I have a multiline textbox that contains 10 digit mobile numbers separated by comma. I need to achieve string in group of at least 100 mobile numbers.
100 mobile numbers will be separated by 99 comma in total. What i am trying to code is to split the strings containing commas less than 100
public static IEnumerable<string> SplitByLength(this string str, int maxLength)
{
for (int index = 0; index < str.Length; index += maxLength) {
yield return str.Substring(index, Math.Min(maxLength, str.Length - index));
}
}
By using above code, I can achieve 100 numbers as 100 numbers will have 10*100(for mobile number)+99(for comma) text length. But the problem here is user may enter wrong mobile number like 9 digits or even 11 digits.
Can anyone guide me on how can I achieve this.
Thank you in advance.
You could use this extension method to put them into max-100 number groups:
public static IEnumerable<string[]> SplitByLength(this string str, string[] splitBy, StringSplitOptions options, int maxLength = int.MaxValue)
{
var allTokens = str.Split(splitBy, options);
for (int index = 0; index < allTokens.Length; index += maxLength)
{
int length = Math.Min(maxLength, allTokens.Length - index);
string[] part = new string[length];
Array.Copy(allTokens, index, part, 0, length);
yield return part;
}
}
Sample:
string text = string.Join(",", Enumerable.Range(0, 1111).Select(i => "123456789"));
var phoneNumbersIn100Groups = text.SplitByLength(new[] { "," }, StringSplitOptions.None, 100);
foreach (string[] part in phoneNumbersIn100Groups)
{
Assert.IsTrue(part.Length <= 100);
Console.WriteLine(String.Join("|", part));
}
You have a few options,
Put some kind of mask on the input data to prevent the user entering invalid data. In your UI you could then flag the error and prompt the user to reenter correct information. If you go down this route then something like this string[] nums = numbers.Split(','); will be fine.
Alternatively, you could use regex.split or regex.match and match on the pattern. Something like this should work assuming your numbers are in a string with a leading comma or space
Regex regex = new Regex("(\s|,)\d{10},)";
string[] nums = regex.Split(numbers);
This be can resolved with a simple Linq code
public static IEnumerable<string> SplitByLength(this string input, int groupSize)
{
// First split the input to the comma.
// this will give us an array of all single numbers
string[] numbers = input.Split(',');
// Now loop over this array in groupSize blocks
for (int index = 0; index < numbers.Length; index+=groupSize)
{
// Skip numbers from the starting position and
// take the following groupSize numbers,
// join them in a string comma separated and return
yield return string.Join(",", numbers.Skip(index).Take(groupSize));
}
}
Related
I want a method to remove the comma from the decimal number and then collect the digits. For example, if the user inputs 1,3 it will remove the comma and collect 1 and 3 together. I mean 1+3 =4. Can I use trim or replace?
public int AddSum(string x1)
{
string x = x1.Trim();
int n = Convert.ToInt32(x);
return n;
}
public int AddSum(string x1)
{
var digitFilter = new Regex(#"[^\d]");
return digitFilter.Replace(x1, "").Select(c => int.Parse(c)).Sum();
}
OR
public int AddSum(string x1)
{
return x1.Where(c => char.IsDigit(c)).Select(c => c - '0').Sum();
}
If you want to iterate over the characters in a string and compute the sum of digits contained therein, it's trivial:
public static int SumOfDigits( string s ) {
int n = 0;
foreach ( char c in s ) {
n += c >= '0' && c <= '9' // if the character is a decimal digit
? c - '0' // - convert to its numeric value
: 0 // - otherwise, default to zero
; // and add that to 'n'
}
return n;
}
It sounds like you want take a comma-separated string of numbers, add the numbers together, then return the result.
