an error shows saying that I have invalid parameters for this code...
can anyone tell me whats wrong? Im supposed to get the image assigned to the clientID.
private void button1_Click(object sender, EventArgs e)
{
MySqlConnection conn = new MySqlConnection(mycon);
MySqlCommand cmd = new MySqlCommand("SELECT clientImage FROM client WHERE clientID='" + label2.Text + "'", conn);
conn.Open();
MySqlDataReader myReader = null;
myReader = cmd.ExecuteReader();
while (myReader.Read())
{
byte[] imgg = (byte[])(myReader["clientImage"]);
if (imgg == null)
{
pictureBox1.Image = null;
}
else
{
MemoryStream mstream = new MemoryStream(imgg);
pictureBox1.Image = System.Drawing.Image.FromStream(mstream);
}
}
conn.Close();
}
This piece of code might come in handy. I have tried it.
byte[] imagedata = (byte [])dataGridView1[4, dataGridView1.SelectedRows[0].Index].Value;
using (System.IO.MemoryStream ms = new System.IO.MemoryStream(imagedata, 0, imagedata.Length))
{
ms.Write(imagedata, 0, imagedata.Length);
//Set image variable value using memory stream.
image = Image.FromStream(ms, true );
}
this code works. MySql Wamp.
using System.IO;
string appPath = Path.GetDirectoryName(Application.Executable) + #"/student Images/";
string imagename;
//put this code below to load form.
getimage();
if(File.Exist(appPath + imagename)
{
PictureBox1.Image = Image.FromFile(appPath + imagename);
}
else
{
PictureBox1.Image = Properties.Resources.Image_notfound;
}
private void getimage()
{
MySqlConnection connect = new MySqlConnection(con);
MySqlCommand cmd = new MySqlCommand("SELECT PictureName as 'pic' FROM userprofile where ID='" + datagrid.CurrentRow.Cells["ID"].ToString() + "'");
cmd.CommandType = CommandType.Text;
cmd.Connection = connect;
connect.Open();
Try
{
MySqlDataReader dr = cmd.ExecuteReader();
while(dr.Read())
{
imagename = dr.GetString("pic");
}
dr.Close();
}
catch(Exception ee)
{
Console.WriteLine(ee.ToString());
}
finally
{
connect.Close();
}
Controller
using System.IO;
using (TESTDBEntities db = new TESTDBEntities())
{
// first create var
var item = (from d in db.Hunger_tbl_MainCategory select d).ToList();
return View(item); // your view
}
View
#model List<WebApplication1.Models.TEST_tbl_IMG`enter code here`>
#foreach (var item in Model)
{
<div class="cards-list">
<div class="card 1">
#{
var base64 = Convert.ToBase64String(item.CategoryImage);
var imgsrc = string.Format("data:image/png;base64,{0}", base64);
}
<div class="card_image"> <img src='#imgsrc'/></div>
</div>
</div>
}
Related
I'm trying to make this catalog app that display images with its "title" and "category" but I can't seem to display the image because of an error
on the line that says
images.Images.Add(row["id"].ToString(), new Bitmap(image_stream));
This is the whole of my code. I need the solution so i can print the image with its corresponding details in a list view. Thank you.
