Develop Reference

Change case in First node in XmlDocument

I have this XML:
<Feedback>
<Officer>Officer</Officer>
<Answers>My text</Answers>
<Date>20190917</Date>
</Feedback>
I want XML to look like this: (Lowercase first letter in main tag)
<feedback>
<Officer>Officer</Officer>
<Answers>My text</Answers>
<Date>20190917</Date>
</feedback>
How to do it using XMLDocument? I can't access this item

If using XmlDocument is not a hard requirement you can do it with linq fairly easily.
You can create a new XML document with the root node named how you want it then loop through the child nodes of the original and add them to your new XML object.
A simple example:
XDocument xDocument = XDocument.Parse("<Feedback><Officer>Officer</Officer><Answers>My text</Answers><Date>20190917</Date></Feedback>");
XDocument newDoc = new XDocument();
XElement rootElement = new XElement("feedback");
newDoc.Add(rootElement);
foreach (var node in xDocument.Root.Elements())
{
newDoc.Root.Add(node);
}
Console.WriteLine(newDoc);
Console.ReadLine();
However here is an example using XmlDocument if you really need to use that:
XmlDocument oldDoc = new XmlDocument();
XmlDocument newXmlDoc = new XmlDocument();
oldDoc.LoadXml("<Feedback><Officer>Officer</Officer><Answers>My text</Answers><Date>20190917</Date></Feedback>");
XmlElement newRoot = newXmlDoc.CreateElement("feedback");
newXmlDoc.AppendChild(newRoot);
XmlNode root = newXmlDoc.DocumentElement;
foreach (XmlNode node in oldDoc.FirstChild.ChildNodes)
{
XmlElement elem = newXmlDoc.CreateElement(node.Name);
elem.InnerText = node.InnerText;
//Add the node to the document.
root.AppendChild(elem);
}
XmlTextWriter writer = new XmlTextWriter(Console.Out);
writer.Formatting = Formatting.Indented;
newXmlDoc.WriteTo(writer);
writer.Flush();
Console.WriteLine();
Console.ReadLine();

In this case, you can change the name directly:
var XML = ""; // Your XML in string
var tempDoc = new XmlDocument();
tempDoc.LoadXml(XML);
tempDoc.InnerXml = tempDoc.InnerXml.Replace("Feedback>", "feedback>");
XML = tempDoc.OuterXml;
This is a simple way to change the name
Do not use in other situations because various errors may arise, e.g another element may end in the same name

how to get(read) data from xmldocument in windows phone, c#

I'm getting data from a web service in my phone application and get the response to xmldocument like below.
XmlDocument XmlDoc = new XmlDocument();
XmlDoc.LoadXml(newx2);
Ther result of XmlDoc is like below.now I want to get the values from this.
<root>
<itinerary>
<FareIndex>0</FareIndex>
<AdultBaseFare>4719</AdultBaseFare>
<AdultTax>566.1</AdultTax>
<ChildBaseFare>0</ChildBaseFare>
<ChildTax>0</ChildTax>
<InfantBaseFare>0</InfantBaseFare>
<InfantTax>0</InfantTax>
<Adult>1</Adult>
<Child>0</Child>
<Infant>0</Infant>
<TotalFare>5285.1</TotalFare>
<Airline>AI</Airline>
<AirlineName>Air India</AirlineName>
<FliCount>4</FliCount>
<Seats>9</Seats>
<MajorCabin>Y</MajorCabin>
<InfoVia>P</InfoVia>
<sectors xmlns:json="http://james.newtonking.com/projects/json">
</itinerary>
</root>
I tried with this.
XmlNodeList xnList = XmlDoc.SelectNodes("/root[#*]");
but it gives null result. the count is 0. how can I read the data from this.hope your help with this.thanx.

