I see several questions that are close to this but none exactly cover it:
How to apply an XSLT Stylesheet in C#
XSLT Transform of XML using Xml data from a web form
How to transform an xml structure generated from a request to a web services
I can cobble something together from these but I worry I am passing it through too many steps to be efficient.
What I currently have is this, to read XML from a HTTP web request:
WebRequest request = WebRequest.Create(url);
WebResponse response = request.GetResponse();
Stream stream = response.GetResponseStream();
StreamReader streamReader = new StreamReader(stream);
string xml = streamReader.ReadToEnd();
This was before the need to apply an XLST transform was needed. Now I have a (possibly null) XslCompiledTransform object.
So I want to add a block like:
if(transform != null)
{
xml = transform.Transform(xml);
}
Clearly this isn't possible as written. I see StringReaders and XmlReaders can be created but is it inefficient to get my xml as a string and then push it back into another object? Can I use my stream or streamReader objects directly to support the same basic flow, but with optional transformation?
Personally I'd use the XmlDocument.Load() function to load the XML from the URL, without using WebRequest in this case.
You can pass the XmlDocument Straight to XSLCompiledTransform.Transform() then.
XmlDocument doc = new XmlDocument();
doc.Load(url);
if (transform != null)
{
XmlDocument tempDoc = new XmlDocument();
using (XmlWriter writer = tempDoc.CreateNavigator().AppendChild())
{
transform.Transform(doc, writer);
}
doc = tempDoc;
} //Use your XmlDocument for your transformed output
Related
I trying to convert JSON output into XML. Unfortunately I get this error:
JSON root object has multiple properties. The root object must have a single property in order to create a valid XML document. Consider specifing a DeserializeRootElementName.
This is what I up to now created.
string url = string.Format("https://graph.facebook.com/{0}?fields=posts.fields(message)&access_token={1}", user_name, access_token);
HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
StreamReader reader = new StreamReader(response.GetResponseStream());
jsonOutput = reader.ReadToEnd();
Console.WriteLine("THIS IS JSON OUTPUT: " + jsonOutput);
}
XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(jsonOutput);
Console.WriteLine(doc);
And this is my JSON output:
{"id":"108013515952807","posts":{"data":[{"id":"108013515952807_470186843068804","created_time":"2013-05-14T20:43:28+0000"},{"message":"TEKST","id":"108013515952807_470178529736302","created_time":"2013-05-14T20:22:07+0000"}
How can I solve this problem?
Despite the fact your JSON provided in the question is not complete, you have multiple properties at the top level as indicated by the exception. You have to define the root for it to get valid XML:
var doc = JsonConvert.DeserializeXmlNode(jsonOutput, "root");
EDIT: In order to print out your XML with indentation you can use XDocument class from System.Xml.Linq namespace: XDocument.Parse(doc.InnerXml).
I thought it's worth linking to the Documentation for turning xml to json and the other way around.
The guys are right..
// To convert an XML node contained in string xml into a JSON string
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
string jsonText = JsonConvert.SerializeXmlNode(doc);
// To convert JSON text contained in string json into an XML node
XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(json);
You can do JSON-to-XML also by using the .NET Framework (System.Runtime.Serialization.Json):
private static XDocument JsonToXml(string jsonString)
{
using (var stream = new MemoryStream(Encoding.ASCII.GetBytes(jsonString)))
{
var quotas = new XmlDictionaryReaderQuotas();
return XDocument.Load(JsonReaderWriterFactory.CreateJsonReader(stream, quotas));
}
}
DeserializeXmlNode returns XDcument.
If needed XNode use FirstNode.
//string jsonOutput="{"id":"108013515952807","posts":{"data":[{"id":"108013515952807_470186843068804","created_time":"2013-05-14T20:43:28+0000"},{"message":"TEKST","id":"108013515952807_470178529736302","created_time":"2013-05-14T20:22:07+0000"}";
var myelement= JsonConvert.DeserializeXmlNode(jsonOutput, "myelement").FirstNode;
Your shared JSON is invalid please go through http://jsonformatter.curiousconcept.com/ and validate your JSON first.
