Get another application standart output in realtime - c#

I want to get output of console application in realtime (same as run via cmd.exe) by my WinForm application. All actions i perform in non-UI thread (using BackgroundWorker's method bwRezerve_DoWork). AddTextToTextbox use Invoke to update UI.
But now i receive output only when application is exited.
I read a lot of question here and on other sites, read similar question Capture output of process synchronously (i.e. "when it happens") but still can't find solution.
Here code snippet:
private void bwRezerve_DoWork(object sender, DoWorkEventArgs e)
{
proc = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = Application.StartupPath + Path.DirectorySeparatorChar + "7z.exe",
Arguments = e.Argument,
UseShellExecute = false,
RedirectStandardOutput = true,
RedirectStandardError = true,
CreateNoWindow = true,
}
};
proc.EnableRaisingEvents = true;
proc.OutputDataReceived += (who, what) => AddTextToTextbox(what.Data);
proc.ErrorDataReceived += (who, what) => AddTextToTextbox(what.Data);
proc.Start();
proc.BeginOutputReadLine();
proc.BeginErrorReadLine();
//same result with next line commented
proc.WaitForExit(5 * 60 * 1000);
}
Also i've tried this instead of OutputDataReceived but result is the same
while (!proc.StandardOutput.EndOfStream)
{
string line = proc.StandardOutput.ReadLine();
AddTextToTextbox(line);
}

Try this code
private void bwRezerve_DoWork(object sender, DoWorkEventArgs e)
{
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = Application.StartupPath + Path.DirectorySeparatorChar + "7z.exe";
psi.Arguments = e.Argument;
psi.UseShellExecute = false;
psi.RedirectStandardError = true;
psi.RedirectStandardOutput = true;
psi.CreateNoWindow = true;
Process proc = Process.Start(psi);
proc.WaitForExit();
while (!proc.StandardOutput.EndOfStream)
{
string line = proc.StandardOutput.ReadLine();
AddTextToTextbox(line);
}
}

I think problem there is problem with your thread your process is running under main thread so your output will display only when process is completed.
So you need use background worker or thread you can also use dispatcher to get output from current process.
while (!proc.StandardOutput.EndOfStream)
{
Application.Current.Dispatcher.Invoke(new Action(() =>
{
string line = proc.StandardOutput.ReadLine();
AddTextToTextbox(line);
}), null);
}
hope its work for you ..
EDIT
you can get current dispatcher using
window base Lib.
Assembly: WindowsBase (in WindowsBase.dll) (Ref MSDN)
System.Windows.Threading.Dispatcher.CurrentDispatcher.Invoke(new Action(() =>
{
string line = proc.StandardOutput.ReadLine();
AddTextToTextbox(line);
}), null);

7zip doesn't use standard output - you can easily see that since it continually rewrites the screen (to show the progress). There's no way to stream that.

Related

how to get Powershell output of this code? [duplicate]

