C# If(textbox.text=number) error - c#

I making a quiz in which users would have to enter a number (e.g. 4) into a TextBox then the program would check if the number entered is correct. Unfortunately, I'm having some trouble with this part of the code.
So currently I have this code:
if(textbox1.Text=4)
but the 4 is underlined with the error message:
cannot implicitly convert type 'int' to 'string'.
Can I trouble you all to help me find out what's wrong with my code? Thank you so much!!

Since textbox1.Text is of type string, you have to parse:
int answer;
// TryParse - the value entered can be treated as a valid integer
// answer == correctAnswer - the answer provided is a correct one
if (int.TryParse(textbox1.Text, out answer) && answer == correctAnswer) {
...
}
Please, notice that the implementation tolerates leading and traling spaces (typical problem in quizes): if user happens to input "4 " (trailing space) the answer will be accepted providing that correctAnswer == 4

if(textbox1.Text == Convert.ToString(4))
or
if(textbox1.Text == "4")

You need to parse to int
if(Int32.Parse(textbox1.Text) == 4)

You are comparing a string (textbox1.Text) with an integer (4). To make this work you have to compare same data types. Some options:
if(textbox1.Text == "4")
or
if(textbox1.Text == 4.ToString())
or
if(int.Parse(textbox1.Text) == 4)
NOTE: In the last option you can get an exception if the text in the textbox is not a number. So if you want to convert to integer than I would suggest:
int guessedNumber;
Int32.TryParse(textbox1.Text, out guessedNumber);
if(guessedNumber == 4)

You are trying to compare a string with an int.
You need to use if(textbox1.text == "4")
also note the double == for comparisons

The Text property is of type string and 4 is an int so the comparison results in a compile time error.
Use the following code to perform the check.
if (int.Parse(textbox1.Text) == 4)
{
// do something
}
If you're unsure whether the user is going to provide the input correctly or if you haven't set any validations on the model, then you should parse the input and then check whether the user entered 4. Here's the rextester link
//Rextester.Program.Main is the entry point for your code. Don't change it.
//Compiler version 4.0.30319.17929 for Microsoft (R) .NET Framework 4.5
using System;
namespace Rextester
{
public class Program
{
public static void Main(string[] args)
{
var input = "hello 4";
// var input = "4";
int number;
var isNumber = int.TryParse(input, out number);
if (isNumber)
{
if (number == 4)
{
Console.WriteLine("The Number is 4");
}
else
{
Console.WriteLine("The Number isn't 4");
}
}
else
{
Console.WriteLine("Not a valid number");
}
}
}
}

if(textbox1.Text == "4")
{
//Do Something
}
One way or another, you have to make sure both values are to make sure you are comparing two values "==" (not "=", unless u want to change the value) and that both values are same data type

Related

Check answer button has incorrect input string format

I am trying to create a check answer button. I have not learned how to use methods yet so i cannot use them in this. I first need to check if the math operation is subtraction or addition and then go from there. Visual studio does not detect any errors but when i run the program and try to check the answer ive inputted i get an error telling me unhandled exception has occured and that input string was not in correct format. I have a feeling the proble is with my int lblMath but im not sure how else to check what the value is inside of that lbl.
{
int First = int.Parse(lblFirst.Text);//The first number in the math equation
int Second = int.Parse(lblSecond.Text);//The second number in the math equation
int UserAnswer = Convert.ToInt32(txtAnswer.Text);//The users answer to math question
int lblMath = int.Parse(lblMathType.Text);//Whether the symbol is + or -
if(lblMath == '+')
{
int AnswerAdd = First + Second;
//Answer is addition
if(UserAnswer == AnswerAdd)
{
MessageBox.Show("Correct");
}
else if(UserAnswer != AnswerAdd)
{
MessageBox.Show("Wrong Answer");
}
}
else if (lblMath == '-')
{
int AnswerSub = First - Second;
//Answer is subtraction
if(UserAnswer == AnswerSub)
{
MessageBox.Show("Correct");
}
else if (UserAnswer != AnswerSub)
{
MessageBox.Show("Wrong Answer");
}
}
You're expecting this to be an integer:
int lblMath = int.Parse(lblMathType.Text);
But then you're immediately expecting it to be a string:
if(lblMath == '+')
(I'm honestly surprised this even compiles.)
What integer value to you expect the string "+" to be and why? The exception is telling you that the string "+" is not an integer. Because it isn't.
It's a string. Use it as a string:
string lblMath = lblMathType.Text;

How do i check if an input matches a specific letter?

