In c# I can fill a polygon in a bitmap image as following.
using (Graphics g = Graphics.FromImage(bitmap))
{
g.FillPolygon(colorBrush, points.ToArray());
}
FillPolygon method fills the pixels inside the polygon, in this case, the white pixels and the black pixels remains the same.
Now, I want just the opposite of this operation. That means, exterior pixels will be filled and interior pixels will remain the same. I this case, black pixels are exterior pixels.
Edit
I need this because let's say, I have a binary image of an object. I need to clip the pixels with background color(black) and the pixels inside the white polygon will remain unchanged.
You can do this by using a GraphicsPath as follows:
Add the polygon to the path.
Add a rectangle to the path which encompasses the area you want to "invert".
Use Graphics.FillPath() to fill the path.
For an example program, create a default Windows Forms app and override OnPaint() as follows:
protected override void OnPaint(PaintEventArgs e)
{
base.OnPaint(e);
var points = new []
{
new PointF(150, 250),
new PointF( 50, 500),
new PointF(250, 400),
new PointF(300, 100),
new PointF(500, 500),
new PointF(500, 50),
};
using (var path = new GraphicsPath())
{
path.AddPolygon(points);
// Uncomment this to invert:
// p.AddRectangle(this.ClientRectangle);
using (var brush = new SolidBrush(Color.Black))
{
e.Graphics.FillPath(brush, path);
}
}
}
If you run that (and resize the window) you'll see a black shape inside a white window.
Uncomment the indicated line and run the program and you'll see a white shape inside a black window (i.e. adding the ClientRectangle inverted it).
Related
Everywhere I look online, I see people posting on how to successfully crop an image. However, I want to 'crop'/ clear a hole out of an image. I want to keep the original image, but crop out a rectangle
As you can see in the image above, I have "cropped" out the kittens face. I maintained the original image, but removed only part of it. I cannot figure out how to do that.
Assuming you want to replace the original pixel colors with transparency you run into a small problem: You can't draw or fill with transparency in GDI+.
But you can use Graphics.Clear(Color.Transparent).
To do that you restrict the region where the Graphics object will draw. Here we can use the simple cropping rectangle but you can clear more complex shapes using a GraphicsPath..
Example using a bitmap bmp:
using (Graphics g = Graphics.FromImage(bmp))
{
Rectangle crop = new Rectangle(222,222,55,55);
g.SetClip(crop);
g.Clear(Color.Transparent);
}
bmp.Save(somefilename, ImageFormat.Png);
Setting your Graphics object's CompositingMode property to CompositingMode.SourceCopy will allow your drawing operations to replace the alpha value instead of proportionally opacifying it:
public static void TestDrawTransparent()
{
//This code will, successfully, draw something transparent overwriting an opaque area.
//More precisely, it creates a 100*100 fully-opaque red square with a 50*50 semi-transparent center.
using(Bitmap bmp = new Bitmap(100, 100, PixelFormat.Format32bppArgb))
{
using(Graphics g = Graphics.FromImage(bmp))
using(Brush opaqueRedBrush = new SolidBrush(Color.FromArgb(255, 255, 0, 0)))
using(Brush semiRedBrush = new SolidBrush(Color.FromArgb(128, 255, 0, 0)))
{
g.Clear(Color.Transparent);
Rectangle bigRect = new Rectangle(0, 0, 100, 100);
Rectangle smallRect = new Rectangle(25, 25, 50, 50);
g.CompositingMode = System.Drawing.Drawing2D.CompositingMode.SourceCopy;
g.FillRectangle(opaqueRedBrush, bigRect);
g.FillRectangle(semiRedBrush, smallRect);
}
bmp.Save(#"C:\FilePath\TestDrawTransparent.png", ImageFormat.Png);
}
}
In this code, I first draw a fully-opaque red square, then a semi-transparent red square "over" it. The result is a semi-transparent "hole" in the square:
And on a black background:
A zero-opacity brush works just as well, leaving a clear hole through the image (I checked).
With that in mind, you should be able to crop any shapes you want, simply by filling them with a zero-opacity brush.
I have a Rectangle (rec) that contains the area in which a smaller image is contained within a larger image. I want to display this smaller image on a Picturebox. However, what I really am doing is using the smaller image as a picture detector for a larger image that is 333x324. So what I want to do is use the coordinates of the smaller image rectangle, and then draw to the Picturebox, starting from lefthand side of the rectangle, going outwards by 333 width and 324 height.