You can use System.Xml.Linq.XElement to parse an xml:
XElement xRoot = XElement.Parse(xmlText);
XElement xItinerary = xRoot.Elements().First();
// or xItinerary = xRoot.Element("itinerary");
foreach (XElement node in xItinerary.Elements())
{
// Read node here: node.Name, node.Value and node.Attributes()
}
If you want to use XmlDocument you can do like this:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlText);
XmlNode itinerary = xmlDoc.FirstChild;
foreach (XmlNode node in itinerary.ChildNodes)
{
string name = node.Name;
string value = node.Value;
// you can also read node.Attributes
}

You can get the value of a particular element like,
var fareIndex = XmlDoc.SelectSingleNode("/root/itinerary/FareIndex").InnerText;
If you want to get the list of all elements that come under root/itinerary -
XmlNodeList xnList = XmlDoc.SelectNodes("/root/itinerary/*");
This link might help you.

How to read a node in an xml in this format

I have an getting an xml response on this format
<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n
<PlatformResponse xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://platform.intuit.com/api/v1\">\r\n
<ErrorMessage>OAuth Token rejected</ErrorMessage>\r\n
<ErrorCode>270</ErrorCode>\r\n
<ServerTime>2012-06-19T00:01:31.5150146Z</ServerTime>\r\n
</PlatformResponse>
I need to grab the value in the <ErrorCode> node, for that I did the following but it is not getting any values..
XmlDocument xml = new XmlDocument();
xml.LoadXml(xmlResponse);
XmlNodeList xnList = xml.SelectNodes("PlatformResponse");
foreach (XmlNode xn in xnList)
{
result.Message = xn["ErrorCode"].InnerText;
}
Any help would be much appreciated.

There seems to be some dirt in your PlatformResponse node that's giving problems, ( xmlns:xsd= etc... )
Using this xml
String sXml = #"<?xml version='1.0' encoding='utf-8'?>
<PlatformResponse >
<ErrorMessage>OAuth Token rejected</ErrorMessage>
<ErrorCode>270</ErrorCode>
<ServerTime>2012-06-19T00:01:31.5150146Z</ServerTime>
</PlatformResponse>";
And select like
XmlNodeList xnList = xml.SelectNodes("/PlatformResponse");
Your code works fine.

I just tested the code and it does work fine:
XmlDocument xml = new XmlDocument();
XmlTextReader reader = new XmlTextReader("Path_to_your_xml");
xml.Load(reader);
XmlNodeList xnList = xml.SelectNodes("PlatformResponse");
foreach (XmlNode xn in xnList)
{
MessageBox.Show(xn["ErrorCode"].InnerText);
}

For this, since the attribute is on the main document element itself, you can simply do
XmlDocument xml = new XmlDocument();
xml.LoadXml(xmlText);
result.Message = xml.DocumentElement["ErrorCode"].InnerText

XML - how to use namespace prefixes

I have this XML at http://localhost/file.xml:
<?xml version="1.0" encoding="utf-8"?>
<val:Root xmlns:val="http://www.hw-group.com/XMLSchema/ste/values.xsd">
<Agent>
<Version>2.0.3</Version>
<XmlVer>1.01</XmlVer>
<DeviceName>HWg-STE</DeviceName>
<Model>33</Model>
<vendor_id>0</vendor_id>
<MAC>00:0A:DA:01:DA:DA</MAC>
<IP>192.168.1.1</IP>
<MASK>255.255.255.0</MASK>
<sys_name>HWg-STE</sys_name>
<sys_location/>
<sys_contact>
HWg-STE:For more information try http://www.hw-group.com
</sys_contact>
</Agent>
<SenSet>
<Entry>
<ID>215</ID>
<Name>Home</Name>
<Units>C</Units>
<Value>27.7</Value>
<Min>10.0</Min>
<Max>40.0</Max>
<Hyst>0.0</Hyst>
<EmailSMS>1</EmailSMS>
<State>1</State>
</Entry>
</SenSet>
</val:Root>
I am trying to read this from my c# code:
static void Main(string[] args)
{
var xmlDoc = new XmlDocument();
xmlDoc.Load("http://localhost/file.xml");
XmlElement root = xmlDoc.DocumentElement;
// Create an XmlNamespaceManager to resolve the default namespace.
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xmlDoc.NameTable);
nsmgr.AddNamespace("val", "http://www.hw-group.com/XMLSchema/ste/values.xsd");
XmlNodeList nodes = root.SelectNodes("/val:SenSet/val:Entry");
foreach (XmlNode node in nodes)
{
string name = node["Name"].InnerText;
string value = node["Value"].InnerText;
Console.Write("name\t{0}\value\t{1}", name, value);
}
Console.ReadKey();
}
}
Problem is that the node is empty. I understand this is a common newbie problem when reading XML, still not able to solve what I am doing wrong, probably something with the Namespace "val" ?

