Find pairs of numbers in an array or List - c#

My goal is to find pairs of numbers in an array or List. A pair in this case is defined by the maximum difference between two entries. For instance
1
50
2
100
102
800
Pairs(if max difference threshold is 2) with line numbers(array number):
1,2 line number of 1 is 0
100,101 line number of 100 is 3
How do I do this?

You can use LINQ to do this:
var numbers = new[]
{
1,
50,
2,
100,
102,
800
};
var treshold = 2;
var numWithIndexes = numbers.Select((value, index) => new { value, index });
var pairs = from num1 in numWithIndexes
from num2 in numWithIndexes
where (num2.value - num1.value <= treshold) && (num2.value - num1.value > 0)
select new[]
{
num1.value, // first number in the pair
num2.value, // second number in the pair
num1.index, // index of the first number in the pair
num2.index // index of the second member in the pair
};
foreach (var pair in pairs)
{
Console.WriteLine("Pair found: " + pair[0] + ", " + pair[1] +
" at line " + pair[2] + ", " + pair[3]);
}

There rather is no library, you can sort array and then itterayt in loop to find pairs.

I don't know of any library that would help you with this. You can use the methods in the framework.
For the case where threshold is 1, if you put the numbers from the array in a hash set you can efficiently look up the numbers that is a part of a pair:
HashSet<int> set = new HashSet<int>(myArray);
int[] pairs = myArray.Where(i => set.Contains(i + 1)).ToArray();
The pairs array will have the lower number of the pairs, e.g. { 1, 100 } when the pairs are 1, 2 and 100, 101.
To get the index instead of the number, iterate the indexes instead:
HashSet<int> set = new HashSet<int>(myArray);
int[] index = Enumerable.Range(myArray.Length).Where(i => set.Contains(myArray[i + 1])).ToArray();
The index array will have the index of the lower numbers of the pairs.

Easily solved by sorting and then using a simple loop:
FindPairs(sequence: new[] { 1, 50, 2, 100, 101, 800 }, threshold: 2); // {1, 2}, {100, 101}.
private List<int[]> FindPairs(IEnumerable<int> sequence, int threshold)
{
var sorted = sequence.OrderBy(x => x).ToList();
var pairs = new List<int[]>();
for (var i = 0; i < sorted.Count - 1; ++i)
{
if (sorted[i + 1] - sorted[i] <= threshold)
{
pairs.Add(new [] { sorted[i], sorted[i + 1] });
}
}
return pairs;
}

Related

C# - How to find the most common and the least common integers in an array?

