How do I get the top most parent element from XML? I need the entire element with its attributes.
It wont always be the first line as there might be comments.
string xmlStr = File.ReadAllText(#"C:\Users\GRPAdmin\Desktop\Test.xml");
XElement str = XElement.Parse(xmlStr);
var h1 = str.Parent;
var h2 = str.XPathSelectElements("..").FirstOrDefault();
var h3 = str.XPathSelectElement("..").Parent;
<FILE NAME="ABC" version="14.0.0.112" State="WIP" Template="ABC123" origin="designer">
<REC NAME="Recipient">
<FLD NAME="FirstName">James</FLD>
</REC>
<REC NAME="Message">
<FLD NAME="Key">123</FLD>
</REC>
<REC NAME="Details">
<FLD NAME="Key">default</FLD>
</REC>
</File>
I would expect to have a var that equals <FILE NAME="ABC" version="14.0.0.112" State="WIP" Template="ABC123" origin="designer"> as the desired result
In XML data model, the opening tag (including all the attributes), tag content, and the closing tag is single XML element object, so it isn't natural to request only the opening tag. I'm not aware of a bult-in .NET function to get that, but you can reconstruct the opening tag string by combining information of the tag name, and all the attribute name-value pairs, for example :
string xmlStr = File.ReadAllText(#"C:\Users\GRPAdmin\Desktop\Test.xml");
XElement str = XElement.Parse(xmlStr);
var attributes = String.Join(" ", str.Attributes().Select(o => String.Format("{0}=\"{1}\"", o.Name, o.Value)));
var result = string.Format("<{0} {1}>", str.Name, attributes);
Console.WriteLine(result);
Dotnetfiddle Demo
output :
<FILE NAME="ABC" version="14.0.0.112" State="WIP" Template="ABC123" origin="designer">
You can use XElement.AncestorsAndSelf() to walk up the chain of parent XML elements to the root element. Enumerable.Last then gives you the root element:
var root = element.AncestorsAndSelf().Last();
If the XElement is contained by some XDocument, you can always do
var root = element.Document.Root;
But in your case you parsed directly to an XElement without bothering to create an XDocument container.
as #har07 already said, str is the top most element. If you want the attributes just iterate over them
string xmlStr = File.ReadAllText(#"C:\Users\GRPAdmin\Desktop\Test.xml");
var root = XElement.Parse(xmlStr);
foreach (var attribute in root.Attributes())
{
Console.WriteLine("{0} : {1}", attribute .Name, attribute.Value);
}
Related
I need to get a node value based on the criteria that another node value meets.
This is the xml example that I am searching through:
<Elements>
<Element>
<ElementID>A1</ElementID>
<ElementName>Element A</ElementName>
<ElementValues>
<ElementValue>
<ValueText>A Value</ValueText>
<ValueDescription>A Type Element</ValueDescription>
</ElementValue>
</ElementValues>
</Element>
<Element>
<ElementID>B1</ElementID>
<ElementName>Element B</ElementName>
<ElementValues>
<ElementValue>
<ValueText>B Value</ValueText>
<ValueDescription>B Type Element</ValueDescription>
</ElementValue>
</ElementValues>
</Element>
</Elements>
I need a tag value from the ValueText tag from the node with certain ElementID. For example: if the search criteria is "A1", than the result should be "A Value". (something like: get ValueText.Value if ElementID = "A1")
Please help me with this one (Linq, XPath, whatever...), I'm just spinning in the circles and getting nowhere.
Thanks in advance!
I really have searched for the answer, but couldn't get the similar one...
If I am right, you can use the XPath expression
//Element[ElementID/text() = \"B1\"]
It will search for every <Element> node in the XML document and select those who have an <ElementID> subnode which additionally has the property that text()(the inner text) has a value of B1. You can modify the "B1" to "A1" and you will get the other node, just be carefull when inserting user input in there, you don't want them to be able to modify your complete XPath expression, which can lead to vulnerabilites.