You need to pass the namespace manager into the SelectNodes()
method.
Edit: corrected code
XmlNodeList nodes = root.SelectNodes("/val:Root/SenSet/Entry", nsmgr);

Just change you Xpath to:
XmlNodeList nodes1 = root.SelectNodes("/val:Root/SenSet/Entry",nsmgr);
Or:
XmlNodeList nodes = root.SelectNodes("SenSet/Entry");

Your xpath query string should be:
XmlNodeList nodes = root.SelectNodes("/val:Root/SenSet/Entry", nsmgr);
or more concisely,
XmlNodeList nodes = root.SelectNodes("//SenSet/Entry", nsmgr);

Read a XML (from a string) and get some fields - Problems reading XML

I have this XML (stored in a C# string called myXML)
<?xml version="1.0" encoding="utf-16"?>
<myDataz xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<listS>
<sog>
<field1>123</field1>
<field2>a</field2>
<field3>b</field3>
</sog>
<sog>
<field1>456</field1>
<field2>c</field2>
<field3>d</field3>
</sog>
</listS>
</myDataz>
and I'd like to browse all <sog> elements. For each of them, I'd like to print the child <field1>.
So this is my code :
XmlDocument xmlDoc = new XmlDocument();
string myXML = "<?xml version=\"1.0\" encoding=\"utf-16\"?><myDataz xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\"><listS><sog><field1>123</field1><field2>a</field2><field3>b</field3></sog><sog><field1>456</field1><field2>c</field2><field3>d</field3></sog></listS></myDataz>"
xmlDoc.Load(myXML);
XmlNodeList parentNode = xmlDoc.GetElementsByTagName("listS");
foreach (XmlNode childrenNode in parentNode)
{
HttpContext.Current.Response.Write(childrenNode.SelectSingleNode("//field1").Value);
}
but seems I can't read a string as XML? I get System.ArgumentException

You should use LoadXml method, not Load:
xmlDoc.LoadXml(myXML);
Load method is trying to load xml from a file and LoadXml from a string. You could also use XPath:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);
string xpath = "myDataz/listS/sog";
var nodes = xmlDoc.SelectNodes(xpath);
foreach (XmlNode childrenNode in nodes)
{
HttpContext.Current.Response.Write(childrenNode.SelectSingleNode("//field1").Value);
}

Use Linq-XML,
XDocument doc = XDocument.Load(file);
var result = from ele in doc.Descendants("sog")
select new
{
field1 = (string)ele.Element("field1")
};
foreach (var t in result)
{
HttpContext.Current.Response.Write(t.field1);
}
OR : Get the node list of <sog> tag.
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(myXML);
XmlNodeList parentNode = xmlDoc.GetElementsByTagName("sog");
foreach (XmlNode childrenNode in parentNode)
{
HttpContext.Current.Response.Write(childrenNode.SelectSingleNode("field1").InnerText);
}

The other answers are several years old (and do not work for Windows Phone 8.1) so I figured I'd drop in another option. I used this to parse an RSS response for a Windows Phone app:
XDocument xdoc = new XDocument();
xdoc = XDocument.Parse(xml_string);

Or use the XmlSerializer class.
XmlSerializer xs = new XmlSerializer(objectType);
obj = xs.Deserialize(new StringReader(yourXmlString));

I used the System.Xml.Linq.XElement for the purpose. Just check code below for reading the value of first child node of the xml(not the root node).
string textXml = "<xmlroot><firstchild>value of first child</firstchild>........</xmlroot>";
XElement xmlroot = XElement.Parse(textXml);
string firstNodeContent = ((System.Xml.Linq.XElement)(xmlroot.FirstNode)).Value;