namespace WindowsFormsApplication2
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
comboBox1.Items.Add("Books");
comboBox1.Items.Add("Games");
comboBox1.Items.Add("Music");
}
SqlConnection connection = new SqlConnection("Data Source=DESKTOP-4T5BLQ6\\SQLEXPRESS;Initial Catalog=CatalogDB;Integrated Security=True");
SqlCommand command = new SqlCommand();
SqlDataAdapter dataAdapter = new SqlDataAdapter();
SqlDataReader dataReader;
DataTable dataTable = new DataTable();
MemoryStream stream1;
byte[] photo_array;
private void Form1_Load(object sender, EventArgs e)
{
}
private void button1_Click(object sender, EventArgs e)
{
connection.Open();
int i = 0;
MemoryStream stream = new MemoryStream();
command.CommandText = "insert into EntryTable(Title,Category,Image) values('" + textBox1.Text + "','" + comboBox1.Text + "','" + pictureBox1.Image + "')";
pictureBox1.Image.Save(stream, System.Drawing.Imaging.ImageFormat.Jpeg);
byte[] pic = stream.ToArray();
if (i > 0)
{
MessageBox.Show("Saved new item in index" + i);
}
connection.Close();
MessageBox.Show("Made New Entry");
showData();
clear();
}
void clear()
{
textBox1.Clear();
pictureBox1.Image = null;
comboBox1.SelectedIndex = -1;
}
private void button2_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "Images only. |*.jpg; *jpeg; *.png; *.gif; *.bmp;";
DialogResult result = ofd.ShowDialog();
if (result == DialogResult.OK)
{
pictureBox1.Image = Image.FromFile(ofd.FileName);
}
}
private void showData()
{
connection.Open();
listView1.Clear();
ImageList images = new ImageList();
images.ColorDepth = ColorDepth.Depth32Bit;
listView1.LargeImageList = images;
listView1.LargeImageList.ImageSize = new System.Drawing.Size(100 , 100);
command.Connection = connection;
command.CommandText = "SELECT * FROM EntryTable";
dataAdapter.SelectCommand = command;
dataTable.Clear();
dataAdapter.Fill(dataTable);
foreach (DataRow row in dataTable.Rows)
{
var image_buffer = (byte[])(row["Image"]);
MemoryStream image_stream = new MemoryStream(image_buffer, true);
image_stream.Write(image_buffer, 0, image_buffer.Length);
images.Images.Add(row["id"].ToString(), new Bitmap(image_stream));
image_stream.Close();
ListViewItem listItem = new ListViewItem();
listItem.Text = row["Title"].ToString();
listItem.ImageKey = row["Image"].ToString();
listView1.Items.Add(listItem);
listView1.Items.Add(row["Category"].ToString());
listView1.Items.Add(row["Title"].ToString());
}
connection.Close();
}
}
}
Xoriel,
You need to be more specific about what you are asking on SO. Your original post only indicates that you have and error and that it is holding up your app development (welcome to coding). You don't even tell us what error you are getting.
Now you ask how to implement a try catch? You should do a bit of research on your own. As far as try catch, you can start Here.
Your code indicates a lack of understanding about how windows winforms are instantiated and their sequence of events. To me, this indicates that you will have further problems after this one is fixed, so I will add a try catch to your code. It will write the exception to your console.
foreach (DataRow row in dataTable.Rows)
{
var image_buffer = (byte[])(row["Image"]);
MemoryStream image_stream = new MemoryStream(image_buffer, true);
image_stream.Write(image_buffer, 0, image_buffer.Length);
try
{
images.Images.Add(row["id"].ToString(), new Bitmap(image_stream));
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
image_stream.Close();
ListViewItem listItem = new ListViewItem();
listItem.Text = row["Title"].ToString();
listItem.ImageKey = row["Image"].ToString();
listView1.Items.Add(listItem);
listView1.Items.Add(row["Category"].ToString());
listView1.Items.Add(row["Title"].ToString());
}
Your true issue is the format in which you are storing the image to the database and the way in which you are retrieving it.
Regards,
Marc
I am using asp.net with c# to build website, but now i come into a problem. I insert image with blob type into mysql database but i cannot retrieve it. There is no picturebox layout for web controls. I want to use image.imageURL to display this image. I searched a lot, some recommend use another aspx page, some recommend using ashx, but i cannot find a detailed solution. Here is what i have now:
protected void Button1_Click(object sender, EventArgs e)
{
String myname = Request.QueryString["Name"];
string myConnection = "server=127.0.0.1;uid=root;" + "pwd=81210ZLK;database=database;" + "Allow User Variables=True";
try
{
MySqlConnection myConn = new MySqlConnection(myConnection);
myConn.ConnectionString = myConnection;
MySqlCommand SelectCommand = new MySqlCommand();
string mySQL = "SELECT iddb1,fullname,age,gender,healthrecord,headpicture FROM database.db1 where fullname = #myname ";
SelectCommand.CommandText = mySQL;
SelectCommand.Parameters.AddWithValue("#myname", myname);
SelectCommand.Connection = myConn;
MySqlDataReader myReader;
myConn.Open();
myReader = SelectCommand.ExecuteReader();
while (myReader.Read())
{
Int16 ID = myReader.GetInt16(0);
string FName = myReader.GetString(1);
Int16 FAge = myReader.GetInt16(2);
string FGender = myReader.GetString(3);
string FRecord = myReader.GetString(4);
ShowID.Text = ID.ToString();
ShowName.Text = FName.ToString();
ShowAge.Text = FAge.ToString();
ShowGender.Text = FGender.ToString();
ShowRecord.Text = FRecord.ToString();
byte[] imgg = (byte[])(myReader["headpicture"]);
if (imgg == null)
Image1.ImageUrl = null;
else {
MemoryStream mstream = new MemoryStream(imgg);
// Image1.ImageURL = System.Drawing.Image.FromStream(mstream);
}
}
myConn.Close();
}
catch (Exception ex)
{
MessageBoxShow(this, ex.Message);
}
}
Here come with the problem and i marked it with \\
Try this ,
Image1.ImageURL = "data:image/jpeg;base64,"+Convert.ToBase64String(imgg);
I want to retrieve an image from an Oracle database to an Image control in asp.net. I tried but it's not working.