Yourt JSON should look like:
{
"id":"108013515952807",
"posts":{
"data":[
{
"id":"108013515952807_470186843068804",
"created_time":"2013-05-14T20:43:28+0000"
},
{
"message":"TEKST",
"id":"108013515952807_470178529736302",
"created_time":"2013-05-14T20:22:07+0000"
}
]
}
}
Adding on #jwaliszko's answer, converting json to XDocument:
XDocument xml = JsonConvert.DeserializeXNode(json);
Lets say The following is my xml input that I receive from my webservice using this code:
string url = txtURL.Text;
HttpWebRequest req = (HttpWebRequest)WebRequest.Create(url);
req.Method = "GET";
HttpWebResponse rep = (HttpWebResponse)req.GetResponse();
XmlDocument doc = new XmlDocument();
doc.Load(rep.GetResponseStream());
rep.Close();
now I have the following xml document in the "doc"
<note>
<parent_element>
<child_element attribute_1="1">
<inner_element> first Text </inner_element>
</child_element>
<child_element attribute_1="2">
<inner_element> second Text </inner_element>
</child_element>
</parent_element>
</note>
Now I want to remove the first child element based on its attribute value. So if the attribute value of the child element is "1" then I want to delete "child_element" and all of its child elements. so my final result should look like this:
<note>
<parent_element>
<child_element attribute_1="2">
<inner_element> second Text </inner_element>
</child_element>
</parent_element>
</note>
Once I have removed the element, I would write it back to the webservice. I know i am asking for a lot, but havent been able to figure it out so far.
I would include my code, but since I am a newbie to xml manipulation, i think that will be of no use (sad face). Any help or direction will be appreciated.
Thank you guys.
First of all: doc.load(txtURL.Text) is enough to load the XML from a remote location.
You can delete a node like this:
XmlDocument doc = new XmlDocument();
doc.Load(filename);
//Select node that needs to be deleted
XmlNode node = doc.SelectSingleNode("/note/parent_element/child_element[#attribute_1 = '1']");
node.ParentNode.RemoveChild(node);
How you write all that back to your web application depends on what it is expecting. I will attach one example that POSTs a XML file against a RESTful web service
WebRequest req = WebRequest.Create(updateURL);
req.ContentType = "text/xml";
req.Method = "POST";
byte[] bytes = System.Text.Encoding.Default.GetBytes(xmldoc);
req.ContentLength = bytes.Length;
Stream data = req.GetRequestStream();
data.Write(bytes, 0, bytes.Length);
data.Close();
I am doing task of loading the live xml file (from live url) to XmlDataDocument, but every time I am getting error:
The operation has timed out
The code is as follows, The url containing the xml feeds , I want to load it into xmlDoc.
XmlDataDocument xmlDoc = new XmlDataDocument();
xmlDoc.Load("http://www.globalgear.com.au/productfeed.xml");
Please suggest any solution.
Don't use the Load method of the XmlDataDocument class directly; you have little to no way of influencing the behaviour when it comes to long running HTTP requests.
Instead, use the HttpWebRequest and HttpWebResponse classes to do the work for you, and then load the subsequent response into your document.
For example:
HttpWebRequest rq = WebRequest.Create("http://www.globalgear.com.au/productfeed.xml") as HttpWebRequest;
//60 Second Timeout
rq.Timeout = 60000;
//Also note you can set the Proxy property here if required; sometimes it is, especially if you are behind a firewall - rq.Proxy = new WebProxy("proxy_address");
HttpWebResponse response = rq.GetResponse() as HttpWebResponse;
XmlTextReader reader = new XmlTextReader(response.GetResponseStream());
XmlDocument doc = new XmlDocument();
doc.Load(reader);
I've tested this code in a local app instance and the XmlDocument is populated with the data from your URL.
You can also substitute in XmlDataDocument for XmlDocument in the example above - I prefer to use XmlDocument as it's not (yet) marked as obsolete.
I've wrapped this in a function for you:
public XmlDocument GetDataFromUrl(string url)
{
XmlDocument urlData = new XmlDocument();
HttpWebRequest rq = (HttpWebRequest)WebRequest.Create(url);
rq.Timeout = 60000;
HttpWebResponse response = rq.GetResponse() as HttpWebResponse;
using (Stream responseStream = response.GetResponseStream())
{
XmlTextReader reader = new XmlTextReader(responseStream);
urlData.Load(reader);
}
return urlData;
}
Simply call using:
XmlDocument document = GetDataFromUrl("http://www.globalgear.com.au/productfeed.xml");
To my knowledge there is no easy way to adjust the timeout with the method you are using.
The easiest change would be to use the webclient class and set the timeout property. This is described here http://w3ka.blogspot.co.uk/2009/12/how-to-fix-webclient-timeout-issue.html. Then use downloadfile on the webclient. Then load the saved file in the XMLDocument.
Set a timeout for your web request:
using System;
using System.Net;
using System.Xml;
namespace Shelver
{
class Program
{
static void Main(string[] args)
{
WebRequest requ = WebRequest.Create("http://www.globalgear.com.au/productfeed.xml");
requ.Timeout = 10 * 60 * 1000; // 10 minutes timeout and not 100s as the default.
var resp = requ.GetResponse();
Console.WriteLine("Will download {0:N0}bytes", resp.ContentLength);
var stream = resp.GetResponseStream();
XmlDocument doc = new XmlDocument();
doc.Load(stream);
}
}
}
This example will set it to 10 minutes.