The first thing you have to do is use the Split() method on the input string. The Split() method takes an input string splits the string into an array of strings based on a character:
string[] numbers = x1.Split(',');
So now we have an array of strings called numbers that hold each number. The next thing you have to do is create an empty variable to hold the running total:
int total = 0;
The next thing is to create a loop that will iterate through the numbers array and each time, add the number to the running total. Remember that numbers is an array of strings and not numbers. so we must use the Parse() method of int to convert the string to a number:
foreach (string number in numbers)
{
total += int.Parse(number);
}
Finally, just return the result:
return total;
Put it all together and you got this:
private static int AddSum(string x1)
{
string[] numbers = x1.Split(',');
int total = 0;
foreach (string number in numbers)
{
total += int.Parse(number);
}
return total;
}
I hope this helps and clarifies things. Keep in mind that this method doesn't do any kind of error checking, so if your input is bad, you'll get an exception probably.
I know how to do a string split if there's a letter, number, that I want to replace.
But how could I do a string.Split() by 2 char counts without replacing any existing letters, number, etc...?
Example:
string MAC = "00122345"
I want that string to output: 00:12:23:45
You could create a LINQ extension method to give you an IEnumerable<string> of parts:
public static class Extensions
{
public static IEnumerable<string> SplitNthParts(this string source, int partSize)
{
if (string.IsNullOrEmpty(source))
{
throw new ArgumentException("String cannot be null or empty.", nameof(source));
}
if (partSize < 1)
{
throw new ArgumentException("Part size has to be greater than zero.", nameof(partSize));
}
return Enumerable
.Range(0, (source.Length + partSize - 1) / partSize)
.Select(pos => source
.Substring(pos * partSize,
Math.Min(partSize, source.Length - pos * partSize)));
}
}
Usage:
var strings = new string[] {
"00122345",
"001223453"
};
foreach (var str in strings)
{
Console.WriteLine(string.Join(":", str.SplitNthParts(2)));
}
// 00:12:23:45
// 00:12:23:45:3
Explanation:
Use Enumerable.Range to get number of positions to slice string. In this case its the length of the string + chunk size - 1, since we need to get a big enough range to also fit leftover chunk sizes.
Enumerable.Select each position of slicing and get the startIndex using String.Substring using the position multiplied by 2 to move down the string every 2 characters. You will have to use Math.Min to calculate the smallest size leftover size if the string doesn't have enough characters to fit another chunk. You can calculate this by the length of the string - current position * chunk size.
String.Join the final result with ":".
You could also replace the LINQ query with yield here to increase performance for larger strings since all the substrings won't be stored in memory at once:
for (var pos = 0; pos < source.Length; pos += partSize)
{
yield return source.Substring(pos, Math.Min(partSize, source.Length - pos));
}
You can use something like this:
string newStr= System.Text.RegularExpressions.Regex.Replace(MAC, ".{2}", "$0:");
To trim the last colon, you can use something like this.
newStr.TrimEnd(':');
Microsoft Document
Try this way.
string MAC = "00122345";
MAC = System.Text.RegularExpressions.Regex.Replace(MAC,".{2}", "$0:");
MAC = MAC.Substring(0,MAC.Length-1);
Console.WriteLine(MAC);
A quite fast solution, 8-10x faster than the current accepted answer (regex solution) and 3-4x faster than the LINQ solution
public static string Format(this string s, string separator, int length)
{
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.Length; i += length)
{
sb.Append(s.Substring(i, Math.Min(s.Length - i, length)));
if (i < s.Length - length)
{
sb.Append(separator);
}
}
return sb.ToString();
}
Usage:
string result = "12345678".Format(":", 2);
Here is a one (1) line alternative using LINQ Enumerable.Aggregate.
string result = MAC.Aggregate("", (acc, c) => acc.Length % 3 == 0 ? acc += c : acc += c + ":").TrimEnd(':');
An easy to understand and simple solution.
This is a simple fast modified answer in which you can easily change the split char.
