Develop Reference

How to split Alphanumeric with Symbol in C#

I want to spilt Alphanumeric with two part Alpha and numeric with special character like -
string mystring = "1- Any Thing"
I want to store like:
numberPart = 1
alphaPart = Any Thing
For this i am using Regex
Regex re = new Regex(#"([a-zA-Z]+)(\d+)");
Match result = re.Match("1- Any Thing");
string alphaPart = result.Groups[1].Value;
string numberPart = result.Groups[2].Value;
If there is no space in between string its working fine but space and symbol both alphaPart and numberPart showing null where i am doing wrong Might be Regex expression is wrong for this type of filter please suggest me on same

Try this:
(\d+)(?:[^\w]+)?([a-zA-Z\s]+)
Demo
Explanation:
(\d+) - capture one or more digit
[^\w]+ match anything except alphabets
? this tell that anything between word and number can appear or not(when not space is between them)
[a-zA-Z\s]+ match alphabets(even if between them have spaces)

Start of string is matched with ^.
Digits are matched with \d+.
Any non-alphanumeric characters are matched with [\W_] or \W.
Anything is matched with .*.
Use
(?s)^(\d+)\W*(.*)
See proof
(?s) makes . match linebreaks. So, it literally matches everything.

Regex working in Regexr but not C#, why?

From the below mentioned input string, I want to extract the values specified in {} for s:ds field. I have attached my regex pattern. Now the pattern I used for testing on http://www.regexr.com/ is:
s:ds=\\\"({[\d\w]{8}\-([\d\w]{4}\-){3}[\d\w]{12}})\\\"
and it works absolutely fine.
But the same in C# code does not work. I have also added \\ instead of \ for c# code and replaced \" with \"" . Let me know if Im doing something wrong. Below is the code snippet.
string inputString is "s:ds=\"{46C01EB7-6D43-4E2A-9267-608DE8AFA311}\" s:ds=\"{37BA4BA0-581C-40DC-A542-FFD9E99BC345}\" s:id=\"{C091E71D-4817-49BC-B120-56CE88BC52C2}\"";
string regex = #"s:ds=\\\""({[\d\w]{8}\-(?:[\d\w]{4}\-){3}[\d\w]{12}})\\\""";
MatchCollection matchCollection = Regex.Matches(layoutField, regex);
if (matchCollection.Count > 1)
{
Log.Info("Collection Found.", this);
}

If you only watch to match the values...
You should be able to just use ([\d\w]{8}\-([\d\w]{4}\-){3}[\d\w]{12}) for your expression if you only want to match the withing your gullwing braces :
string input = "s:ds=\"{46C01EB7-6D43-4E2A-9267-608DE8AFA311} ...";
// Use the following expression to just match your GUID values
string regex = #"([\d\w]{8}\-([\d\w]{4}\-){3}[\d\w]{12})";
// Store your matches
MatchCollection matchCollection = Regex.Matches(input, regex);
// Iterate through each one
foreach(var match in matchCollection)
{
// Output the match
Console.WriteLine("Collection Found : {0}", match);
}
You can see a working example of this in action here and example output demonstrated below :
If you want to only match those following s:ds...
If you only want to capture the values for s:ds sections, you could consider appending (?<=(s:ds=""{)) to the front of your expression, which would be a look-behind that would only match values that were preceded by "s:ds={" :
string regex = #"(?<=(s:ds=""{))([\d\w]{8}\-([\d\w]{4}\-){3}[\d\w]{12})";
You can see an example of this approach here and demonstrated below (notice it doesn't match the s:id element :
Another Consideration
Currently you are using \w to match "word" characters within your expression and while this might work for your uses, it will match all digits \d, letters a-zA-z and underscores _. It's unlikely that you would need some of these, so you may want to consider revising your character sets to use just what you would expect like [A-Z\d] to only match uppercase letters and numbers or [0-9A-Fa-f] if you are only expected GUID values (e.g. hex).