I can't figure out how to check whether the input is a specific letter. I know how to check if it's a specific int/double but when it's a string I don't know what to do.
Any help would be greatly appreciated. I'm just trying to make a basic 3 question quiz that checks whether the user answers with the correct letter (a, b or c) and then adds that to the current score.
class Program
{
static void Main()
{
var a1 = "a";
var a2 = "b";
var a3 = "c";
var qa = 0;
while (qa != 3)
{
if (qa == 0)
{
Console.Write("What is the answer to question 1? ");
var entry1 = Console.Read();
if()
{
}
}
else if (qa == 1)
{
Console.Write("What is the answer to question 2? ");
Console.ReadLine();
}
else if (qa == 2)
{
Console.Write("What is the answer to question 3? ");
Console.ReadLine();
}
}
}
}
For example operator == can't be applied to strings
this is not true. It can be applied:
if(entry.ToString() == a1)
The documentation for the == operator tells us:
For the string type, == compares the values of the strings
another possibility would be to use the String.Equals method
if(entry.ToString().Equals(a1))
EDIT:
Looking closer at your code I realized that you are using Console.Read
which
Reads the next character from the standard input stream.
That means that it returns a char (and only 1).
I guess you want the entire line that the user types in. So you should use ReadLine instead. It returns a string and allows you for a direct comparison
string entry1 = Console.ReadLine();
if(entry == a1)
when you use var for the declaration of types the compiler infers the type and the error becomes obvious at a later stage. you cannot use the == operator on string and char . Read() returns a char so that's why you were not able to compare it in the first place
Note that in "Question 1" you wrote Console.Read(), (not Console.ReadLine()) which returns a char, not a string. So "==" cannot be applied to entry1 and a1 since entry1 will be a char while a1 is a string.
If you compare compatible variables, everything should be fine
string input1;
var input2 = "";
var input3 = 0;
// assign some input values, then compare
// strings
if (input1 == "a") // ok
{ }
if (input2 == "a") // ok
{ }
if (input3 == "a") // not ok, comparing int to string
{ }
// numbers
if (input1 == 1) // not ok, comparing string to int
{ }
if (input3 == 1) // ok
{ }
If you want to, you could try matching the ASCII value of the character by using Console.Read();. This would eliminate the need to press enter. If you were trying to match to uppercase A:
int input = Console.Read();
if (input == (int)char.GetNumericValue(A))
{
Console.WriteLine("True");
Console.Read();
}
else
{
Console.WriteLine("False");
Console.Read();
}

