I want to add icon inside a button. Here is my code
private void Printbutton_Click(object sender, EventArgs e)
{
// Assign an image to the button.
Printbutton.Image = Image.FromFile("D:\\Downloads\\print.png");
// Align the image and text on the button.
Printbutton.ImageAlign = ContentAlignment.MiddleRight;
Printbutton.TextAlign = ContentAlignment.MiddleLeft;
// Give the button a flat appearance.
Printbutton.FlatStyle = FlatStyle.Flat;
if (SetupThePrinting())
printDocument1.Print();
}
The problem here is that the icon doesn't appear at first , it appears when I click to the button.
What's wrong here ?
you added the icon in printbutton_click event instead defining it in Form initializecomponents
public Form2()
{
InitializeComponent();
// Assign an image to the button.
Printbutton.Image = Image.FromFile("D:\\Downloads\\print.png");
// Align the image and text on the button.
Printbutton.ImageAlign = ContentAlignment.MiddleRight;
Printbutton.TextAlign = ContentAlignment.MiddleLeft;
// Give the button a flat appearance.
Printbutton.FlatStyle = FlatStyle.Flat;
}
private void Printbutton_Click(object sender, EventArgs e)
{
if (SetupThePrinting())
printDocument1.Print();
}
Like this
public Form1()
{
InitializeComponent();
// Assign an image to the button.
button1.Image = Image.FromFile("C:\\Yourfolder");
// Align the image and text on the button.
button1.ImageAlign = ContentAlignment.MiddleRight;
button1.TextAlign = ContentAlignment.MiddleLeft;
// Give the button a flat appearance.
button1.FlatStyle = FlatStyle.Flat;
}
private void button1_Click(object sender, EventArgs e)
{
// Your print code.
}
Related
I want to build a Windows Forms App that has a menu (several labels) on it's left side which is toggled. On the right side there should be some columns i can scroll through. Jst like Excel with it's fixed rownumbers.
Is there a way to do this? Preferably an easy one.
I think you can use two panels to make the form like the picture you provided.
The following code is a code example and you can refer to it.
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
ScrollBar hScrollBar1 = new HScrollBar();
private void Form1_Load(object sender, EventArgs e)
{
panel1.BorderStyle = BorderStyle.FixedSingle;
panel1.Dock = DockStyle.Left;
panel2.BorderStyle = BorderStyle.FixedSingle;
panel2.Dock = DockStyle.Fill;
hScrollBar1.Dock = DockStyle.Bottom;
hScrollBar1.Scroll += new ScrollEventHandler(hScroller_Scroll);
panel2.Controls.Add(hScrollBar1);
panel2.HorizontalScroll.Visible = false;
panel2.HorizontalScroll.Enabled = true;
}
private void hScroller_Scroll(object sender, ScrollEventArgs e)
{
panel2.HorizontalScroll.Value = e.NewValue;
}
}
The specific result:
I'm using WinForms. In my form i have 2 panels which i want to dock up or down on button click.
The issue i'm running into is that my panels is not docking correctly.
When i click on the up button, panel one label gets covered by panel2.
Panel 1: (Anchor: Top, Left, Right)
Panel 2: (Anchor: Top, Bottom, Left, Right)
private void Up_Btn_Click(object sender, EventArgs e)
{
panel1.Dock = System.Windows.Forms.DockStyle.Fill;
panel2.Dock = System.Windows.Forms.DockStyle.Top;
}
private void Down_Btn_Click(object sender, EventArgs e)
{
panel1.Dock = System.Windows.Forms.DockStyle.Fill;
panel2.Dock = System.Windows.Forms.DockStyle.Bottom;
}
Incorrect the label should not be covered by the panels
What supposed to happen when Up button is clicked
What supposed to happen when Down button is clicked
public Form1()
{
InitializeComponent();
panel1.BringToFront();
}
private void Up_Click(object sender, EventArgs e)
{
panel1.Dock = DockStyle.Fill;
panel2.Dock = DockStyle.Top;
}
private void Down_Click(object sender, EventArgs e)
{
panel1.Dock = DockStyle.Fill;
panel2.Dock = DockStyle.Bottom;
}
The trick is to correct the order of the controls.
See here: Docking multiple controls - one fills remaining space
I've got a smaller image in my form. When the user hovers over the image it brings up a larger view of the image (that follows the mouse, but stays a certain distance from the mouse). In order to do this I am generating a Form with no FormBorderStyles when the cursor hovers the image.
The problem I'm running into is that the first form doesn't seem to detect any longer that the mouse is hovering or leaving the PictureBox once the form activates. The Form also doesn't follow the cursor.
