Develop Reference

Using a generic stream to create a zipped file with SharpCompress

Since System.IO.Compression seems to be out of reach for now if I want to use both dotnet core + net461, I've tried with SharpCompress.
The "read zip" part was easy, but I am having trouble finding out how to write to a zip stream.
The wiki of the project is a bit outdated. This is the only example that I've found that applies to writing to streams. I've tried to follow it and adapt it to my needs, but I am stuck at the exception it throws:
using Microsoft.VisualStudio.TestTools.UnitTesting;
using SharpCompress.Common;
using SharpCompress.Compressors.Deflate;
using SharpCompress.Writers;
using System;
using System.IO;
namespace DbManager.DjdbCore.Tests
{
[TestClass]
public class ZipTests
{
public ZipTests()
{
Directory.SetCurrentDirectory(AppContext.BaseDirectory);
}
[TestMethod]
public void Test()
{
var zip = File.OpenWrite(#"..\..\..\..\..\test-resources\zip_file_test.zip");
var writerOptions = new WriterOptions(CompressionType.Deflate);
var zipWriter = WriterFactory.Open(zip, ArchiveType.Zip, writerOptions);
var memoryStream = new MemoryStream();
var binaryWriter = new BinaryWriter(memoryStream);
binaryWriter.Write("Test string inside binary file - text to fill it up: qoiwjqefñlawijfñlaskdjfioqwjefñalskvndñaskvnqo`wiefowainvñaslkfjnwpowiqjfeopwiqjnfjñlaskdjfñlasdfjiowiqjefñaslkdjfñalskjfpqwoiefjqw");
var deflateStream = new DeflateStream(memoryStream, SharpCompress.Compressors.CompressionMode.Compress);
deflateStream.Write(memoryStream.ToArray(), 0, Convert.ToInt32(memoryStream.Length));
// EXCEPTION: SharpCompress.Compressors.Deflate.ZlibException: 'Cannot Read after Writing.'
// Source code: if (_streamMode != StreamMode.Reader) { throw new ZlibException("Cannot Read after Writing."); }
zipWriter.Write("test_file_inside_zip.bin", deflateStream, DateTime.Now);
zip.Flush();
zipWriter.Dispose();
zip.Dispose();
}
}
}
In case it helps, this is what I used (and it worked, but only in dotnet core) using the library System.IO.Compression:
private void WriteAsZipBinary()
{
//Open the zip file if it exists, else create a new one
var zip = ZipPackage.Open(this.FileFullPath, FileMode.OpenOrCreate, FileAccess.ReadWrite);
var zipStream = ZipManager.GetZipWriteStream(zip, nameOfFileInsideZip);
var memoryStream = new MemoryStream();
var binaryWriter = new BinaryWriter(memoryStream);
// Here is where strings etc are written to the binary file:
WriteStuffInBinaryStream(ref binaryWriter);
//Read all of the bytes from the file to add to the zip file
byte[] bites = new byte[Convert.ToInt32(memoryStream.Length - 1) + 1];
memoryStream.Position = 0;
memoryStream.Read(bites, 0, Convert.ToInt32(memoryStream.Length));
binaryWriter.Dispose();
binaryWriter = null;
memoryStream.Dispose();
memoryStream = null;
zipStream.Position = 0;
zipStream.Write(bites, 0, bites.Length);
zip.Close();
}
public static Stream GetZipWriteStream(Package zip, string renamedFileName)
{
//Replace spaces with an underscore (_)
string uriFileName = renamedFileName.Replace(" ", "_");
//A Uri always starts with a forward slash "/"
string zipUri = string.Concat("/", Path.GetFileName(uriFileName));
Uri partUri = new Uri(zipUri, UriKind.Relative);
string contentType = "Zip"; // System.Net.Mime.MediaTypeNames.Application.Zip;
//The PackagePart contains the information:
// Where to extract the file when it's extracted (partUri)
// The type of content stream (MIME type): (contentType)
// The type of compression: (CompressionOption.Normal)
PackagePart pkgPart = zip.CreatePart(partUri, contentType, CompressionOption.Normal);
//Compress and write the bytes to the zip file
return pkgPart.GetStream();
}