Looks like you might be over-escaping.
Give this a shot:
#"s:ds=\""({[\d\w]{8}\-([\d\w]{4}\-){3}[\d\w]{12}})\"""

Regex to match a word beginning with a period and ending with an underscore?

I'm quite the Regex novice, but I have a series of strings similar to this "[$myVar.myVar_STATE]" I need to replace the 2nd myVar that begins with a period and ends with an underscore. I need it to match it exactly, as sometimes I'll have "[$myVar.myVar_moreMyVar_STATE]" and in that case I wouldn't want to replace anything.
I've tried things like "\b.myVar_\b", "\.\bmyVar_\b" and several more, all to no luck.

How about this:
\[\$myVar\.([^_]+)_STATE\]
Matches:
[$myVar.myVar_STATE] // matches and captures 'myvar'
[$myVar.myVar_moreMyVar_STATE] // no match
Working regex example:
http://regex101.com/r/yM9jQ3
Or if _STATE was variable, you could use this: (as long as the text in the STATE part does not have underscores in it.)
\[\$myVar\.([^_]+)_[^_]+\]
Working regex example:
http://regex101.com/r/kW8oE1
Edit: Conforming to OP's comments below, This should be what he's going for:
(\[\$myVar\.)([^_]+)(_[^_]+\])
Regex replace example:
http://regex101.com/r/pU6yL8
C#
var pattern = #"(\[\$myVar\.)([^_]+)(_[^_]+\])";
var replaced = Regex.Replace(input, pattern, "$1"+ newVar + "$3")

What about something like:
.*.(myVar_).*
This looks for anything then a . and "myVar_" followed by anything.
It matches:
"[$myVar.myVar_STATE]"
And only the first myVar_ here:
"[$myVar.myVar_moremyVar_STATE]"
See it in action.

This should do it:
\[\$myVar\.(.*?)_STATE\]
You can use this little trick to pick out the groups, and build the replacement at the end, like so:
var replacement = "something";
var input = #"[$myVar.myVar_STATE]";
var pattern = #"(\[\$myVar\.)(.*?)_(.*?)]";
var replaced = Regex.Replace(input, pattern, "$1"+ replacement + "_$2]")

C# already has builtin method to do this
string text = ".asda_";
Response.Write((text.StartsWith(".") && text.EndsWith("_")));

Is Regex really required?
string input = "[$myVar.myVar_STATE]";
string oldVar = "myVar";
string newVar = "myNewVar";
string result = input.Replace("." + oldVar + "_STATE]", "." + newVar + "_STATE]");
In case "STATE" is a variable part, then we'll need to use Regex. The easiest way is to use this Regex pattern which matches a position between a prefix and a suffix. Prefix and suffix are used for searching but are not included in the resulting match:
(?<=prefix)find(?=suffix)
result =
Regex.Replace(input, #"(?<=\.)" + Regex.Escape(oldVar) + "(?=_[A-Z]+])", newVar);
Explanation:
The prefix part is \., which stand for ".".
The find part is the escaped old variable to be replaced. Regex escaping makes sure that characters with a special meaning in Regex are escaped.
The suffix part is _[A-Z]+], an underscore followed by at least one letter followed by "]". Note: the second ] needs not to be escaped. An opening bracket [ would have to be escaped like this: \[. We cannot use \w for word characters for the STATE-part as \w includes underscores. You might have to adapt the [A-Z] part to exactly match all possible states (e.g. if state has digits, use [A-Z0-9].

Regular expression and removing signs

I'm new in regular expressions. I've got a little problem and i can't find the answer. I'm looking for redundant brackets using this regular espression:
public Regex RedundantBrackets = new Regex("[(](\\s?)[a-z](\\s?)[)]");
When i find something i want to modife string in this way:
text1 (text2) text3 => text1 text2 text3 - so as you can se i want only to remove brackets. How can i do this? I was trying to use Replace method, but using it i can only replace every sign of "(text2)".
Thanks in advance!

