I have a problem with the option to select the button once when it is open, what am I doing wrong?
private Boolean buttonWasClicked = false;
private void Button_Click(object sender, RoutedEventArgs e)
{
buttonWasClicked = true;
if ( buttonWasClicked == true)
{
new SettingsWindow().Show();
var test = new SettingsWindow();
test.Owner = System.Windows.Application.Current.MainWindow;
test.WindowStartupLocation = WindowStartupLocation.CenterOwner;
test.Top = this.Top + 20;
}
else {
buttonWasClicked = false;
}
}`
I would avoid to keep your own flag variable and manage its setting by hand. For example, if the user closes the window how do you change back the variable to allow again opening a SettingsWindow?. There is a more robust system based approach at this problem. Looking at system provided informations will help you to avoid opening a second time the settings window until there is already one instance opened.
To check if there is already an instance of a SettingsWindow open you could use informations provided by the system with code like this
private void Button_Click(object sender, RoutedEventArgs e)
{
// Check if, in the Application.Current.Windows collection
// there is at least one window of type SettingsWindow
SettingsWindow w = Application.Current.Windows
.OfType<SettingsWindow>()
.FirstOrDefault();
if(w == null)
{
// No window of the type required, open a new one....
w = new SettingsWindow();
w.Owner = System.Windows.Application.Current.MainWindow;
w.WindowStartupLocation = WindowStartupLocation.CenterOwner;
w.Top = this.Top + 20;
}
// Show it NON MODALLY....
w.Show();
}
The call to Show returns immediately (Non modally) and thus your program continue as usual with the MainWindow still active.
Instead, if you want to use a modal approach, (meaning that until the SettingsWindow is open nothing in your MainWindow is active) you could simply create the SettingsWindow, set its Owner and eventually its Position and finally call ShowDialog (Do not forget to set the Owner property). In this way your code is blocked in the ShowDialog and doesn't return until the user closes the SettingsWindow instance just opened. (And you could remove all the checking above)
Pretty sure this will always be true
Go with the excellent answer from Steve
buttonWasClicked = true;
if (buttonWasClicked == true)
{
// this will execute every time
}
else
{
// this will never execute
}
For two days, I have tried various methods for making it so that on loadButton click, it opens a secondary window and disables the loadButton; Then, when that secondary window has been closed, the loadButton will be re-enabled. Although, obviously all of my attempts have been unsucessful.
I have been reading about using the isClosing event, although, I haven't figured out how to properly implement it. So I decided to go with this route.
private void loadButton_Click(object sender, RoutedEventArgs e)
{
var richWindow = RichTextWindow.GetWindow(new RichTextWindow());
if (richWindow.IsActive != true)
{
loadButton.IsEnabled = false;
richWindow.Show();
}
else
{
loadButton.IsEnabled = true;
}
}
Issue here is, the first half is executed. Once I click the loadButton, it does disable. However, on closing the new Window, the loadButton is still disabled.
Could anyone point me in the right direction on where I need to go with this?
I think what you want is something like this:
private void loadButton_Click(object sender, RoutedEventArgs e)
{
var richWindow = RichTextWindow.GetWindow(new RichTextWindow());
richWindow.Closed += (s, e) => loadButton.IsEnabled = true;
loadButton.IsEnabled = false;
richWindow.Show();
}
Basically, disable the button before opening the window. Then, listen for the window to close and enable the button again.
richWindow.Loaded +=
{
loadedButton.IsEnabled = false;
};
richWindow.Closing +=
{
loadedButton.IsEnabled = true;
}
I'm a beginner and having some dicciculties with XAML.
I have a main view A, which has a button to open a pop-up-window B. When this happens, Window A should still be visible and openened, but disabled. I've done this in code behind (maybe not the cleanest way, but the only way I know how). The code i used for this is the following:
//Code behind from view A
private void X-Button_Click(object sender, RoutedEventArgs e)
{
var BWindow = new BView();
BWindow.Show();
this.IsEnabled = false;
}
I would like to get window A enabled again once i close window B, but i can t seem to get this work. Any help would be very much appreciated.