I was asked to make a Dice program with two arrays (one for each dice) and add the two results, e.g.: 2 (dice 1) + 6 (dice 2) = 8.
The program must roll the dices 100 times and show the sum each time.
I could do it so far, but the program also must show which sum is the most frequent, and which sum is the least frequent.
Like this: sum = [2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6]. Most common: 2; Least common: 5.
How can I do it?
This is how my code looks like:
static void Main(string[] args)
{
Random gerador = new Random();
int[] soma = new int[100];
int rolagem = 0;
for(int i = 0; i < soma.Length; i++)
{
rolagem = 0;
rolagem += gerador.Next(6) + 1;
rolagem += gerador.Next(6) + 1;
soma[i] = rolagem;
}
var mais = soma.GroupBy(item => item).OrderByDescending(g => g.Count()).Select(g => g.Key).First();
//NEED TO FIND OUT LEAST COMMON SUM
for (int j = 1; j < soma.Length; j++)
{
Console.Write("{0} ", soma[j]);
}
Console.WriteLine("Soma mais frequente: {0}, Soma menos frequente: {1}", mais, menos);
Console.ReadKey();
}
You're almost there, you can find the least common one similarly:
var array = new[] { 1, 1, 1, 1, 4, 2, 2, 3, 3, 3, 5, 5 };
var result = array.GroupBy(i => i).OrderBy(g => g.Count()).Select(g => g.Key).ToList();
var mostCommon = result.Last();
var leastCommon = result.First();
If you have code that rolls the dice 100 times, you are pretty close. All you need to do is frequency counters.
A roll of a pair of dice yields a number between 2 and 12, inclusive. Make an int count[13] array before entering the loop.
In the loop each time you have two numbers, say, d1 and d2, increment the count as follows:
count[d1+d2]++;
Once the loop is over, find the highest and the lowest numbers in the array between indexes 2 and 12, inclusive. The index of the highest number will be the number with the highest roll count; the index of the lowest number will be the number with the lowest roll count.
Tuple<int, int> least = new Tuple<int, int>(-1, -1), most = new Tuple<int, int>(-1, -1);
List<int> arr = new List<int> { 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6 };
var grp = arr.GroupBy(x => x).Select(x=>x).ToList();
foreach (var item in grp)
{
if (least.Item2 == -1 || least.Item2>item.Count())
{
var x = new Tuple<int, int>(item.Key, item.Count());
least = x;
}
if (most.Item2 == -1 || most.Item2 < item.Count())
{
var x = new Tuple<int, int>(item.Key, item.Count());
most = x;
}
}
Console.WriteLine("Least : "+least.Item1+" repeated " + least.Item2+"times");
Console.WriteLine("Most : "+most.Item1 + " repeated " + most.Item2 + "times");
Or as m1kael suggested,
Tuple<int, int> least = new Tuple<int, int>(-1, -1), most = new Tuple<int, int>(-1, -1);
List<int> arr = new List<int> { 2, 2, 2, 2, 3, 3, 4, 4, 5, 6, 6 };
var grp = arr.GroupBy(x => x).OrderBy(x=>x.Count()).Select(x => x.Key).ToList();
Console.WriteLine("Least : "+ grp.First());
Console.WriteLine("Most : "+ grp.Last());
There is a small chance for more than one most or least common:
var a = Enumerable.Repeat(new Random(), 100).Select(r => r.Next(6) + r.Next(6) + 2);
var groups = a.GroupBy(i => i).GroupBy(g => g.Count(), g => g.Key).OrderBy(g => g.Key).ToList();
var mostCommon = string.Join(", ", groups.Last());
var leastCommon = string.Join(", ", groups[0]);

