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Extracting detail records of XML via C# LINQ

I have the following XML excerpt. I have no problem extracting the first step of XML but I can't figure out how to get to the second layer and extract each layer. Specifically, the user info in XML below.
Any help will be appreciated...
<?xml version="1.0" encoding="UTF-8" ?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
<S:Body>
<ns2:getStatusReportResponse xmlns:ns2="http://xxxxxxxxx.com/">
<return>
<statusReport>
<record>
<assessorDate />
<assessorOffice />
<availableDate />
<awardDate>01/01/2014</awardDate>
<awardValue>1000000</awardValue>
<businessSector>SYSTEMS</businessSector>
<user>
<accessGrantedDate />
<emailAddress>john.usda#noemail.mil</emailAddress>
<name>JOHN USDA</name>
<phoneNumber>XXX-XXX-XXXX</phoneNumber>
<role>Focal Point</role>
</user>
<user>
<accessGrantedDate />
<emailAddress>john.usda#noemail.mil</emailAddress>
<name>JOHN USDA</name>
<phoneNumber>XXX-XXX-XXXX</phoneNumber>
<role>Focal Point</role>
</user>
</record>
</statusReport>
</return>
</ns2:getStatusReportResponse>
</S:Body>
</S:Envelope>
I've tried this but it only get's me a list of the first user record and not all of them.
var records = from x in xml.Descendants("record")
select new
{
awardDate = (string) x.Descendants("awardDate").FirstOrDefault().Value
,userList = (List<string>) x.Descendants("user").Elements() //.Elements("accessGrantedDate")
.Select(a => a.Value).ToList()
};

I am assuming this is the model of your User class:
public class User
{
public DateTime? AccessGrantedDate { get; set; }
public string EMailAddress { get; set; }
public string Name { get; set; }
public string PhoneNumber { get; set; }
public string Role { get; set; }
}
And this is extracting the User class from the XML:
var records = from x in xml.Descendants("record")
select new
{
AwardDate = (string)x.Element("awardDate"),
UserList = x.Descendants("user").Select(user => new User
{
AccessGrantedDate = string.IsNullOrEmpty((string)user.Element("accessGrantedDate")) ?
(DateTime?) null : DateTime.Parse((string)user.Element("accessGrantedDate")),
EMailAddress = (string)user.Element("emailAddress"),
Name = (string)user.Element("name"),
PhoneNumber = (string)user.Element("phoneNumber"),
Role = (string)user.Element("role")
})
};

As far as I can tell, your code gets the data of all users in the file, but only the values of nodes.
The more organized way to do this would be:
class User
{
public string accessGrantedDate { get; set; }
public string emailAddress { get; set; }
public string name { get; set; }
public string phoneNumber { get; set; }
public string role { get; set; }
}
then:
var records = from x in xml.Descendants("record")
select new
{
awardDate = (string) x.Descendants("awardDate").FirstOrDefault().Value
,userList = x.Descendants("user").Select(a=>new User
{
accessGrantedDate= a.Element("accessGrantedDate").Value,
emailAddress=a.Element("emailAddress").Value,
name=a.Element("name").Value,
phoneNumber=a.Element("phoneNumber").Value,
role = a.Element("role").Value
}).ToList()
};
or, if you don't want to organize your data this way, you may use a list of lists:
var records = from x in xml.Descendants("record")
select new
{
awardDate = (string)x.Descendants("awardDate").FirstOrDefault().Value,
userList = x.Descendants("user").Select(a => a.Elements().Select(b=>b.Value).ToList()).ToList()
};

I solved it by using a 2nd query for detail records, therefore, creating a List as a object inside the outer list.
var records = from x in xml.Descendants("record")
select new
{
awardDate = x.Element("awardDate")
,
userList = from u in x.Descendants("user")
select new
{
accessGrantedDate = (string) u.Element("accessGrantedDate")
,emailAddress =(string) u.Element("emailAddress"
,name = (string) u.Element("name")
,phoneNumber = (string) u.Element("phoneNumber")
,role = (string) u.Element("role")
}
};