This is the code used for inserting image into database:
protected void btnUpload_Click(object sender, EventArgs e)
{
int imgLength = 0;
string imgContentType = null;
string imgFileName = null;
Stream imgStream = FileUpload.PostedFile.InputStream;
imgLength = FileUpload.PostedFile.ContentLength;
imgContentType = FileUpload.PostedFile.ContentType;
imgFileName = FileUpload.PostedFile.FileName;
if (imgContentType == "image/jpeg" || imgContentType == "image/gif" ||
imgContentType == "image/pjpeg"
|| imgContentType == "image/bmp")
{
OracleConnection DbConnection = new OracleConnection(con1);
DbConnection.Open();
FileStream fls;
fls = new FileStream(#imgFileName, FileMode.Open, FileAccess.Read);
byte[] blob = new byte[fls.Length];
fls.Read(blob, 0, System.Convert.ToInt32(fls.Length));
fls.Close();
string query = "insert into image(id,name,photo) values(1,'" + imgFileName + "'," + " :BlobParameter )";
// Establish a new OracleCommand
OracleCommand cmd = new OracleCommand();
cmd.CommandText = query;
cmd.Connection = DbConnection;
cmd.CommandType = CommandType.Text;
System.Data.OracleClient.OracleParameter paramImage = new System.Data.OracleClient.OracleParameter("image",
Oracle.DataAccess.Client.OracleDbType.Blob);
paramImage.ParameterName = "BlobParameter";
paramImage.Value = blob;
paramImage.Direction = ParameterDirection.Input;
cmd.Parameters.Add(paramImage);
cmd.ExecuteNonQuery();
}
Table:
Id Name Photo
1 C:\\user\pictures\animal.jpeg (BLOB)
Below is the code used to retrieve the image into an image control but this code is not working.
For the past two days I've been struggling with this
void GetImagesFromDatabase()
{
try
{
OracleConnection DbConnection = new OracleConnection(con1);
DbConnection.Open();
OracleCommand cmd = new OracleCommand("Select name,photo from Image", DbConnection);
OracleDataReader oda = cmd.ExecuteReader();
while (oda.Read())
{
string path = oda[0].ToString();
img.ImageUrl = path;
if(oda.GetValue(1).ToString() !=""){
FileStream fls;
fls = new FileStream(#path, FileMode.Open, FileAccess.Read);
byte[] blob = new byte[fls.Length];
fls.Read(blob, 0, System.Convert.ToInt32(fls.Length));
fls.Close();
MemoryStream memStream = new MemoryStream(blob);
img.ImageUrl = oda[2].ToString();
}
}
}
catch (Exception ex)
{
}
}
Any ideas? Thanks in advance
maybe this code can help you:
public Image byteArrayToImage(byte[] byteArrayIn)
{
MemoryStream ms = new MemoryStream(byteArrayIn);
Image returnImage = Image.FromStream(ms);
return returnImage;
}
i'm trying to load images from database to a PictureBox. I use these following codes in order to load them to my picture. I've written some code but don't know what I should do for continuing.