I would like to run an external command line program from my Mono/.NET app.
For example, I would like to run mencoder. Is it possible:
To get the command line shell output, and write it on my text box?
To get the numerical value to show a progress bar with time elapsed?
When you create your Process object set StartInfo appropriately:
var proc = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = "program.exe",
Arguments = "command line arguments to your executable",
UseShellExecute = false,
RedirectStandardOutput = true,
CreateNoWindow = true
}
};
then start the process and read from it:
proc.Start();
while (!proc.StandardOutput.EndOfStream)
{
string line = proc.StandardOutput.ReadLine();
// do something with line
}
You can use int.Parse() or int.TryParse() to convert the strings to numeric values. You may have to do some string manipulation first if there are invalid numeric characters in the strings you read.
You can process your output synchronously or asynchronously.
1. Synchronous example
static void runCommand()
{
Process process = new Process();
process.StartInfo.FileName = "cmd.exe";
process.StartInfo.Arguments = "/c DIR"; // Note the /c command (*)
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.RedirectStandardError = true;
process.Start();
//* Read the output (or the error)
string output = process.StandardOutput.ReadToEnd();
Console.WriteLine(output);
string err = process.StandardError.ReadToEnd();
Console.WriteLine(err);
process.WaitForExit();
}
Note that it's better to process both output and errors: they must be handled separately.
(*) For some commands (here StartInfo.Arguments) you must add the /c directive, otherwise the process freezes in the WaitForExit().
2. Asynchronous example
static void runCommand()
{
//* Create your Process
Process process = new Process();
process.StartInfo.FileName = "cmd.exe";
process.StartInfo.Arguments = "/c DIR";
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.RedirectStandardError = true;
//* Set your output and error (asynchronous) handlers
process.OutputDataReceived += new DataReceivedEventHandler(OutputHandler);
process.ErrorDataReceived += new DataReceivedEventHandler(OutputHandler);
//* Start process and handlers
process.Start();
process.BeginOutputReadLine();
process.BeginErrorReadLine();
process.WaitForExit();
}
static void OutputHandler(object sendingProcess, DataReceivedEventArgs outLine)
{
//* Do your stuff with the output (write to console/log/StringBuilder)
Console.WriteLine(outLine.Data);
}
If you don't need to do complicate operations with the output, you can bypass the OutputHandler method, just adding the handlers directly inline:
//* Set your output and error (asynchronous) handlers
process.OutputDataReceived += (s, e) => Console.WriteLine(e.Data);
process.ErrorDataReceived += (s, e) => Console.WriteLine(e.Data);
Alright, for anyone who wants both Errors and Outputs read, but gets deadlocks with any of the solutions, provided in other answers (like me), here is a solution that I built after reading MSDN explanation for StandardOutput property.
Answer is based on T30's code:
static void runCommand()
{
//* Create your Process
Process process = new Process();
process.StartInfo.FileName = "cmd.exe";
process.StartInfo.Arguments = "/c DIR";
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.RedirectStandardError = true;
//* Set ONLY ONE handler here.
process.ErrorDataReceived += new DataReceivedEventHandler(ErrorOutputHandler);
//* Start process
process.Start();
//* Read one element asynchronously
process.BeginErrorReadLine();
//* Read the other one synchronously
string output = process.StandardOutput.ReadToEnd();
Console.WriteLine(output);
process.WaitForExit();
}
static void ErrorOutputHandler(object sendingProcess, DataReceivedEventArgs outLine)
{
//* Do your stuff with the output (write to console/log/StringBuilder)
Console.WriteLine(outLine.Data);
}
The standard .NET way of doing this is to read from the Process' StandardOutput stream. There is an example in the linked MSDN docs. Similar, you can read from StandardError, and write to StandardInput.
It is possible to get the command line shell output of a process as described here : http://www.c-sharpcorner.com/UploadFile/edwinlima/SystemDiagnosticProcess12052005035444AM/SystemDiagnosticProcess.aspx