I'll post here the answer on github from #adamhathcock (the owner of the project):
[TestMethod]
public void Test()
{
var writerOptions = new WriterOptions(CompressionType.Deflate);
using(var zip = File.OpenWrite(#"..\..\..\..\..\test-resources\zip_file_test.zip"))
using(var zipWriter = WriterFactory.Open(zip, ArchiveType.Zip, writerOptions))
{
var memoryStream = new MemoryStream();
var binaryWriter = new BinaryWriter(memoryStream);
binaryWriter.Write("Test string inside binary file - text to fill it up: qoiwjqefñlawijfñlaskdjfioqwjefñalskvndñaskvnqo`wiefowainvñaslkfjnwpowiqjfeopwiqjnfjñlaskdjfñlasdfjiowiqjefñaslkdjfñalskjfpqwoiefjqw");
memoryStream.Position = 0;
zipWriter.Write("test_file_inside_zip.bin", memoryStream, DateTime.Now);
}
}
2 things:
You forgot to reset the MemoryStream after writing to it so it can be read.
You don't need to manually use the DeflateStream. You've told the ZipWriter what compression to use. If it worked, you would have double compressed the bytes which would be garbage really.

How can I unzip a file to a .NET memory stream?

I have files (from 3rd parties) that are being FTP'd to a directory on our server. I download them and process them even 'x' minutes. Works great.
Now, some of the files are .zip files. Which means I can't process them. I need to unzip them first.
FTP has no concept of zip/unzipping - so I'll need to grab the zip file, unzip it, then process it.
Looking at the MSDN zip api, there seems to be no way i can unzip to a memory stream?
So is the only way to do this...
Unzip to a file (what directory? need some -very- temp location ...)
Read the file contents
Delete file.
NOTE: The contents of the file are small - say 4k <-> 1000k.

Zip compression support is built in:
using System.IO;
using System.IO.Compression;
// ^^^ requires a reference to System.IO.Compression.dll
static class Program
{
const string path = ...
static void Main()
{
using(var file = File.OpenRead(path))
using(var zip = new ZipArchive(file, ZipArchiveMode.Read))
{
foreach(var entry in zip.Entries)
{
using(var stream = entry.Open())
{
// do whatever we want with stream
// ...
}
}
}
}
}
Normally you should avoid copying it into another stream - just use it "as is", however, if you absolutely need it in a MemoryStream, you could do:
using(var ms = new MemoryStream())
{
stream.CopyTo(ms);
ms.Position = 0; // rewind
// do something with ms
}

You can use ZipArchiveEntry.Open to get a stream.
This code assumes the zip archive has one text file.
using (FileStream fs = new FileStream(path, FileMode.Open))
using (ZipArchive zip = new ZipArchive(fs) )
{
var entry = zip.Entries.First();
using (StreamReader sr = new StreamReader(entry.Open()))
{
Console.WriteLine(sr.ReadToEnd());
}
}

using (ZipArchive archive = new ZipArchive(webResponse.GetResponseStream()))
{
foreach (ZipArchiveEntry entry in archive.Entries)
{
Stream s = entry.Open();
var sr = new StreamReader(s);
var myStr = sr.ReadToEnd();
}
}

Looks like here is what you need:
using (var za = ZipFile.OpenRead(path))
{
foreach (var entry in za.Entries)
{
using (var r = new StreamReader(entry.Open()))
{
//your code here
}
}
}

You can use SharpZipLib among a variety of other libraries to achieve this.
You can use the following code example to unzip to a MemoryStream, as shown on their wiki:
using ICSharpCode.SharpZipLib.Zip;
// Compresses the supplied memory stream, naming it as zipEntryName, into a zip,
// which is returned as a memory stream or a byte array.
//
public MemoryStream CreateToMemoryStream(MemoryStream memStreamIn, string zipEntryName) {
MemoryStream outputMemStream = new MemoryStream();
ZipOutputStream zipStream = new ZipOutputStream(outputMemStream);
zipStream.SetLevel(3); //0-9, 9 being the highest level of compression
ZipEntry newEntry = new ZipEntry(zipEntryName);
newEntry.DateTime = DateTime.Now;
zipStream.PutNextEntry(newEntry);
StreamUtils.Copy(memStreamIn, zipStream, new byte[4096]);
zipStream.CloseEntry();
zipStream.IsStreamOwner = false; // False stops the Close also Closing the underlying stream.
zipStream.Close(); // Must finish the ZipOutputStream before using outputMemStream.
outputMemStream.Position = 0;
return outputMemStream;
// Alternative outputs:
// ToArray is the cleaner and easiest to use correctly with the penalty of duplicating allocated memory.
byte[] byteArrayOut = outputMemStream.ToArray();
// GetBuffer returns a raw buffer raw and so you need to account for the true length yourself.
byte[] byteArrayOut = outputMemStream.GetBuffer();
long len = outputMemStream.Length;
}