Converting a long nested Excel formula to c#

I am tasked to transform an Excel VBA to a web-based application. I am using Web Forms. I am stuck with a long Excel formula but I have converted half of the long formula into C#.
Here is the Excel formula:
IF(AND(D7="u", H7/F7>1), 0, INDEX(Scoring!$O$8:$O$10, SUMPRODUCT(--(E28 <= Scoring!$N8:$N10),--(E28 >= Scoring!$N8:$N10), ROW(INDIRECT("'Scoring'!$M1:$M3"))))
While here is my progress on the C# method. I need help on the ELSE part:
IF (variable = "u" && ((CurrentValue / AcceptedValue) > 1)){
return 0;
ELSE {
// the INDEX clause on the Excel Formula
}
O8 - O10 values are {2, 1, 0}
N8 - N10 values are {1, 1.5, 9999999999}
E28 is 0
I have also got the result of the remainder of the formula piece by piece. I just need guidance on how to put it in C#.
=INDEX(Scoring!$O$8:$O$10, SUMPRODUCT({1,1,1}, {0,0,0}, 1))
The double minus(--) made it return 0/1 instead of true/false. ROW(INDIRECT($M1-$M3)) is equivalent to 1.
I could use some help on transforming the Excel formula into C# code.
Here is some C# code to replicate this part of your formula:
INDEX(Scoring!$O$8:$O$10, SUMPRODUCT(--(E28 <= Scoring!$N8:$N10),--(E28 >= Scoring!$N8:$N10), ROW(INDIRECT("'Scoring'!$M1:$M3")))
In the code I've had to assign the array {1, 1, 1} for ROW(INDIRECT("'Scoring'!$M1:$M3")). There is some ambiguity in your question around the action of SUMPRODUCT. According to support.office.com
Multiplies corresponding components in the given arrays, and returns the sum of those products.
But some of your detail in the question makes me think you are thinking that each array get summed up and then those results get multiplied together. Anyway, check out the comments in the code below to follow the logic:
// inputs
double[] o8o10 = new double[] { 2, 1, 0 }; // Scoring!$O$8:$O$10
double[] n8n10 = new double[] { 1, 1.5, 9999999999 }; // Scoring!$N8:$N10
double e28 = 0; // E28
// entries to SUMPRODUCT
List<int> test1 = new List<int>();
List<int> test2 = new List<int>();
Array.ForEach(n8n10, x => { test1.Add((e28 <= x) ? 0 : 1); });
Array.ForEach(n8n10, x => { test2.Add((e28 >= x) ? 0 : 1); });
// ROW(INDIRECT("'Scoring'!$M1:$M3")) should be an array !
List<int> test3 = new List<int> { 1, 1, 1 };
// evalue SUMPRODUCT
int sumProductResult = 0;
for (var i=0; i<test1.Count; i++)
{
sumProductResult += test1[i] * test2[i] * test3[i];
}
// evalute INDEX
double indexResult = 0;
indexResult = o8o10[sumProductResult];
// output
Console.WriteLine(indexResult);
Console.ReadKey();
The output for me is 2 because that is the 0th element of the o8o10 array. We get 0 for the array index because
=SUMPRODUCT({1, 1, 1}, {0, 0, 0}, {1, 1, 1})
resolves to:
=SUM(1*0*1, 1*0*1, 1*0*1}
Which gives 0.
HTH
ROW(INDIRECT("'Scoring'!$M1:$M3")) actually evaluates to {1; 2; 3} and
--(E28 <= Scoring!$N8:$N10),--(E28 >= Scoring!$N8:$N10) is --(E28 = Scoring!$N8:$N10)
so the SUMPRODUCT formula is just:
(E28 = Scoring!$N8) * 1 + (E28 = Scoring!$N9) * 2 + (E28 = Scoring!$N10) * 3
and in C#:
double[] n8n10 = { 1, 2, 3 }; double e28 = 2;
double sumProduct = n8n10.Select((d, i) d == e28 ? i + 1 : 0).Sum();
But! because Scoring!$O$8:$O$10 is only 3 cells and the SUMPRODUCT can in theory result in more than 3, the actual aim of the INDEX SUMPRODUCT part seems to be something like this:
double[] o8o10 = { 4, 5, 6 }, n8n10 = { 1, 2, 3 };
double e28 = 2, result = o8o10[0]; // INDEX(array, 0) results in array
if (n8n10[1] == e28) result = o8o10[1];
else if (n8n10[2] == e28) result = o8o10[2];

How to sort a List of integer arrays of varying size?