This depends on mencoder. If it ouputs this status on the command line then yes :)
you can use shared memory for the 2 processes to communicate through, check out MemoryMappedFile
you'll mainly create a memory mapped file mmf in the parent process using "using" statement then create the second process till it terminates and let it write the result to the mmf using BinaryWriter, then read the result from the mmf using the parent process, you can also pass the mmf name using command line arguments or hard code it.
make sure when using the mapped file in the parent process that you make the child process write the result to the mapped file before the mapped file is released in the parent process
Example:
parent process
private static void Main(string[] args)
{
using (MemoryMappedFile mmf = MemoryMappedFile.CreateNew("memfile", 128))
{
using (MemoryMappedViewStream stream = mmf.CreateViewStream())
{
BinaryWriter writer = new BinaryWriter(stream);
writer.Write(512);
}
Console.WriteLine("Starting the child process");
// Command line args are separated by a space
Process p = Process.Start("ChildProcess.exe", "memfile");
Console.WriteLine("Waiting child to die");
p.WaitForExit();
Console.WriteLine("Child died");
using (MemoryMappedViewStream stream = mmf.CreateViewStream())
{
BinaryReader reader = new BinaryReader(stream);
Console.WriteLine("Result:" + reader.ReadInt32());
}
}
Console.WriteLine("Press any key to continue...");
Console.ReadKey();
}
Child process
private static void Main(string[] args)
{
Console.WriteLine("Child process started");
string mmfName = args[0];
using (MemoryMappedFile mmf = MemoryMappedFile.OpenExisting(mmfName))
{
int readValue;
using (MemoryMappedViewStream stream = mmf.CreateViewStream())
{
BinaryReader reader = new BinaryReader(stream);
Console.WriteLine("child reading: " + (readValue = reader.ReadInt32()));
}
using (MemoryMappedViewStream input = mmf.CreateViewStream())
{
BinaryWriter writer = new BinaryWriter(input);
writer.Write(readValue * 2);
}
}
Console.WriteLine("Press any key to continue...");
Console.ReadKey();
}
to use this sample, you'll need to create a solution with 2 projects inside, then you take the build result of the child process from %childDir%/bin/debug and copy it to %parentDirectory%/bin/debug then run the parent project
childDir and parentDirectory are the folder names of your projects on the pc
good luck :)
You can log process output using below code:
ProcessStartInfo pinfo = new ProcessStartInfo(item);
pinfo.CreateNoWindow = false;
pinfo.UseShellExecute = true;
pinfo.RedirectStandardOutput = true;
pinfo.RedirectStandardInput = true;
pinfo.RedirectStandardError = true;
pinfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
var p = Process.Start(pinfo);
p.WaitForExit();
Process process = Process.Start(new ProcessStartInfo((item + '>' + item + ".txt"))
{
UseShellExecute = false,
RedirectStandardOutput = true
});
process.WaitForExit();
string output = process.StandardOutput.ReadToEnd();
if (process.ExitCode != 0) {
}
How to launch a process (such as a bat file, perl script, console program) and have its standard output displayed on a windows form:
processCaller = new ProcessCaller(this);
//processCaller.FileName = #"..\..\hello.bat";
processCaller.FileName = #"commandline.exe";
processCaller.Arguments = "";
processCaller.StdErrReceived += new DataReceivedHandler(writeStreamInfo);
processCaller.StdOutReceived += new DataReceivedHandler(writeStreamInfo);
processCaller.Completed += new EventHandler(processCompletedOrCanceled);
processCaller.Cancelled += new EventHandler(processCompletedOrCanceled);
// processCaller.Failed += no event handler for this one, yet.
this.richTextBox1.Text = "Started function. Please stand by.." + Environment.NewLine;
// the following function starts a process and returns immediately,
// thus allowing the form to stay responsive.
processCaller.Start();
You can find ProcessCaller on this link: Launching a process and displaying its standard output
I was running into the infamous deadlock problem when calling Process.StandardOutput.ReadLine and Process.StandardOutput.ReadToEnd.
My goal/use case is simple. Start a process and redirect it's output so I can capture that output and log it to the console via .NET Core's ILogger<T> and also append the redirected output to a file log.