This answer also checks if the number is even or odd , to make the suitable string.Split().
input : 00122345
output : 00:12:23:45
input : 0012234
output : 00:12:23:4
//The List that keeps the pairs
List<string> MACList = new List<string>();
//Split the even number into pairs
for (int i = 1; i <= MAC.Length; i++)
{
if (i % 2 == 0)
{
MACList.Add(MAC.Substring(i - 2, 2));
}
}
//Make the preferable output
string output = "";
for (int j = 0; j < MACList.Count; j++)
{
output = output + MACList[j] + ":";
}
//Checks if the input string is even number or odd number
if (MAC.Length % 2 == 0)
{
output = output.Trim(output.Last());
}
else
{
output += MAC.Last();
}
//input : 00122345
//output : 00:12:23:45
//input : 0012234
//output : 00:12:23:4
1) I need to count how much words i have in the sentence.
But what if i have more than one white space? It will count as a word. Need solution for this.
There is four words. / count as 4 words
There is four words. / count as 5 words
I use:
int countWords = txt.Split().Length;
2) I need to extract numbers from string and then get sum. My code is not working, No overload for method error.
All my code:
Console.Write("Ievadiet tekstu: ");
string txt = Console.ReadLine();
int sum = 0;
int countWords = txt.Split().Length;
foreach (char num in txt)
{
if (char.IsDigit(num))
sum += Int32.TryParse(num).ToString();
}
Console.WriteLine("There are {0} words in this sentence.",countWords);
Console.WriteLine("Summ is "+sum);
Use the overload of String.Split with StringSplitOptions.RemoveEmptyEntries. You can use an empty char[](or string[]) to get the same behaviour as String.Split without an argument, so that it splits by all white-space characters like space,tab or new-line characters.
If you want to sum the "words" which could be parsed to int then do that, use int.TryParse on all words which were extracted by String.Split. You could use LINQ:
string[] words = text.Split(new char[] {}, StringSplitOptions.RemoveEmptyEntries);
int wordCount = words.Length;
int num = 0;
int sum = words.Where(w => int.TryParse(w, out num)).Sum(w => num);
Here is a simple console app to do what you intend to.
It uses a Regular expression to capture number characters and sums them. The TryParse is just a fail-safe (i believe it is not needed in this case since the regex ensures only digits are captured).
static void Main(string[] args)
{
Regex digitRegex = new Regex("(\\d)");
string text = Console.ReadLine();
int wordCount = text.Split(new char[]{' '}, StringSplitOptions.RemoveEmptyEntries).Length;
int sum = 0;
foreach (Match x in digitRegex.Matches(text, 0))
{
int num;
if (int.TryParse(x.Value, out num))
sum += num;
}
Console.WriteLine("Word Count:{0}, Digits Total:{1}", wordCount, sum);
Console.ReadLine();
}
Hope it helps. Cheers
string num = db.SelectNums(id);
string[] numArr = num.Split('-').ToArray();
string num contain for an example "48030-48039";
string[] numArr will therefor contain (48030, 48039).
Now I have two elements, a high and low. I now need to get ALL the numbers from 48030 to 48039. The issue is that it has to be string since there will be telephone numbers with leading zeroes now and then.
Thats why I cannot use Enumerable.Range().ToArray() for this.
Any suggestions? The expected result should be 48030, 48031, 48032, ... , 48039
This should work with your leading zero requirement:
string num = db.SelectNums(id);
string[] split = num.Split('-');
long start = long.Parse(split[0]);
long end = long.Parse(split[1]);
bool includeLeadingZero = split[0].StartsWith("0");
List<string> results = new List<string>();
for(int i = start; i <= end; i++)
{
string result = includeLeadingZero ? "0" : "";
result += i.ToString();
results.Add(result);
}
string[] arrayResults = results.ToArray();
A few things to note:
It assumes your input will be 2 valid integers split by a single hyphen
I am giving you a string array result, personally I would prefer to work with a List<int> in the end
If the first number contains a single leading zero, then all results will contain a single leading zero
It uses long to cater for longer numbers, beware that the max number that will parse is 9,223,372,036,854,775,807, you could double this value (not length) by using ulong
Are you saying this?