You could do it in the following way.
You register yourself on the Closed event of the window, and when it gets closed, you unregister the event, and re-enable the this form.
private void Button_Click(object sender, RoutedEventArgs e)
{
Window BWindow = new BWindow();
BWindow.Show();
BWindow.Closed += BWindow_Closed;
this.IsEnabled = false;
}
void BWindow_Closed(object sender, EventArgs e)
{
Window win = sender as Window;
if (win != null)
{
win.Closed -= BWindow_Closed;
}
this.IsEnabled = true;
}
I assume you are looking for modal window. See similar question asked here: How do make modal dialog in WPF?
The solution is in using ShowDialog method from Window class. See here for reference:
http://msdn.microsoft.com/en-us/library/system.windows.window.showdialog.aspx
Modal window is the concept when you open new window B from the existing window A. While the B is open, the A is disabled and cannot be used. Window A become active only when the B is closed.
I have an application that I do not want to show in the taskbar. When the application is minimized it minimizes to the SysTray.
The problem is, when I set ShowInTaskbar = false the minimized application shows above the task bar, just aboe the Windows 7 start button. If I set ShowInTaskbar = true the application minimizes correctly, but obviously the application shows in the taskbar.
Any idea why this is happening and how I can fix it?
EDIT: For the sake of clarity, here is the code I'm using:
private void Form1_Resize(object sender, EventArgs e)
{
if (WindowState == FormWindowState.Minimized) {
this.Hide();
this.Visible = false;
notifyIcon1.Visible = true;
}
else
{
notifyIcon1.Visible = false;
}
}
private void btnDisable_Click(object sender, EventArgs e)
{
// Minimize to the tray
notifyIcon1.Visible = true;
WindowState = FormWindowState.Minimized; // Minimize the form
}
There is no event handler to establish when a form's minimise request has been fired. So to 'get in' before the form has been minimised you'll have to hook into the WndProc procedure
private const int WM_SYSCOMMAND = 0x0112;
private const int SC_MINIMIZE = 0xF020;
[SecurityPermission(SecurityAction.LinkDemand,
Flags = SecurityPermissionFlag.UnmanagedCode)]
protected override void WndProc(ref Message m)
{
switch(m.Msg)
{
case WM_SYSCOMMAND:
int command = m.WParam.ToInt32() & 0xfff0;
if (command == SC_MINIMIZE && this.minimizeToTray)
{
PerformYourOwnOperation(); // For example
}
break;
}
base.WndProc(ref m);
}
and then you can merely hide the form in the PerformYourOwnOperation(); method
public void PerformYourOwnOperation()
{
Form form = GetActiveForm();
form.Hide();
}
You will then need some mechanism to Show() the hidden form otherwise it will be lost.
Another way is using the the form's resize event. However, this fires after the form is minimised. To do this you can do something like
private void Form_Resize(object sender, EventArgs e)
{
if (WindowState == FormWindowState.Minimized)
{
// Do some stuff.
}
}
I hope this helps.
My guess is that you also have to hide the window. To get this behavior in WPF, I have to do the following:
WindowState = WindowState.Minimized;
Visibility = Visibility.Hidden;
ShowInTaskbar = false;
Since WPF and WinForms both ultimately come down to Win32 windows, you probably have to do the same thing.
Here is one of the simplest solutions (I think so):
//Deactivate event handler for your form.
private void Form1_Deactivate(object sender, EventArgs e)
{
if (WindowState == FormWindowState.Minimized) Hide();
}
You can use a NotifyIcon to get the program to show up in the system tray, and watch for the window's resize event to toggle the visibility to hidden.
Here is how to watch for the window's resize event.
How to detect when a windows form is being minimized?
Here is a tutorial for using the NotifyIcon provided by CodeProject. The NotifyIcon is a windows forms element so it will still work in your application.
http://www.codeproject.com/Articles/36468/WPF-NotifyIcon
Add handler for resizing:
private void Form1_Resize(object sender, EventArgs e)
{
Visible = WindowState != FormWindowState.Minimized;
}
I have an application with one form in it, and on the Load method I need to hide the form.
