Develop Reference

Convert DateTime.Now to DateOnly in dd/mm/yyyy

I'm working with a DateOnly variable and I'm trying to get the DateTime.Now time in a dd/mm/yyyy format, however it's only returning the date on mm/dd/yyyy format.
I strictly need the current date in a dd/mm/yyyy format, and I haven't been able to figure it out how to.
This is an example how I'm working to convert the DateTime.Now to DateOnly type
public class Example
{
public DateOnly? Date{get; set;}
}
public class Process1
{
Example example = new Example();
{
example.Date= DateOnly.FromDateTime(DateTime.Now);
//this is returning the current date in a mm/dd/yyyy format
}
}

Formatting can only be done by string not by date only.
save date in dateonly datatype
example.Date= DateOnly.FromDateTime(DateTime.Now);
but when you need specify format then use string like below
string s = example.Date.ToString("dd/M/yyyy", CultureInfo.InvariantCulture);
or
s = example.Date.ToString("dd/MM/yyyy");
For More detail refer this Link

I set the Date variable as a DateTime property in the Example Class :
public DateTime Date { get; set; } = DateTime.Now;
In the main code, i converted the Date property into a string and assigned it to dateOnly Variable:
string dateOnly = Convert.ToString(example.Date.ToString("dd-mm-yyyy"));

Serialize XML with formatter

I would like serialize object to XML. This part is easy.
But i would serialize properties (like DateTime) with a specific format.
My current code is this one :
[XmlIgnore]
private DateTime _paymentDate { get; set; }
public string PaymentDate
{
get
{
return this._paymentDate.ToString("yyyy-MM-dd HH:mm:ss");
}
set
{
this._paymentDate = DateTime.ParseExact(value, "yyyy-MM-dd HH:mm:ss", CultureInfo.InvariantCulture);
}
}
But it's very bad. If i have 100 DateTime properties, i should duplicate this code 100 times.
So, i would like to use a formatter (like with Newtonsoft JSON).
How can i do it ?
Thanks a lot :)

C# : Could not parse the correct date and time to the current system time zone

I have a service which returns a json like this :
[
{
"title":"First event",
"startDate":"\/Date(1495512000000-0400)\/",
"endDate":"\/Date(1495857540000-0400)\/",
}
]
I deserialize the json output to the list with respect to the model I have defined :
Model
public class EventModel
{
[JsonProperty("title")]
public string Title { get; set; }
[JsonProperty("startDate")]
public DateTime StartDate { get; set; }
[JsonProperty("endDate")]
public DateTime EndDate { get; set; }
}
C# Code of deserialization
I am using Newtonsoft.Json package for deserialization.
List< EventModel > lstEvent = new List< EventModel >();
lstEvent = JsonConvert.DeserializeObject<List< EventModel >>(await objMyServices.GetData());
So in this case when I debug I get the following output in two different timezone:
For GMT+5:30 (Kolkata - India):
Start Time : 23-05-2017 09:30:00
End Time : 27-05-2017 09:29:00
For GMT-4:00 (New York):
Start Time : 23-05-2017 00:00:00
End Time : 26-05-2017 23:59:00
Therefore for every record, start time is not parsed to the respective system time zone when I switch to GMT-4:00 (New York).
What is the thing I am missing here ?

Json.NET allows you to specify what kind of DateTime to return (UTC, Local) through the DateTimeZoneHandling serializer setting. The default is Local.
To return a UTC DateTime, use DateTimeZoneHandling.Utc :
var settings = new Newtonsoft.Json.JsonSerializerSettings()
{
DateTimeZoneHandling = DateTimeZoneHandling.Utc
};
var content=await objMyServices.GetData();
var lstEvent = JsonConvert.DeserializeObject<List<EventModel>>(content, settings);
Perhaps a better option is to change the property types to DateTimeOffset. This type preserves the original offset.

You can use Ticks in Web API for this. This is much convenient when you are working with multiple time zones. Refer below example .
DateTime.UtcNow.Ticks

Get date from ISO8601 format in C#

I am working with the you-tube API, which returns JSON data. The video published date is in this format: "publishedAt": "2017-04-30T18:18:41.000Z".
After deserializing the JSON object, I want to get the date from the published DateTime in C#.
How can I do it, and what is this format of DateTime?

There's absolutely no need to manually parse a well-formatted ISO 8601 date.
Simply change the property on your model from string to DateTime:
public class VideoData
{
[JsonProperty("publishedAt")]
public DateTime PublishedAt { get; set; }
}
And then deserialize into that:
var model = JsonConvert.DeserializeObject<VideoData>(jsonString);
And Json.NET will handle the rest.

using Json ATTRIBUTE to serialize datetime to look like /Date(1486516302715) in C#

class className
{
Datetime dateTime {get; set;}
}
className object = new className();
When I use Json(object) this returns the dateTime field in this format :
{"dateTime":"/Date(1486516302715)/"}
But what I want is to return the same value using an attribute to the dateTime parameter instead.
Something like :
[JsonConverter(typeof(JavaScriptDateTimeConverter))]
Datetime dateTime {get; set;}
Only the JavaScriptDateTimeConverter is not the one which gives me the date in the right format.

In javascript you could use the new Date method.
new Date(parseInt(date.substr(6))); // date= "/Date(1486516302715)/"