Here's a sample program.
public static void Main(string[] args)
{
string xml = #"<Elements>
<Element>
<ElementID>A1</ElementID>
<ElementName>Element A</ElementName>
<ElementValues>
<ElementValue>
<ValueText>A Value</ValueText>
<ValueDescription>A Type Element</ValueDescription>
</ElementValue>
</ElementValues>
</Element>
<Element>
<ElementID>B1</ElementID>
<ElementName>Element B</ElementName>
<ElementValues>
<ElementValue>
<ValueText>B Value</ValueText>
<ValueDescription>B Type Element</ValueDescription>
</ElementValue>
</ElementValues>
</Element>
</Elements>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
XmlNode root = doc.DocumentElement;
/* Select all "<Element>" nodes which have an <ElementID> subnode where the text equals "B1". */
var nodes = root.SelectNodes("//Element[ElementID/text() = \"B1\"]");
foreach(XmlNode node in nodes){
Console.WriteLine("Found matching Element: \n {0}", node.InnerXml);
}
}
Outputs
Found matching Element:
<ElementID>B1</ElementID><ElementName>Element B</ElementName><ElementValues><ElementValue><ValueText>B Value</ValueText><ValueDescription>B Type Element</ValueDescription></ElementValue></ElementValues>
Here is a straightforward LINQ query:
string xml = ...;
var root = XElement.Parse(xml);
string elementID = "A1";
var result = root.Elements("Element")
.Where(e => e.Element("ElementID").Value == elementID)
.Select(e => e.Element("ElementValues").Element("ElementValue").Element("ValueText").Value)
.FirstOrDefault();
Working with XML and LINQ to XML provides an object oriented approach of working with XML. For example, when the XML is initially parsed, the entire XML strucutre is the object, i.e., the Root. When selecting nodes, each node becomes it's own object. From your example, assuming you already have the XML is a string (could be a file, or stream, whatever):
var doc = XDocument.Parse(xml);
// retrieve the parent node of A1
XElement a1 = doc.Root.Elements("Element")
.First(x => x.Element("ElementID").Value == "A1");
// a1 now has an XML structure of:
// <Element>
// <ElementID>A1</ElementID>
// <ElementName>Element A</ElementName>
// <ElementValues>
// <ElementValue>
// <ValueText>A Value</ValueText>
// <ValueDescription>A Type Element</ValueDescription>
// </ElementValue>
// </ElementValues>
// </Element>
// get the value of ValueText w/ a verbose path:
string verbosePath = a1.Element("ElementValues")
.Element("ElementValue")
.Element("ValueText").Value;
// alternatively, short-circuit the path:
string shortPath = a1.Descendants("ValueText").First().Value;
Done with LINQ, replace elementId with the element id you want the value text of.
var xDoc = XDocument.Parse(xml);
var elements = xDoc.Element("Elements");
var element = elements.Elements("Element").Single(e => e.Element("ElementID").Value.Equals(elementId));
var valueText = element.Descendants("ValueText").Single().Value;
Actullay, I need to get all elements except root node from first xml document and so that I could insert them as child nodes to an element(that has same name as a previous doc's root name) in a new document.
So I have tried various ways to achieve it, one of them is removing the root node of first and then trying to add elements to a new one's as given below:
I have tried the following but could not achieve it.
XDocument testDoc = XDocument.Parse(Mydocument);
testDoc.Descendants().Where(e => e.Name.LocalName == "rootName").Select(m=>m).Single().Remove();
var resultDoc = testDoc;
The above code is giving me an empty "{}" result.
my xml document looks something like the below one's:
<rootName xsi:schemaLocation="" xmlns:xsi="" xmlns="">
<main>
<child>
</child>
<anotherchild>
</anotherchild>
</main>
</rootName>
And another way is getting all the elements of first document as the following:
var resultDoc = testDoc.Descendants(ns + "rootName").Elements();
the above statement is giving me the list of elements in the "testDoc" which
I need to do something like below, I am clueless:
<AnotherDocument xsi:schemaLocation="" xmlns:xsi="" xmlns="">
<firstNode>
<rootName>
<main>
<child>
</child>
<anotherchild>
</anotherchild>
</main>
</rootName>
</firstNode>
Please let me know how to insert those elements in a new document as above if I am correct else let me know the way to resolve this issue.
Thanks in advance.