Try this replace
Regex.Replace("text1 (text2) text3", // Input
#"([()])", // Pattern to match
string.Empty) // Item to replace
/* result: text1 text2 text3*/
Explanation
Regex replace looks across the whole string for a match. If it finds a match it will replace that item. So our match pattern looks like this ([()]). Which means this
( is what is required within the pattern to start the match and needs a closing ) otherwise the match pattern is not balanced.
[] in the pattern says, I am searching for a character, and [ and ] define a set. They are considered set matches. The most common one is [A-Z] which is any set of characters, starting with A and ending in Z. We will define our own set. *Remember [ and ] mean to regex we are looking for 1 character but we specify a set of many characters within that.
( and ) within our set [()] which also could be specified as [)(] as well means we have a set of two characters. Those two characters are the opening and closing parenthesis ().
So taken all together we are looking to match (1) any character in the set (2) that is either a ( or a ). When that match is found, replace the ( or ) with string.empty.
When we run the regex replace on your text it finds two matches the (text2 and finally the match text2). Those are replaced with string.empty.

First off, it can be handy to use verbatim strings so you don't have to escape the slashes etc.
public Regex RedundantBrackets = new Regex(#"[(]\s?([a-z]+)\s?[)]");
We want to wrap [a-z] in parenthesis because that's what we're trying to capture. We can then use $1 to place that capture into the replacement
RedundantBrackets.Replace("text (text) text", "$1");
EDIT: I forgot to add repetition to [a-z] => [a-z]+

this will remove all charaters using regex
finalString = Regex.Replace(finalString, #"[^\w ]", "");

Replace with wildcards

I need some advice. Suppose I have the following string: Read Variable
I want to find all pieces of text like this in a string and make all of them like the following:Variable = MessageBox.Show. So as aditional examples:
"Read Dog" --> "Dog = MessageBox.Show"
"Read Cat" --> "Cat = MessageBox.Show"
Can you help me? I need a fast advice using RegEx in C#. I think it is a job involving wildcards, but I do not know how to use them very well... Also, I need this for a school project tomorrow... Thanks!
Edit: This is what I have done so far and it does not work: Regex.Replace(String, "Read ", " = Messagebox.Show").

You can do this
string ns= Regex.Replace(yourString,"Read\s+(.*?)(?:\s|$)","$1 = MessageBox.Show");
\s+ matches 1 to many space characters
(.*?)(?:\s|$) matches 0 to many characters till the first space (i.e \s) or till the end of the string is reached(i.e $)
$1 represents the first captured group i.e (.*?)

You might want to clarify your question... but here goes:
If you want to match the next word after "Read " in regex, use Read (\w*) where \w is the word character class and * is the greedy match operator.
If you want to match everything after "Read " in regex, use Read (.*)$ where . will match all characters and $ means end of line.
With either regex, you can use a replace of $1 = MessageBox.Show as $1 will reference the first matched group (which was denoted by the parenthesis).
Complete code:
replacedString = Regex.Replace(inStr, #"Read (.*)$", "$1 = MessageBox.Show");

The problem with your attempt is, that it cannot know that the replacement string should be inserted after your variable. Let's assume that valid variable names contain letters, digits and underscores (which can be conveniently matched with \w). That means, any other character ends the variable name. Then you could match the variable name, capture it (using parentheses) and put it in the replacement string with $1:
output = Regex.Replace(input, #"Read\s+(\w+)", "$1 = MessageBox.Show");
Note that \s+ matches one or more arbitrary whitespace characters. \w+ matches one or more letters, digits and underscores. If you want to restrict variable names to letters only, this is the place to change it:
output = Regex.Replace(input, #"Read\s+([a-zA-Z]+)", "$1 = MessageBox.Show");
Here is a good tutorial.
Finally note, that in C# it is advisable to write regular expressions as verbatim strings (#"..."). Otherwise, you will have to double escape everything, so that the backslashes get through to the regex engine, and that really lessens the readability of the regex.