The form will display itself when it has a need to (think along the lines of a outlook 2003 style popup), but I can' figure out how to hide the form on load without something messy.
Any suggestions?
I'm coming at this from C#, but should be very similar in vb.net.
In your main program file, in the Main method, you will have something like:
Application.Run(new MainForm());
This creates a new main form and limits the lifetime of the application to the lifetime of the main form.
However, if you remove the parameter to Application.Run(), then the application will be started with no form shown and you will be free to show and hide forms as much as you like.
Rather than hiding the form in the Load method, initialize the form before calling Application.Run(). I'm assuming the form will have a NotifyIcon on it to display an icon in the task bar - this can be displayed even if the form itself is not yet visible. Calling Form.Show() or Form.Hide() from handlers of NotifyIcon events will show and hide the form respectively.
Usually you would only be doing this when you are using a tray icon or some other method to display the form later, but it will work nicely even if you never display your main form.
Create a bool in your Form class that is defaulted to false:
private bool allowshowdisplay = false;
Then override the SetVisibleCore method
protected override void SetVisibleCore(bool value)
{
base.SetVisibleCore(allowshowdisplay ? value : allowshowdisplay);
}
Because Application.Run() sets the forms .Visible = true after it loads the form this will intercept that and set it to false. In the above case, it will always set it to false until you enable it by setting allowshowdisplay to true.
Now that will keep the form from displaying on startup, now you need to re-enable the SetVisibleCore to function properly by setting the allowshowdisplay = true. You will want to do this on whatever user interface function that displays the form. In my example it is the left click event in my notiyicon object:
private void notifyIcon1_MouseClick(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Left)
{
this.allowshowdisplay = true;
this.Visible = !this.Visible;
}
}
I use this:
private void MainForm_Load(object sender, EventArgs e)
{
if (Settings.Instance.HideAtStartup)
{
BeginInvoke(new MethodInvoker(delegate
{
Hide();
}));
}
}
Obviously you have to change the if condition with yours.
protected override void OnLoad(EventArgs e)
{
Visible = false; // Hide form window.
ShowInTaskbar = false; // Remove from taskbar.
Opacity = 0;
base.OnLoad(e);
}
At form construction time (Designer, program Main, or Form constructor, depending on your goals),
this.WindowState = FormWindowState.Minimized;
this.ShowInTaskbar = false;
When you need to show the form, presumably on event from your NotifyIcon, reverse as necessary,
if (!this.ShowInTaskbar)
this.ShowInTaskbar = true;
if (this.WindowState == FormWindowState.Minimized)
this.WindowState = FormWindowState.Normal;
Successive show/hide events can more simply use the Form's Visible property or Show/Hide methods.
Try to hide the app from the task bar as well.
To do that please use this code.
protected override void OnLoad(EventArgs e)
{
Visible = false; // Hide form window.
ShowInTaskbar = false; // Remove from taskbar.
Opacity = 0;
base.OnLoad(e);
}
Thanks.
Ruhul
Extend your main form with this one:
using System.Windows.Forms;
namespace HideWindows
{
public class HideForm : Form
{
public HideForm()
{
Opacity = 0;
ShowInTaskbar = false;
}
public new void Show()
{
Opacity = 100;
ShowInTaskbar = true;
Show(this);
}
}
}
For example:
namespace HideWindows
{
public partial class Form1 : HideForm
{
public Form1()
{
InitializeComponent();
}
}
}
More info in this article (spanish):
http://codelogik.net/2008/12/30/primer-form-oculto/
I have struggled with this issue a lot and the solution is much simpler than i though.
I first tried all the suggestions here but then i was not satisfied with the result and investigated it a little more.