int[] nums = new int[numArr.Length];
for (int i = 0; i < numArr.Length; i++)
{
nums[i] = Convert.ToInt32(numArr[i]);
}
Array.Sort(nums);
for (int n = nums[0]; n <= nums[nums.Length - 1]; n++)
{
Console.WriteLine(n);
}
here link
I am expecting your string always have valid two integers, so using Parse instead TryParse
string[] strList = "48030-48039".Split('-').ToArray();
var lst = strList.Select(int.Parse).ToList();
var min = lst.OrderBy(l => l).FirstOrDefault();
var max = lst.OrderByDescending(l => l).FirstOrDefault();
var diff = max - min;
//adding 1 here otherwise 48039 will not be there
var rng = Enumerable.Range(min,diff+1);
If you expecting invalid string
var num = 0;
var lst = (from s in strList where int.TryParse(s, out num) select num).ToList();
This is one way to do it:
public static string[] RangeTest()
{
Boolean leadingZero = false;
string num = "048030-48039"; //db.SelectNums(id);
if (num.StartsWith("0"))
leadingZero = true;
int min = int.Parse(num.Split('-').Min());
int count = int.Parse(num.Split('-').Max()) - min;
if (leadingZero)
return Enumerable.Range(min, count).Select(x => "0" + x.ToString()).ToArray();
else
return Enumerable.Range(min, count).Select(x => "" + x.ToString()).ToArray(); ;
}
You can use string.Format to ensure numbers are formatted with leading zeros. That will make the method work with arbitrary number of leading zeros.
private static string CreateRange(string num)
{
var tokens = num.Split('-').Select(s => s.Trim()).ToArray();
// use UInt64 to allow huge numbers
var start = UInt64.Parse(tokens[0]);
var end = UInt64.Parse(tokens[1]);
// if your start number is '000123', this will create
// a format string with 6 zeros ('000000')
var format = new string('0', tokens[0].Length);
// use StringBuilder to make GC happy.
// (if only there was a Enumerable.Range<ulong> overload...)
var sb = new StringBuilder();
for (var i = start; i <= end; i++)
{
// format ensures that your numbers are padded properly
sb.Append(i.ToString(format));
sb.Append(", ");
}
// trim trailing comma after the last element
if (sb.Length >= 2) sb.Length -= 2;
return sb.ToString();
}
Usage example:
// prints 0000012, 0000013, 0000014
Console.WriteLine( CreateRange("0000012-0000014") );
Three significant issues were brought up in comments:
The phone numbers have enough digits to exceed Int32.MaxValue so
converting to int isn't viable.
The phone numbers can have leading zeros (presumeably for some
international calling?)
The possible range of numbers can theoretically exceed the maximum size of an array (which may have memory issues, and I think may not be represented as a string)
As such, you may need to use long instead of int, and I would suggest using deferred execution if needed for very large ranges.
public static IEnumerable<string> EnumeratePhoneNumbers(string fromAndTo)
{
var split = fromAndTo.Split('-');
return EnumeratePhoneNumbers(split[0], split[1]);
}
public static IEnumerable<string> EnumeratePhoneNumbers(string fromString, string toString)
{
long from = long.Parse(fromString);
long to = long.Parse(toString);
int totalNumberLength = fromString.Length;
for (long phoneNumber = from; phoneNumber <= to; phoneNumber++)
{
yield return phoneNumber.ToString().PadLeft(totalNumberLength, '0');
}
}
This assumes that the padded zeros are already included in the lower bound fromString text. It will iterate and yield out numbers as you need them. This can be useful if you're churning out a lot of numbers and don't need to fill up memory with them, or if you just need the first 10 or 100. For example:
var first100Numbers =
EnumeratePhoneNumbers("0018155500-7018155510")
.Take(100)
.ToArray();
Normally that range would produce 7 billion results which cannot be stored in an array, and might run into memory issues (I'm not even sure if it can be stored in a string); by using deferred execution, you only create the 100 needed.
