Let me preface by stating that I' somewhat new to dealing with zipping/unzipping/reading/reading files. That being said, I'm doing a PoC that will retrieve data via api and write the responses to a database. The response is a zip file and inside this zip is the json data I will be reading and writing to the database.
I'm having some trouble unzipping and reading the information. Please find the code below:
HttpClient client = new HttpClient();
HttpRequestMessage request = new HttpRequestMessage
{
Method = HttpMethod.Get,
RequestUri = new Uri(baseUrl),
Headers =
{
{ "X-API-TOKEN", apiKey },
},
};
using (var response = await client.SendAsync(request))
{
response.EnsureSuccessStatusCode();
var body = await response.Content.ReadAsStringAsync();
// here is where I am stuck - not sure how I would unzip and read the contents
}
Thanks
Assuming you actually have a .zip file, you don't need a MemoryStream, you just need to pass the existing stream to ZipArchive
static HttpClient client = new HttpClient(); // always keep static client
async Task GetZip()
{
using var request = new HttpRequestMessage(HttpMethod.Get, new Uri(baseUrl))
{
Headers = {
{ "X-API-TOKEN", apiKey },
},
};
using var response = await client.SendAsync(request, HttpCompletionOption.ResponseHeadersRead);
response.EnsureSuccessStatusCode();
using var stream = await response.Content.ReadAsStreamAsync();
await ProcessZip(stream);
}
async Task ProcessZip(Stream zipStream)
{
using var zip = new ZipArchive(zipStream, ZipArchiveMode.Read);
foreach (var file in zip.Entries)
{
using var entryStream = file.Open();
await ....; // do stuff here
}
}
You can convert body to a byte array and then unzip it using MemoryStream.
byte[] bytes = Encoding.ASCII.GetBytes(body);
using (var mso = new MemoryStream(bytes)) {
using (var gs = new GZipStream(msi, CompressionMode.Decompress)) {
CopyTo(gs, mso);
}
return Encoding.UTF8.GetString(mso.ToArray());
}
Does anyone know how to use the HttpClient in .Net 4.5 with multipart/form-data upload?
I couldn't find any examples on the internet.
my result looks like this:
public static async Task<string> Upload(byte[] image)
{
using (var client = new HttpClient())
{
using (var content =
new MultipartFormDataContent("Upload----" + DateTime.Now.ToString(CultureInfo.InvariantCulture)))
{
content.Add(new StreamContent(new MemoryStream(image)), "bilddatei", "upload.jpg");
using (
var message =
await client.PostAsync("http://www.directupload.net/index.php?mode=upload", content))
{
var input = await message.Content.ReadAsStringAsync();
return !string.IsNullOrWhiteSpace(input) ? Regex.Match(input, #"http://\w*\.directupload\.net/images/\d*/\w*\.[a-z]{3}").Value : null;
}
}
}
}
It works more or less like this (example using an image/jpg file):
async public Task<HttpResponseMessage> UploadImage(string url, byte[] ImageData)
{
var requestContent = new MultipartFormDataContent();
// here you can specify boundary if you need---^
var imageContent = new ByteArrayContent(ImageData);
imageContent.Headers.ContentType =
MediaTypeHeaderValue.Parse("image/jpeg");
requestContent.Add(imageContent, "image", "image.jpg");
return await client.PostAsync(url, requestContent);
}
(You can requestContent.Add() whatever you want, take a look at the HttpContent descendant to see available types to pass in)
When completed, you'll find the response content inside HttpResponseMessage.Content that you can consume with HttpContent.ReadAs*Async.