Here's my solution using the built in async event handlers Process.OutputDataReceived and Process.ErrorDataReceived.
var p = new Process
{
StartInfo = new ProcessStartInfo(
command.FileName, command.Arguments
)
{
RedirectStandardOutput = true,
RedirectStandardError = true,
UseShellExecute = false,
}
};
// Asynchronously pushes StdOut and StdErr lines to a thread safe FIFO queue
var logQueue = new ConcurrentQueue<string>();
p.OutputDataReceived += (sender, args) => logQueue.Enqueue(args.Data);
p.ErrorDataReceived += (sender, args) => logQueue.Enqueue(args.Data);
// Start the process and begin streaming StdOut/StdErr
p.Start();
p.BeginOutputReadLine();
p.BeginErrorReadLine();
// Loop until the process has exited or the CancellationToken is triggered
do
{
var lines = new List<string>();
while (logQueue.TryDequeue(out var log))
{
lines.Add(log);
_logger.LogInformation(log)
}
File.AppendAllLines(_logFilePath, lines);
// Asynchronously sleep for some time
try
{
Task.Delay(5000, stoppingToken).Wait(stoppingToken);
}
catch(OperationCanceledException) {}
} while (!p.HasExited && !stoppingToken.IsCancellationRequested);
The solution that worked for me in win and linux is the folling
// GET api/values
[HttpGet("cifrado/{xml}")]
public ActionResult<IEnumerable<string>> Cifrado(String xml)
{
String nombreXML = DateTime.Now.ToString("ddMMyyyyhhmmss").ToString();
String archivo = "/app/files/"+nombreXML + ".XML";
String comando = " --armor --recipient bibankingprd#bi.com.gt --encrypt " + archivo;
try{
System.IO.File.WriteAllText(archivo, xml);
//String comando = "C:\\GnuPG\\bin\\gpg.exe --recipient licorera#local.com --armor --encrypt C:\\Users\\Administrador\\Documents\\pruebas\\nuevo.xml ";
ProcessStartInfo startInfo = new ProcessStartInfo() {FileName = "/usr/bin/gpg", Arguments = comando };
Process proc = new Process() { StartInfo = startInfo, };
proc.StartInfo.RedirectStandardOutput = true;
proc.StartInfo.RedirectStandardError = true;
proc.Start();
proc.WaitForExit();
Console.WriteLine(proc.StandardOutput.ReadToEnd());
return new string[] { "Archivo encriptado", archivo + " - "+ comando};
}catch (Exception exception){
return new string[] { archivo, "exception: "+exception.ToString() + " - "+ comando };
}
}
System.Diagnostics.Process is not the most pleasant to work with, so you may want to try CliWrap. It offers many different models for working with output, including piping, buffering, and real-time streaming. Here are some examples (taken from readme).
Simply launch a command line executable:
using CliWrap;
var result = await Cli.Wrap("path/to/exe")
.WithArguments("--foo bar")
.WithWorkingDirectory("work/dir/path")
.ExecuteAsync();
// Result contains:
// -- result.ExitCode (int)
// -- result.StartTime (DateTimeOffset)
// -- result.ExitTime (DateTimeOffset)
// -- result.RunTime (TimeSpan)
Launch a command line executable and buffer stdout/stderr in-memory:
using CliWrap;
using CliWrap.Buffered;
// Calling `ExecuteBufferedAsync()` instead of `ExecuteAsync()`
// implicitly configures pipes that write to in-memory buffers.
var result = await Cli.Wrap("path/to/exe")
.WithArguments("--foo bar")
.WithWorkingDirectory("work/dir/path")
.ExecuteBufferedAsync();
// Result contains:
// -- result.StandardOutput (string)
// -- result.StandardError (string)
// -- result.ExitCode (int)
// -- result.StartTime (DateTimeOffset)
// -- result.ExitTime (DateTimeOffset)
// -- result.RunTime (TimeSpan)
Launch a command line executable with manual pipe configuration:
using CliWrap
var buffer = new StringBuilder();
var result = await Cli.Wrap("foo")
.WithStandardOutputPipe(PipeTarget.ToFile("output.txt"))
.WithStandardErrorPipe(PipeTarget.ToStringBuilder(buffer))
.ExecuteAsync();
Launch a command line executable as an event stream:
using CliWrap;
using CliWrap.EventStream;
var cmd = Cli.Wrap("foo").WithArguments("bar");
await foreach (var cmdEvent in cmd.ListenAsync())
{
switch (cmdEvent)
{
case StartedCommandEvent started:
_output.WriteLine($"Process started; ID: {started.ProcessId}");
break;
case StandardOutputCommandEvent stdOut:
_output.WriteLine($"Out> {stdOut.Text}");
break;
case StandardErrorCommandEvent stdErr:
_output.WriteLine($"Err> {stdErr.Text}");
break;
case ExitedCommandEvent exited:
_output.WriteLine($"Process exited; Code: {exited.ExitCode}");
break;
}
}

