I work on a project in C# which requires to use arabic numbers, but then it must store as integer in database, I need a solution to convert arabic numbers into int in C#.
Any solution or help please?
thanks in advance
From comments:
I have arabic numbers like ١،٢،٣،٤... and must convert to 1,2,3, or ٢٣٤ convert to 234
Updated: You can use StringBuilder for memory optimization.
private static string ToEnglishNumbers(string input)
{
StringBuilder sbEnglishNumbers = new StringBuilder(string.Empty);
for (int i = 0; i < input.Length; i++)
{
if (char.IsDigit(input[i]))
{
sbEnglishNumbers.Append(char.GetNumericValue(input, i));
}
else
{
sbEnglishNumbers.Append(input[i].ToString());
}
}
return sbEnglishNumbers.ToString();
}
Original Answer: use this Method
private string toEnglishNumber(string input)
{
string EnglishNumbers = "";
for (int i = 0; i < input.Length; i++)
{
if (Char.IsDigit(input[i]))
{
EnglishNumbers += char.GetNumericValue(input, i);
}
else
{
EnglishNumbers += input[i].ToString();
}
}
return EnglishNumbers;
}
Unfortunately it is not yet possible to parse the complete string representation by passing in an appropriate IFormatProvider(maybe in the upcoming versions). However, the char type has a GetNumericValue method which converts any numeric Unicode character to a double. For example:
double two = char.GetNumericValue('٢');
Console.WriteLine(two); // prints 2
You could use it to convert one digit at a time.
Arabic digits like ١،٢،٣،٤ in unicode are encoded as characters in the range 1632 to 1641. Subtract the unicode for arabic zero (1632) from the unicode value of each arabic digit character to get their digital values. Multiply each digital value with its place value and sum the results to get the integer.
Alternatively use Regex.Replace to convert the string with Arabic digits into a string with decimal digits, then use Int.Parse to convert the result into an integer.
A simple way to convert Arabic numbers into integer
string EnglishNumbers="";
for (int i = 0; i < arabicnumbers.Length; i++)
{
EnglishNumbers += char.GetNumericValue(arabicnumbers, i);
}
int convertednumber=Convert.ToInt32(EnglishNumbers);
This is my solution :
public static string arabicNumToEnglish(string input)
{
String[] map={"٠","١","٢","٣","٤","٥","٦","٧","٨","٩"};
for (int i = 0; i <= 9; i++)
{
input=input.Replace(map[i],i.ToString());
}
return input;
}
to get the value of a digit, substract the zero character from it, e.g in normal numeric, '1'-'0' = 1, '2'-'0' = 2. etc.
For multidigit number you can use something like this
result =0;
foreach(char digit in number)
{
result *= 10; //shift the digit, multiply by ten for each shift
result += (digit - '0)'; //add the int value of the current digit.
}
just replace the '0' with the arabic zero if your number uses Arabic character. This works for any numeric symbols, as long as 0-9 in that symbol system are encoded consecutively.
I know this question is a bit old, however I faced similar case in one of my projects and passed by this question and decided to share my solution which did work perfectly for me, and hope it will serve others the same.
private string ConvertToWesternArbicNumerals(string input)
{
var result = new StringBuilder(input.Length);
foreach (char c in input.ToCharArray())
{
//Check if the characters is recognized as UNICODE numeric value if yes
if (char.IsNumber(c))
{
// using char.GetNumericValue() convert numeric Unicode to a double-precision
// floating point number (returns the numeric value of the passed char)
// apend to final string holder
result.Append(char.GetNumericValue(c));
}
else
{
// apend non numeric chars to recreate the orignal string with the converted numbers
result.Append(c);
}
}
return result.ToString();
}
now you can simply call the function to return the western Arabic numerals.
try this extension:
public static class Extension
{
public static string ToEnglishNumbers(this string s)
{
return s.Replace("۰", "0").Replace("۱", "1").Replace("۲", "2").Replace("۳", "3").Replace("۴", "4")
.Replace("۵", "5").Replace("۶", "6").Replace("۷", "7").Replace("۸", "8").Replace("۹", "9");
}
public static int ToNumber(this string s)
{
if (int.TryParse(s.ToEnglishNumbers(), out var result))
{
return result;
}
return -1;
}
public static string ToArabicNumbers(this string s)
{
return s.Replace("0", "۰").Replace("1", "۱").Replace("2", "۲").Replace("3", "۳").Replace("4", "۴")
.Replace("5", "۵").Replace("6", "۶").Replace("7", "۷").Replace("8", "۸").Replace("9", "۹");
}
}
Related
lets say I have a string that contains binary, like this:
string test = "01001010";
so I want to do something like this:
someFunc(test);
and this function would return exactly what the test variable says, but in byte form instead of string.
example:
using System;
class Program
{
static void Main()
{
Console.WriteLine(Convert.ToChar(someFunc(Console.ReadLine())));
}
}
this program prompts you to enter a byte using Console.ReadLine (which returns a string), turns it into a byte, then turns it into a char.
