i++;
if(c.PropertyType.Name == typeof(DateTime).Name || c.PropertyType.Name == typeof(DateTime?).Name)
workSheet.Column(i).Style.Numberformat.Format = DateTimeFormatInfo.CurrentInfo.ShortDatePattern; ;
if (c.PropertyType.Name == typeof(int).Name || c.PropertyType.Name == typeof(int?).Name)
workSheet.Column(i).Style.Numberformat.Format = "0";
}
}

Office Open XML SDK Spreadsheet how to display currency symbol in front of number?

As you've read in the title, I've been looking for a way to format a spreadsheet cell with currency format. Using the code below I do get my currency format but the currency symbol is displayed after the numbers.
// currency format
stylesheet.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.CellFormats>().InsertAt<DocumentFormat.OpenXml.Spreadsheet.CellFormat>(
new DocumentFormat.OpenXml.Spreadsheet.CellFormat()
{
NumberFormatId = 164,
ApplyNumberFormat = true
},
8);
Does anyone know the NumberFormatId for currency format that display currency symbol in the front?

It turns out I need to add basic style to my spreadsheet. The code below adds basic style for currency.
// Currency
stylesheet.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.NumberingFormats>().InsertAt<DocumentFormat.OpenXml.Spreadsheet.NumberingFormat>(
new DocumentFormat.OpenXml.Spreadsheet.NumberingFormat()
{
NumberFormatId = 164,
FormatCode = "\"" + System.Globalization.CultureInfo.CurrentUICulture.NumberFormat.CurrencySymbol + "\"\\ " + "#,##0.00"
},0);
Thanks #Vadim for replying.

I tried to improve above suggestion because I tried same and didn't get $ sign with negative value. I applied following changes and fixed the $ sign issue with negative values.
stylesheet.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.NumberingFormats>().InsertAt<DocumentFormat.OpenXml.Spreadsheet.NumberingFormat>(
new DocumentFormat.OpenXml.Spreadsheet.NumberingFormat()
{
NumberFormatId = 164,
FormatCode = "\"" + System.Globalization.CultureInfo.CurrentUICulture.NumberFormat.CurrencySymbol + "\"\\ " + "#,##0.00;" + "\"(" + System.Globalization.CultureInfo.CurrentUICulture.NumberFormat.CurrencySymbol + "\"\\ " + "#,##.00)[Red];0.00"
}, 0);
Output : for positive values $ 1.23
for negative values ($ 1.23) { font color is read)

How about changing the text direction of the cell? Worked for me.

Issue with data table Select statement

The following VB line, where _DSversionInfo is a DataSet, returns no rows:
_DSversionInfo.Tables("VersionInfo").Select("FileID=88")
but inspection shows that the table contains rows with FileID's of 92, 93, 94, 90, 88, 89, 215, 216. The table columns are all of type string.
Further investigation showed that using the ID of 88, 215 and 216 will only return rows if the number is quoted.
ie _DSversionInfo.Tables("VersionInfo").Select("FileID='88'")
All other rows work regardless of whether the number is quoted or not.
Anyone got an explanation of why this would happen for some numbers but not others? I understand that the numbers should be quoted just not why some work and others don't?
I discovered this in some VB.NET code but (despite my initial finger pointing) don't think it is VB.NET specific.

According to the MSDN documentation on building expressions, strings should always be quoted. Failing to do so produces some bizarro unpredictable behavior... You should quote your number strings to get predictable and proper behavior like the documentation says.
I've encounted what you're describing in the past, and kinda tried to figure it out - here, pop open your favorite .NET editor and try the following:
Create a DataTable, and into a string column 'Stuff' of that DataSet, insert rows in the following order: "6", "74", "710", and Select with the filter expression "Stuff = 710". You will get 1 row back. Now, change the first row into any number greater than 7 - suddenly, you get 0 rows back.
As long as the numbers are ordered in proper descending order using string ordering logic (i.e., 7 comes after 599) the unquoted query appears to work.
My guess is that this is a limitation of how DataSet filter expressions are parsed, and it wasn't meant to work this way...
The Code:
// Unquoted filter string bizzareness.
var table = new DataTable();
table.Columns.Add(new DataColumn("NumbersAsString", typeof(String)));
var row1 = table.NewRow(); row1["NumbersAsString"] = "9"; table.Rows.Add(row1); // Change to '66
var row2 = table.NewRow(); row2["NumbersAsString"] = "74"; table.Rows.Add(row2);
var row4 = table.NewRow(); row4["NumbersAsString"] = "90"; table.Rows.Add(row4);
var row3 = table.NewRow(); row3["NumbersAsString"] = "710"; table.Rows.Add(row3);
var results = table.Select("NumbersAsString = 710"); // Returns 0 rows.
var results2 = table.Select("NumbersAsString = 74"); // Throws exception "Min (1) must be less than or equal to max (-1) in a Range object." at System.Data.Select.GetBinaryFilteredRecords()
Conclusion: Based on the exception text in that last case, there appears to be some wierd casting going on inside filter expressions that is not guaranteed to be safe. Explicitely putting single quotes around the value for which you're querying avoids this problem by letting .NET know that this is a literal.