If you do have a small range, you can still join up your results into a string as you desired:
string numberRanges = String.Join(", ", EnumeratePhoneNumbers("0018155500-0018155510"));
And naturally you can put this array creation into your own helper method:
public static string GetPhoneNumbersListing(string fromAndTo)
{
return String.Join(", ", EnumeratePhoneNumbers("0018155500-0018155510"));
}
So your usage would be:
string numberRanges = GetPhoneNumbersListing("0018155500-0018155510");
A complete solution inspired by the answer by #Dan-o:
Inputs:
Start: 48030
End: 48039
Digits: 6
Expected String Output:
048030, 048031, 048032, 048033, 048034, 048035, 048036, 048037, 048038, 048039
Program:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
public class Program
{
public static void Main()
{
int first = 48030;
int last = 48039;
int digits = 6;
Console.WriteLine(CreateRange(first, last, digits));
}
public static string CreateRange(int first, int last, int numDigits)
{
string separator = ", ";
var sb = new StringBuilder();
sb.Append(first.ToString().PadLeft(numDigits, '0'));
foreach (int num in Enumerable.Range(first + 1, last - first))
{
sb.Append(separator + num.ToString().PadLeft(numDigits, '0'));
}
return sb.ToString();
}
}
For Each item In Enumerable.Range(min, count).ToArray()
something = item.PadLeft(5, "0")
Next
I have a string like this: C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg
Now, what I want to do is to dynamically combine the last 4 numbers, in this case its 10000080 as result. My idea was ti split this and combine them in some way, is there an easier way? I cant rely on the array index, because the path can be longer or shorter as well.
Is there a nice way to do that?
Thanks :)
A compact way using string.Join and Regex.Split.
string text = #"C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg";
string newString = string.Join(null, Regex.Split(text, #"[^\d]")); //10000080
Use String.Split
String toSplit = "C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg";
String[] parts = toSplit.Split(new String[] { #"\" });
String result = String.Empty;
for (int i = 5, i > 1; i--)
{
result += parts[parts.Length - i];
}
// Gives the result 10000080
You can rely on array index if the last part always is the filename.
since the last part is always
array_name[array_name.length - 1]
the 4 parts before that can be found by
array_name[array_name.length - 2]
array_name[array_name.length - 3]
etc
If you always want to combine the last four numbers, split the string (use \ as the separator), start counting from the last part and take 4 numbers, or the 4 almost last parts.
If you want to take all the digits, just scan the string from start to finish and copy just the digits to a new string.
string input = "C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg";
string[] parts = toSplit.Split(new char[] {'\\'});
IEnumerable<string> reversed = parts.Reverse();
IEnumerable<string> selected = reversed.Skip(1).Take(4).Reverse();
string result = string.Concat(selected);
The idea is to extract the parts, reverse them to keep only the last 4 (excluding the file name) and re reversing to rollback to the initial order, then concat.
Using LINQ:
string path = #"C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg";
var parts = Path.GetDirectoryName(path).Split('\\');
string numbersPart = parts.Skip(parts.Count() - 4)
.Aggregate((acc, next) => acc + next);
Result: "10000080"
var r = new Regex(#"[^\d+]");
var match = r
.Split(#"C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg")
.Aggregate((i, j) => i + j);
return match.ToString();
to find the number you can use regex:
(([0-9]{2})\\){4}
use concat all inner Group ([0-9]{2}) to get your searched number.
This will always find your searched number in any position in the given string.
Sample Code:
static class TestClass {
static void Main(string[] args) {
string[] tests = { #"C:\Projects\test\whatever\files\media\10\00\00\80\test.jpg",
#"C:\Projects\test\whatever\files\media\10\00\00\80\some\foldertest.jpg",
#"C:\10\00\00\80\test.jpg",
#"C:\10\00\00\80\test.jpg"};
foreach (string test in tests) {
int number = ExtractNumber(test);
Console.WriteLine(number);
}
Console.ReadLine();
}
static int ExtractNumber(string path) {
Match match = Regex.Match(path, #"(([0-9]{2})\\){4}");
if (!match.Success) {
throw new Exception("The string does not contain the defined Number");
}
//get second group that is where the number is
Group #group = match.Groups[2];
//now concat all captures
StringBuilder builder = new StringBuilder();
foreach (var capture in #group.Captures) {
builder.Append(capture);
}
//pares it as string and off we go!
return int.Parse(builder.ToString());
}
}