I have some int values such as hour and minute. I would like to use these values to create a DateTime format so I can check whether the current time of the computer is after a predefined time.
Any help on this would be highly appreciated as I have looked and found nothing so far.
Have you tried one of the DateTime constructors:
public DateTime(
int year,
int month,
int day,
int hour,
int minute,
int second
)
So you can do something like:
var h = 12;
var m = 34;
var s = 10;
var example = new DateTime(2016,6,22,h,m,s);
Just for completeness' sake, you can add the time part to DateTime.Today :
DateTime.Today.Add(new TimeSpan(hours,minutes,seconds));
This makes the intention of the code clearer:
var target=DateTime.Today.Add(new TimeSpan(hours,minutes,seconds));
if (target>DateTime.Now) ...
create a date time object , with only hours, minute, second field using your custom values
var myDate= new DateTime (DateTime.Today.Year, DateTime.Today.Month, DateTime.Today.Day, hours, minute, second);
DateTime dt = DateTime.ParseExact(timeAsInt, "HHmm", CultureInfo.InvariantCulture);
Related
Im new to C# and I am making a program that saves different times. And I wonder how can I write out a single Date with three textBox strings (by typing in the value for day, month and year seperately) and how can I do the same for Time (write the hours and minutes).
int a = int.Parse(textBox_DDVzleta.Text);
int b = int.Parse(textBox_MMVzleta.Text);
int c = int.Parse(textbox_YYVzleta.Text);
DateTime Vzlet = new DateTime(a, b, c);
I tried converting it into a integer but it just doesnt work.
I think you passes your parameters with wrong position.
You use DateTime(year, month, day) constructor but you pass them as DateTime(day, month, year) to this constructor.
Just change your parameter positions like;
DateTime Vzlet = new DateTime(c, b, a);
how can I do the same for Time (write the hours and minutes).
If you mean TimeSpan with Time, you can use it's TimeSpan(hour, minute, second) constructor as well.
TimeSpan ts = new TimeSpan(hour, minute, 0);
There is a so called DateTime Constructor (MSDN Reference). You can initialize this with the given year, month and day integer and it creates for you the datetime object.
DateTime date1 = new DateTime(2010, 8, 18);
In this case you could do
DateTime date1 = new DateTime(int.Parse(textBox_DDVzleta.Text), int.Parse(textBox_MMVzleta.Text), int.Parse(textbox_YYVzleta.Text));
See Screenshot below for the result.
Update
I have also tried your way with converting to int first.
int a = int.Parse("30");
int b = int.Parse("01");
int c = int.Parse("2016");
DateTime date2 = new DateTime(c, b, a); // new DateTime(year, month, day)
Console.WriteLine(date2.ToString());
the result:
You can do this by using string type variable and concatenation.
example:
string x = a.tostring()+b.tostring()+c.tostring();
for spaces between values You can write it as following.
string x = a.tostring() + " " + b.tostring() + " " + c.tostring();
I have problem in finding the date using day of the week.
For example : i have past date lets say,
Date date= Convert.TodateTime("01/08/2013");
08th Jan 2013 th Day of the week is Tuesday.
Now i want current week's tuesday's date. How i can do it.
Note : The past date is dynamic. It will change in every loop.
You can use the enumeration DayOfWeek
The DayOfWeek enumeration represents the day of the week in calendars
that have seven days per week. The value of the constants in this
enumeration ranges from DayOfWeek.Sunday to DayOfWeek.Saturday. If
cast to an integer, its value ranges from zero (which indicates
DayOfWeek.Sunday) to six (which indicates DayOfWeek.Saturday).
