Check if ipaddress have match - c#

I have a xml with many Ip addresses. Like this:
<settings>
<ipaddresses>
<ipaddress>1288</ipaddress>
<ipaddress>1999</ipaddress>
<ipaddress>555</ipaddress>
<ipaddress>88888</ipaddress>
</ipaddresses>
</settings>
And Now I want to check if one of the Ip Addresses match the Ip address of a pc. So that that user is allowed to see the product.
If the one of the Ipaddresses in the XML not match the Ipaddress of the pc, then a error message has to return. I try it like this:
XDocument doc = XDocument.Parse(product.AuthenticationSettings);
var IpAddress = doc.Descendants("ipaddress");
foreach (var IpAddresses in IpAddress)
{
bool IppAddressMatch = false;
if (GetClientIp() == IpAddresses.Value)
{
IppAddressMatch = true;
}
if (GetClientIp() != IpAddresses.Value)
{
// log message
return Content("<h1>403 Forbidden</h1>", "text/html");
}
}
But I get this error:
Error 6 Warning as Error: The variable 'IppAddressMatch' is assigned
but its value is never used

The code should probably be something like:
XDocument doc = XDocument.Parse(product.AuthenticationSettings);
var IpAddress = doc.Descendants("ipaddress");
bool IppAddressMatch = false;
foreach (var IpAddresses in IpAddress)
{
if (GetClientIp() == IpAddresses.Value)
{
IppAddressMatch = true;
break;
}
}
if (!IppAddressMatch)
{
// log message
return Content("<h1>403 Forbidden</h1>", "text/html");
}
The point is: if the address of the PC is contained in the XML, then everything is OK, but if the address of the PC isn't contained in the XML, then error. Clearly when you find one matching address, you can stop looking for matching addresses (the break)

You have two option to solve this:
Remove the IppAddressMatch variable, because you are not using it.
Change the "treat warnings as errors" option. See Warning as error - How to rid these

Related

Fast searching an Outlook Address list

I want to search an huge address list from outlook for an AddressEntry by the email address. Searching by name is not problem, as you can write:
Microsoft.Office.Interop.Outlook.AddressEntry = AddressEntries[Name];
But I want to find the Entry by its email. This code is working but extremely slow:
public static string GetUserDataByEmailAddress(string EmailAddress)
{
Microsoft.Office.Interop.Outlook.Application OLApp = null;
bool OutlookWasRunning = false;
string UserName = string.Empty;
if (System.Diagnostics.Process.GetProcessesByName("OUTLOOK").Count() > 0)
{
OLApp = System.Runtime.InteropServices.Marshal.GetActiveObject("Outlook.Application") as Microsoft.Office.Interop.Outlook.Application;
OutlookWasRunning = true;
}
else
{
OLApp = new Microsoft.Office.Interop.Outlook.Application();
Microsoft.Office.Interop.Outlook.NameSpace nameSpace = OLApp.GetNamespace("MAPI");
nameSpace.Logon("", "", System.Reflection.Missing.Value, System.Reflection.Missing.Value);
nameSpace = null;
OutlookWasRunning = false;
}
Microsoft.Office.Interop.Outlook.AddressLists GALs = null;
GALs = OLApp.Session.AddressLists;
if (GALs == null) { throw new System.Exception("ERROR: Unable to get address book collection from MS Outlook!"); }
Microsoft.Office.Interop.Outlook.AddressList gal = null;
gal = GALs["Globale Adressliste"];
if (gal == null) { throw new System.Exception("ERROR: Unable to get address book 'Global Address List' from MS Outlook!"); }
foreach (Microsoft.Office.Interop.Outlook.AddressEntry ent in gal.AddressEntries)
{
if(ent.Address == EmailAddress) { UserName = ent.Name; }
}
if (!OutlookWasRunning) { OLApp.Quit(); }
return UserName;
}
Ok, but this way works very slow. Now, I tried to use the AddressEntries as an IEnumeratable to do this:
var output = from a in gal.AddressEntries.AsQueryable() where (a as Microsoft.Office.Interop.Outlook.AddressEntry).Address == EmailAddress select a;
Doing that, I get the error:
Severity Code Description Project File Line Suppression State Error CS1936 Could not find an implementation of the query pattern for source type 'IQueryable'. 'Where' not found.
Does anybody know an fast way to search for the correct AddressEntry?
Regards,
Jan
Do not loop through all items in a container - some containers can contain tens of thousands of entries or more.
You can use Namespace.CreateRecipient / Recipient.Resolve in OOM - that will resolve a name (or address) against all containers. This is equivalent to typing a name in the To edit box in Outlook and hitting Ctrl+K.
If you want to resolve against a particular container (e.g. "All Users" GAL container), you would need to use Extended MAPI (C++ or Delphi only). You can use Redemption (I am its author - any language) - it exposes RDOSession.AddressBook.ResolveName / ResolveNameEx and RDOAddresList.ResolveName / ResolveNameEx .
Keep in mind that resolving against a particular container (PR_ANR resolution in MAPI) might not work if using an SMTP address (GAL limitation).

