Develop Reference

How can I save a PictureBox graphics object to a Stream? [duplicate]

i wanna save a picture that loaded in a picturebox to stream .when i save in png format it work properly but when i want save it in other formats i get
A Generic error occured in GDI + exception
its my code:
Image Img = pictureBox1.Image;
byte[] inputImage = new byte[Img.Width * Img.Height];
System.IO.MemoryStream ms = new System.IO.MemoryStream();
ms.Read(inputImage, 0, Img.Width * Img.Height);
if (System.Drawing.Imaging.ImageFormat.Jpeg.Equals(Img.RawFormat))
{
pictureBox1.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg);
}
else if (System.Drawing.Imaging.ImageFormat.Gif.Equals(Img.RawFormat))
{
ms.Seek(0, SeekOrigin.Begin);
pictureBox1.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Gif);
}
else if (System.Drawing.Imaging.ImageFormat.Png.Equals(Img.RawFormat))
{
pictureBox1.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Png);
}
else if (System.Drawing.Imaging.ImageFormat.Bmp.Equals(Img.RawFormat))
{
pictureBox1.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
}

Try this method:
public Stream ImageToStream(Image image, System.Drawing.Imaging.ImageFormat format)
{
MemoryStream ms = new MemoryStream();
image.Save(ms, format);
return ms;
}
and use it:
using(Stream stream = ImageToStream(pictureBox1.Image,
System.Drawing.Imaging.ImageFormat.Gif))
{
...
}

C# : MemoryStream problems in sending and receiving image bytes

I have a problem with memory-stream
I'm making a rat program and trying to send an image but when I save it's bytes to a memory-stream using png format then send it. I just receive a small part of it and when I use bmp it gives me an error (Parameter is not valid) and when I use jpeg sometimes I receive the image missing some parts so please can anyone help me?
Server Send Code : ( this code should send PC name and an image )
string PC = Environment.MachineName + "/" + Environment.UserName+ count;
int Width = Screen.PrimaryScreen.Bounds.Width;
int Height = Screen.PrimaryScreen.Bounds.Height;
Bitmap ScreenShot = new Bitmap(Width, Height);
Graphics ScreenShotGraphics = Graphics.FromImage(ScreenShot);
ScreenShotGraphics.CopyFromScreen(0, 0, 0, 0, new Size(Width, Height), CopyPixelOperation.SourceCopy);
MemoryStream MemoryStream = new MemoryStream();
ScreenShot.Save(MemoryStream, System.Drawing.Imaging.ImageFormat.Bmp);
byte[] ScreenShotToByte = MemoryStream.ToArray();
byte[] Image = ScreenShotToByte;
MemoryStream CollectMemoryStream = new MemoryStream();
CollectMemoryStream.Write(StringToByteArray("1"), 0, 1);
CollectMemoryStream.Write(StringToByteArray(SplitChar), 0, SplitChar.Length);
CollectMemoryStream.Write(StringToByteArray(PC), 0, PC.Length);
CollectMemoryStream.Write(StringToByteArray(SplitChar), 0, SplitChar.Length);
CollectMemoryStream.Write(Image, 0, Image.Length);
Client.Client.Send(CollectMemoryStream.ToArray(), 0, CollectMemoryStream.ToArray().Length, SocketFlags.None);
Client receive Code : ( this Code should receive the PC name and the image )
SplitText is a string[] holds the order and the PC name and the image converted to string from byte[] and got split
string PCName = SplitText[1];
this.Invoke((Action)(() => { int NewClientNumber = listBox1.Items.Add(PCName); }));
MemoryStream GetThumpBytes = new MemoryStream();
GetThumpBytes.Write(ByteArray, SplitText[0].Length + SplitChar.Length + SplitText[1].Length + SplitChar.Length, ByteArray.Length-(SplitText[0].Length + SplitChar.Length + SplitText[1].Length + SplitChar.Length));
byte[] ThumpBytes = GetThumpBytes.ToArray();
MemoryStream MemoryStream = new MemoryStream();
MemoryStream.Write(ThumpBytes, 0, ThumpBytes.Length);
Image Thumb = Image.FromStream(MemoryStream);
pictureBox1.Image = Thumb;
Png Try Image :
Jpeg Try Image :
Bmp Try Image :