Ok so combining all of the above, suppose you want to in a very simple way take a zip file called
"file.zip" and extract it to "C:\temp" folder. (Note: This example was only tested for compress text files) You may need to do some modifications for binary files.
using System.IO;
using System.IO.Compression;
static void Main(string[] args)
{
//Call it like this:
Unzip("file.zip",#"C:\temp");
}
static void Unzip(string sourceZip, string targetPath)
{
using (var z = ZipFile.OpenRead(sourceZip))
{
foreach (var entry in z.Entries)
{
using (var r = new StreamReader(entry.Open()))
{
string uncompressedFile = Path.Combine(targetPath, entry.Name);
File.WriteAllText(uncompressedFile,r.ReadToEnd());
}
}
}
}

Read last line in open file [duplicate]

This question already has answers here:
How to read a text file reversely with iterator in C#
(11 answers)
Closed 8 years ago.
I'm fairly new all this, but I feel like I'm pretty close to making this work, I just need a little help! I want to create a DLL which can read and return the last line in a file that is open in another application. This is what my code looks like, I just don't know what to put in the while statement.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.IO;
namespace SharedAccess
{
public class ReadShare {
static void Main(string path) {
FileStream stream = File.Open(path, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
StreamReader reader = new StreamReader(stream);
while (!reader.EndOfStream)
{
//What goes here?
}
}
}
}

To read last line,
var lastLine = File.ReadLines("YourFileName").Last();
If it's a large File
public static String ReadLastLine(string path)
{
return ReadLastLine(path, Encoding.ASCII, "\n");
}
public static String ReadLastLine(string path, Encoding encoding, string newline)
{
int charsize = encoding.GetByteCount("\n");
byte[] buffer = encoding.GetBytes(newline);
using (FileStream stream = new FileStream(path, FileMode.Open))
{
long endpos = stream.Length / charsize;
for (long pos = charsize; pos < endpos; pos += charsize)
{
stream.Seek(-pos, SeekOrigin.End);
stream.Read(buffer, 0, buffer.Length);
if (encoding.GetString(buffer) == newline)
{
buffer = new byte[stream.Length - stream.Position];
stream.Read(buffer, 0, buffer.Length);
return encoding.GetString(buffer);
}
}
}
return null;
}
I refered here,
How to read only last line of big text file

File ReadLines should work for you.
var value = File.ReadLines("yourFile.txt").Last();

Why does one method of string compression return an empty string but another one doesn't?

I'm using GZipStream to compress a string, and I've modified two different examples to see what works. The first code snippet, which is a heavily modified version of the example in the documentation, simply returns an empty string.
public static String CompressStringGzip(String uncompressed)
{
String compressedString;
// Convert the uncompressed source string to a stream stored in memory
// and create the MemoryStream that will hold the compressed string
using (MemoryStream inStream = new MemoryStream(Encoding.Unicode.GetBytes(uncompressed)),
outStream = new MemoryStream())
{
using (GZipStream compress = new GZipStream(outStream, CompressionMode.Compress))
{
inStream.CopyTo(compress);
StreamReader reader = new StreamReader(outStream);
compressedString = reader.ReadToEnd();
}
}
return compressedString;
and when I debug it, all I can tell is nothing is read from reader, which is compressedString is empty. However, the second method I wrote, modified from a CodeProject snippet is successful.
public static String CompressStringGzip3(String uncompressed)
{
//Transform string to byte array
String compressedString;
byte[] uncompressedByteArray = Encoding.Unicode.GetBytes(uncompressed);
using (MemoryStream outStream = new MemoryStream())
{
using (GZipStream compress = new GZipStream(outStream, CompressionMode.Compress))
{
compress.Write(uncompressedByteArray, 0, uncompressedByteArray.Length);
compress.Close();
}
byte[] compressedByteArray = outStream.ToArray();
StringBuilder compressedStringBuilder = new StringBuilder(compressedByteArray.Length);
foreach (byte b in compressedByteArray)
compressedStringBuilder.Append((char)b);
compressedString = compressedStringBuilder.ToString();
}
return compressedString;
}
Why is the first code snippet not successful while the other one is? Even though they're slightly different, I don't know why the minor changes in the second snippet allow it to work. The sample string I'm using is SELECT * FROM foods f WHERE f.name = 'chicken';