How could I do this?
You could write it in this way:
using System;
class Program
{
static byte someFunc(string text)
{
byte t = 0;
for (int i = 0; i < 8; i++)
t = (byte)(t * 2 + (text[i] - '0'));
return t;
}
static void Main()
{
Console.WriteLine(Convert.ToChar(someFunc(Console.ReadLine())));
}
}
But it would be useful before using someFunc() to check if string is not okey (for example, that there would be shown an error message if input is "10102010")
Use Convert.ToInt32(string, int) where string is the string you want to convert, and int is the base of the number system you want to convert from, in your case base 2 or binary. Or if you really desperately need it to be a byte, then you can use Convert.ToByte(string, int). Like so:
using System;
class Program
{
public static void Main()
{
var input = Console.ReadLine(); // 01001010
var number = Convert.ToInt32(input, 2);
Console.WriteLine(number); // prints '74'
}
}
Be warned that Convert.ToXyz() will throw an exception of type FormatException if the given input string contains character that are illegal for the given base. For base 2 that would be any character that's not a 0 or 1, you might want to catch such exceptions, or check that all characters in the input string are either a '0' or '1' beforehand
Edited:
Take char after char, add it to result byte and multiply by 2 to convert from binary to decimal (except for the last char, it should be just added).
Then return byte as char.
public static char someFunc(string bs) {
byte result = 0;
for (int i = 0; i < bs.Length - 1; i++)
{
if (bs[i].Equals('1'))
{
result += 1;
}
result *= 2;
}
if (bs[bs.Length - 1].Equals('1'))
{
result++;
}
return (char) result;
}
returns J for "01001010"
Hi this is one implementation which i use in java, but this will ork for c# as well. My be you need some syntax changes.
static int someFunc(String s){
int binary = 0x00;
for(int i=0;i<8;i++){
if(s.charAt(i) == '1')
binary =(binary<<1) | 0x01;
else if(s.charAt(i) == '0')
binary =(binary<<1) | 0x00;
}
return binary;
}
I have a large float that I want to convert into a string with commas without rounding.
Here is what I have:
String.Format("{0:#,###}", val);
This turns 17154177 into 17,154,180
I would like to keep the commas but not round at the end using c#.
This may be what you're looking for
using System;
class MainClass {
public static void Main (string[] args) {
float original = 17154177;
// 1. Convert the number to a string
string value = original.ToString("R");
// 2. Reverse the string
string reversed = Reverse(value);
// 3. Add the comma on each third number, backwards
string formatted = "";
for(int i = 0; i < reversed.Length; i++) {
if ((i+1) % 3 == 0) {
formatted += reversed[i] + ",";
} else {
formatted += reversed[i];
}
}
// 4. Reverse it back to the original order
formatted = Reverse(formatted);
Console.WriteLine (formatted);
}
/* Reverses a string */
public static string Reverse(string text)
{
char[] cArray = text.ToCharArray();
string reverse = String.Empty;
for (int i = cArray.Length - 1; i > -1; i--)
{
reverse += cArray[i];
}
return reverse;
}
}
I got the reverse method from this question.
Change your data type to decimal (28-29 significant digits) to have higher precision compared to float (7 digits).
Or you can change it to var. It will let the compiler figure out the best data type to use.
var number = 17154177;
Console.WriteLine(String.Format("{0:#,###}", number));
See this fiddler link, working code
Below is my string in C# which I am converting it to Character array & in need to get the ASCII value of each character in the string.
static void Main(string[] args)
{
string s = "Test";
var arr = s.ToCharArray();
foreach(var a in arr)
{
var n = Encoding.ASCII.GetByteCount(a.ToString());
Console.WriteLine(a);
Console.WriteLine(n);
}
}
This outputs as
T
1
e
1
s
1
t
1
On googling I got number of links but none of them suffice my need.