I found that if I add the:
this.visible=false;
/* to the InitializeComponent() code just before the */
this.Load += new System.EventHandler(this.DebugOnOff_Load);
It is working just fine.
but I wanted a more simple solution and it turn out that if you add the:
this.visible=false;
/* to the start of the load event, you get a
simple perfect working solution :) */
private void
DebugOnOff_Load(object sender, EventArgs e)
{
this.Visible = false;
}
You're going to want to set the window state to minimized, and show in taskbar to false. Then at the end of your forms Load set window state to maximized and show in taskbar to true
public frmMain()
{
Program.MainForm = this;
InitializeComponent();
this.WindowState = FormWindowState.Minimized;
this.ShowInTaskbar = false;
}
private void frmMain_Load(object sender, EventArgs e)
{
//Do heavy things here
//At the end do this
this.WindowState = FormWindowState.Maximized;
this.ShowInTaskbar = true;
}
Put this in your Program.cs:
FormName FormName = new FormName ();
FormName.ShowInTaskbar = false;
FormName.Opacity = 0;
FormName.Show();
FormName.Hide();
Use this when you want to display the form:
var principalForm = Application.OpenForms.OfType<FormName>().Single();
principalForm.ShowInTaskbar = true;
principalForm.Opacity = 100;
principalForm.Show();
This works perfectly for me:
[STAThread]
static void Main()
{
try
{
frmBase frm = new frmBase();
Application.Run();
}
When I launch the project, everything was hidden including in the taskbar unless I need to show it..
Override OnVisibleChanged in Form
protected override void OnVisibleChanged(EventArgs e)
{
this.Visible = false;
base.OnVisibleChanged(e);
}
You can add trigger if you may need to show it at some point
public partial class MainForm : Form
{
public bool hideForm = true;
...
public MainForm (bool hideForm)
{
this.hideForm = hideForm;
InitializeComponent();
}
...
protected override void OnVisibleChanged(EventArgs e)
{
if (this.hideForm)
this.Visible = false;
base.OnVisibleChanged(e);
}
...
}
Launching an app without a form means you're going to have to manage the application startup/shutdown yourself.
Starting the form off invisible is a better option.
This example supports total invisibility as well as only NotifyIcon in the System tray and no clicks and much more.
More here: http://code.msdn.microsoft.com/TheNotifyIconExample
As a complement to Groky's response (which is actually the best response by far in my perspective) we could also mention the ApplicationContext class, which allows also (as it's shown in the article's sample) the ability to open two (or even more) Forms on application startup, and control the application lifetime with all of them.
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
MainUIForm mainUiForm = new MainUIForm();
mainUiForm.Visible = false;
Application.Run();
}
I had an issue similar to the poster's where the code to hide the form in the form_Load event was firing before the form was completely done loading, making the Hide() method fail (not crashing, just wasn't working as expected).
The other answers are great and work but I've found that in general, the form_Load event often has such issues and what you want to put in there can easily go in the constructor or the form_Shown event.
Anyways, when I moved that same code that checks some things then hides the form when its not needed (a login form when single sign on fails), its worked as expected.
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Form1 form1 = new Form1();
form1.Visible = false;
Application.Run();
}
private void ExitToolStripMenuItem_Click(object sender, EventArgs e)
{
this.Close();
Application.Exit();
}
Here is a simple approach:
It's in C# (I don't have VB compiler at the moment)
public Form1()
{
InitializeComponent();
Hide(); // Also Visible = false can be used
}
private void Form1_Load(object sender, EventArgs e)
{
Thread.Sleep(10000);
Show(); // Or visible = true;
}
In the designer, set the form's Visible property to false. Then avoid calling Show() until you need it.
A better paradigm is to not create an instance of the form until you need it.
Based on various suggestions, all I had to do was this:
To hide the form:
Me.Opacity = 0
Me.ShowInTaskbar = false
To show the form:
Me.Opacity = 100
Me.ShowInTaskbar = true
Why do it like that at all?
Why not just start like a console app and show the form when necessary? There's nothing but a few references separating a console app from a forms app.
No need in being greedy and taking the memory needed for the form when you may not even need it.
I do it like this - from my point of view the easiest way:
set the form's 'StartPosition' to 'Manual', and add this to the form's designer:
Private Sub InitializeComponent()
.
.
.
Me.Location=New Point(-2000,-2000)
.
.
.
End Sub
Make sure that the location is set to something beyond or below the screen's dimensions. Later, when you want to show the form, set the Location to something within the screen's dimensions.