This is an example of how to post string and file stream with HTTPClient using MultipartFormDataContent. The Content-Disposition and Content-Type need to be specified for each HTTPContent:
Here's my example. Hope it helps:
private static void Upload()
{
using (var client = new HttpClient())
{
client.DefaultRequestHeaders.Add("User-Agent", "CBS Brightcove API Service");
using (var content = new MultipartFormDataContent())
{
var path = #"C:\B2BAssetRoot\files\596086\596086.1.mp4";
string assetName = Path.GetFileName(path);
var request = new HTTPBrightCoveRequest()
{
Method = "create_video",
Parameters = new Params()
{
CreateMultipleRenditions = "true",
EncodeTo = EncodeTo.Mp4.ToString().ToUpper(),
Token = "x8sLalfXacgn-4CzhTBm7uaCxVAPjvKqTf1oXpwLVYYoCkejZUsYtg..",
Video = new Video()
{
Name = assetName,
ReferenceId = Guid.NewGuid().ToString(),
ShortDescription = assetName
}
}
};
//Content-Disposition: form-data; name="json"
var stringContent = new StringContent(JsonConvert.SerializeObject(request));
stringContent.Headers.Add("Content-Disposition", "form-data; name=\"json\"");
content.Add(stringContent, "json");
FileStream fs = File.OpenRead(path);
var streamContent = new StreamContent(fs);
streamContent.Headers.Add("Content-Type", "application/octet-stream");
//Content-Disposition: form-data; name="file"; filename="C:\B2BAssetRoot\files\596090\596090.1.mp4";
streamContent.Headers.Add("Content-Disposition", "form-data; name=\"file\"; filename=\"" + Path.GetFileName(path) + "\"");
content.Add(streamContent, "file", Path.GetFileName(path));
//content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
Task<HttpResponseMessage> message = client.PostAsync("http://api.brightcove.com/services/post", content);
var input = message.Result.Content.ReadAsStringAsync();
Console.WriteLine(input.Result);
Console.Read();
}
}
}
Try this its working for me.
private static async Task<object> Upload(string actionUrl)
{
Image newImage = Image.FromFile(#"Absolute Path of image");
ImageConverter _imageConverter = new ImageConverter();
byte[] paramFileStream= (byte[])_imageConverter.ConvertTo(newImage, typeof(byte[]));
var formContent = new MultipartFormDataContent
{
// Send form text values here
{new StringContent("value1"),"key1"},
{new StringContent("value2"),"key2" },
// Send Image Here
{new StreamContent(new MemoryStream(paramFileStream)),"imagekey","filename.jpg"}
};
var myHttpClient = new HttpClient();
var response = await myHttpClient.PostAsync(actionUrl.ToString(), formContent);
string stringContent = await response.Content.ReadAsStringAsync();
return response;
}
Here is another example on how to use HttpClient to upload a multipart/form-data.
It uploads a file to a REST API and includes the file itself (e.g. a JPG) and additional API parameters. The file is directly uploaded from local disk via FileStream.
See here for the full example including additional API specific logic.
public static async Task UploadFileAsync(string token, string path, string channels)
{
// we need to send a request with multipart/form-data
var multiForm = new MultipartFormDataContent();
// add API method parameters
multiForm.Add(new StringContent(token), "token");
multiForm.Add(new StringContent(channels), "channels");
// add file and directly upload it
FileStream fs = File.OpenRead(path);
multiForm.Add(new StreamContent(fs), "file", Path.GetFileName(path));
// send request to API
var url = "https://slack.com/api/files.upload";
var response = await client.PostAsync(url, multiForm);
}
Here's a complete sample that worked for me. The boundary value in the request is added automatically by .NET.
var url = "http://localhost/api/v1/yourendpointhere";
var filePath = #"C:\path\to\image.jpg";
HttpClient httpClient = new HttpClient();
MultipartFormDataContent form = new MultipartFormDataContent();
FileStream fs = File.OpenRead(filePath);
var streamContent = new StreamContent(fs);
var imageContent = new ByteArrayContent(streamContent.ReadAsByteArrayAsync().Result);
imageContent.Headers.ContentType = MediaTypeHeaderValue.Parse("multipart/form-data");
form.Add(imageContent, "image", Path.GetFileName(filePath));
var response = httpClient.PostAsync(url, form).Result;
Example with preloader Dotnet 3.0 Core
ProgressMessageHandler processMessageHander = new ProgressMessageHandler();
processMessageHander.HttpSendProgress += (s, e) =>
{
if (e.ProgressPercentage > 0)
{
ProgressPercentage = e.ProgressPercentage;
TotalBytes = e.TotalBytes;
progressAction?.Invoke(progressFile);
}
};
using (var client = HttpClientFactory.Create(processMessageHander))
{
var uri = new Uri(transfer.BackEndUrl);
client.DefaultRequestHeaders.Authorization =
new AuthenticationHeaderValue("Bearer", AccessToken);
using (MultipartFormDataContent multiForm = new MultipartFormDataContent())
{
multiForm.Add(new StringContent(FileId), "FileId");
multiForm.Add(new StringContent(FileName), "FileName");
string hash = "";
using (MD5 md5Hash = MD5.Create())
{
var sb = new StringBuilder();
foreach (var data in md5Hash.ComputeHash(File.ReadAllBytes(FullName)))
{
sb.Append(data.ToString("x2"));
}
hash = result.ToString();
}
multiForm.Add(new StringContent(hash), "Hash");
using (FileStream fs = File.OpenRead(FullName))
{
multiForm.Add(new StreamContent(fs), "file", Path.GetFileName(FullName));
var response = await client.PostAsync(uri, multiForm);
progressFile.Message = response.ToString();
if (response.IsSuccessStatusCode) {
progressAction?.Invoke(progressFile);
} else {
progressErrorAction?.Invoke(progressFile);
}
response.EnsureSuccessStatusCode();
}
}
}
I'm adding a code snippet which shows on how to post a file to an API which has been exposed over DELETE http verb. This is not a common case to upload a file with DELETE http verb but it is allowed. I've assumed Windows NTLM authentication for authorizing the call.