In addition to the previous answers, which should be the first step towards fixing this, I continued to get this exception despite having already loaded the response and closing the connections.
The solution for me: the Load() and LoadXml() methods would throw their own Timeout exception if the value provided wasn't actually XML. Checking to verify that the response content was XML worked in our case (this will require that the host you are getting your response from actually sets content types).
Building upon dash's answer:
public XmlDocument GetDataFromUrl(string url)
{
XmlDocument urlData = new XmlDocument();
HttpWebRequest rq = (HttpWebRequest)WebRequest.Create(url);
rq.Timeout = 60000;
HttpWebResponse response = rq.GetResponse() as HttpWebResponse;
// New check added to dash's answer.
if (response.ContentType.Contains("text/xml")
{
using (Stream responseStream = response.GetResponseStream())
{
XmlTextReader reader = new XmlTextReader(responseStream);
urlData.Load(reader);
}
}
return urlData;
}
I have to sent the XML document as an parameter to request an WebRequest from the Service using the Post method.
Can anyone help be about how to sent the XML document as an parameter, or how to get the whole document in the string to pass as in as Document.
If you want to POST your Xml data using a named form parameter you need to do something like this:
HttpWebRequest request = HttpWebRequest.Create("http://yourdomain.com/whatever") as HttpWebRequest;
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
Encoding e = Encoding.GetEncoding("iso-8859-1");
XmlDocument doc = new XmlDocument();
doc.LoadXml("<foo><bar>baz</bar></foo>");
string rawXml = doc.OuterXml;
// you need to encode your Xml before you assign it to your parameter
// the POST parameter name is myxmldata
string requestText = string.Format("myxmldata={0}", HttpUtility.UrlEncode(rawXml, e));
Stream requestStream = request.GetRequestStream();
StreamWriter requestWriter = new StreamWriter(requestStream, e);
requestWriter.Write(requestText);
requestWriter.Close();
Read this article Which is explained about the XML document and web service
Passing XML document as an parameter to Web services
[WebMethod]
public System.Xml.XmlDocument SampelXmlMethod( System.Xml.XmlDocument xmldoc)
string xmldata = "<xform>" +
"<instance>" +
"<FirstName>Andrew</FirstName>" +
"<LastName>Fuller</LastName>" +
"<BirthDate>2/19/1952</BirthDate>" +
"</instance>" +
"</xform>";
//Load xmldata into XmlDocument Object
System.Xml.XmlDocument SendingXmlDoc = new System.Xml.XmlDocument();
SendingXmlDoc.LoadXml(xmldata);
//Call web service and get xmldocument back
System.Xml.XmlDocument ReceivingXmlDoc = new System.Xml.XmlDocument();
XmlService ser = new XmlService(); //Your web srevice..
ReceivingXmlDoc = ser.SampelXmlMethod(SendingXmlDoc);
I want to generate html content based on a result returned by http url.
http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=X1-ZWz1c239bjatxn_5taq0&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA
This page will give you some XML results. I want to convert to use that XML to generate HTML. I am not getting any idea where to start? Would someone offer any guidelines or sample code for asp.net?
For details: http://www.zillow.com/howto/api/GetDeepSearchResults.htm
To fetch the data you can use the HttpWebRequest class, this is an example I have to hand but it may be slightly overdone for your needs (and you need to make sure you're doing the right thing - I suspect the above to be a GET rather than a POST).
Uri baseUri = new Uri(this.RemoteServer);
HttpWebRequest rq = (HttpWebRequest)HttpWebRequest.Create(new Uri(baseUri, action));
rq.Method = "POST";
rq.ContentType = "application/x-www-form-urlencoded";
rq.Accept = "text/xml";
rq.AutomaticDecompression = DecompressionMethods.GZip | DecompressionMethods.Deflate;
Encoding encoding = Encoding.GetEncoding("UTF-8");
byte[] chars = encoding.GetBytes(body);
rq.ContentLength = chars.Length;
using (Stream stream = rq.GetRequestStream())
{
stream.Write(chars, 0, chars.Length);
stream.Close();
}
XDocument doc;
WebResponse rs = rq.GetResponse();
using (Stream stream = rs.GetResponseStream())
{
using (XmlTextReader tr = new XmlTextReader(stream))
{
doc = XDocument.Load(tr);
responseXml = doc.Root;
}
if (responseXml == null)
{
throw new Exception("No response");
}
}
return responseXml;
Once you've got the data back you need to render HTML, lots and lots of choices - if you just want to convert what you've got into HTML with minimal further processing then you can use XSLT - which is a question all on its own. If you need to do stuff with it then the question is too vague and you'll need to be more specific.
Create a xsl stylesheet, and inject the stylesheet element into the resulting xml from teh page