One issue I see is that assigning the image is most likely on the wrong thread.
this.Invoke(() => pictureBox1.Image = Thumb);

Convert bitmapimage into byte array

I am trying to convert bitmap Image to Byte array. I have select all the image by using MediaLibrary class and added it into a list of bitmap images. Here is my code
using (IsolatedStorageFile store = IsolatedStorageFile.GetUserStoreForApplication())
{
if (!store.DirectoryExists("ImagesZipFolder"))
{
store.CreateDirectory("ImagesZipFolder");
for (int i = 0; i < imgname.Count(); i++)
{
using (IsolatedStorageFileStream stream = new IsolatedStorageFileStream(#"ImagesZipFolder\" + imgname[i], System.IO.FileMode.CreateNew, store))
{
byte[] bytes = null;
using (MemoryStream ms = new MemoryStream())
{
WriteableBitmap wBitmap = new WriteableBitmap(ImgCollection[i]);
wBitmap.SaveJpeg(ms, wBitmap.PixelWidth, wBitmap.PixelHeight, 0, 100);
stream.Seek(0, SeekOrigin.Begin);
bytes = ms.GetBuffer();
stream.Write(bytes, 0, bytes.Length);
}
// byte[] bytes = Encoding.UTF8.GetBytes(imgname[i]);//new byte[ImgCollection[i].PixelWidth * ImgCollection[i].PixelHeight * 4];
// stream.Write(bytes, 0, bytes.Length);
}
}
}
else {
directory = true;
}
}
Basically what I am trying to do is, selecting all images or photo from device and create a zip file of that images. I was successful in creating a zip file of images. When I extract that file there is some images, but the problem is when I double click on image, I can't see that image. I think the problem is in reading the bytes of image. I am not getting what's wrong? Is my code is correct ?

Perhaps you can try the below. I know this code maintains the image, so if you have no luck using this, you may have a different issue.
// Convert the new image to a byte[]
ImageConverter converter = new ImageConverter();
byte[] newBA = (byte[])converter.ConvertTo(newImage, typeof(byte[]));
The ImageConverter is of the System.Drawing namespace.
Update:
http://msdn.microsoft.com/en-GB/library/system.windows.media.imagesourceconverter.convertto.aspx
You should be able to use this in place of the System.Drawing type I suggested.

There is no need to save the WriteableBitmap to a MemoryStream and then copy it to an IsolatedStorageFileStream. Just save the bitmap directly to the IsolatedStorageFileStream.
using (IsolatedStorageFileStream stream = new IsolatedStorageFileStream(#"ImagesZipFolder\" + imgname[i], System.IO.FileMode.CreateNew, store))
{
WriteableBitmap wBitmap = new WriteableBitmap(ImgCollection[i]);
wBitmap.SaveJpeg(stream, wBitmap.PixelWidth, wBitmap.PixelHeight, 0, 100);
}
This will allow you to save on memory as well. If you really want to save memory, you could reuse the WriteableBitmap.

Parameter is not valid - error when sending a bitmap via TCP with C#

I have a file transfer program. The program (Client) does following operations to send a bitmap via TCP socket: get screenshot -> grab Bitmap from memory -> convert to stream -> send
MemoryStream Fs = new MemoryStream();
//////////////11111
Bitmap bmp = TakeScreen();
///////////////2222
//Bitmap bmp = new Bitmap(#"C:\temp\001.bmp");
bmp.Save(Fs, ImageFormat.Bmp);
Byte[] buffer = Fs.ToArray();
Fs.Read(buffer, 0, buffer.Length);
TcpClient socket = new TcpClient("192.168.0.131", 1095);
NetworkStream nw = socket.GetStream();
nw.Write(buffer, 0, buffer.Length);
nw.Close();
Fs.Dispose();
socket.Close();
bmp.Dispose();
If I choose to transfer image directly from memory - no errors.
If I try to load Bitmap from file first - getting "Parameter is not valid" error on a server's side.
here is the server side:
NetworkStream Nw = new NetworkStream(handlerSocket.Client);
int thisRead = 0;
int Blocksize = 1024;
Byte[] dataByte = new Byte[Blocksize];
Bitmap screen = getScreen(Nw, dataByte, thisRead, Blocksize);
Nw.Close();
and
private Bitmap getScreen(NetworkStream Nw, Byte[] dataByte, int thisRead, int Blocksize)
{
Bitmap bitmap;
using (var strm = new MemoryStream())
{
while (true)
{
thisRead = Nw.Read(dataByte, 0, Blocksize);
strm.Write(dataByte, 0, thisRead);
if (thisRead == 0)
break;
}
bitmap = new Bitmap(strm); // Error here
}
Bitmap bm3 = new Bitmap(bitmap);
bitmap.Dispose();
return bm3;
}
What's causing this error? I guess it has something to do with the MemoryStream.
edit: simplified the question