I've done some extensive searching for this so if this is a duplicate please slaughter me :D
I have a List of byte arrays (List) where the arrays are of varying length. I need to sort the list by the array lengths in ascending order then by the bytes in the array (please see example).
Example:
I want to go from:
{0,1,2}
{0,4}
{0,3,2}
{0,1,3}
{0,2,4,6,1}
{0,1,1}
{0,3,4,5}
to:
{0,4}
{0,1,1}
{0,1,2}
{0,1,3}
{0,3,2}
{0,3,4,5}
{0,2,4,6,1}
It's essentially alphabetical order but with a set of numbers instead of characters (arguably the same thing), any ideas?
The only thing you need to do is implement a IComparer<T> interface and provide that to the sorting algorithm. In this case the algorithm looks like:
public ByteArrayComparer : IComparer<byte[]> {
public int Compare (byte[] ba, byte[] bb) {
int n = ba.Length; //fetch the length of the first array
int ci = n.CompareTo(bb.Length); //compare to the second
if(ci != 0) { //if not equal return the compare result
return ci;
} else { //else elementwise comparer
for(int i = 0; i < n; i++) {
if(ba[i] != bb[i]) { //if not equal element, return compare result
return ba[i].CompareTo(bb[i]);
}
}
return 0; //if all equal, return 0
}
}
}
Next you can use the List<T>.Sort method:
List<byte[]> data = new List<byte[]>();
//add arrays to data
data.Sort(new ByteArrayComparer());
//data is now sorted
The sorting algorithm requires that the comparator is valid, a comparator is valid if it satisfies the three constraints on an ordering relation:
Reflexivity: if an elements is compared with itself, return 0;
Anti-symmetric: If x is smaller than y (return something less than 0), then y is greater than x (something greater than 0);
Transitive: if x is smaller than y and y is smaller than z, then x is smaller than z.
If the comparer doesn't satisfy that relation, the sorting algorithm will fail to sort correctly, simply because your order makes no sense.
Why not simply use LINQ
MyList = MyList.OrderBy(arr=>arr.Length).ThenBy(arr =>arr.Sum()).ToList();
A working example :
List<int[]> a = new List<int[]>();
int[] t1 = { 0, 4 };
int[] t2 = { 0, 1, 2 };
int[] t3 = { 0, 1, 3 };
int[] t4 = { 0, 2, 4, 6, 1 };
int[] t5 = { 0, 1, 1 };
int[] t6 = { 0, 3, 4, 5 };
a.Add(t1);
a.Add(t2);
a.Add(t3);
a.Add(t4);
a.Add(t5);
a.Add(t6);
a = a.OrderBy(arr=>arr.Length).ThenBy(arr =>arr.Sum()).ToList();
foreach (int[] item in a)
{
foreach (int item2 in item)
{
Console.Write(" "+item2);
}
Console.WriteLine();
}
Sample output :
0 4
0 1
0 1 2
0 1 3
0 3 4 5
0 2 4 6 1
And as pointed out this could fail in scenarios like {3 4 5} , {4 5 3}