Reading XML values from different namespaces in same LINQ Query

I hope you guys will be able to help me out?
I have this XML structure:
<DataBase
xsi:schemaLocation="http://somestuff.new/xml http://somestuff.xsd"
xmlns:ns3="http://somestuff.new/ns3"
xmlns:ns2="http://somestuff.new/ns2"
xmlns="http://somestuff.new/ns"
xmlns:xsi="http://somestuff.new/XMLScema-instance"
xmlns:ns4="http://somestuff.new/ns4">
<Cars>
<SmallCars attribute="Something">
<Id>licenceplate</Id>
<Parts attribute="All Parts">
<Extras>
<Gauges xmlns="http://somestuff.new/ns3">
<Speed>100</Speed>
<Rpm>3200</Rpm>
</Gauges>
</Extras>
</Parts>
</SmallCars>
</Cars>
</DataBase>
I have then created a class of Cars like this:
public class Cars
{
public string CarType { get; set; }
public List<Parts> CarParts { get; set; }
}
And a Class of Parts:
public class Parts
{
public List<Gauges> CarExtras { get; set; }
}
And last but not least a class of Gauges:
public class Gauges
{
public double Speed { get; set; }
public int Rpm { get; set; }
}
Now I would like to create a LINQ query that gets the values from the Gauges part of the XML but I seem to fail in my attempt:
XDocument xml = XDocument.Load(file);
XNamespace xmlns =XNamespace.Get("http://somestuff.new/ns");
XNamespace ns3 = XNamespace.Get("http://somestuff.new/ns3");
var Cars = from car in xml.Descendants(ns + "Cars")
select new Cars
{
CarParts = (from part in car.Descendants(ns + "Parts")
select new Parts
{
CarExtras = (from extra in part.Descendants(ns + "Extras")
select new Gauges
{
Speed = (double?)extra.Element(ns3 + "Speed") ?? 0.0,
Rpm = (int?)extra.Element(ns3 + "Rpm") ?? 0
})
})
});
I have tried a lot of combinations with the namespaces because it changes when I get to Gauges but I do not get any values returned.
Hope someone can help me out here?

Notice that extra in in your linq-to-xml code is <Extras> element, and since <Speed> and <Rpm> are not direct child of <Extras> you can't select any of them by using extra.Element(ns3 + "elementName"). You can use Descendants instead of Element in this case :
XNamespace ns =XNamespace.Get("http://somestuff.new/ns");
XNamespace ns3 = XNamespace.Get("http://somestuff.new/ns3");
var Cars = from car in xml.Descendants(ns + "Cars")
select new Cars
{
CarParts = (from part in car.Descendants(ns + "Parts")
select new Parts
{
CarExtras =
(from extra in part.Descendants(ns + "Extras")
select new Gauges
{
Speed =
(double?)
extra.Descendants(ns3 + "Speed").FirstOrDefault() ??
0.0,
Rpm =
(int?)
extra.Descendants(ns3 + "Rpm").FirstOrDefault() ?? 0
}).ToList()
}).ToList()
};

Correct way to convert Xml to Objects?