You nee to seek to the beginning of the stream before you can create the Bitmap in getScreen.
private Bitmap getScreen(NetworkStream Nw, Byte[] dataByte, int thisRead, int Blocksize)
{
Bitmap bitmap;
using (var strm = new MemoryStream())
{
while (true)
{
thisRead = Nw.Read(dataByte, 0, Blocksize);
strm.Write(dataByte, 0, thisRead);
if (thisRead == 0)
break;
}
stream.Seek(0, SeekOrigin.Begin; // <-- Go Back to beginning of stream
bitmap = new Bitmap(strm); // Error here
}
Bitmap bm3 = new Bitmap(bitmap);
bitmap.Dispose();
return bm3;
}
EDIT
Detailed explanation: After writing the last byte to the stream, the stream's current position is a the end of the stream. Creating a Bitmap from the screen now tries to read the bitmap from the stream, which doesn't work, as there is no more data after the current position (= the end of the stream).
So what you need to do is tell the stream to set the current position back to the beginning of the stream. Then, the bitmap information can be read.

Image.FromStream() method returns Invalid Argument exception

I am capturing images from a smart camera imager and receiving the byte array from the camera through socket programming (.NET application is the client, camera is the server).
The problem is that i get System.InvalidArgument exception at runtime.
private Image byteArrayToImage(byte[] byteArray)
{
if(byteArray != null)
{
MemoryStream ms = new MemoryStream(byteArray);
return Image.FromStream(ms, false, false);
/*last argument is supposed to turn Image data validation off*/
}
return null;
}
I have searched this problem in many forums and tried the suggestions given by many experts but nothing helped.
I dont think there is any problem with the byte array as such because When i feed the same byte array into my VC++ MFC client application, i get the image. But this doesn't somehow work in C#.NET.
Can anyone help me ?
P.S :
Other methods i've tried to accomplish the same task are:
1.
private Image byteArrayToImage(byte[] byteArray)
{
if(byteArray != null)
{
MemoryStream ms = new MemoryStream();
ms.Write(byteArray, 0, byteArray.Length);
ms.Position = 0;
return Image.FromStream(ms, false, false);
}
return null;
}
2.
private Image byteArrayToImage(byte[] byteArray)
{
if(byteArray != null)
{
TypeConverter tc = TypeDescriptor.GetConverter(typeof(Bitmap));
Bitmap b = (Bitmap)tc.ConvertFrom(byteArray);
return b;
}
return null;
}
None of the above methods worked. Kindly help.

Image.FromStream() expects a stream that contains ONLY one image!
It resets the stream.Position to 0. I've you have a stream that contains multiple images or other stuff, you have to read your image data into a byte array and to initialize a MemoryStream with that:
Image.FromStream(new MemoryStream(myImageByteArray));
The MemoryStream has to remain open as long as the image is in use.
I've learned that the hard way, too.

Maybe the image is embedded in an OLE field and you have to consider the 88 bytes OLE header plus payload:
byteBlobData = (Byte[]) reader.GetValue(0);
stream = new MemoryStream(byteBlobData, 88, byteBlobData.Length - 88);
img = Image.FromStream(stream);

I'm guessing that something is going wrong when receiving the file from the server. Perhaps you're only getting part of the file before trying to convert it to an Image? Are you sure it's the exact same byte array you're feeding the C++ application?
Try saving the stream to a file and see what you get. You might be able to uncover some clues there.
You can also add a breakpoint and manually compare some of the bytes in the byte array to what they're supposed to be (if you know that).
Edit: It looks like there's nothing wrong with receiving the data. The problem is that it's in raw format (not a format that Image.FromStream understands). The Bitmap(Int32, Int32, Int32, PixelFormat, IntPtr) constructor may be of use here. Or, you can create the blank bitmap and blt it manually from the raw data.