Any help will be appreciated.
private void button1_Click(object sender, EventArgs e)
{
sql = new SqlConnection(#"Data Source=PC-PC\PC;Initial Catalog=Test;Integrated Security=True");
cmd = new SqlCommand();
cmd.Connection = sql;
cmd.CommandText = ("select Image from Entry where EntryID =#EntryID");
cmd.Parameters.AddWithValue("#EntryID", Convert.ToInt32(textBox1.Text));
}
Continue with something like this in the button1_Click:
// Your code first, here.
var da = new SqlDataAdapter(cmd);
var ds = new DataSet();
da.Fill(ds, "Images");
int count = ds.Tables["Images"].Rows.Count;
if (count > 0)
{
var data = (Byte[])ds.Tables["Images"].Rows[count - 1]["Image"];
var stream = new MemoryStream(data);
pictureBox1.Image = Image.FromStream(stream);
}
Assuming we have a simple database with a table called BLOBTest:
CREATE TABLE BLOBTest
(
BLOBID INT IDENTITY NOT NULL,
BLOBData IMAGE NOT NULL
)
We could retrieve the image to code in the following way:
try
{
SqlConnection cn = new SqlConnection(strCn);
cn.Open();
//Retrieve BLOB from database into DataSet.
SqlCommand cmd = new SqlCommand("SELECT BLOBID, BLOBData FROM BLOBTest ORDER BY BLOBID", cn);
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataSet ds = new DataSet();
da.Fill(ds, "BLOBTest");
int c = ds.Tables["BLOBTest"].Rows.Count;
if(c>0)
{ //BLOB is read into Byte array, then used to construct MemoryStream,
//then passed to PictureBox.
Byte[] byteBLOBData = new Byte[0];
byteBLOBData = (Byte[])(ds.Tables["BLOBTest"].Rows[c - 1]["BLOBData"]);
MemoryStream stmBLOBData = new MemoryStream(byteBLOBData);
pictureBox1.Image= Image.FromStream(stmBLOBData);
}
cn.Close();
}
catch(Exception ex)
{MessageBox.Show(ex.Message);}
This code retrieves the rows from the BLOBTest table in the database into a DataSet, copies the most recently added image into a Byte array and then into a MemoryStream object, and then loads the MemoryStream into the Image property of the PictureBox control.
Full reference guide:
http://support.microsoft.com/kb/317701
private void btnShowImage_Click(object sender, EventArgs e)
{
string constr = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=.\\PIS(ACU).mdb;";
Con = new OleDbConnection(#constr);
Con.Open();
Com = new OleDbCommand();
Com.Connection = Con;
Com.CommandText = "SELECT Photo FROM PatientImages WHERE Patient_Id = " + val + " ";
OleDbDataReader reader = Com.ExecuteReader();
if (reader.Read())
{
byte[] picbyte = reader["Photo"] as byte[] ?? null;
if (picbyte != null)
{
MemoryStream mstream = new MemoryStream(picbyte);
pictureBoxForImage.Image = System.Drawing.Image.FromStream(mstream);
{
System.Drawing.Bitmap bmp = new System.Drawing.Bitmap(mstream);
}
}
HERE IS A TOTAL ANOTHER WAY TO DO SO:
You can simply convert the Image to Text before saving it into DataBase and the then convert it back to the Image after reading it:
public string ImageToStringFucntion(Image img)
{
try
{
using (MemoryStream ms = new MemoryStream())
{
img.Save(ms, System.Drawing.Imaging.ImageFormat.Png);
byte[] imgBytes = ms.ToArray();
string FinalText = Convert.ToBase64String(imgBytes, 0 , imgBytes.Length);
return FinalText;
}
}
catch
{
return null;
}
}
Now you can Insert or Update your Database...
Now Let's consider you want it back:
public Image StringToImage_(string input_)
{
try
{
byte[] imgBytes = Convert.FromBase64String(input_);
using (MemoryStream ms = new MemoryStream(imgBytes))
{
Image img = Image.FromStream(ms, true);
return img;
}
}
catch (Exception ex)
{
return null;
}
}
Now you can do as follow:
// Considering you have already pulled your data
// from database and set it in a DataSet called 'ds',
// and you picture is on the field number [1] of your DataRow
pictureBox1.Image = StringToImage_(ds.Table[0].Rows[0][1].ToString());
I have binary data of an image in my database, and I want to display it in an image control in ASP.NET. How? If it is impossible, please find another way to save it in the database and display it in an image control.