Y/N or y/n in loop

I have trouble implementing the Y/N or y/n in the loop. I've designed it in a way that a user can use both the capital and small letters of the Y and N for their answer in a loop. by the way here's my code but can't seem to make it work:
do
{
Console.WriteLine("\nSelect additional topping/s\n");
Console.WriteLine("1 - Extra meat: 200");
Console.WriteLine("2 - Extra cheese: 100");
Console.WriteLine("3 - Extra veggies: 80\n");
int selectedTopping = Convert.ToInt32(Console.ReadLine());
switch (selectedTopping)
{
case 1:
pizza = new MeatToppings(pizza);
break;
case 2:
pizza = new CheeseToppings(pizza);
break;
case 3:
pizza = new VeggieToppings(pizza);
break;
default:
break;
}
Console.WriteLine("\nAdd more toppings? Y/N");
}
while ((Console.ReadLine() == "Y") || (Console.ReadLine() == "y"));
while ((Console.ReadLine() == "Y") || (Console.ReadLine() == "y"));
This is going to read 2 different lines since you're calling ReadLine() twice. You need to call it once and save the value.
You can use ToUpper
while ((Console.ReadLine().ToUpper() == "Y") );
Try to use String.Equals and StringComparison:
String.Equals(Console.ReadLine(), "y", StringComparison.CurrentCultureIgnoreCase);
from MSDN:
CurrentCultureIgnoreCase: Compare strings using culture-sensitive sort rules, the current culture, and ignoring the case of the strings being compared.
OrdinalIgnoreCase: Compare strings using ordinal sort rules and ignoring the case of the strings being compared.
To check Y or y ignoring case, you should use string.Equals(string,StringComparison) overload.
while (Console.ReadLine().Equals("Y", StringComparison.InvariantCultureIgnoreCase));
Please see the The Turkish İ Problem and Why You Should Care before using ToUpper or ToLower for string comparison with ignore case.
Your current code is reading the lines from console twice, that is why your code is holding up for the 2nd value.
As Austin just pointed out, you are using ReadLine twice in the while loop statement.
One thing worth mentioning is try to follow the rule of modularity, it will help speed up implementing and debugging our code.
It's been a while since I did any C# programming so sudo-coding this in Java style.
Since it's a command line programming you are probably have to validate user input more than once. One thing I would do is make a utility class to contains common user input tasks.
public class TerminalUtil {
private TerminalUtil() {}
public static boolean isYes(String msg){ return (msg.ToUpper() == "Y" || msg.ToUpper() == "YES"); }
public static boolean isNo(String msg){ return (msg.ToUpper() == "N" || msg.ToUpper() == "NO"); }
// You also might want basic conditionals to check if string is numeric or contains letters.
// I like using recursion for command line utilities so having a method that can re-print messages is handy
public static void display(String[] messages){
for(String msg : messages){
Console.WriteLine(msg);
}
}
public static boolean enterYesOrNo(String[] messages, String[] errorMessages){
display(messages)
String input = Console.ReadLine();
if( isYes(input) ){
return true;
} else if( isNo(input) ){
return false;
} else {
display(errorMessages); // Maybe something like, you didn't enter a yes or no value.
enterYesOrNo(messages, errorMessages); // Recursive loop to try again.
}
}
}
Here is what the code to order a pizza might look like
public class OrderPizza{
public static int selectToppings(){
String[] message = new String[4];
message[0] = ("\nSelect additional topping/s\n");
message[1] = ("1 - Extra meat: 200");
message[2] = ("2 - Extra cheese: 100");
message[3] = ("3 - Extra veggies: 80\n");
int option = TerminalUtils.entryNumeric(message, {"You entered an non-numeric character, try again"} );
if( option > 0 && option <= 3 ){
return option;
} else {
Console.WriteLine("Number must be between 1 - 3, try again.");
return selectToppings();
}
}
public static Pizza order(){
Pizza pizza = new Pizza();
while(true){
int toppingCode = selectTopping();
pizza.addTopping(toppingCode);
if(!TerminalUtil.enterYesOrNo({"\nAdd more toppings? Y/N"}, {"Please enter a 'Y'es or 'N'o"}) ){
break;
}
}
}
}
The main benefit of this is that the business logic of the while loop has been reduced and you can reuse the code in TerminalUtils. Also this is by no mean a elegant solution, I'm lazy and it's 3am IRL, but it's should be enough to the ball rolling.
One thing you should probably reconsider doing is using integer codes to represent toppings. Using an enum might make things easier to implement.
I also notice that you add three different types of pizza's, which I'm assuming three separate objects.
Since you are looping to add toppings to a pizza, make an abstract class of pizza. This way you could extend it generic pre-built pizzas such as pepperoni or cheese and use the abstract pizza class if you want the customer to customize their order.
I didn't found better way than:
while ( str!="N" )
{
str = Console.ReadLine();
str = str.ToUpper();
if (str == "Y");
break;
};

C#- Getting user input for Age.. but receiving error?

I am trying to make improve my programming and getting things drilled into my head so I'm just quickly developing an application that gets user's input and prints their name. But also gets their input for "Age verification".
I'm practicing IF & ELSE statements as well as nesting classes.
However my compiler is shooting me an error and I just cannot seem to figure it out. I'm trying to get the user to input his age, and then proceed with the IF & ELSE statement.
Compiler is shooting error that . ""Cannot implicitly convert type
string to int"
The only error in the program right now is the
myCharacter.age = Console.ReadLine();
using System;
namespace csharptut
{
class CharPrintName
{
static void Main()
{
Character myCharacter = new Character();
Console.WriteLine("Please enter your name to continue: ");
myCharacter.name = Console.ReadLine();
Console.WriteLine("Hello {0}!", myCharacter.name);
Console.WriteLine("Please enter your age for verification purposes: ");
myCharacter.age = Console.ReadLine();
if (myCharacter.age <= 17)
{
Console.WriteLine("I'm sorry {0}, you're too young to enter!",myCharacter.name);
}
else if (myCharacter.age >= 18)
{
Console.WriteLine("You can enter!");
}
}
}
class Character
{
public string name;
public int age;
}
}
As the error says you can't implicitly type a string to an int. You need to parse it into an int.
string input = Console.ReadLine();
int age;
if (int.TryParse(input, out age)
{
// input is an int
myCharacter.age = age;
}
else
{
// input is not an int
}
You are trying to assign a string value to an int with this line:
myCharacter.age = Console.ReadLine();
Try:
myCharacter.age = Int32.Parse(Console.ReadLine());
character.age expects an Int but ReadLine() returns a string, you need to look at using int.Parse or int.TryParse to avoid exceptions
e.g.
if (!int.TryParse(Console.ReadLine(),out myCharacter.age)) {
Console.WriteLine("You didn't enter a number!!!");
} else if (myCharacter.age <= 17) {
Console.WriteLine("I'm sorry {0}, you're too young to enter!",myCharacter.name);
} else {
Console.WriteLine("You can enter!");
}
This looks like a student project.
The input coming from the ReadLine() is always of type string. You're then comparing a string to 17 which isn't valid, as 17 is an int. Use TryParse versus parse to avoid throwing an exception at runtime.
string typedAge = Console.ReadLine();
int Age = 0;
if (!int.TryParse(typedAge, out Age))
Console.WriteLine("Invalid age");
if (Age <= 17)
Console.WriteLine("You're awfully young.");
OK. The problem here is that the age is defined as an int and Console.ReadLine() always returns a string so thus you have to convert the user input from string to integer in order to correctly store the age.
Something like this:
myCharacter.age = Int32.Parse(Console.ReadLine());
When you read input from the console, it returns it to you in the form of a string. In C#, which is a statically typed language, you cannot simply take one type and apply it to another type. You need to convert it somehow, there are several ways to do this.
The first way would be casting:
myCharacter.age = (int)Console.ReadLine();
This won't work because a string and an integer are two completely different types and you can't simply cast one to the other. Do some reading on casting types for more information.
The second way would be to convert it, again there are a couple of ways to do this:
myCharacter.age = Int32.Parse(Console.ReadLine());
This will work as long as you type in an actual number, in this case the Parse method reads the string and figures out what the appropriate integer is for you. However, if you type in "ABC" instead, you will get an exception because the Parse method doesn't recognize that as an integer. So the better way would be to:
string newAge = Console.ReadLine();
int theAge;
bool success = Int32.TryParse(newAge, out theAge);
if(!success)
Console.WriteLine("Hey! That's not a number!");
else
myCharacter.age = theAge;
In this case the TryParse method tries to parse it, and instead of throwing an exception it tells you it can't parse it (via the return value) and allows you to handle that directly (rather than thru try/catch).
That's a little verbose, but you said you're learning so I thought I'd give you some stuff to consider and read up on.