I've had this problem when doing this:
MemoryStream stream = new MemoryStream();
screenshot.Save(stream, ImageFormat.Png);
byte[] bytes = new byte[stream.Length];
stream.Save(bytes, 0, steam.Length);
With the last 2 lines being the problem. I fixed it by doing this:
MemoryStream stream = new MemoryStream();
screenshot.Save(stream, ImageFormat.Png);
byte[] bytes = stream.ToArray();
And then this worked:
MemoryStream stream = new MemoryStream(bytes);
var newImage = System.Drawing.Image.FromStream(stream);
stream.Dispose();

System.InvalidArgument means The stream does not have a valid image format, i.e. an image type that is not supported.

Try this:
public Image byteArrayToImage(byte[] item)
{
Image img=Image.FromStream(new MemoryStream(item));
img.Save(Response.OutputStream, ImageFormat.Gif);
return img;
}
Hope it helps!

I've had the same problem in the past and it was caused by a leak within the windows GDI libraries, which is what 'Bitmap' uses. If this happening all the time for you then its probably unrelated, however.

this code is working
string query="SELECT * from gym_member where Registration_No ='" + textBox9.Text + "'";
command = new SqlCommand(query,con);
ad = new SqlDataAdapter(command);
DataTable dt = new DataTable();
ad.Fill(dt);
textBox1.Text = dt.Rows[0][1].ToString();
textBox2.Text = dt.Rows[0][2].ToString();
byte[] img = (byte[])dt.Rows[0][18];
MemoryStream ms = new MemoryStream(img);
pictureBox1.Image = Image.FromStream(ms);
ms.Dispose();

Try to use something similar to what is described here https://social.msdn.microsoft.com/Forums/vstudio/en-US/de9ee1c9-16d3-4422-a99f-e863041e4c1d/reading-raw-rgba-data-into-a-bitmap
Image ImageFromRawBgraArray(
byte[] arr,
int charWidth, int charHeight,
int widthInChars,
PixelFormat pixelFormat)
{
var output = new Bitmap(width, height, pixelFormat);
var rect = new Rectangle(0, 0, width, height);
var bmpData = output.LockBits(rect, ImageLockMode.ReadWrite, output.PixelFormat);
// Row-by-row copy
var arrRowLength = width * Image.GetPixelFormatSize(output.PixelFormat) / 8;
var ptr = bmpData.Scan0;
for (var i = 0; i < height; i++)
{
Marshal.Copy(arr, i * arrRowLength, ptr, arrRowLength);
ptr += bmpData.Stride;
}
output.UnlockBits(bmpData);
return output;
}

After load from DataBase byteArray has more byte than one image. In my case it was 82.
MemoryStream ms = new MemoryStream();
ms.Write(byteArray, 82, byteArray.Length - 82);
Image image = Image.FromStream(ms);
And for save in the DB I insert 82 byte to begin stream. Properties.Resources.ImgForDB - it is binary file that contain those 82 byte. (I get it next path - Load Image from DB to MemoryStream and save to binary file first 82 byte. You can take it here - https://yadi.sk/d/bFVQk_tdEXUd-A)
MemoryStream temp = new MemoryStream();
MemoryStream ms = new MemoryStream();
OleDbCommand cmd;
if (path != "")
{
Image.FromFile(path).Save(temp, System.Drawing.Imaging.ImageFormat.Bmp);
ms.Write(Properties.Resources.ImgForDB, 0, Properties.Resources.ImgForDB.Length);
ms.Write(temp.ToArray(), 0, temp.ToArray().Length);
cmd = new OleDbCommand("insert into Someone (first, Second, Third) values (#a,#b,#c)", connP);
cmd.Parameters.AddWithValue("#a", fio);
cmd.Parameters.AddWithValue("#b", post);
cmd.Parameters.AddWithValue("#c", ms.ToArray());
cmd.ExecuteNonQuery();