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How to retrieve attribute from XML file in C#

I'm complete rookie I need to retrieve the value of last id in XML file here is

You can also use XPath within the Xml DOM like this :
string title;
XmlDocument xml = new XmlDocument();
xml.Load("~/purchases.xml");
// Or any other method to load your xml data in the XmlDocument.
// For example if your xml data are in a string, use the LoadXml method.
XmlElement elt = xml.SelectSingleNode("//SubMenu[#id='1']") as XmlElement;
if(elt!=null)
{
name=elt.GetAttribute("title");
}
Reference

As Jon suggested, you can use Linq To XML here.
XElement books = XElement.Load(filePath);
var lastId = books.Descendants("book").Select(x=>Int32.Parse(x.Attribute("ID").Value)).Last();
This will give you the last ID in the current list.You can now create your new Node
books.Add(new XElement("book",new XAttribute("ID",(lastId+1).ToString()),
new XAttribute("title","New Title"),
new XAttribute("price","1234")));
books.Save(filePath);

XmlDocument doc = new XmlDocument();
doc.Load("Yourxmlfilepath.xml");
//Display all the book titles.
XmlNodeList xNodeList = doc.SelectNodes("/bookstore/book");
foreach (XmlNode xNode in xNodeList)
{
var employeeName = xNode.OuterXml;
XmlDocument docnew = new XmlDocument();
docnew.LoadXml(employeeName);
foreach (XmlElement report in docnew.SelectNodes("book"))
{
string ID = report.GetAttribute("ID");
string title = report.GetAttribute("title");
string quantity = report.GetAttribute("quantity");
string price = report.GetAttribute("price");
}
}

Reading SOAP xml answer

I have to read a SOAP answer from the file below
<?xml version="1.0"?>
<Envelopes>
<env:Envelope xmlns:env="http://www.w3.org/2003/05/soap-envelope">
<env:Body>
<env:Fault>
<env:Code>
<env:Value>env:Receiver</env:Value>
<env:Subcode>
<env:Value>-1</env:Value>
</env:Subcode>
</env:Code>
<env:Reason>
<env:Text xml:lang="en">CServiceData::SetPropertyValue failed; '</env:Text>
</env:Reason>
<env:Detail>
<Object>4</Object>
<ObjectIndex>1</ObjectIndex>
<Command>AddObject</Command>
<SessionID>B8FE2330-4252-4BB1-A3EE-053F4413A0C0</SessionID>
</env:Detail>
</env:Fault>
</env:Body>
</env:Envelope>
</Envelopes>
I only need the content of the Text tag CServiceData::SetPropertyValue failed;

You can use XPath:
public string GetErrorMessage(string xml)
{
using (StringReader sr = new StringReader(xml))
{
var doc = new XPathDocument(sr);
var nav = doc.CreateNavigator();
var xmlNs = new XmlNamespaceManager(nav.NameTable);
xmlNs.AddNamespace("env", #"http://www.w3.org/2003/05/soap-envelope");
var node = nav.SelectSingleNode("//env:Text", xmlNs);
return node.Value;
}
}
or you can use LINQ To XML:
public string GetErrorMessage(string xml)
{
var doc = XDocument.Parse(xml);
var node = doc.Descendants(XName.Get("Text", #"http://www.w3.org/2003/05/soap-envelope"))
.FirstOrDefault();
return node.Value;
}

Creating XMLDocument throguh code in asp.net

am trying to generate an XML document like this through code.
<TestRequest xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="http://localhost:2292/RMSchema.xsd">
<Version>3</Version>
<ApplicationHeader>
<AppLanguage />
<UserId>rmservice</UserId>
</ApplicationHeader>
<CustomerData>
<ExistingCustomerData>
<MTN>2084127182</MTN>
</ExistingCustomerData>
</CustomerData>
</TestRequest>
I tried some samples. But they create xmlns for the children, which i dont need. Any help is really appreciated.
I have tried the below code. But it is adding only xmlns to all children, which i dont need
XmlDocument xDocument = new XmlDocument();
xDocument.AppendChild(xDocument.CreateXmlDeclaration("1.0", "windows-1252", null));
XmlElement xRoot = xDocument.CreateElement("TestRequest", "XNamespace.Xmlns=http://www.w3.org/2001/XMLSchema-instance" + " xsi:noNamespaceSchemaLocation=" + "http://localhost:2292/RMSchema.xsd");
xDocument.AppendChild(xRoot);
xRoot.AppendChild(xDocument.CreateElement("Version")).InnerText = 1;
Thanks
Tutu
I have tried with
var xsi = "http://www.w3.org/2001/XMLSchema-instance";
XmlElement xRoot = xDocument.CreateElement("xsi","RMRequest",xsi);
xRoot.SetAttribute("noNamespaceSchemaLocation", xsi, "http://localhost:2292/RMSchema.xsd");
xDocument.AppendChild(xRoot);
Now the response is
<?xml version=\"1.0\" encoding=\"windows-1252\"?><xsi:TestRequest xsi:noNamespaceSchemaLocation=\"http://localhost:2292/RMSchema.xsd\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\">