Currently my code works but it only displays the small image that was being used for detection purposes. I want it to display the smaller image + 300 width and + 300 height.
I fiddled with this code for hours and I must be doing something extremely basic wrong. If anyone can help me I would appreciate it so much!
My code for the class:
public static class Worker
{
public static void doWork(object myForm)
{
//infinitely search for maps
for (;;)
{
//match type signature for Threading
var myForm1 = (Form1)myForm;
//capture screen
Bitmap currentBitmap = new Bitmap(CaptureScreen.capture());
//detect map
Detector detector = new Detector();
Rectangle rec = detector.searchBitmap(currentBitmap, 0.1);
//if it actually found something
if(rec.Width != 0)
{
// Create the new bitmap and associated graphics object
Bitmap bmp = new Bitmap(rec.X, rec.Y);
Graphics g = Graphics.FromImage(bmp);
// Draw the specified section of the source bitmap to the new one
g.DrawImage(currentBitmap, 0,0, rec, GraphicsUnit.Pixel);
// send to the picture box &refresh;
myForm1.Invoke(new Action(() =>
{
myForm1.getPicturebox().Image = bmp;
myForm1.getPicturebox().Refresh();
myForm1.Update();
}));
// Clean up
g.Dispose();
bmp.Dispose();
}
//kill
currentBitmap.Dispose();
//do 10 times per second
System.Threading.Thread.Sleep(100);
}
}
}
If I understand correctly, the rec variable contains a rectangle with correct X and Y which identifies a rectangle with Width=333 and Height=324.
So inside the if statement, start by setting the desired size:
rec.Width = 333;
rec.Height = 324;
Then, note that the Bitmap constructor expects the width and height, so change
Bitmap bmp = new Bitmap(rec.X, rec.Y);
to
Bitmap bmp = new Bitmap(rec.Width, rec.Height);
and that's it - the rest of the code can stay the way it is now.
I am learning about GraphicsPath and Region. And using it with Invalidate.
So, I have a Rectangle object and I want to erase this rectangle. But, I only want to erase the edge of the rectangle (that is, the lines).
At the moment I have this:
if(bErase)
{
Rectangle rcRubberBand = GetSelectionRectangle();
GraphicsPath path = new GraphicsPath();
path.AddRectangle(rcLastRubberBand);
Region reg = new Region(path);
myControl3.Invalidate(reg);
myControl3.Update();
}
It works, but it is invalidating the complete rectangle shape. I only need to invalidate the rectangle lines that I had drawn. Can I make such a path with GraphicsPath?
You can't get the system to invalidate anything but a full rectangle.
So you can't use an outline path to save time.
However it can be useful for other things. Let's look at two options :
You can create an outline path
You can exclude parts of a region
The simplest way to create an outline GraphicsPath is to widen a given path with a Pen:
GraphicsPath gp = new GraphicsPath();
gp.AddRectangle(r0);
using (Pen pen = new Pen(Color.Green, 3f)) gp.Widen(pen);
This let's you make use of all the many options of a Pen, including DashStyles, Alignment, LineJoins etc..
An alternative way is to create it with the default FillMode.Alternate and simply add a smaller figure:
Rectangle r0 = new Rectangle(11, 11, 333, 333);
Rectangle r1 = r0;
r1.Inflate(-6, -6);
GraphicsPath gp = new GraphicsPath();
gp.AddRectangle(r0);
gp.AddRectangle(r1);
Now you can fill the path
g.FillPath(Brushes.Red, gp);
or use it to clip the ClipBounds of a Graphics object g :
g.SetClip(gp);
After this anything you draw including a Clear will only affect the pixels inside the outline.
When you are done you can write:
g.ResetClip();
and continue drawing on the full size of your graphics target.
Or you can use the path as the basis for a Region:
Region r = new Region(gp);
and restrict a Control to it..:
somecontrol.Region = r;
Regions support several set operations so instead of using the above outline path you could also write this with the same result:
Region r = new Region(r0);
r.Exclude(r1);
I have written a small application which will be used in my work environment for cropping images. The windows form (.NET 3.5) that contains the image has a transparent rectangle which I use for dragging over a section of an image and hitting a button to get me whatever was behind the rectangle.
Currently I am using the code below, this is causing me issues because the area that it is capturing is off by quite a few pixels, and I think it's something to do with my CopyFromScreen function.