You can replace content of rootName element in another document with elements from first document root:
var xDoc = XDocument.Parse(Mydocument);
var anotherXDoc = XDocument.Load("anotherdata.xml");
XNamespace ns = "http://..."; // your xml namespance
var rootName = anotherXDoc.Descendants(ns + "rootName").First();
rootName.ReplaceNodes(xDoc.Root.Elements());
By this page_nodes gets all nodes now you can used all node by for each loop
var page_nodes = from p in xdoc.Descendants.Where(e => e.Name.LocalName == "rootName").Select(m=>m).Single().Remove() select p;
foreach (var page_node in page_nodes)
{
//Do stuff
}
Wouldn't removing a root node, remove all its child nodes as well? The result you are getting is to be expected I think. You should probably get all the children of the root and copy them to your new document.
I'm trying to write an XML file that will be picked up and parsed by another service. In order for this to happen the XML must be formatted in a very specific way, namely:
<?xml version="1.0"?>
<Feedbacks:Feedbacks xmlns:Feedbacks="Feedbacks">
<Feedbacks:Elements>
<Feedback:XMLFeedback xmlns:Feedback="Feedback">
<Feedback:MfgUnitID></Feedback:MfgUnitID>
<Feedback:MachineId></Feedback:MachineId>
<Feedback:OperationCode></Feedback:OperationCode>
<Feedback:ItemSeqNum></Feedback:ItemSeqNum>
<Feedback:OperDispositionCd></Feedback:OperDispositionCd>
<Feedback:ItemId></Feedback:ItemId>
<Feedback:ParentItemId></Feedback:ParentItemId>
<Feedback:ItemEndSize>1821</Feedback:ItemEndSize>
<Feedback:ItemDispositionCd></Feedback:ItemDispositionCd>
<Feedback:OperStartDate></Feedback:OperStartDate>
<Feedback:OperEndDate></Feedback:OperEndDate>
</Feedback:XMLFeedback>
</Feedbacks:Elements>
</Feedbacks:Feedbacks>
with data of course between the innermost elements. Here's the issue though, no matter what I do, I can't get any of the C# classes to keep the semicolons on the innermost nodes. As far as I know these need to stay, so is there a way in C# to force it to format the nodes this way? I've tried all of the create methods that I could find in the XMLDocument class. I can get the outer nodes formatted fine, but the inner ones just keep creating problems.
Edit, sorry here's the code that makes the inner nodes.
private void AppendFile(string filename, string[] headers, Dictionary<string, string> values)
{
XmlDocument doc = new XmlDocument();
doc.Load(filename);
XmlNode node = doc.GetElementsByTagName(headers[headers.Length - 2]).Item(0);
string[] hPieces = headers[headers.Length - 1].Split(':');
XmlElement appendee = doc.CreateElement(hPieces[0].Trim(), hPieces[1].Trim(), hPieces[0].Trim());
node.AppendChild(appendee);
foreach (KeyValuePair<string, string> pair in values)
{
string[] ePieces = pair.Key.Split(':');
//XmlElement element = doc.CreateElement(ePieces[0].Trim(), string.Empty, ePieces[1].Trim());
//XmlText text = doc.CreateTextNode(pair.Value);
XmlNode innerNode = doc.CreateNode(XmlNodeType.Element, ePieces[1].Trim(), ePieces[0].Trim());
node.InnerText = pair.Value;
// element.AppendChild(text);
appendee.AppendChild(innerNode);
}
doc.Save(filename);
}
The data for the inner nodes comes in as key value pairs in the dictionary. Where the keys contain the intended name.