C# Running exe through process, how to hide window

Im running an exe through process in my c# program, i want the process to be completely invisible without the console of it popping up.
This is my code
Process process2 = new Process();
process2.StartInfo.FileName = "cmd.exe";
process2.StartInfo.UseShellExecute = false;
process2.StartInfo.CreateNoWindow = true;
process2.StartInfo.RedirectStandardOutput = true;
process2.StartInfo.RedirectStandardError = true;
process2.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process2 = Process.Start(path3);
even with this code the console window still opens and shows, any help will be appreciated :)
Using
UseShellExecute = false; CreateNoWindow = true;
Should hide the process although it depends on the path in which you are opening, if the process has a force show
Try the following:
private void RunCmd(string exePath, string arguments = null)
{
//create new instance
ProcessStartInfo startInfo = new ProcessStartInfo(exePath, arguments);
startInfo.Arguments = arguments; //arguments
startInfo.CreateNoWindow = true; //don't create a window
startInfo.RedirectStandardError = true; //redirect standard error
startInfo.RedirectStandardOutput = true; //redirect standard output
startInfo.RedirectStandardInput = false;
startInfo.UseShellExecute = false; //if true, uses 'ShellExecute'; if false, uses 'CreateProcess'
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.ErrorDialog = false;
//create new instance
using (Process p = new Process { StartInfo = startInfo, EnableRaisingEvents = true })
{
//subscribe to event and add event handler code
p.ErrorDataReceived += (sender, e) =>
{
if (!String.IsNullOrEmpty(e.Data))
{
//ToDo: add desired code
Debug.WriteLine("Error: " + e.Data);
}
};
//subscribe to event and add event handler code
p.OutputDataReceived += (sender, e) =>
{
if (!String.IsNullOrEmpty(e.Data))
{
//ToDo: add desired code
Debug.WriteLine("Output: " + e.Data);
}
};
p.Start(); //start
p.BeginErrorReadLine(); //begin async reading for standard error
p.BeginOutputReadLine(); //begin async reading for standard output
//waits until the process is finished before continuing
p.WaitForExit();
}
}
See also this post.
I fixed it by renaming the window instead ty for all your help

Run command line command passing STDIN [duplicate]