I ended up using the following code for compression and decompression:
public static String Compress(String decompressed)
{
byte[] data = Encoding.UTF8.GetBytes(decompressed);
using (var input = new MemoryStream(data))
using (var output = new MemoryStream())
{
using (var gzip = new GZipStream(output, CompressionMode.Compress, true))
{
input.CopyTo(gzip);
}
return Convert.ToBase64String(output.ToArray());
}
}
public static String Decompress(String compressed)
{
byte[] data = Convert.FromBase64String(compressed);
using (MemoryStream input = new MemoryStream(data))
using (GZipStream gzip = new GZipStream(input, CompressionMode.Decompress))
using (MemoryStream output = new MemoryStream())
{
gzip.CopyTo(output);
StringBuilder sb = new StringBuilder();
return Encoding.UTF8.GetString(output.ToArray());
}
}
The explanation for a part of the problem comes from this question. Although I fixed the problem by changing the code to what I included in this answer, these lines (in my original code):
foreach (byte b in compressedByteArray)
compressedStringBuilder.Append((char)b);
are problematic, because as dlev aptly phrased it:
You are interpreting each byte as its own character, when in fact that is not the case. Instead, you need the line:
string decoded = Encoding.Unicode.GetString(compressedByteArray);
The basic problem is that you are converting to a byte array based on an encoding, but then ignoring that encoding when you retrieve the bytes.
Therefore, the problem is solved, and the new code I'm using is much more succinct than my original code.

You need to move the code below outside the second using statement:
using (GZipStream compress = new GZipStream(outStream, CompressionMode.Compress))
{
inStream.CopyTo(compress);
outStream.Position = 0;
StreamReader reader = new StreamReader(outStream);
compressedString = reader.ReadToEnd();
}
CopyTo() is not flushing the results to the underlying MemoryStream.
Update
Seems that GZipStream closes and disposes it's underlying stream when it is disposed (not the way I would have designed the class). I've updated the sample above and tested it.

Create new FileStream out of a byte array

I am attempting to create a new FileStream object from a byte array. I'm sure that made no sense at all so I will try to explain in further detail below.
Tasks I am completing:
1) Reading the source file which was previously compressed
2) Decompressing the data using GZipStream
3) copying the decompressed data into a byte array.
What I would like to change:
1) I would like to be able to use File.ReadAllBytes to read the decompressed data.
2) I would then like to create a new filestream object usingg this byte array.
In short, I want to do this entire operating using byte arrays. One of the parameters for GZipStream is a stream of some sort, so I figured I was stuck using a filestream. But, if some method exists where I can create a new instance of a FileStream from a byte array - then I should be fine.
Here is what I have so far:
FolderBrowserDialog fbd = new FolderBrowserDialog(); // Shows a browser dialog
fbd.ShowDialog();
// Path to directory of files to compress and decompress.
string dirpath = fbd.SelectedPath;
DirectoryInfo di = new DirectoryInfo(dirpath);
foreach (FileInfo fi in di.GetFiles())
{
zip.Program.Decompress(fi);
}
// Get the stream of the source file.
using (FileStream inFile = fi.OpenRead())
{
//Create the decompressed file.
string outfile = #"C:\Decompressed.exe";
{
using (GZipStream Decompress = new GZipStream(inFile,
CompressionMode.Decompress))
{
byte[] b = new byte[blen.Length];
Decompress.Read(b,0,b.Length);
File.WriteAllBytes(outfile, b);
}
}
}
Thanks for any help!
Regards,
Evan

It sounds like you need to use a MemoryStream.

Since you don't know how many bytes you'll be reading from the GZipStream, you can't really allocate an array for it. You need to read it all into a byte array and then use a MemoryStream to decompress.
const int BufferSize = 65536;
byte[] compressedBytes = File.ReadAllBytes("compressedFilename");
// create memory stream
using (var mstrm = new MemoryStream(compressedBytes))
{
using(var inStream = new GzipStream(mstrm, CompressionMode.Decompress))
{
using (var outStream = File.Create("outputfilename"))
{
var buffer = new byte[BufferSize];
int bytesRead;
while ((bytesRead = inStream.Read(buffer, 0, BufferSize)) != 0)
{
outStream.Write(buffer, 0, bytesRead);
}
}
}
}

Here is what I ended up doing. I realize that I did not give sufficient information in my question - and I apologize for that - but I do know the size of the file I need to decompress as I am using it earlier in my program. This buffer is referred to as "blen".
string fi = #"C:\Path To Compressed File";
// Get the stream of the source file.
// using (FileStream inFile = fi.OpenRead())
using (MemoryStream infile1 = new MemoryStream(File.ReadAllBytes(fi)))
{
//Create the decompressed file.
string outfile = #"C:\Decompressed.exe";
{
using (GZipStream Decompress = new GZipStream(infile1,
CompressionMode.Decompress))
{
byte[] b = new byte[blen.Length];
Decompress.Read(b,0,b.Length);
File.WriteAllBytes(outfile, b);
}
}
}