Convert String to int in C#

I am trying to write a simple program that asks the user to enter a number and then I will use that number to decide what the cost of the ticket will be for their given age. I am having trouble when trying to convert the string to int. Otherwise the program layout is fine. Any suggestions?
thanks
using System;
class ticketPrice
{
public static void Main(String[] args)
{
Console.WriteLine("Please Enter Your Age");
int input = Console.ReadLine();
if (input < 5)
{
Console.WriteLine("You are "+input+" and the admisson is FREE!");
}
else if (input > 4 & input < 18)
{
Console.WriteLine("You are "+input+" and the admission is $5");
}
else if (input > 17 & input < 56)
{
Console.WriteLine("You are "+input+" and the admission is $10");
}
else if (input > 55)
{
Console.WriteLine("You are "+input+" and the admission is $8");
}
}
}
Try the int.TryParse(...) method. It doesn't throw an exception.
http://msdn.microsoft.com/en-us/library/f02979c7.aspx
Also, you should use && not & in your conditions. && is logical AND and & is bitwise AND.
For easy parsing of strings to integers (and other number types), use that number type's .TryParse(inputstring, yourintegervariable) method. This method will output a Boolean (True/False), letting you know whether the operation passed or failed. If the result is false, you can give an error message before going any further (don't have to worry about crashing your program).
Previous text concerning switch statements has been removed
In C#, you need to use the && operator for logical AND. & is not the same and may not work the way you believe it will.
I suggest to use the Int32.TryParse() method. Further I suggest to refactor your code - you can make it much cleaner (assuming this is not just example code). One solution is to use a key value pair list to map from age to admission.
using System;
using System.Collections.Generic;
using System.Linq;
static class TicketPrice
{
private static readonly IList<KeyValuePair<Int32, String>> AgeAdmissionMap =
new List<KeyValuePair<Int32, String>>
{
new KeyValuePair<Int32, String>(0, "FREE!"),
new KeyValuePair<Int32, String>(5, "$5."),
new KeyValuePair<Int32, String>(18, "$10."),
new KeyValuePair<Int32, String>(56, "$8.")
};
public static void Main(String[] args)
{
Console.WriteLine("Please Enter Your Age!");
UInt32 age;
while (!UInt32.TryParse(Console.ReadLine(), out age)) { }
String admission = TicketPrice.AgeAdmissionMap
.OrderByDescending(pair => pair.Key)
.First(pair => pair.Key <= age)
.Value;
Console.WriteLine(String.Format(
"You are {0} and the admission is {1}",
age,
admission));
}
}
I used an unsigned integer to prevent entering negative ages and put the input into a loop. This way the user can correct an invalid input.
int number = int.Parse(Console.ReadLine());
Be aware that this will throw an exception if they enter an invalid number.
The first thing you need to do is change your input variable to a string:
string input = Console.ReadLine();
Once you have that, there are several ways to convert it to an integer. See this answer for more info:
Better way to cast object to int

Categories

Resources