Find a series of the same number in a List

I have a List of items containing either 1 or 0, I'm looking to output the items only where there are six 1's back to back in the list. So only write to the console if the item in this list is part of a group of six.
1
1
1
1
1
1
0
1
1
1
0
In the above list, the first six items would be output but the bottom set of three 1s would not as they are not part of a group of six.
Is this a job for LINQ or RegEx?
You can concatenate all values into string, then split it by zeros. From substrings select those which have at least 6 characters:
List<int> values = new List<int> { 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0 };
var series = String.Concat(values)
.Split(new[] { '0' }, StringSplitOptions.RemoveEmptyEntries)
.Where(s => s.Length >= 6);
For given input data series will contain single item "111111" which you can output to console.
Classic run length encoding, O(n), lazy evaluated, stack agnostic, generic for any equatable type.
public void TestRunLength()
{
var runs = new List<int>{ 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 3, 4, 4, 0, 4};
var finalGroup = RunLength(runs).FirstOrDefault(i => i.Count == 6 && i.First() == 1);
}
private IEnumerable<List<T>> RunLength<T>(IEnumerable<T> source) where T : IEquatable<T>
{
T current = default(T);
var requiresInit = true;
var list = new List<T>();
foreach (var i in source)
{
if (requiresInit)
{
current = i;
requiresInit = false;
}
if (i.Equals(current))
{
list.Add(i);
}
else
{
yield return list;
list = new List<T>{ i };
current = i;
}
}
if (list.Any())
{
yield return list;
}
}
And because it's lazy it works on infinite sequences (yes I know its not infinite, but it is large)!
public void TestRunLength()
{
var random = new Random();
var runs = Enumerable.Range(int.MinValue, int.MaxValue)
.Select(i => random.Next(0, 10));
var finalGroup = RunLength(runs)
.FirstOrDefault(i => i.Count == 6);
}
Probably it can be done with Regex too if you concatenate your numbers into a string. But I would prefer linq:
var bits = new List<int> {1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0};
int bitCountPerGroup = 6;
var result = bits // (1) (2)
.Select((x,idx) => bits.Skip(idx).TakeWhile(y => y == x))
.Where(g => g.Count() == bitCountPerGroup); // (3)
foreach (var set in result)
Console.WriteLine(string.Join(" ", set));
This code gets a number-set for each number by starting from the number (1) and taking the next numbers as long as they are equal (2). Then filter the groups and gets only those groups which have 6 numbers (3).
If for example your list is of an unknown size,or better,you do not know the items in it you could do this recursive example(note that i placed more zeros so it would fetch 2 sets of data,it works with yours also),and pass to the method the amout to group by:
//this is the datastructure to hold the results
static List<KeyValuePair<string, List<int>>> Set = new List<KeyValuePair<string, List<int>>>();
private static void GetData(List<int> lst, int group)
{
int count = 1;
int pivot = lst.First();
if (lst.Count < group)
{
return;
}
else
{
foreach (int i in lst.Skip(1))
{
if (i == pivot)
{
count++;
}
else if (count == group)
{
Set.Add(new KeyValuePair<string, List<int>>("Set of items " + pivot, lst.Take(count).ToList()));
GetData(lst.Skip(count).ToList(), group);
break;
}
else
{
GetData(lst.Skip(count).ToList(), group);
break;
}
}
}
}
Then in Main():
static void Main(string[] args)
{
List<int> test = new List<int> { 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0 };
GetData(test, 6);
foreach (var item in Set)
{
Console.WriteLine("\t" + item.Key);
foreach (var subitem in item.Value)
{
Console.WriteLine(subitem);
}
}
}

How can I get the sum (average) value of three lists in C#?

I have three lists which each list represents only 0s and 1s which related to the pixel values of three images.
My question is how can I get the sum (average) of those three lists and represent it in a new list?
here is example of my image1:
List<int> image1 = new List<int>();
int blackColor = 0;
for (int x = 0; x < bmp1.Width; x++)
{
for (int y = 0; y < bmp1.Height; y++)
{
Color color = bmp1.GetPixel(x, y);
if (color.ToArgb() == Color.Black.ToArgb())
{
image1.Add(0);
blackColor++;
}
else
{
image1.Add(1);
}
}
}
Let me makes sure I understand the problem. You have three lists of the same length:
list A: 1, 2, 4, 3
list B: 3, 2, 4, 1
List C: 2, 7, 1, 8
and you wish to get a third list that is the average of each:
List D: 2, 4, 3, 4
Yes?
This is a job for zip join.
var sumOfFirstTwo = list1.Zip(list2, (x, y)=>x + y);
sumOfFirstTwo is now the sequence that is the sum of the first two lists.
var sumOfAllThree = sumOfFirstTwo.Zip(list3, (x, y)=>x + y);
sumOfAllThree is now the sequence that is the sum of all three lists.
var average = sumOfAllThree.Select(x=>x/3).ToList();
Make sense?
This works for an arbitrary number of lists
var firstList = new[] { 1, 2, 3, 1 };
var secondList = new[] { 2, 3, 1, 1 };
var thirdList = new[] { 3, 1, 2, 2 };
var lists = new[] { firstList, secondList, thirdList };
var listLengths = lists.Select(x => x.Count());
if (listLengths.Distinct().Count() != 1)
throw new Exception("Line lengths must be the same");
var lengthOfEachList = listLengths.First();
var averages = new List<double>();
for (var i = 0; i != lengthOfEachList; ++i) {
averages.Add(lists.Average(x => x[i]));
}
The LINQ way would be
var averages = Enumerable.Range(0, lengthOfEachList).Select(x => lists.Average(y => y[x]));

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