Create a regular HTML img element like so:
<img runat="server" id="image" />
And in code behind do this:
image.src = "data:image/png;base64," + Convert.ToBase64String(imageBytes);
Where imageBytes is a byte[].
You are done. The image will be displayed.
Most likely the image is being stored as a byte array in the database. If so, then you can use this:
public static System.Drawing.Image ByteArrayToImage(byte[] bArray)
{
if (bArray == null)
return null;
System.Drawing.Image newImage;
try
{
using (MemoryStream ms = new MemoryStream(bArray, 0, bArray.Length))
{
ms.Write(bArray, 0, bArray.Length);
newImage = System.Drawing.Image.FromStream(ms, true);
}
}
catch (Exception ex)
{
newImage = null;
//Log an error here
}
return newImage;
}
public Byte[] Ret_image(Int32 id)
{
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "select * from tbimage where imageid=#id";
cmd.Connection = con;
cmd.Parameters.Add("#id", SqlDbType.Int).Value = id;
SqlDataReader dr = cmd.ExecuteReader();
dr.Read();
Byte[] ar = (Byte[])(dr[1]);
dr.Close();
cmd.Dispose();
return ar;
}
protected void Button2_Click(object sender, EventArgs e)
{
Byte[] ar = Ret_image(Convert.ToInt32(TextBox2.Text));
String st = Server.MapPath("abc.jpg");
FileStream fs = new FileStream(st, FileMode.Create, FileAccess.Write);
fs.Write(ar, 0, ar.Length);
fs.Close();
Image1.ImageUrl = "abc.jpg";
}
Use this event for the button click to retrieve image and call the Ret_Image method here.
In a generic handler (.ashx):
public class ImageHandler : IHttpHandler
{
public void ProcessRequest(HttpContext context)
{
if(!string.IsNullOrEmpty(context.Request.QueryString["ImageId"]))
{
try
{
string ImageId = context.Request.QueryString["ImageId"].ToString();
ImageDataModel idm = new ImageDataModel();
byte[] ImageData = idm.getImageData(ImageId);
context.Response.ContentType = "image/JPEG";
context.Response.OutputStream.Write(ImageData, 0, ImageData.Length);
}
catch(Exception ex){}
}
}
}
SqlConnection con = new SqlConnection();
string _path;
Using SYstem.IO;
Using System.Data.SQLClient;
//convert Image to binary and save in DB
private void button1_Click(object sender, EventArgs e)
{
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
_path = openFileDialog1.FileName;
InsertInSQL(_path);
}
}
private void InsertInSQL(string _path)
{
con.ConnectionString = Pic.Properties.Settings.Default.ConnectionS;
string strQ = "insert into dbo.PicTBL(Pic)values(#p)";
SqlCommand command = new SqlCommand(strQ,con);
command.Parameters.AddWithValue("#p",ImageToBinary(_path));
con.Open();
command.ExecuteNonQuery();
con.Close();
}
public static byte[] ImageToBinary(string _path)
{
FileStream fS = new FileStream(_path, FileMode.Open, FileAccess.Read);
byte[] b = new byte[fS.Length];
fS.Read(b, 0, (int)fS.Length);
fS.Close();
return b;
}
//Convert Binary to imge and save in a folder
private void button1_Click_1(object sender, EventArgs e)
{
DataTable dt = Rimage();
foreach (DataRow row in dt.Rows)
{
byte[] b = (byte[])row["Pic"];
Image img = BinaryToImage(b);
img.Save("D:\\NewFolder\\" + row["ID"].ToString() + ".jpg");
}
}
private Image BinaryToImage(byte[] b)
{
if (b == null)
return null;
MemoryStream memStream = new MemoryStream();
memStream.Write(b, 0, b.Length);
return Image.FromStream(memStream);
}
private DataTable Rimage()
{
con.ConnectionString = Pic.Properties.Settings.Default.ConnectionS;
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "select * from dbo.PicTBL";
cmd.Connection = con;
SqlDataAdapter adp = new SqlDataAdapter(cmd);
DataTable dt = new DataTable();
con.Open();
adp.Fill(dt);
return dt;
}