This question already has answers here:
Capturing console output from a .NET application (C#)
(8 answers)
Closed 6 years ago.
I need to spawn a child process that is a console application, and capture its output.
I wrote up the following code for a method:
string retMessage = String.Empty;
ProcessStartInfo startInfo = new ProcessStartInfo();
Process p = new Process();
startInfo.CreateNoWindow = true;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardInput = true;
startInfo.UseShellExecute = false;
startInfo.Arguments = command;
startInfo.FileName = exec;
p.StartInfo = startInfo;
p.Start();
p.OutputDataReceived += new DataReceivedEventHandler
(
delegate(object sender, DataReceivedEventArgs e)
{
using (StreamReader output = p.StandardOutput)
{
retMessage = output.ReadToEnd();
}
}
);
p.WaitForExit();
return retMessage;
However, this does not return anything. I don't believe the OutputDataReceived event is being called back, or the WaitForExit() command may be blocking the thread so it will never callback.
Any advice?
EDIT: Looks like I was trying too hard with the callback. Doing:
return p.StandardOutput.ReadToEnd();
Appears to work fine.
Here's code that I've verified to work. I use it for spawning MSBuild and listening to its output:
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.OutputDataReceived += (sender, args) => Console.WriteLine("received output: {0}", args.Data);
process.Start();
process.BeginOutputReadLine();
I just tried this very thing and the following worked for me:
StringBuilder outputBuilder;
ProcessStartInfo processStartInfo;
Process process;
outputBuilder = new StringBuilder();
processStartInfo = new ProcessStartInfo();
processStartInfo.CreateNoWindow = true;
processStartInfo.RedirectStandardOutput = true;
processStartInfo.RedirectStandardInput = true;
processStartInfo.UseShellExecute = false;
processStartInfo.Arguments = "<insert command line arguments here>";
processStartInfo.FileName = "<insert tool path here>";
process = new Process();
process.StartInfo = processStartInfo;
// enable raising events because Process does not raise events by default
process.EnableRaisingEvents = true;
// attach the event handler for OutputDataReceived before starting the process
process.OutputDataReceived += new DataReceivedEventHandler
(
delegate(object sender, DataReceivedEventArgs e)
{
// append the new data to the data already read-in
outputBuilder.Append(e.Data);
}
);
// start the process
// then begin asynchronously reading the output
// then wait for the process to exit
// then cancel asynchronously reading the output
process.Start();
process.BeginOutputReadLine();
process.WaitForExit();
process.CancelOutputRead();
// use the output
string output = outputBuilder.ToString();
Here's some full and simple code to do this. This worked fine when I used it.
var processStartInfo = new ProcessStartInfo
{
FileName = #"C:\SomeProgram",
Arguments = "Arguments",
RedirectStandardOutput = true,
UseShellExecute = false
};
var process = Process.Start(processStartInfo);
var output = process.StandardOutput.ReadToEnd();
process.WaitForExit();
Note that this only captures standard output; it doesn't capture standard error. If you want both, use this technique for each stream.
I needed to capture both stdout and stderr and have it timeout if the process didn't exit when expected. I came up with this:
Process process = new Process();
StringBuilder outputStringBuilder = new StringBuilder();
try
{
process.StartInfo.FileName = exeFileName;
process.StartInfo.WorkingDirectory = args.ExeDirectory;
process.StartInfo.Arguments = args;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.CreateNoWindow = true;
process.StartInfo.UseShellExecute = false;
process.EnableRaisingEvents = false;
process.OutputDataReceived += (sender, eventArgs) => outputStringBuilder.AppendLine(eventArgs.Data);
process.ErrorDataReceived += (sender, eventArgs) => outputStringBuilder.AppendLine(eventArgs.Data);
process.Start();
process.BeginOutputReadLine();
process.BeginErrorReadLine();
var processExited = process.WaitForExit(PROCESS_TIMEOUT);
if (processExited == false) // we timed out...
{
process.Kill();
throw new Exception("ERROR: Process took too long to finish");
}
else if (process.ExitCode != 0)
{
var output = outputStringBuilder.ToString();
var prefixMessage = "";
throw new Exception("Process exited with non-zero exit code of: " + process.ExitCode + Environment.NewLine +
"Output from process: " + outputStringBuilder.ToString());
}
}
finally
{
process.Close();
}
I am piping the stdout and stderr into the same string, but you could keep it separate if needed. It uses events, so it should handle them as they come (I believe). I have run this successfully, and will be volume testing it soon.
It looks like two of your lines are out of order. You start the process before setting up an event handler to capture the output. It's possible the process is just finishing before the event handler is added.
Switch the lines like so.
p.OutputDataReceived += ...
p.Start();
Redirecting the stream is asynchronous and will potentially continue after the process has terminated. It is mentioned by Umar to cancel after process termination process.CancelOutputRead(). However that has data loss potential.
This is working reliably for me:
process.WaitForExit(...);
...
while (process.StandardOutput.EndOfStream == false)
{
Thread.Sleep(100);
}
I didn't try this approach but I like the suggestion from Sly:
if (process.WaitForExit(timeout))
{
process.WaitForExit();
}
You need to call p.Start() to actually run the process after you set the StartInfo. As it is, your function is probably hanging on the WaitForExit() call because the process was never actually started.
The answer from Judah did not work for me (or is not complete) as the application was exiting after the first BeginOutputReadLine();
This works for me as a complete snippet, reading the constant output of a ping:
var process = new Process();
process.StartInfo.FileName = "ping";
process.StartInfo.Arguments = "google.com -t";
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.UseShellExecute = false;
process.OutputDataReceived += (sender, a) => Console.WriteLine(a.Data);
process.Start();
process.BeginOutputReadLine();
process.WaitForExit();
Here's a method that I use to run a process and gets its output and errors :
public static string ShellExecute(this string path, string command, TextWriter writer, params string[] arguments)
{
using (var process = Process.Start(new ProcessStartInfo { WorkingDirectory = path, FileName = command, Arguments = string.Join(" ", arguments), UseShellExecute = false, RedirectStandardOutput = true, RedirectStandardError = true }))
{
using (process.StandardOutput)
{
writer.WriteLine(process.StandardOutput.ReadToEnd());
}
using (process.StandardError)
{
writer.WriteLine(process.StandardError.ReadToEnd());
}
}
return path;
}
For example :
#"E:\Temp\MyWorkingDirectory".ShellExecute(#"C:\Program Files\Microsoft SDKs\Windows\v6.0A\Bin\svcutil.exe", Console.Out);