We can use the conversion to integer to calculate the difference from the current date of the same week day
DateTime dtOld = new DateTime(2013,1,8);
int num = (int)dtOld.DayOfWeek;
int num2 = (int)DateTime.Today.DayOfWeek;
DateTime result = DateTime.Today.AddDays(num - num2);
This also seems appropriate to create an extension method
public static class DateTimeExtensions
{
public static DateTime EquivalentWeekDay(this DateTime dtOld)
{
int num = (int)dtOld.DayOfWeek;
int num2 = (int)DateTime.Today.DayOfWeek;
return DateTime.Today.AddDays(num - num2);
}
}
and now you could call it with
DateTime weekDay = Convert.ToDateTime("01/08/2013").EquivalentWeekDay();
I may be a bit late to the party, but my solution is very similar:
DateTime.Today.AddDays(-(int)(DateTime.Today.DayOfWeek - DayOfWeek.Tuesday));
This will get the Tuesday of the current week, where finding Tuesday is the primary goal (I may have misunderstood the question).
You can use this....
public static void Main()
{
//current date
DateTime dt = DateTime.UtcNow.AddHours(6);
//you can use it custom date
var cmYear = new DateTime(dt.Year, dt.Month, dt.Day);
//here 2 is the day value of the week in a date
var customDateWeek = cmYear.AddDays(-2);
Console.WriteLine(dt);
Console.WriteLine(cmYear);
Console.WriteLine("Date: " + customDateWeek);
Console.WriteLine();
Console.ReadKey();
}
I have been getting an annoying issues. I have two datetime variables. Date of employment and termination date. I need to get the number of days work. termindation date - date of employment.
how do i go about getting this?
DateTime empDate = int.Parse((employeeEmploy.ElementAt(i).dateofEmpl).GetValueOrDefault().ToString("yyyyMMdd"));
DateTime terminDate = int.Parse((employeeEmploy.ElementAt(i).terminDate ).GetValueOrDefault().ToString("yyyyMMdd"));
int? dWorked = terminDate - empDate;
I tried that but that didnt work
Well, you're trying to deal with DateTime values - so you shouldn't be using int.Parse to start with. Use DateTime.ParseExact. Once you've got two DateTime values, you can use subtraction to get a TimeSpan, and then compute the total days from that:
DateTime employmentDate = ...;
DateTime terminationDate = ...;
TimeSpan employmentDuration = terminationDate - employmentDate;
int days = (int) employmentDuration.TotalDays;
Personally I'd actually use my Noda Time project to do all of this, mind you:
private static LocalDatePattern TextPattern =
LocalDatePattern.CreateWithInvariantInfo("yyyyMMdd");
...
LocalDate employmentDate = TextPattern.Parse(...).Value;
LocalDate terminationDate = TextPattern.Parse(...).Value;
int days = Period.Between(employmentDate, terminationDate, PeriodUnits.Days)
.Days;
Subtracting DateTime objects produces TimeSpan. So, use TimeSpan.TotalDays to get total days count between two dates:
int dWorked = (terminDate - empDate).TotalDays;
UPDATE: For LINQ to Enitites use EntityFunctions.DiffDays method, which calculates days between two nullable dates:
from x in context.Foo
select EntityFunctions.DiffDays(x.FromDate, x.ToDate)
try something along the lines of
var numDays = (terminDate - empDate ).TotalDays;
dworked = (int)Math.Round(numDays, MidpointRounding.AwayFromZero);
You can easily substract the two Datetimes which gets you a TimeSpan!
DateTime employmentDate = new DateTime(2013,03,8);
DateTime terminationDate = new DateTime(2013,03,11);
TimeSpan days = terminationDate - employmentDate;
Console.WriteLine("Days: " + days.TotalDays); //Result: "Days: 3"
I was just wondering if there is a way to get the current time and set it into a value.
If its 12:06 AM.. I want to get that time and set it into currentTime.
Example
float currentTime = 0;
currentTime = 12.06;
As others have mentioned, the DateTime class would be ideal for this, and to work out the difference between 2 date/times:
DateTime end = DateTime.Now;
DateTime start = new DateTime(2011, 12, 5, 12, 6,0);
double hours = (end - start).TotalHours;
The subtraction of DateTime objects results in a TimeSpan object that you can use to see the hours/minutes etc.
try DateTime class
DateTime dt = DateTime.Now;
Is this what you're looking for?
DateTime currentTime;
currentTime = DateTime.Now;
Don't use floats or strings. You can do all kinds of cool things using DateTime.