Here is the slimmed down version of what I've got:
C#
bool formOpen = false;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
pictureBox1.MouseHover += pictureBox1_MouseHover;
pictureBox1.MouseLeave +=pictureBox1_MouseLeave;
}
void pictureBox1_MouseHover(object sender, EventArgs e)
{
if (formOpen == false)
{
Form form = new Form();
form.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
form.BackColor = Color.Orchid;
//Show the form
form.Show();
form.Name = "imageForm";
this.AddOwnedForm(form);
//Set event handler for when the mouse leaves the image area.
//form.MouseLeave += form_MouseLeave;
//Set the location of the form and size
form.BackColor = Color.Black;
form.Dock = DockStyle.Fill;
form.Size = new Size(30, 30);
form.BackgroundImageLayout = ImageLayout.Center;
this.TopMost = true;
formOpen = true;
form.Location = new Point(Cursor.Position.X, Cursor.Position.Y);
}
}
private void pictureBox1_MouseLeave(object sender, EventArgs e)
{
//MessageBox.Show("Worked");
}
}
The MouseLeave (and other events) was not recognized because the opening of the popup window and especially making it topmost=true took away the focus from the original form and its PictureBox.
It also didn't move because not code for moving was provided..
Here are a few changes that will make the form move:
You need a reference to it at the form1 level
you need to move it in the MouseMove event
Note that Hover is a once-only type of event. It fires only once until you leave the control.. (Note: Setsu has switched from Hover to Enter. This works fine, but lacks the short delay before showing the 2nd Form. If you want that back you can either switch back to Hover or you can fake the hover delay by a Timer, which is what I often do.)
// class level variable
Form form;
private void Form1_Load(object sender, EventArgs e)
{
pictureBox1.MouseEnter += pictureBox1_MouseEnter;
pictureBox1.MouseLeave +=pictureBox1_MouseLeave;
pictureBox1.MouseMove += pictureBox1_MouseMove; // here we move the form..
}
// .. with a little offset. The exact numbers depend on the cursor shape
void pictureBox1_MouseMove(object sender, MouseEventArgs e)
{
if ((form != null) && form.Visible)
{
form.Location = new Point(Cursor.Position.X + 5, Cursor.Position.Y + 5);
}
}
void pictureBox1_MouseEnter(object sender, EventArgs e)
{
// we create it only once. Could also be done at startup!
if (form == null)
{
form = new Form();
form.FormBorderStyle = System.Windows.Forms.FormBorderStyle.None;
//form.BackColor = Color.Orchid;
form.Name = "imageForm";
this.AddOwnedForm(form);
form.BackColor = Color.Black;
form.Dock = DockStyle.Fill;
form.Size = new Size(30, 30);
form.BackgroundImageLayout = ImageLayout.Center;
//this.TopMost = true; // wrong! this will steal the focus!!
form.ShowInTaskbar = false;
}
// later we only show and update it..
form.Show();
form.Location = new Point(Cursor.Position.X + 5, Cursor.Position.Y + 5);
// we want the Focus to be on the main form!
Focus();
}
private void pictureBox1_MouseLeave(object sender, EventArgs e)
{
if (form!= null) form.Hide();
}
MouseHover = Occurs when the mouse pointer rests on the control. (msdn)
Try MouseMove instead.
I have a pictureBox with an image inside.
I want, when i click on a button the image should hide and click again to show the image.
In the pictureBox, using paint event i am drawing some lines.
So if im doing pictureBox1.Refresh(); it will draw the lines. I want that if i click on a button the image will not display on/off.
pictureBox1 = null; or pictureBox1.Image.Dispose(); doesn't work it's showing me big red x with white background.
To hide it:
pictureBox.Visible = false;
To hide/show it in a click event:
void SomeButton_Click(Object sender, EventArgs e)
{
pictureBox.Visible = !pictureBox.Visible;
}
For toggling the image in your PictureBox you can create a 1 pixel bitmap and assign it to the picture box when you want hide your image, then assign your image back again. I am a little unclear of what the second part of your question is asking, any drawing in the picturebox's Paint Event will remain unless you exclude it in the Paint Event based on some Condition. If you want to draw a line in the box an toggle it on/off from a button see my second example.
i.e.