How to get ASCII value of string in C#
https://www.codeproject.com/Questions/516802/ConvertingpluscharsplustoplusASCIIplusinplusC
I am in need to get the ASCII value of each character in string.???
Any help/suggestion highly appreciated.
A string can be directly enumerated to a IEnumerable<char>. And each char can be casted to a integer to see its UNICODE "value" (code point). UTF-16 maps the 128 characters of ASCII (0-127) to the UNICODE code points 0-127 (see for example https://en.wikipedia.org/wiki/Code_point), so you can directly print this number.
string s = "Test";
foreach (char a in s)
{
if (a > 127)
{
throw new Exception(string.Format(#"{0} (code \u{1:X04}) is not ASCII!", a, (int)a));
}
Console.WriteLine("{0}: {1}", a, (int)a);
}
GetByteCount will return the count of bytes used, so for each character it will be 1 byte.
Try GetBytes
static void Main(string[] args)
{
string s = "Test";
var n = ASCIIEncoding.ASCII.GetBytes(s);
for (int i = 0; i < s.Length; i++)
{
Console.WriteLine($"Char {s[i]} - byte {n[i]}");
}
}
Every character is represented in the ASCII table with a value between 0 and 127. Converting the chars to an Integer you will be able to get the ASCII value.
static void Main(string[] args)
{
string s = "Test";
for (int i = 0; i < s.Length; i++)
{
//Convert one by one every leter from the string in ASCII value.
int value = s[i];
Console.WriteLine(value);
}
}
You're asking for the byte count when you should be asking for the bytes themselves. Use Encoding.ASCII.GetBytes instead of Encoding.ASCII.GetByteCount. Like in this answer: https://stackoverflow.com/a/400777/3129333
Console.WriteLine(a);
Console.WriteLine(((int)a).ToString("X"));
You need to convert in int and then in hex.
GetByteCount will return the count of bytes used, so for each character it will be 1.
You can read also: Need to convert string/char to ascii values
Is there a way I could encode a long number (e.g. 12349874529768521) as lower-case letters AND numbers for the purposes of reducing its length? The idea is that a user might have a long number on a piece of paper.
It seems to me that if there are more symbols available, that the resulting number could be made shorter. So I'm looking for something like hexadecimal but using the larger symbol space of A-Z instead of just A-F.
This would be in C# (if it matters)
Base32 encoding is designed to produce an unambiguous, compact, human-readable (and non-obscene!) representation. From Wikipedia:
Base32 has a number of advantages over Base64:
The resulting character set is all one case, which can often be beneficial when using a case-insensitive filesystem, spoken language, or human memory.
The
result can be used as a file name because it can not possibly contain the '/' symbol, which is the Unix path separator.
The alphabet can be selected to avoid similar-looking pairs of different symbols, so the strings can be accurately transcribed by hand. (For example, the RFC 4648 symbol set omits the digits for one, eight and zero, since they could be confused with the letters 'I', 'B', and 'O'.)
A result excluding padding can be included in a URL without encoding any characters.
Base32 also has advantages over hexadecimal/Base16: Base32
representation takes roughly 20% less space. (1000 bits takes 200
characters, compared to 250 for Base16)
Douglas Crockford's original article on Base32 encoding is also well worth a read.