The problem that one might face is that all the overloads of HttpClient.DeleteAsync method have no parameters for HttpContent the way we get it in PostAsync method
var requestUri = new Uri("http://UrlOfTheApi");
using (var streamToPost = new MemoryStream("C:\temp.txt"))
using (var fileStreamContent = new StreamContent(streamToPost))
using (var httpClientHandler = new HttpClientHandler() { UseDefaultCredentials = true })
using (var httpClient = new HttpClient(httpClientHandler, true))
using (var requestMessage = new HttpRequestMessage(HttpMethod.Delete, requestUri))
using (var formDataContent = new MultipartFormDataContent())
{
formDataContent.Add(fileStreamContent, "myFile", "temp.txt");
requestMessage.Content = formDataContent;
var response = httpClient.SendAsync(requestMessage).GetAwaiter().GetResult();
if (response.IsSuccessStatusCode)
{
// File upload was successfull
}
else
{
var erroResult = response.Content.ReadAsStringAsync().GetAwaiter().GetResult();
throw new Exception("Error on the server : " + erroResult);
}
}
You need below namespaces at the top of your C# file:
using System;
using System.Net;
using System.IO;
using System.Net.Http;
P.S. You are seeing a number of using blocks(IDisposable pattern) in the above code snippet which doesn't look very clean. Unfortunately, the syntax of using construct doesn't support initializing multiple variables in single statement.
X509Certificate clientKey1 = null;
clientKey1 = new X509Certificate(AppSetting["certificatePath"],
AppSetting["pswd"]);
string url = "https://EndPointAddress";
FileStream fs = File.OpenRead(FilePath);
var streamContent = new StreamContent(fs);
var FileContent = new ByteArrayContent(streamContent.ReadAsByteArrayAsync().Result);
FileContent.Headers.ContentType = MediaTypeHeaderValue.Parse("ContentType");
var handler = new WebRequestHandler();
handler.ClientCertificateOptions = ClientCertificateOption.Manual;
handler.ClientCertificates.Add(clientKey1);
handler.ServerCertificateValidationCallback = (httpRequestMessage, cert, cetChain, policyErrors) =>
{
return true;
};
using (var client = new HttpClient(handler))
{
// Post it
HttpResponseMessage httpResponseMessage = client.PostAsync(url, FileContent).Result;
if (!httpResponseMessage.IsSuccessStatusCode)
{
string ss = httpResponseMessage.StatusCode.ToString();
}
}
public async Task<object> PassImageWithText(IFormFile files)
{
byte[] data;
string result = "";
ByteArrayContent bytes;
MultipartFormDataContent multiForm = new MultipartFormDataContent();
try
{
using (var client = new HttpClient())
{
using (var br = new BinaryReader(files.OpenReadStream()))
{
data = br.ReadBytes((int)files.OpenReadStream().Length);
}
bytes = new ByteArrayContent(data);
multiForm.Add(bytes, "files", files.FileName);
multiForm.Add(new StringContent("value1"), "key1");
multiForm.Add(new StringContent("value2"), "key2");
var res = await client.PostAsync(_MEDIA_ADD_IMG_URL, multiForm);
}
}
catch (Exception e)
{
throw new Exception(e.ToString());
}
return result;
}
I was trying to attach a csv file as a body parameter in my test script. But still as per the below code controller expect file and just curious how should I pass that.