DataTable builds an index on the columns to make Select() queries fast. That index is sorted by value, then it uses a binary search to select the range of records that matches the query expression.
So the records will be sorted like this 215,216,88,89,90,92,93,94. A binary search is done treating them as integer (as per our filter expression) cannot locate certain records because, it is designed to only search properly sorted collections.
It indexes the data as string and Binary search searches as number. See the below explanation.
string[] strArr = new string[] { "115", "118", "66", "77", "80", "81", "82" };
int[] intArr = new int[] { 215, 216, 88, 89, 90, 92, 93, 94 };
int i88 = Array.BinarySearch(intArr, 88); //returns -ve index
int i89 = Array.BinarySearch(intArr, 89); //returns +ve index
This should be a bug in the framework.

this error usually comes due to invalid data table column type in which you are going to search
i got this error when i was using colConsultDate instead of Convert(colConsultDate, 'System.DateTime')
because colConsultDate was a data table column of type string which i must have to convert into System.DateTime therefor your search query should be like
string query = "Convert(colConsultDate, 'System.DateTime') >= #" + sdateDevFrom.ToString("MM/dd/yy") + "# AND Convert(colConsultDate, 'System.DateTime') <= #" + sdateDevTo.ToString("MM/dd/yy") + "#";
DataRow[] dr = yourDataTable.Select(query);
if (dr.Length > 0)
{
nextDataTabel = dr.CopyToDataTable();
}

#Val Akkapeddi just wanna add things to your answer.
if you do something like this it would be benefited specially when you have to use comparison operators. because you put quotes around 74 it will be treated as string. please see yourself by actually writing code. Comparison operators
(decimal is just for reference you can add your desired datatype instead.)
var results2 = table.Select("Convert(NumbersAsString , 'System.Decimal') = 74.0")

Format a string into columns

Is there a cool way to take something like this:
Customer Name - City, State - ID
Bob Whiley - Howesville, TN - 322
Marley Winchester - Old Towne, CA - 5653
and format it to something like this:
Customer Name - City, State - ID
Bob Whiley - Howesville, TN - 322
Marley Winchester - Old Towne, CA - 5653
Using string format commands?
I am not too hung up on what to do if one is very long. For example this would be ok by me:
Customer Name - City, State - ID
Bob Whiley - Howesville, TN - 322
Marley Winchester - Old Towne, CA - 5653
Super Town person - Long Town Name, WA- 45648
To provide some context. I have a drop down box that shows info very similar to this. Right now my code to create the item in the drop down looks like this:
public partial class CustomerDataContract
{
public string DropDownDisplay
{
get
{
return Name + " - " + City + ", " + State + " - " + ID;
}
}
}
I am looking for a way to format this better. Any ideas?
This is what I ended up with:
HttpContext.Current.Server.HtmlDecode(
String.Format("{0,-27} - {1,-15}, {2, 2} - {3,5}",
Name, City, State, ID)
.Replace(" ", " "));
The HtmlDecode changes the to a space that can withstand the space removing formatting of the dropdown list.

You can specify the number of columns occupied by the text as well as alignment using Console.WriteLine or using String.Format:
// Prints "--123 --"
Console.WriteLine("--{0,-10}--", 123);
// Prints "-- 123--"
Console.WriteLine("--{0,10}--", 123);
The number specifies the number of columns you want to use and the sign specifies alignment (- for left alignment, + for right alignment). So, if you know the number of columns available, you could write for example something like this:
public string DropDownDisplay {
get {
return String.Format("{0,-10} - {1,-10}, {2, 10} - {3,5}"),
Name, City, State, ID);
}
}
If you'd like to calculate the number of columns based on the entire list (e.g. the longest name), then you'll need to get that number in advance and pass it as a parameter to your DropDownDisplay - there is no way to do this automatically.

In addition to Tomas's answer I just want to point out that string interpolation can be used in C# 6 or newer.
// with string format
var columnHeaders1 = string.Format($"|{0,-30}|{1,-4}|{2,-15}|{3,-30}|{4,-30}|{5,-30}|{6,-30}", "ColumnA", "ColumnB", "ColumnC", "ColumnD", "ColumnE", "ColumnF", "ColumnG");
// with string interpolation
var columnHeaders2 = $"|{"ColumnA",-30}|{"ColumnB",-4}|{"ColumnC",-15}|{"ColumnD",-30}|{"ColumnE",-30}|{"ColumnF",-30}|{"ColumnG",-30}";

I am unable to add a comment above, but in the accepted answer it was stated:
If you'd like to calculate the number of columns based on the entire list (e.g. the longest name), then you'll need to get that number in advance and pass it as a parameter to your DropDownDisplay - there is no way to do this automatically.
This can in fact be done programmatically at runtime by creating the format string 'on the fly':
string p0 = "first";
string p1 = "separated by alignment value x";
int x = n * 10; // calculate the alignment x as needed
// now use x to give something like: {0,-20}, {1}
string fmt = "{0,-" + x + "},{1}"; // or whatever formatting expression you want
// then use the fmt string
string str = string.Format(fmt, p0, p1)
// with n = 2 this would give us
"first ,separated by alignment value x"