I have very simple Xml structure that I want to convert to list of objects. My code does work but I think this is not the correct way of doing this and since I never did this I think there might be simpler way of doing what I want.
Xml example
<root>
<item>
<name>Item 1</name>
<price>30.00</price>
</item>
<item>
<name>Item 2</name>
<price>55.00</price>
</item>
</root>
Code to gather xml and create list of objects
class Program
{
static void Main(string[] args)
{
List<Item> itemList = new List<Item>();
var url = "http://xmlurl.com/xml";
// Load xml data
XmlDocument myXmlDocument = new XmlDocument();
myXmlDocument.Load(url);
// Select items and loop
var xmlItems = myXmlDocument.SelectNodes("/root/item");
foreach (XmlNode item in xmlItems)
{
var newItem = new Item();
foreach (XmlNode i in item)
{
// Since I cannot query them properly I need to check every item node
switch (i.Name)
{
case "name":
newItem.Name = i.InnerText;
break;
case "price":
newItem.Price = Convert.ToDecimal(i.InnerText);
break;
}
}
itemList.Add(newItem);
}
// Test it out
foreach (var item in itemList.OrderBy(x => x.Price))
{
Console.WriteLine(item.Name + " | " + item.Price);
}
Console.ReadLine();
}
}
class Item
{
public string Name { get; set; }
public decimal Price { get; set; }
}

Using LINQ:
XDocument xdoc = XDocument.Load("myXml.xml");
List<Item> items = (from item in xdoc.Descendants("item")
select new Item {
Name = item.Element("name").Value,
Price = item.Element("price").Value
}).ToList();

You should use XmlSerializer, example:
Classes:
[XmlType(TypeName="item")]
public class Item {
public string Name { get; set; }
public decimal Price { get; set; }
}
[XmlRoot(ElementName = "root")]
public class ItemList : List<Item> {
}
Getting them from markup:
const string test = #"<root>
<item>
<name>Item 1</name>
<price>30.00</price>
</item>
<item>
<name>Item 2</name>
<price>55.00</price>
</item>
</root>";
var serializer = new XmlSerializer(typeof(ItemList));
List<Item> result;
using (var reader = new StringReader(test)) {
result = (List<Item>)serializer.Deserialize(reader);
}

You can define your class:
[XmlType("item")]
public class Item
{
[XmlElement("name")]
public string Name { get; set; }
[XmlElement("price")]
public decimal Price { get; set; }
}
And then deserialize the Xml:
var xml = #"<root>
<item>
<name>Item 1</name>
<price>30.00</price>
</item>
<item>
<name>Item 2</name>
<price>55.00</price>
</item>
</root>";
List<Item> items;
var serializer = new XmlSerializer(typeof(List<Item>),
new XmlRootAttribute("root"));
using(var stream = new StringReader(xml))
{
items = (List<Item>)serializer.Deserialize(stream);
}
if(items != null)
{
foreach(var item in items)
{
Console.Write(item);
}
}

LINQ to XML join with idref

I have a XML structure like the following:
[...]
<Fruits>
<Fruit>
<Specification>id_1001_0</Specification>
<Weight>23</Weight>
</Fruit>
</Fruits>
<FruitSpecification id="id_1001_0">
<Type>Apple</Type>
</FruitSpecification>
[...]
I want to use Linq to XML to read this into (non-anonymous) objects.
Let´s say i have the following code:
var fruits = from xele in xDoc.Root.Element("Fruits").Elements("Fruit")
select new Fruit()
{
Weight = xele.Element("Weight").Value
}
How can i extend the query to join the correct FruitSpecification tag?
The goal would be to be able to write this:
var fruits = from xele in xDoc.Root.Element("Fruits").Elements("Fruit")
//some join?
select new Fruit()
{
Weight = xele.Element("Weight").Value,
Type = xjoinedelement.Element("Type").Value
}
I hope this is understandable, i made this "fruit" sample up, my actual XML is much more complicated...