Here is the awesome LINQ to XML. Enjoy!
XNamespace xsi = "http://www.w3.org/2001/XMLSchema-instance";
XDocument doc = new XDocument(new XDeclaration("1.0", "windows-1252", null),
new XElement("TestRequest",
new XAttribute(XNamespace.Xmlns + "xsi", "http://www.w3.org/2001/XMLSchema-instance"),
new XAttribute(xsi + "noNamespaceSchemaLocation", "http://localhost:2292/RMSchema.xsd"),
new XElement("Version",
new XText("3")
),
new XElement("ApplicationHeader",
new XElement("AppLanguage"),
new XElement("UserId",
new XText("rmservice")
)
),
new XElement("CustomerData",
new XElement("ExistingCustomerData",
new XElement("MTN",
new XText("2084127182")
)
)
)
)
);
doc.Save(filePath);
If you really want the old API, here it is:
var xDocument = new XmlDocument();
xDocument.AppendChild(xDocument.CreateXmlDeclaration("1.0", "windows-1252", null));
var xsi = "http://www.w3.org/2001/XMLSchema-instance";
var xRoot = xDocument.CreateElement("TestRequest");
var attr = xDocument.CreateAttribute("xsi", "noNamespaceSchemaLocation", xsi);
attr.Value = "http://localhost:2292/RMSchema.xsd";
xRoot.Attributes.Append(attr);
xRoot.AppendChild(xDocument.CreateElement("Version")).InnerText = "1";
// .. your other elemets ...
xDocument.AppendChild(xRoot);
xDocument.Save(filePath);
EDIT: From your comments, it looks like you want the xmlns:xsi and other attribute in that specific order. If so, you may have to trick the XmlDocument to add the xmlns:xsi attribute first.
var xDocument = new XmlDocument();
xDocument.AppendChild(xDocument.CreateXmlDeclaration("1.0", "windows-1252", null));
var xsi = "http://www.w3.org/2001/XMLSchema-instance";
var xRoot = xDocument.CreateElement("TestRequest");
// add namespace decl are attribute
var attr = xDocument.CreateAttribute("xmlns:xsi");
attr.Value = xsi;
xRoot.Attributes.Append(attr);
// no need to specify prefix, XmlDocument will figure it now
attr = xDocument.CreateAttribute("noNamespaceSchemaLocation", xsi);
attr.Value = "http://localhost:2292/RMSchema.xsd";
xRoot.Attributes.Append(attr);
xRoot.AppendChild(xDocument.CreateElement("Version")).InnerText = "1";
// .. your other elemets ...
xDocument.AppendChild(xRoot);
xDocument.Save(filePath);

Are you looking for something like this:-
XmlDocument xmldoc = new XmlDocument();
XmlNode root = xmldoc.AppendChild(xmldoc.CreateElement("Root"));
XmlNode child = root.AppendChild(xmldoc.CreateElement("Child"));
XmlAttribute childAtt =child.Attributes.Append(xmldoc.CreateAttribute("Attribute"));
childAtt.InnerText = "My innertext";
child.InnerText = "My node Innertext";
xmldoc.Save("ABC.xml");

How to update the XMLDocument using c#?