//Pass in a rectangle
private void SnapshotImage(Rectangle rect)
{
Point ptPosition = new Point(rect.X, rect.Y);
Point ptRelativePosition;
//Get me the screen coordinates, so that I get the correct area
ptRelativePosition = PointToScreen(ptPosition);
//Create a new bitmap
Bitmap bmp = new Bitmap(rect.Width, rect.Height, PixelFormat.Format32bppArgb);
//Sort out getting the image
Graphics g = Graphics.FromImage(bmp);
//Copy the image from screen
g.CopyFromScreen(this.Location.X + ptPosition.X, this.Location.Y + ptPosition.Y, 0, 0, bmp.Size, CopyPixelOperation.SourceCopy);
//Change the image to be the selected image area
imageControl1.Image.ChangeImage(bmp);
}
If anyone can spot why when the image is redrawn its quite a bit out, I'd be eternally grateful at this point. Also, the ChangeImage function is fine - it works if I use a form as a select area but using a rectangle has jazzed things up a bit.
You've retrieved the relative position to the screen as ptRelativePosition, but you never actually use that - you add the rectangle's location to your form's location, which doesn't account for the form's border.
Here's that fixed, with a few optimizations:
// Pass in a rectangle
private void SnapshotImage(Rectangle rect)
{
// Get me the screen coordinates, so that I get the correct area
Point relativePosition = this.PointToScreen(rect.Location);
// Create a new bitmap
Bitmap bmp = new Bitmap(rect.Width, rect.Height, PixelFormat.Format32bppArgb);
// Copy the image from screen
using(Graphics g = Graphics.FromImage(bmp)) {
g.CopyFromScreen(relativePosition, Point.Empty, bmp.Size);
}
// Change the image to be the selected image area
imageControl1.Image.ChangeImage(bmp);
}
Interestingly, this was because of the space between the main form and the control that the image was on and the toolbar at the top of the form separating the control and the top of the main form. To get around this I simply modified one line in capture screen to account for those pixels, as shown below:
g.CopyFromScreen(relativePosition.X + 2, relativePosition.Y+48, Point.Empty.X, Point.Empty.Y, bmp.Size);
Cheers
I'm facing a really perplexing problem..
I have a .Net 2.0 C# WinForms project.
I'm trying to stretch a bitmap onto a drawing area, but for some reason it is not stretched properly - I get alpha channel gradient on the right and bottom margins of my drawing area.
It took me quite a while to isolate this problem. I create a few lines of code that reproduce the problem (see code snippet and screenshot below).
Can anyone please shed some light over this matter?
Thanks in advance.
--
private void Form1_Paint( object sender, PaintEventArgs e )
{
// Create a black bitmap resource sized 10x10
Image resourceImg = new Bitmap( 10, 10 );
Graphics g = Graphics.FromImage( resourceImg );
g.FillRectangle( Brushes.Black, 0, 0, resourceImg.Width, resourceImg.Height );
Rectangle drawingArea = new Rectangle( 0, 0, 200, 200 ); // Set the size of the drawing area
e.Graphics.FillRectangle( Brushes.Aqua, drawingArea ); // Fill an aqua colored rectangle
e.Graphics.DrawImage( resourceImg, drawingArea ); // Stretch the resource image
// Expected result: The resource image should completely cover the aqua rectangle.
// Actual Result: The right and bottom edges become gradiently transparent (revealing the aqua rectangle under it)
}
The behavior has to do with how GDI+ handles edges. In this case, you're scaling a very small image over a large area, and you haven't told GDI+ how to handle the edge. If you use the ImageAttributes class and set the WrapMode appropriately, you can get around this issue.
For example:
private void Form1_Paint(object sender, PaintEventArgs e)
{
using (var resourceImg = new Bitmap(10, 10))
{
using (var g = Graphics.FromImage(resourceImg))
{
g.FillRectangle(Brushes.Black, 0, 0,
resourceImg.Width, resourceImg.Height);
}
var drawingArea = new Rectangle(0, 0, 200, 200);
e.Graphics.FillRectangle(Brushes.Aqua, drawingArea);
using (var attribs = new ImageAttributes())
{
attribs.SetWrapMode(WrapMode.TileFlipXY);
e.Graphics.DrawImage(resourceImg, drawingArea,
0, 0, resourceImg.Width, resourceImg.Height,
GraphicsUnit.Pixel, attribs);
}
}
}
The above code should produce an all black image. If you comment out the attribs.SetWrapMode(WrapMode.TileFlipXY); statement, you should see the blue gradient. With the wrap mode set, you're telling GDI+ to flip the image at the edges, so it will pick up more black and not fade things out at the edge when it scales the image.