Yes, simple join will do the trick:
var fruits =
from f in xdoc.Root.Element("Fruits").Elements("Fruit")
join fs in xdoc.Root.Elements("FruitSpecification")
on (string)f.Element("Specification") equals (string)fs.Attribute("id")
select new Fruit()
{
Weight = (int)f.Element("Weight"),
Type = (string)fs.Element("Type")
};
Fruit class definition:
public class Fruit
{
public int Weight { get; set; }
public string Type { get; set; }
}

Try this:
class Fruit
{
public int Weight { get; set; }
public string Type { get; set; }
}
string xml = #"
<root>
<Fruits>
<Fruit>
<Specification>id_1001_0</Specification>
<Weight>23</Weight>
</Fruit>
<Fruit>
<Specification>id_1002_0</Specification>
<Weight>25</Weight>
</Fruit>
</Fruits>
<FruitSpecification id='id_1001_0'>
<Type>Apple</Type>
</FruitSpecification>
<FruitSpecification id='id_1002_0'>
<Type>Orange</Type>
</FruitSpecification>
</root>";
XElement element = XElement.Parse(xml);
IEnumerable<XElement> xFruites = element.Descendants("Fruit");
IEnumerable<XElement> xFruitSpecifications = element.Descendants("FruitSpecification");
IEnumerable<Fruit> frits = xFruites.Join(
xFruitSpecifications,
f => f.Element("Specification").Value,
s => s.Attribute("id").Value,
(f, s) =>
new Fruit
{
Type = s.Element("Type").Value,
Weight = int.Parse(f.Element("Weight").Value)
});

XMLSerialization for a List

I have class like this below shown. which contains the shopping items where the number can vary from 0 to n.
namespace SerializationPOC
{
public class ShoppingItems
{
public string CustomerName { get; set; }
public string Address { get; set; }
public List<Item> Items { get; set; }
}
public class Item
{
public string Name { get; set; }
public string Price { get; set; }
}
}
Is it possible to get the class serialized like to get the XML Schema like below.
<?xml version="1.0" encoding="utf-8" ?>
<ShoppingItems>
<CustomerName>John</CustomerName>
<Address>Walstreet,Newyork</Address>
<Item1>Milk</Item1>
<Price1>1$</Price1>
<Item2>IceCream</Item2>
<Price2>1$</Price2>
<Item3>Bread</Item3>
<Price3>1$</Price3>
<Item4>Egg</Item4>
<Price4>1$</Price4>
<Item..n>Egg</Item..n>
<Price..n>1$</Price..n>
</ShoppingItems>
I would like to know if this can be achieved by using the Serilization if not whats the best way to achieve this Schema?

There is no standard serializer that supports that layout. You will have to do it yourself. Personally, I would say "you're doing it wrong"; I strongly suggest (if it is possible) using a format like
<Item name="IceCream" Price="1$"/>
or
<Item><Name>IceCream</Name><Price>1$</Price></Item>
both of which would be trivial with XmlSerializer.
LINQ-to-XML is probably your best option, something like:
var items = new ShoppingItems
{
Address = "Walstreet,Newyork",
CustomerName = "John",
Items = new List<Item>
{
new Item { Name = "Milk", Price = "1$"},
new Item { Name = "IceCream", Price = "1$"},
new Item { Name = "Bread", Price = "1$"},
new Item { Name = "Egg", Price = "1$"}
}
};
var xml = new XElement("ShoppingItems",
new XElement("CustomerName", items.CustomerName),
new XElement("Address", items.Address),
items.Items.Select((item,i)=>
new[] {
new XElement("Item" + (i + 1), item.Name),
new XElement("Price" + (i + 1), item.Price)}))
.ToString();

Can you please have a look on my article, [^]
As an example you can look into the below code. The Serialize method is given on the article.
var test = new ShoppingItems()
{
CustomerName = "test",
Address = "testAddress",
Items = new List<Item>()
{
new Item(){ Name = "item1", Price = "12"},
new Item(){Name = "item2",Price = "14"}
},
};
var xmlData = Serialize(test);
And it will return the string given below,
<?xml version="1.0" encoding="utf-16"?>
<ShoppingItems xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<CustomerName>test</CustomerName>
<Address>testAddress</Address>
<Items>
<Item>
<Name>item1</Name>
<Price>12</Price>
</Item>
<Item>
<Name>item2</Name>
<Price>14</Price>
</Item>
</Items>
</ShoppingItems>