Getting command line output dynamically

I'm running a program using command line in c# this program produce some logs while its running in need to display this logs whenever it get change. I wrote the following code but it shows all the logs once the process has been killed and during the running time my program is not responding. how can I fix it?
regards
ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd", "/c " + "C:\\server.py");
Process proc = new Process();
procStartInfo.WindowStyle = ProcessWindowStyle.Hidden;
procStartInfo.UseShellExecute = false;
procStartInfo.RedirectStandardOutput = true;
//procStartInfo.CreateNoWindow = true;
proc.StartInfo = procStartInfo;
proc.Start();
string output = proc.StandardOutput.ReadToEnd();
proc.WaitForExit(300);
LogstextBox.Text = output;
Edited:
well, I tried to use OutputDataReceived but it doesn't show any result, here is the changed code:
{
//processCaller.FileName = #"ping";
//processCaller.Arguments = "4.2.2.4 -t"; this is working
processCaller.FileName = #"cmd.exe";
processCaller.Arguments = "/c c:\\server.py"; //this is not working
processCaller.StdErrReceived += new DataReceivedHandler(writeStreamInfo);
processCaller.StdOutReceived += new DataReceivedHandler(writeStreamInfo);
processCaller.Completed += new EventHandler(processCompletedOrCanceled);
processCaller.Cancelled += new EventHandler(processCompletedOrCanceled);
this.richTextBox1.Text = "Server Started.." + Environment.NewLine;
processCaller.Start();
}
private void writeStreamInfo(object sender, DataReceivedEventArgs e)
{
this.richTextBox1.AppendText(e.Text + Environment.NewLine);
}
This is the problem:
string output = proc.StandardOutput.ReadToEnd();
You won't get to the "end" of standard output until the process has terminated.
You should be reading a line at a time - or possibly just subscribing to the OutputDataReceived event (and following the documented other requirements for that event).
EDIT: Here's sample code which works for me:
using System;
using System.Diagnostics;
using System.Threading;
class Program
{
public static void Main()
{
ProcessStartInfo startInfo = new ProcessStartInfo("cmd", "/c " + "type Test.cs")
{
WindowStyle = ProcessWindowStyle.Hidden,
UseShellExecute = false,
RedirectStandardOutput = true,
CreateNoWindow = true
};
Process process = Process.Start(startInfo);
process.OutputDataReceived += (sender, e) => Console.WriteLine(e.Data);
process.BeginOutputReadLine();
process.WaitForExit();
// We may not have received all the events yet!
Thread.Sleep(5000);
}
}
Note that in your sample code, you're accessing the UI on whatever thread the OutputDataReceived handler is called - that looks like a bad idea to me.
You can use the Process.BeginOutputReadLine Method. The link shows a complete working example in C# which uses the OutputDataReceived event. That code example should do what you want.

Capturing console output from a .NET application (C#)