Edit2: This is what the file output looks like
<?xml version="1.0" encoding="utf-8"?>
<Feedbacks:Feedbacks xmlns:Feedbacks="Feedbacks">
<Feedbacks:Elements>
<Feedback:XMLFeedback xmlns:Feedback="Feedback">
<MfgUnitID></MfgUnitID>
<MachineId></MachineId>
<OperationCode</OperationCode>
<ItemSeqNum></ItemSeqNum>
<OperDispositionCd></OperDispositionCd>
<ItemId></ItemId>
<ParentItemId></ParentItemId>
<ItemEndSize></ItemEndSize>
<ItemDispositionCd></ItemDispositionCd>
<OperStartDate></OperStartDate>
<OperEndDate></OperEndDate>
</Feedback:XMLFeedback>
</Feedbacks:Elements>
</Feedbacks:Feedbacks>
You can accompish this easily with XLinq:
using System.Xml.Linq;
XNamespace ns1 = "Feedbacks";
XNamespace ns2 = "Feedback";
var doc = new XElement("Feedbacks",
new XAttribute(XNamespace.Xmlns+"Feedbacks", ns1));
doc.Add(new XElement(ns1 + "Elements",
new XElement(ns2 + "Feedback",
new XAttribute(XNamespace.Xmlns+"Feedback", ns2),
new XElement(ns2 + "Unit"))));
Gives
<Feedbacks xmlns:Feedbacks="Feedbacks">
<Feedbacks:Elements>
<Feedback:Feedback xmlns:Feedback="Feedback">
<Feedback:Unit />
</Feedback:Feedback>
</Feedbacks:Elements>
</Feedbacks>
Although I believe that your own output should be valid XML, relying on the parent namespcae.
In my previous question here, I didn’t understand how to solve my problem.
Linq to XML, how to acess an element in C#?
Here is my XML I need to parse:
<root>
<photo>/filesphoto.jpg</photo>
<photo:mtime>12</photo:mtime>
<text>some text</text>
</root>
To access the element I use this code:
var doc = XDocument.Parse(xml.Text);
doc.Descendants("text").FirstOrDefault().Value;
How can I access ?
I have try http://aspnetgotyou.blogspot.com/2010/06/xdocument-or-xelement-with-xmlnamespace.html,
But it is ignored <photo:mtime> and I need to access it.
Please write some code.
Contrary to #BrokenGlass' comments, your XML is not invalid. In fact the technique in the link you provided in your question (for loading namespaces) works fine. Maybe you just didn't change the example for your own needs. Here's a more compact generalization for parsing xml fragments with namespaces into an XElement:
public static XElement parseWithNamespaces(String xml, String[] namespaces) {
XmlNamespaceManager nameSpaceManager = new XmlNamespaceManager(new NameTable());
foreach (String ns in namespaces) { nameSpaceManager.AddNamespace(ns, ns); }
return XElement.Load(new XmlTextReader(xml, XmlNodeType.Element,
new XmlParserContext(null, nameSpaceManager, null, XmlSpace.None)));
}
Using your exact input:
string xml =
#"<root>
<photo>/filesphoto.jpg</photo>
<photo:mtime>12</photo:mtime>
<text>some text</text>
</root>";
XElement x = parseWithNamespaces(xml, new string[] { "photo" });
foreach (XElement e in x.Elements()) {
Console.WriteLine("{0} = {1}", e.Name, e.Value);
}
Console.WriteLine(x.Element("{photo}mtime").Value);
Prints:
photo = /filesphoto.jpg
{photo}mtime = 12
text = some text
12
Try this: (Your xml is changed a little, see )
string xml = "<root><photo>/filesphoto.jpg</photo><photoMtime>12</photoMtime><text>some text</text></root>";
var doc = XDocument.Parse(xml);
string value = doc.Descendants("text").FirstOrDefault().Value;
MessageBox.Show(value);
I have this XML:
<chunk type="manufacturer_info" id="" note="">test: <chunk type="style" style="link">${manufacturer_website}</chunk></chunk>
I need to get "test: " separately from the inner element.
EDIT:
This is coming into a function as an XElement.
The <chunk> element has two child nodes: a text node and a <chunk> element.
You can get the value of the text node as follows:
var element = XElement.Parse(#"<chunk type=""manufacturer_info"" ...");
var result = string.Concat(element.Nodes().OfType<XText>());
// result == "test: "
Here you go.
string xml = #"<Chunks><chunk type='manufacturer_info' id='' note=''>test: <chunk type='style' style='link'>${manufacturer_website}</chunk></chunk></Chunks>";
var xDoc = XDocument.Parse(xml);
var res = xDoc.DescendantNodes().OfType<XText>().First().Value;