Here's how you'd get the hours that someone worked:
var clockIn = new DateTime(2011,12,4,9,0,0); // December 4th, 9 AM
var clockOut = new DateTime(2011,12,4,17,0,0); // December 4th, 5 PM
var duration = clockOut - clockIn; // TimeSpan
Console.Write(duration.TotalHours); // 8
A few people have mentioned how, but as a 'better' recommendation you should use
DateTime currentTime = DateTime.UtcNow
Otherwise you have issues when the clocks go back, if your timing code is run on those days. (plus it is far easier to alter the UTC time to local time than it is to convert a '1am' to UTC (as there will be two of them when the clocks go back)
Well if you really what it as a float then try:
var currentDate = DateTime.Now;
float currentTime = float.Parse((currentDate.Hour > 12 ? currentDate.Hour -12 :
currentDate.Hour) + "." + currentDate.Minute);
I wouldn't recommend comparing dates or time with floats. A better options would be to use timespans.
You should be using a Timespan instance for time related values, you can use the flexibility to get the required values like
TimeSpan ts = DateTime.Now.TimeOfDay;
ts.ToString("hh:mm") // this could be what you are looking for
You could then use ts.TotalHours which would give you fractional hours (as a double) else you could construct a string specifically using ts.Hours ..ts.Minutes play around and it could be prove useful.
Try the following:
DateTime StartTime=StartTime value;
DateTime CurrentTime=DateTime.Now;
TimeSpan dt = CurrentTime.Subtract(StartTime);
In dt you will get a working time period.
If you want to have the difference between two times, then do this:
DateTime dateOne = DateTime.Parse(enteredTime);
DateTime dateTwo = DateTime.Now;
TimeSpan difference = dateOne - dateTwo;
I'm having some trouble here.
Did some research on Google but I can't seem to find what I'm looking for.
I'm trying to ask for two inputs (datetimes) in hh:mm format, subtract one for the other then return the result of that value in minutes.
The problem is that I want to return that value as an integer and I can't seem to find the right way to do it.
In C/C++ I wouldn't have this kind of issues...
Anyways, here's a snippet of what I'm talking about.
private int DuraçaoTreino(DateTime dtInicioTreino, DateTime dtFimTreino, int dtDuraçao)
{
Console.WriteLine("Introduza a hora de inicio (hh:mm): ");
dtInicioTreino = Convert.ToDateTime(Console.Read());
Console.WriteLine("Introduza a hora de fim (hh:mm): ");
dtFimTreino = Convert.ToDateTime(Console.Read());
dtDuraçao = (dtFimTreino - dtInicioTreino); // duração da sessão de treino
dtDuraçao = Convert.ToDecimal(Console.Read());
return dtDuraçao;
}
And that's pretty much it... I'm new to C# so if you see anything wrong please be kind.
Thanks in advance.
What you're talking about is a TimeSpan:
DateTime dtBegin = new DateTime(2011,5,1,22,0,0) ; // 10pm 1 May 2011
DateTime dtEnd = new DateTime(2011,5,1,23,0,0) ; // 11pm 1 May 2011
TimeSpan tmElapsed = dtEnd - dtBegin ; // tmElapsed is a TimeSpan with a value of 60 minutes
To return the minutes, do something like:
int elapsedTimeInMinutes = (int) Math.Round( tmElapsed.TotalMinutes , 0 ,MidpointRounding.ToEven ) ;
var timeInMinutes = new DateTime(2011, 12, 25).Subtract(new DateTime(2010, 1, 1)).TotalMinutes;
Instead of creating the DateTime objects using the constructor I used, you can use DateTime.Parse, or better still DateTime.ParseExact to convert the strings to date times. (I know I am only using date parts here but you choose only to use time parts if you wish)
Convert DateTime objects to TimeSpan's, substract and call TimeSpan.TotalMinutes (or smth like that - dont' have VS at hand):
DateTime dt1, dt2;
// Assign some dates, then:
TimeSpan ts = dt2 - dt1;
double minutes = ts.TotalMinutes;