I want to update the xml document and i need to return the updated xml in string. I am trying like below. when i save the document it expects the file name. but i dont want to save this as file. i just want to get the updated xml in string.
string OldXml = #"<Root>
<Childs>
<first>this is first</first>
<second>this is second </second>
</Childs
</Root>";
XmlDocument NewXml = new XmlDocument();
NewXml.LoadXml(OldXml );
XmlNode root = NewXml.DocumentElement;
XmlNodeList allnodes = root.SelectNodes("*");
foreach (XmlNode eachnode in allnodes)
{
if (eachnode.Name == "first")
{
eachnode.InnerText = "1";
}
}
NewXml.Save();
string newxml = NewXml.OuterXml;

You don't need to call Save method because string is immutable, your problem is in root.SelectNodes("*"), it just get child nodes, not all level of nodes. You need to go one more level:
foreach (XmlNode eachnode in allnodes)
{
var firstNode = eachnode.ChildNodes.Cast<XmlNode>()
.SingleOrDefault(node => node.Name == "first");
if (firstNode != null)
{
firstNode.InnerText = "1";
}
}
string newxml = NewXml.OuterXml;
It would be strongly recommended using LINQ to XML, it's simpler:
var xDoc = XDocument.Parse(OldXml);
foreach (var element in xDoc.Descendants("first"))
element.SetValue(1);
string newXml = xDoc.ToString();

Your iteration never reaches a node called "first". Else it would work fine without saving the NewXml.
You could however use a XElement and iterate over all descendants.
string OldXml = #"<Root>
<Childs>
<first>this is first</first>
<second>this is second </second>
</Childs>
</Root>";
var NewXml = XElement.Parse(OldXml);
foreach (var node in NewXml.Descendants())
{
if (node.Name.LocalName == "first")
{
node.Value = "1";
}
}
var reader = NewXml.CreateReader();
reader.MoveToContent();
string newxml = reader.ReadInnerXml();

Deleting XML using a selected Xpath and a for loop

I currently have the following code:
XPathNodeIterator theNodes = theNav.Select(theXPath.ToString());
while (theNodes.MoveNext())
{
//some attempts i though were close
//theNodes.RemoveChild(theNodes.Current.OuterXml);
//theNodes.Current.DeleteSelf();
}
I have set xpath to what I want to return in xml and I want to delete everything that is looped. I have tried a few ways of deleting the information but it does't like my syntax. I found an example on Microsoft support: http://support.microsoft.com/kb/317666 but I would like to use this while instead of a for each.
Any comments or questions are appreciated.

Why not to use XDocument?
var xmlText = "<Elements><Element1 /><Element2 /></Elements>";
var document = XDocument.Parse(xmlText);
var element = document.XPathSelectElement("Elements/Element1");
element.Remove();
var result = document.ToString();
result will be <Elements><Element2 /></Elements>.
Or:
var document = XDocument.Load(fileName);
var element = document.XPathSelectElement("Elements/Element1");
element.Remove();
document.Savel(fileName);
[Edit] For .NET 2, you can use XmlDocument:
XmlDocument document = new XmlDocument();
document.Load(fileName);
XmlNode node = document.SelectSingleNode("Elements/Element1");
node.ParentNode.RemoveChild(node);
document.Save(fileName);
[EDIT]
If you need to remove all child elements and attributes:
XmlNode node = document.SelectSingleNode("Elements");
node.RemoveAll();
If you need to keep attributes, but delete elements:
XmlNode node = document.SelectSingleNode("Elements");
foreach (XmlNode childNode in node.ChildNodes)
node.RemoveChild(childNode);

string nodeXPath = "your x path";
XmlDocument document = new XmlDocument();
document.Load(/*your file path*/);
XmlNode node = document.SelectSingleNode(nodeXPath);
node.RemoveAll();
XmlNode parentnode = node.ParentNode;
parentnode.RemoveChild(node);
document.Save("File Path");

You can use XmlDocument:
string nodeXPath = "your x path";
XmlDocument document = new XmlDocument();
document.Load(/*your file path*/);//or document.LoadXml(...
XmlNode node = document.SelectSingleNode(nodeXPath);
if (node.HasChildNodes)
{
//note that you can use node.RemoveAll(); it will remove all child nodes, but it will also remove all node' attributes.
for (int childNodeIndex = 0; childNodeIndex < node.ChildNodes.Count; childNodeIndex++)
{
node.RemoveChild(node.ChildNodes[childNodeIndex]);
}
}
document.Save("your file path"));