I appreciate this is a little bit niche, but I thought I would ask anyway. I'm writing a small c# application to utilise the HMRC web portal and electronically submit VAT returns in XML format. According to the HMRC specification it is just a simple Http 1.1 POST action required, and retrieving the response in XML. The application is built, however, I am having trouble with this code. I get an "OK" HttpWebResponse, but the HMRC server returns this spurious error message which they can't seem to tell me what it means. Here is my code:
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(destinationUrl);
byte[] bytes;
bytes = System.Text.Encoding.ASCII.GetBytes(requestXml);
request.ContentType = "text/xml; charset='utf-8'";
request.ContentLength = bytes.Length;
request.Method = "POST";
Stream requestStream = request.GetRequestStream();
requestStream.Write(bytes, 0, bytes.Length);
requestStream.Close();
HttpWebResponse response;
response = (HttpWebResponse)request.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
Stream responseStream = response.GetResponseStream();
string responseStr = new StreamReader(responseStream).ReadToEnd();
return responseStr;
}
And the error is:
1001 - The submitted XML document either failed to validate against the GovTalk schema for this class of document or its body was badly formed.
I know the XML is ok, because when I test it using a third-party tool like "Postman" it submits 100% and the Transaction Engine returns no errors, so it must be my code. Does anything look glaringly wrong to post an XML? I have tried different Content/MIME Types and also I have confirmed that 'utf-8' is the correct encoding.
I was just wondering if any developers out there had worked on the Transaction Engine and could share their submit/post code?
The answer is that the code converting the file contents into the Byte Array was actually converting the file name.
I changed this line:
bytes = System.Text.Encoding.ASCII.GetBytes(requestXml);
To this:
bytes = File.ReadAllBytes(requestXml);
Related
I am new to .net and APIs and am currently using .Net 4.5 to connect to an API using rest. The problem I am having is I get an exception thrown back in the return xml that says "Cannot forward request to server with name", "Cannot read data from connection", Connection reset", full error below.
What is odd is this script works fine on smaller datasets but when the response is large enough, I get that exception from the server thrown back. What has helped setting the keep alive to true, using httpversion10, and specifying gzip and sendchunked. I am using advanced rest client to test the server in chrome addins and it returns data fine on there with these larger dataset. It will not with the script below. I am suspecting there is a difference in the way I am telling the server to handle my response verses the chrome add in. Any suggestions on how I improve the performance of this?
This is what the advanced rest client settings look like that work for the Chrome add in.
This is the code I have which appears to need changes to make it handle the request/response better.
HttpWebRequest req = (HttpWebRequest)WebRequest.Create(#"magicalwebsite");
req.KeepAlive = true;
req.ProtocolVersion = HttpVersion.Version10;
req.ServicePoint.ConnectionLimit = 24;
req.Timeout = 2000000000;
req.Method = "Post";
req.Accept = "*/*";
req.SendChunked = true;
req.AutomaticDecompression = DecompressionMethods.GZip;
//Xml request file for data
string postData = System.IO.File.ReadAllText(#"C:\Users\yo\Desktop\testtest.txt");
//sending header and content
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
req.ContentType = "text/xml";
req.ContentLength = byteArray.Length;
req.Headers["Authorization"] = "Basic " + Convert.ToBase64String(Encoding.Default.GetBytes("xxxx:xxxxx"));
Stream dataStream = req.GetRequestStream();
dataStream.Write(byteArray, 0, byteArray.Length);
dataStream.Close();
//Requesting response of data
HttpWebResponse resp = req.GetResponse() as HttpWebResponse;
//Grabbing response
using (Stream stream = resp.GetResponseStream())
{
StreamReader reader = new StreamReader(stream, Encoding.UTF8);
String responseString = reader.ReadToEnd();
}
This is the exception I am getting in the xml being thrown back.
<?xml version="1.0" encoding="UTF-8"?>
<response success="false">
<messages>
<message key="exception-caught">Caught Exception: Caught Exception:
Cannot forward request to server with name=prod-euapp01
com.magicalpony.exception.APException: Cannot forward request to server with name=prod-euapp01
at com.magicalpony.webservices.APIForwarder.forward(APIForwarder.java:105)
at com.magicalpony.webservices.APIServlet.forwardRequest(APIServlet.java:270)
at com.magicalpony.webservices.APIServlet.wrongServer(APIServlet.java:253)
at com.magicalpony.webservices.APIServlet.service(APIServlet.java:124)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:304)
at org.apache.catalina.core.ApplicationFilterChain.doFilter
(ApplicationFilterChain.java:210)
at com.magicalpony.system.WebServiceMonitor.doFilter(WebServiceMonitor.java:61)
at org.apache.catalina.core.
ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at com.magicalpony.system.HitTracer.doFilter(HitTracer.java:133)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:164)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:462)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:563)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:399)
at org.apache.coyote.ajp.AjpProcessor.process(AjpProcessor.java:303)
at org.apache.coyote.ajp.AjpProtocol$AjpConnectionHandler.process(AjpProtocol.java:183)
at org.apache.coyote.ajp.AjpProtocol$AjpConnectionHandler.process(AjpProtocol.java:169)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:311)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at java.lang.Thread.run(Thread.java:745)
Caused by: com.magicalpony.exception.APException:
Cannot read data from connection
at com.magicalpony.webservices.NetUtil.readData(NetUtil.java:61)
at com.magicalpony.webservices.APIForwarder.forward(APIForwarder.java:102)
... 26 more
Caused by: java.net.SocketException: Connection reset
at java.net.SocketInputStream.read(SocketInputStream.java:196)
at
java.net.SocketInputStream.read(SocketInputStream.java:122)
at java.io.BufferedInputStream.fill(BufferedInputStream.java:235)
at java.io.BufferedInputStream.read1(BufferedInputStream.java:275)
at java.io.BufferedInputStream.read(BufferedInputStream.java:334)
at sun.net.www.http.HttpClient.parseHTTPHeader(HttpClient.java:687)
at sun.net.www.http.HttpClient.parseHTTP(HttpClient.java:633)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1323)
at com.magicalpony.webservices.NetUtil.readData(NetUtil.java:58)
... 27 more</message>
</messages>
</response>
The problem is with DNS resolution.
Step 1: Enter your domain name in a browser and see if Server is available.
Step 2: If server is available with domain name then you got to fix the IP Address or DNS resolution.
You can fix this by updating the IP Address in your PC (Follow steps below)
Go to a folder: C:\Windows\System32\drivers\etc
Copy and paste "hosts" file to desktop.
Update your host file with your IP Address and domain name.
Step 3: Copy and Paste hosts file in original folder (C:\Windows\System32\drivers\etc).
Step 4: Test your API.
I'm trying to get data from the Microsoft Live API. However, when I try to get the access_token, I instead get a 415(Unsupported Media Type) error message. I have looked pretty much everywhere, but I can't find any answer (that worked for me).
Here is my (partial) code that tries to get the token (dataToWrite is cut-up for readability, it's one line in the actual code):
WebRequest request;
request = WebRequest.Create("https://login.live.com/oauth20_token.srf");
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
var dataToWrite = "code=[code]&
client_id=[client_id]&
client_secret=[client_secret]&
redirect_uri=[redirect_uri]&
grant_type=authorization_code";
var buffer = Encoding.ASCII.GetBytes(dataToWrite);
request.ContentLength = buffer.Length;
var dataStream = request.GetRequestStream();
dataStream.Write(buffer, 0, buffer.Length);
dataStream.Close();
var response = request.GetResponse();
var responseStream = response.GetResponseStream();
Where the '[]' are:
[code] is a string, given by Microsoft after user logs in (this part of the code works);
[client_id] is a string, given by Microsoft, representing my client id;
[client_secret] is a string, given by Microsoft, representing my client secret;
[redirect_uri] is the URL of the site's return location (same as the URL used in the code for the user consent(see [code]))
According to the manual of Microsoft Live API(http://msdn.microsoft.com/en-us/library/live/hh243647.aspx) this should work. However, the documentation isn't very detailed.
Does anyone know why I keep getting the error?
Thanks!
Never mind, I'm an idiot...
It does work after all. I did another request after this one. And that one failed because I did not include the parameters there.
how would I be able to do something like http://myanimelist.net/modules.php?go=api#verifycred
aka "curl -u user:password http://myanimelist.net/api/account/verify_credentials.xml"
I wish to option the id
my code so far is
string url = "http://myanimelist.net/api/account/verify_credentials.xml";
WebRequest request = WebRequest.Create(url);
request.ContentType = "xml";
request.Method = "GET";
request.Credentials = new NetworkCredential(username, password);
byte[] buffer = Encoding.GetEncoding("UTF-8").GetBytes("xml/user/id"); // i think this line?