EDIT: here's a bit of C# that'll do base-N encoding of integers:
class Program {
private const string BINARY = "01";
private const string DECIMAL = "0123456789";
private const string HEX = "0123456789abcdef";
private const string BASE32 = "0123456789abcdefghjkmnpqrstvwxyz";
static string EncodeInt32(string alphabet, int value) {
var sb = new StringBuilder();
while (value > 0) {
sb.Insert(0, alphabet[value % alphabet.Length]);
value = value / alphabet.Length;
}
return sb.ToString();
}
static int DecodeInt32(string alphabet, string value) {
int result = 0;
int b = alphabet.Length;
int pow = 0;
for (var i = value.Length-1; i >= 0; i--) {
result += (int)(Math.Pow(b, pow++)) * alphabet.IndexOf(value[i]);
}
return (result);
}
static void Main(string[] args) {
for (var i = 0; i < 1234567890; i += 1234567) {
Console.WriteLine("{0} {1} {2}", i, EncodeInt32(BASE32, i), DecodeInt32(BASE32, EncodeInt32(BASE32, i)));
}
Console.ReadKey(false);
}
}
Example output showing typical reduction in string length:
1227159598 14j9y1e 1227159598
1228394165 14kfknn 1228394165
1229628732 14mn99w 1229628732
1230863299 14ntyy3 1230863299
1232097866 14q0mja 1232097866
1233332433 14r6a6h 1233332433
1234567000 14sbztr 1234567000
How about a BaseN Method to encode/decode your long into a string with characters you defined on your own
public static class BaseN
{
private const string CharList = "0123456789abcdefghijklmnopqrstuvwxyz";
public static String Encode(long input)
{
if (input < 0) throw new ArgumentOutOfRangeException("input", input, "input cannot be negative");
var result = new System.Collections.Generic.Stack<char>();
while (input != 0)
{
result.Push(CharList[(int)(input % CharList.Length)]);
input /= CharList.Length;
}
return new string(result.ToArray());
}
public static long Decode(string input)
{
long result = 0, pos = 0;
foreach (char c in input.Reverse())
{
result += CharList.IndexOf(c) * (long)Math.Pow(CharList.Length, pos);
pos++;
}
return result;
}
}
Usage:
long number = 12349874529768521;
string result = BaseN.Encode(number);
Sample:
https://dotnetfiddle.net/odwFlk
Here's a similar approach to the others, using a Base-N conversion:
using System;
using System.Text;
namespace ConsoleApp3
{
class Program
{
static void Main()
{
long n = 12349874529768521;
string baseChars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz##";
var encoded = AsBaseN(n, baseChars.ToCharArray());
Console.WriteLine(encoded); // Prints "9HXNyK2uh"
long decoded = AsLong(encoded, baseChars.ToCharArray());
Console.WriteLine(decoded); // Prints "12349874529768521"
}
public static string AsBaseN(long value, char[] baseChars)
{
var result = new StringBuilder();
int targetBase = baseChars.Length;
do
{
result.Append(baseChars[value % targetBase]);
value /= targetBase;
}
while (value > 0);
return result.ToString();
}
public static long AsLong(string number, char[] baseChars)
{
long result = 0;
int numberBase = baseChars.Length;
long multiplier = 1;
foreach (char c in number)
{
result += multiplier * Array.IndexOf(baseChars, c);
multiplier *= numberBase;
}
return result;
}
}
}
If you want a different set of allowable characters, just change baseChars as appropriate. For example, if you just want 0-9 and A-Z:
string baseChars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
This gives a result of T3OPA1YNLD3 (base 36) instead of 9HXNyK2uh (base 64).
I presume you mean you want to represent the number with fewer characters.
Base 36 will do this (0-9, a-z).
You can use a base 36 encoder.
Base36 is a binary-to-text encoding scheme that represents binary data in an ASCII string format by translating it into a radix-36 representation. The choice of 36 is convenient in that the digits can be represented using the Arabic numerals 0–9 and the Latin letters A–Z1 (the ISO basic Latin alphabet).
Here's an example of one, but any should work: https://github.com/thewindev/csharpbase36
Example Usage
// Encoding
Base36.Encode(10); // returns "A"
Base36.Encode(10000); // returns "7PS"
// Decoding
Base36.Decode("Z"); // returns 35L
Base36.Decode("10"); // returns 36L
Base36.Decode("7PS"); // returns 10000L
By default uppercase letters are used. If you really wanted to lowercase then a simple string.ToLowerInvarient() can change that.
However, uppercase is usually easier to read, which is why it's used by default, so you might want to consider using uppercase rather than lowercase.
You could look to Base64 encoding. It uses 0-9, A-Z, a-z, + and / characters. Or Base36, if you're interested only in 0-9 and A-Z.
How can i convert from example "1.234.567.890 VNĐ" or any string not in a correct number format.
output: 1234567890
I try: int.Parse, convert.ToInt32 or int.tryParse, double,.... But not working.
If all you want is the integer numbers that are contained within a string, you can just loop through the string and take all numbers.
string yourString = "1.234.567.890 VNĐ";
string tmpString = String.Empty;
for (int i = 0; i < yourString.Length; i++)
{
if (char.IsDigit(yourString, i))
{
tmpString += yourString[i];
}
}
int finalInt = int.Parse(tmpString);
char.IsDigit(string, int) (see documentation) checks if the char at position i in the string is a digit (not only 0..9, but also other numbers). If that's the case, add it to your string. At the end, you have all your numbers and can cast them to int.