I have an exe file I'm calling with p.StartInfo. This exe takes some time till it finishes, so in the meanwhile I want a 'Wait' window to be on top, and not modal (so the GUI stays responsive).
So this is my code:
Task.Factory.StartNew(() =>
{
Process[] FileProcess = Process.GetProcessesByName("SomeFile.exe");
if (FileProcess.Length == 1)
wait_debug.ShowDialog();
});
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.FileName = "SomeFile.exe";
p.StartInfo.WorkingDirectory = work_directory;
p.EnableRaisingEvents = true;
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
p.Start();
The problem is the wait_debug window is not always shown, and this is strange, because in the task manager the SomeFile.exe IS running, but nevertheless, the wait window is not shown. It's hard to 'catch' the failures with the debugger, and so far I did not manage doing so. Some times it pops up, sometimes it doesn't. very annoying.
Any idea why, or what is a better solution?
btw, I'm using .Net 4 (I know some solutions only work with 4.5).
Thanks!
Related
I have a C# program that launches a child process and captures its output in a string. This works on most Windows machines (Windows 7 and newer), but when Kaspersky anti-virus is present, Process.StandardOutput.ReadToEnd() returns null. There is no error code or exception. The child process is a trusted console application. The process takes 5 or 6 seconds to run.
The code for launching the child process is as follows:
ProcessStartInfo psi = new ProcessStartInfo();
psi.UseShellExecute = false;
psi.CreateNoWindow = true;
psi.RedirectStandardOutput = true;
psi.RedirectStandardError = true;
psi.WindowStyle = ProcessWindowStyle.Hidden;
psi.FileName = "icao.exe";
psi.Arguments = im_path + "image.jpg";
Process p = new Process();
p.StartInfo = psi;
p.Start();
string output = p.StandardOutput.ReadToEnd();
string error = p.StandardError.ReadToEnd();
MessageBox.Show(error);
p.WaitForExit();
int exitCode = p.ExitCode;
MessageBox.Show(exitCode+"");
Why does output end up being null when Kaspersky is present?
My guess is that Kaspersky's heuristics are seeing that your program wants to execute another exe. Because nothing is telling Kaspersky that this is ok, it flags your program as possible malware, because it wants to interface with other programs that are developed by other companies. If you are able to I would try white listing your program with Kaspersky and see if that solves your issue.
I have a winforms application where I run a process (code shown below) in a loop. Suppose I have 10 items, I get 10 command windows where the actions are run. So, I wanted to know if there is a way where I can run the process 10 times but have just one command window open where all my actions are run.
Process p = new Process();
try
{
var pInfo = new ProcessStartInfo(executable, args);
pInfo.UseShellExecute = false;
pInfo.RedirectStandardOutput = true;
pInfo.RedirectStandardError = true;
pInfo.WorkingDirectory = workingDir;
p.StartInfo = pInfo;
p.EnableRaisingEvents = true;
SubscribeEvents(p);
p.Start();
p.WaitForExit();
}
I guess if you are doing winforms, you actually already probably have a main window open.
You can use this to hide your other windows:
pInfo.CreateNoWindow = true;
I have built MeteroJS application that I want to start as NodeJS application from C# code.
Here is Windows Form application that is used as control panel for starting and stopping the NodeJS application
I can start NodeJS application manually with command line: (this works!)
set MONGO_URL=mongodb://someAdmin:password#localhost:27017/some_db
set ROOT_URL=http://someservice:8080
set PORT=8080
node bundle\main.js
I want to repeat all action above from command line, this time inside C# application.
This is code that executes on Start button click:
Environment.SetEnvironmentVariable("MONGO_URL", String.Format("mongodb://{0}:{1}#localhost:27017/{2}", usernameTxt.Text, passwordTxt.Text, databaseTxt.Text), EnvironmentVariableTarget.Machine);
Environment.SetEnvironmentVariable("ROOT_URL", String.Format("http://someservice:{0}", portTxt.Text), EnvironmentVariableTarget.Machine);
Environment.SetEnvironmentVariable("PORT", portTxt.Text, EnvironmentVariableTarget.Machine);
Process.Start("CMD.exe", #"/C node bundle\main.js");
I am not sure if this is even possible. This simply does not work and left no logs.
Could you please check what I am doing wrong and advise.
Use the following code to execute the node.js cmd
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.FileName = #"c:\node\node.exe";**//Path to node installed folder****
string argument = "\\ bundle\main.js";
p.StartInfo.Arguments = #argument;
p.Start();
This code may help you:
Process p = new Process();
p.StartInfo.WorkingDirectory= #"C:\Users\USERNAME\Documents\Visual Studio 2015\Projects\Proyecto 1.3\Proyecto 1.3\bin\Debug\server";
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/c node app.js";
p.Start();
I'm trying to launch a command in a console window / I'm using a gtk form/
So I've tried to launch it this way:
Process p = new Process ();
p.StartInfo.UseShellExecute = false;
p.StartInfo.FileName = "bash";
p.StartInfo.CreateNoWindow = false;
p.StartInfo.Arguments ="/tmp/test.sh";
p.Start ();
p.WaitForExit ();
but it won't show any thing.
for those who only use windows, it's something like:
p.StartInfo.FileName = "cmd";
p.StartInfo.Arguments =" c:\\test.bat";
I've tried to change UseShellExecute to true but the problem still exist..
Any Ideas??
Bash runs the script but if you want to see output, you need to run it in a terminal.
Process p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.FileName = "gnome-terminal"; // Replace with whichever terminal you want to use
p.StartInfo.CreateNoWindow = false;
p.StartInfo.Arguments ="-x bash /tmp/test.sh";
//p.StartInfo.Arguments ="-e \"bash -c /tmp/test.sh;bash\""; // Use this if you want the terminal window to stay open
p.Start();
p.WaitForExit();
I have a C# code that uses command prompt to call a python script. The script currently takes about 25 seconds to run. When run in command prompt, the python script has several outputs until finally outputting "done". My C# code runs the script, but never closes the command prompt if I use "WaitForExit". So my thought is I need some kind of logic to check to see if "done" has been outputted, but the internet has not been very helpful with methodology.
Here's what I have, it currently only outputs the first line, "Microsoft Windows [Version 6.1.7601]". Obviously, no good.
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.WorkingDirectory = #"C:\Optimization";
p.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardInput = true;
p.Start();
p.StandardInput.WriteLine(#"ipy spot_for_labview.py");
StreamReader mySR = p.StandardOutput;
string mystr = mySR.ReadLine();
Debug.WriteLine(mystr);
p.WaitForExit(25000); //25000 is a placeholder until better method found.
p.Close();
If there's anyway to close the process after it finishes, or to get all the cmd output I'm all ears.
Any help is appreciated.
did you try this event ? Process.OutputDataReceived Event
or Process.ErrorDataReceived Event
here is the code from MSDN
Process sortProcess;
sortProcess = new Process();
sortProcess.StartInfo.FileName = "Sort.exe";
sortProcess.OutputDataReceived += new DataReceivedEventHandler(SortOutputHandler);
...
....
...
private static void SortOutputHandler(object sendingProcess,
DataReceivedEventArgs outLine)
{
}