public partial class Form1 : Form
{
Bitmap nullBitmap = new Bitmap(1, 1); // create a 1 pixel bitmap
Bitmap myImage = new Bitmap("Load your Image Here"); // Load your image
bool showImage; // boolean variable so we know what image is assigned
public Form1()
{
InitializeComponent();
pictureBox1.Image = myImage;
showImage = true;
}
private void button1_Click(object sender, EventArgs e)
{
if (showImage)
{
pictureBox1.Image = nullBitmap;
showImage = false;
}
else
{
pictureBox1.Image = myImage;
showImage = true;
}
}
}
Second Example
public partial class Form1 : Form
{
bool showLines;
public Form1()
{
InitializeComponent();
showLines = true;
}
private void button1_Click(object sender, EventArgs e)
{
if (showLines)
{
showLines = false;
pictureBox1.Invalidate();
}
else
{
showLines = true;
pictureBox1.Invalidate();
}
}
private void pictureBox1_Paint(object sender, PaintEventArgs e)
{
if(showLines)
e.Graphics.DrawLine(Pens.Purple, 0, 0, 100, 100);
}
}
picturebox1.BackgroundImage = null
I want to make a custom button control (image button is ok) like this one.
I'm a new user, so I can't post image here. So I uploaded the picture here
I'm kind of desperate right now after trying some tutorials
Any suggestion is highly appreciated.
Thanks
Updated 08/10/2019: I asked this question so many years ago, and at that time I didn't have the permission to upload image, so the image I uploaded to the third party site is long gone now. I got many requests about re-uploading the image, so here is what I remember from that project I did eight years ago, I just find some random images about window form that match my memory
This is when the button is in normal state
This is when the button is hovered or clicked, with the rounded border
You could create a class that inherits from Button to keep all your styling in one place. To do the hover and pressed states you can override the mouse enter / leave events of the button and change style.
Here is an example from one of our projects (I changed the colours but your get the idea). Where we change some colours you could switch the images.
public class MossieButton : Button
{
private static Font _normalFont = new Font("Arial", 10F, System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, ((byte)(0)));
private static Color _back = System.Drawing.Color.Grey;
private static Color _border = System.Drawing.Color.Black;
private static Color _activeBorder = System.Drawing.Color.Red;
private static Color _fore = System.Drawing.Color.White;
private static Padding _margin = new System.Windows.Forms.Padding(5, 0, 5, 0);
private static Padding _padding = new System.Windows.Forms.Padding(3, 3, 3, 3);
private static Size _minSize = new System.Drawing.Size(100, 30);
private bool _active;
public MossieButton()
: base()
{
base.Font = _normalFont;
base.BackColor = _border;
base.ForeColor = _fore;
base.FlatAppearance.BorderColor = _back;
base.FlatStyle = System.Windows.Forms.FlatStyle.Flat;
base.Margin = _margin;
base.Padding = _padding;
base.MinimumSize = _minSize;
}
protected override void OnControlAdded(ControlEventArgs e)
{
base.OnControlAdded(e);
UseVisualStyleBackColor = false;
}
protected override void OnMouseEnter(System.EventArgs e)
{
base.OnMouseEnter(e);
if (!_active)
base.FlatAppearance.BorderColor = _activeBorder;
}
protected override void OnMouseLeave(System.EventArgs e)
{
base.OnMouseLeave(e);
if (!_active)
base.FlatAppearance.BorderColor = _border;
}
public void SetStateActive()
{
_active = true;
base.FlatAppearance.BorderColor = _activeBorder;
}
public void SetStateNormal()
{
_active = false;
base.FlatAppearance.BorderColor = _border;
}
}
Can't see the picture but I guess you can change the border of the button and set a background image.
button1.FlatStyle = FlatStyle.Flat;
button1.BackgroundImage = Bitmap.FromFile("image.jpg");
I think the simplest way is set some properties of the button like below and
this.button1.FlatStyle = System.Windows.Forms.FlatStyle.Flat;
this.button1.Image = "Any Image"
this.button1.ImageAlign = System.Drawing.ContentAlignment.MiddleLeft;
this.button1.TextImageRelation = System.Windows.Forms.TextImageRelation.ImageBeforeText;
then write the code for
private void button1_Click(object sender, EventArgs e)
{
//Code for Image Appearance.
button1.Text = "OnClick";
}
private void button1_MouseEnter(object sender, EventArgs e)
{
//Code for Image Appearance.
button1.Text = "Enter";
}
private void button1_MouseLeave(object sender, EventArgs e)
{
//Code for Image Appearance.
button1.Text = "Normal";
}
Update:
I don't know whether I am going correct or not but I think You can also achive your goal by putting a Button and a label inside a panel and arrange them according to your choice. Make the button1.FlatStyle = System.Windows.Forms.FlatStyle.Flat at initial with Label.Text="Normal". Then on Mouse enter to the Panel draw a rectangle with a border around the button and change the text of the label to "Hover". Like that Clicking on the Panel also you change the rectangle border according to you and make the label.Text="OnClick".