I run test script in below order
Method-1
public void AttachedRatesFile(string fileName)
{
_form = string.IsNullOrWhiteSpace(fileName)
? _form = new StringContent(string.Empty)
: _form = new StreamContent(File.OpenRead($"{ResourceFolder}{fileName}"));
_form.Headers.ContentType = new MediaTypeHeaderValue("application/csv");
_form.Headers.ContentDisposition = new ContentDispositionHeaderValue(fileName);
}
Method-2
public void PostRequestExecutes(string resource)
{
var content = new MultipartFormDataContent{_form};
WhenThePostRequestExecutesWithContent(resource, content);
}
Method-3
public async void WhenThePostRequestExecutesWithContent(string resource, HttpContent content)
{
ResponseMessage = await HttpClient.PostAsync(resource, content);
}
I see null in below file parameter
Controller:
public async Task<IActionResult> SeedData(IFormFile file)
{
var result = await _seedDataService.SeedData(file);
return Ok(new { IsUploadSuccesful = result});
}
I would add that to the body as a stream
var memoryContentStream = new MemoryStream();
using (var streamWriter = new StreamWriter(memoryContentStream, Encoding.UTF8, 1000,
true))
{
using (var jsonTextWriter = new JsonTextWriter(streamWriter))
{
var jsonSerializer = new JsonSerializer();
jsonSerializer.Serialize(jsonTextWriter, OBJECT);
jsonTextWriter.Flush();
}
}
if (memoryContentStream.CanSeek)
{
memoryContentStream.Seek(0, SeekOrigin.Begin);
}
Then
using (var streamContent = new StreamContent(memoryContentStream))
{
streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/json");
request.Content = streamContent;
using (var response = await _httpClient.SendAsync(request, HttpCompletionOption.ResponseHeadersRead))
{
var stream = await response.Content.ReadAsStreamAsync();
response.EnsureIsSuccessStatusCode();
}
}
The above would first write the content as a memory stream and then when creating the POST request you can send the stream as a streamContent
I send a zipfile as a response.Content:
[HttpGet]
[Route("Package")]
public async Task<HttpResponseMessage> GetLogsPackage()
{
HttpResponseMessage response = new HttpResponseMessage(HttpStatusCode.OK);
using (var stream = new MemoryStream())
{
using (var zipFile = ZipFile.Read((Path.Combine(path, opId.ToString()) + ".zip")))
{
zipFile.Save(stream);
response.Content = new StreamContent(stream);
response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
response.Content.Headers.ContentLength = stream.Length;
}
}
return response;
}
how to get this stream after call to this method? My code doesn't work( can't read as zipfile)
I send stream.lenght ,for example, 345673, but receive response with 367 lenght.
What is wrong?
var response = await _coreEndpoint.GetLogsPackage();
using (var stream = response.Content.ReadAsStreamAsync())
using (var zipFile = ZipFile.Read(stream))
{ //do something with zip-file
Looks like you should be await'ing ReadAsStreamAsync:
using (var stream = await response.Content.ReadAsStreamAsync())
Currently your code is passing a Task<Stream> to ZipFile.Read, which is probably not what you intend.
My CurrentCode:
using (var client = new HttpClient
{
Timeout = TimeSpan.FromMilliseconds(2000)
})
{
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var response = await client.GetAsync(new Uri(Constants.mUrl));
// convert stream to string
StreamReader reader = new StreamReader(respons);
var myItems = Newtonsoft.Json.JsonConvert.DeserializeObject<ModelClassObject>(response);
return myItems;
}
Use ReadAsStreamAsync on the content of the response
using(var response = await client.GetAsync(new Uri(Constants.mUrl))) {
var stream = await response.Content.ReadAsStreamAsync();
//...
}
If you want to parse JOSN directly from the response, then
using(var response = await client.GetAsync(new Uri(Constants.mUrl))) {
var myItems = await response.Content.ReadAsAsync<ModelClassObject>();
return myItems;
}