Stream reqstr = request.GetRequestStream();
reqstr.Write(buffer, 0, buffer.Length);
reqstr.Close();
but I get a error on "reqstr.Write(buffer, 0, buffer.Length)"
Cannot send a content-body with this verb-type, I have tried googling but with no prevail, I am using c#
Your snippet is trying to send a GET request with request data (you're calling GetRequestStream and then writing some data to the request stream). The HTTP protocol does not allow this - you can only send data with POST request.
However, the API that you are trying to call is actually doing something different - you do not need to send it the XML data. The XML data (with user ID and user name) is the response that you get when you successfully login.
So, instead of calling GetRequestStream and writing the XML data, you need to call GetResponse and then GetResponseStream to read the XML data!
I need to post data to a website. So I created a small app in C#.net where I open this website and fill in all the controls (radio buttons, text boxes, checkboxes etc) with the values from my database. I also have a click event on the SUBMIT button. The app then waits for 10-15 seconds and then copies the response from the webpage to my database.
As you can see, this is really a hectic process. If there are thousands of records to upload, this app takes much longer (due to fact that it waits 15s for the response).
Is there any other way to post data? I am looking for something like concatenating all the fields with its value and uploading it like a stream of data. How will this work if the website is https and not http?
You can use HttpWebRequest to do this, and you can concatenate all the values you want to post into a single string for the request. It could look something like this:
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("https://www.yoursite.com");
request.Method = "POST";
formContent = "FormValue1=" + someValue +
"&FormValue2=" + someValue2 +
"&FormValue=" + someValue2;
byte[] byteArray = Encoding.UTF8.GetBytes(formContent);
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = byteArray.Length;
Stream dataStream = request.GetRequestStream();
dataStream.Write(byteArray, 0, byteArray.Length);
dataStream.Close();
WebResponse response = request.GetResponse();
dataStream = response.GetResponseStream();
StreamReader reader = new StreamReader(dataStream);
string responseFromServer = HttpUtility.UrlDecode(reader.ReadToEnd());
//You may need HttpUtility.HtmlDecode depending on the response
reader.Close();
dataStream.Close();
response.Close();
This method should work fine for http and https.
MSDN has a great article with step-by-step instructions detailing how you can use the WebRequest class to send data. Link below:
http://msdn.microsoft.com/en-us/library/debx8sh9.aspx
Yes, there is a WebClient class. Look into documentation. There're some usful method to make GET and POST requests.
I found this snippet of code here that allows you to log into a website and get the response from the logged in page. However, I'm having trouble understanding all the part of the code. I've tried my best to fill in whatever I understand so far. Hope you guys can fill in the blanks for me. Thanks
string nick = "mrbean";
string password = "12345";
//this is the query data that is getting posted by the website.
//the query parameters 'nick' and 'password' must match the
//name of the form you're trying to log into. you can find the input names
//by using firebug and inspecting the text field
string postData = "nick=" + nick + "&password=" + password;
// this puts the postData in a byte Array with a specific encoding
//Why must the data be in a byte array?
byte[] data = Encoding.ASCII.GetBytes(postData);
// this basically creates the login page of the site you want to log into
WebRequest request = WebRequest.Create("http://www.mrbeanandme.com/login/");
// im guessing these parameters need to be set but i dont why?
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = data.Length;
// this opens a stream for writing the post variables.
// im not sure what a stream class does. need to do some reading into this.
Stream stream = request.GetRequestStream();
// you write the postData to the website and then close the connection?
stream.Write(data, 0, data.Length);
stream.Close();
// this receives the response after the log in
WebResponse response = request.GetResponse();
stream = response.GetResponseStream();
// i guess you need a stream reader to read a stream?
StreamReader sr = new StreamReader(stream);
// this outputs the code to console and terminates the program
Console.WriteLine(sr.ReadToEnd());
Console.ReadLine();
A Stream is a sequence of bytes.
In order to use text with a Stream, you need to convert it into a sequence of bytes.
This can be done manually with the Encoding classes or automatically with StreamReader and StreamWriter. (which read and write strings to streams)
As stated in the documentation for GetRequestStream,
You must call the Stream.Close method to close the stream and release the connection for reuse. Failure to close the stream causes your application to run out of connections.
The Method and Content-* properties reflect the underlying HTTP protocol.