How do I invoke a console application from my .NET application and capture all the output generated in the console?
(Remember, I don't want to save the information first in a file and then relist as I would love to receive it as live.)
This can be quite easily achieved using the ProcessStartInfo.RedirectStandardOutput property. A full sample is contained in the linked MSDN documentation; the only caveat is that you may have to redirect the standard error stream as well to see all output of your application.
Process compiler = new Process();
compiler.StartInfo.FileName = "csc.exe";
compiler.StartInfo.Arguments = "/r:System.dll /out:sample.exe stdstr.cs";
compiler.StartInfo.UseShellExecute = false;
compiler.StartInfo.RedirectStandardOutput = true;
compiler.Start();
Console.WriteLine(compiler.StandardOutput.ReadToEnd());
compiler.WaitForExit();
This is bit improvement over accepted answer from #mdb. Specifically, we also capture error output of the process. Additionally, we capture these outputs through events because ReadToEnd() doesn't work if you want to capture both error and regular output. It took me while to make this work because it actually also requires BeginxxxReadLine() calls after Start().
Asynchronous way:
using System.Diagnostics;
Process process = new Process();
void LaunchProcess()
{
process.EnableRaisingEvents = true;
process.OutputDataReceived += new System.Diagnostics.DataReceivedEventHandler(process_OutputDataReceived);
process.ErrorDataReceived += new System.Diagnostics.DataReceivedEventHandler(process_ErrorDataReceived);
process.Exited += new System.EventHandler(process_Exited);
process.StartInfo.FileName = "some.exe";
process.StartInfo.Arguments = "param1 param2";
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.RedirectStandardOutput = true;
process.Start();
process.BeginErrorReadLine();
process.BeginOutputReadLine();
//below line is optional if we want a blocking call
//process.WaitForExit();
}
void process_Exited(object sender, EventArgs e)
{
Console.WriteLine(string.Format("process exited with code {0}\n", process.ExitCode.ToString()));
}
void process_ErrorDataReceived(object sender, DataReceivedEventArgs e)
{
Console.WriteLine(e.Data + "\n");
}
void process_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
Console.WriteLine(e.Data + "\n");
}
Use ProcessStartInfo.RedirectStandardOutput to redirect the output when creating your console process.
Then you can use Process.StandardOutput to read the program output.
The second link has a sample code how to do it.
ConsoleAppLauncher is an open source library made specifically to answer that question. It captures all the output generated in the console and provides simple interface to start and close console application.
The ConsoleOutput event is fired every time when a new line is written by the console to standard/error output. The lines are queued and guaranteed to follow the output order.
Also available as NuGet package.
Sample call to get full console output:
// Run simplest shell command and return its output.
public static string GetWindowsVersion()
{
return ConsoleApp.Run("cmd", "/c ver").Output.Trim();
}
Sample with live feedback:
// Run ping.exe asynchronously and return roundtrip times back to the caller in a callback
public static void PingUrl(string url, Action<string> replyHandler)
{
var regex = new Regex("(time=|Average = )(?<time>.*?ms)", RegexOptions.Compiled);
var app = new ConsoleApp("ping", url);
app.ConsoleOutput += (o, args) =>
{
var match = regex.Match(args.Line);
if (match.Success)
{
var roundtripTime = match.Groups["time"].Value;
replyHandler(roundtripTime);
}
};
app.Run();
}
I've added a number of helper methods to the O2 Platform (Open Source project) which allow you easily script an interaction with another process via the console output and input (see http://code.google.com/p/o2platform/source/browse/trunk/O2_Scripts/APIs/Windows/CmdExe/CmdExeAPI.cs)
Also useful for you might be the API that allows the viewing of the console output of the current process (in an existing control or popup window). See this blog post for more details: http://o2platform.wordpress.com/2011/11/26/api_consoleout-cs-inprocess-capture-of-the-console-output/ (this blog also contains details of how to consume the console output of new processes)
I made a reactive version that accepts callbacks for stdOut and StdErr.
onStdOut and onStdErr are called asynchronously,
as soon as data arrives (before the process exits).
public static Int32 RunProcess(String path,
String args,
Action<String> onStdOut = null,
Action<String> onStdErr = null)
{
var readStdOut = onStdOut != null;
var readStdErr = onStdErr != null;
var process = new Process
{
StartInfo =
{
FileName = path,
Arguments = args,
CreateNoWindow = true,
UseShellExecute = false,
RedirectStandardOutput = readStdOut,
RedirectStandardError = readStdErr,
}
};
process.Start();
if (readStdOut) Task.Run(() => ReadStream(process.StandardOutput, onStdOut));
if (readStdErr) Task.Run(() => ReadStream(process.StandardError, onStdErr));
process.WaitForExit();
return process.ExitCode;
}
private static void ReadStream(TextReader textReader, Action<String> callback)
{
while (true)
{
var line = textReader.ReadLine();
if (line == null)
break;
callback(line);
}
}
Example usage
The following will run executable with args and print
stdOut in white
stdErr in red
to the console.
RunProcess(
executable,
args,
s => { Console.ForegroundColor = ConsoleColor.White; Console.WriteLine(s); },
s => { Console.ForegroundColor = ConsoleColor.Red; Console.WriteLine(s); }
);
From PythonTR - Python Programcıları Derneği, e-kitap, örnek:
Process p = new Process(); // Create new object
p.StartInfo.UseShellExecute = false; // Do not use shell
p.StartInfo.RedirectStandardOutput = true; // Redirect output
p.StartInfo.FileName = "c:\\python26\\python.exe"; // Path of our Python compiler
p.StartInfo.Arguments = "c:\\python26\\Hello_C_Python.py"; // Path of the .py to be executed
Added process.StartInfo.**CreateNoWindow** = true; and timeout.
private static void CaptureConsoleAppOutput(string exeName, string arguments, int timeoutMilliseconds, out int exitCode, out string output)
{
using (Process process = new Process())
{
process.StartInfo.FileName = exeName;
process.StartInfo.Arguments = arguments;
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.CreateNoWindow = true;
process.Start();
output = process.StandardOutput.ReadToEnd();
bool exited = process.WaitForExit(timeoutMilliseconds);
if (exited)
{
exitCode = process.ExitCode;
}
else
{
exitCode = -1;
}
}
}

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