Why email is not sending even if the path is working

This is a piece of code for genrating mail which works until I didnt attach path as a parameter . the thing is if I attach the path it didnt throw any error(no logs). Just the page started being unresponsive,and debugger not even jump to next line.
any help wil help me to understand my mistake . Thanks
public ActionResult Mailsending(string list)
{
try
{
string strIdeas = string.Empty;
string Certpath = System.Configuration.ConfigurationManager.AppSettings["UploadPath"];
List<int> list = new List<int>();
List<string> pramAttachment = new List<string>();
pramAttachment.Add(Server.MapPath(Certpath) + "MyPdf.pdf"); ///Path of the generated pdf.
Submitidlist = new CommonBL().GetSubmiidListForGenerateMail();
new CommonBL().UpdateIsGenerateStatus(ideaidlist, UserID);
foreach (var item in ideaidlist)
{
strIdeas = strIdeas + item.ToString() + ",";
}
GenerateMyPDF(list); //Here pdf is generating
string path = GenerateMail(strIdeas.TrimEnd(','));
if (path != string.Empty)
{
new CommonBL().AddGenerateImagePath(path, UserId);
new MailSender().SendMail((int)eMailType.GenerateMail, null, pramAttachment); // here path is added as parameter,and after this debugger not jump out of this scope.
}
return Json("Mail generated Successfully."); ///no message showing
}
catch (Exception ex)
{
return Json("Error");
}
}
Edit :
public class MailSender : IDisposable
{
public bool SendMail(short mailId, List<KeyValuePair<string, string>> parameters, List<string> attachmentsPath = null);
}
Possibly still leaving lock on the generated PDF, so MailSender is not able to access it due to that exclusive lock. Can you send emails with files previously generated?
adding a point which apparently is also an answer of this question, is :
After debugging whole code, I found that my smtp server is not allowing to send me a mail, so even if the above code is right, it shows processing.
So if anyone is working with above code will work fine.
An update : Now it works fine after configuring my mail service from control panel. So if any one wants to take reference from this can go ahead . the code is fine .

parse regex from array

I am trying to parse out IP addresses from Outlook email headers. I've started writing some stuff in C# (because that is the example I was leveraging) and have come up with something close.
I can split the headers with the string lines[] = Regex.Split(headers, #"\r\n"); command okay, but when I try to iterate through the lines[] array, my regex for IP address fails and does not store the value in a second array:
Code:
private void button1_Click(object sender, EventArgs e)
{
// use a string constant to define the mapi property
string PidTagTransportMessageHeaders = #"http://schemas.microsoft.com/mapi/proptag/0x007D001E";
string mypattern = #"(#{1,3}\.)(#{1,3}\.)([0-9]{1,3}\.)([0-9]{1,3})";
// string[] ip = Regex.Split(lines[i], (#"(\(|\[)(#{1,3}\.)(#{1,3}\.)([0-9]{1,3}\.)([0-9]{1,3})(\)|\])"));
// get a handle on the current message
Outlook.MailItem message = (Outlook.MailItem)this.OutlookItem;
// use the property accessor to retreive the header
string headers = string.Empty;
try
{
headers = (string)message.PropertyAccessor.GetProperty(PidTagTransportMessageHeaders);
}
catch {
}
// if getting the internet headers is successful, put into textbox
string[] lines = Regex.Split(headers, "\r\n");
Regex regexObj = new Regex(mypattern);
for (int i = 0; i < lines.Length; i++)
{
MatchCollection matches = regexObj.Matches(lines[i]);
}
//eventually write the found IP array into textBox1.Text
textBox1.Text = headers;
}
}
}
Any help or suggestions?
Change your #'s to \d's:
string mypattern = #"(\d{1,3}\.)(\d{1,3}\.)(\d{1,3}\.)(\d{1,3})";
Note that a more accurate IPv4 address capture regular expression would be something like:
\b(?:(?:25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])\.){3}(?:25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])\b
...or at least add word boundaries...
\b(\d{1,3}\.)(\d{1,3}\.)(\d{1,3}\.)(\d{1,3})\b
For a simple IPv6 (standard) I like:
(?<![:.\w])(?:[A-F0-9]{1,4}:){7}[A-F0-9]{1,4}(?![:.\w])
IPAddress.Parse Method do not reinvent the wheel.
If you're trying to match off IPv4, then try this beast, should be fairly close to what an actual IPv4 can be, the enclosing \b mean beginning and end of a word, so you should be able to remove those and tweak to your heart's content to get the ip based on your header format
\b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b

Get closest Domain Controller in current AD site without hard coding information

For instances when Active Directory takes too long to replicate data between sites, I need to ensure that the local AD replica contains the most up to date information.
How can I get a list of DomainControllers for the current site?
I haven't found anything on Codeproject or on StackOverflow
Going to all this trouble is probably wasted effort. Unless you are experiencing issues with the built in logic for finding a domain controller you should just go with the built in method that returns one. According to Microsoft it automatically tries to find the closes one: http://technet.microsoft.com/en-us/library/cc978016.aspx.
Just use the static DomainController.FindOne method and pass in your directorycontext.
Update
Alright, try the code below, let me know how it works for you. It pings each, returns the roundtrip time, if -1 (no connection) it skips it. Flags PDC status if present. Orders by PDC status, followed by ping round trip.
static void Main(string[] args)
{
var dcsInOrder = (from DomainController c in Domain.GetCurrentDomain().DomainControllers
let responseTime = Pinger(c.Name)
where responseTime >=0
let pdcStatus = c.Roles.Contains(ActiveDirectoryRole.PdcRole)
orderby pdcStatus, responseTime
select new {DC = c, ResponseTime = responseTime}
).ToList();
foreach (var dc in dcsInOrder)
{
System.Console.WriteLine(dc.DC.Name + " - " + dc.ResponseTime);
}
System.Console.ReadLine();
}
private static int Pinger(string address)
{
Ping p = new Ping();
try
{
PingReply reply = p.Send(address, 3000);
if (reply.Status == IPStatus.Success) return (int)reply.RoundtripTime;
}
catch { }
return -1;
}
First, I'll answer the question that you actually asked:
System.DirectoryServices.ActiveDirectory.ActiveDirectorySite.GetComputerSite().Servers
But it seems like you're asking how to make sure that you're talking to the closest domain controller possible. Windows doesn't exactly provide this functionality, the best it will do is give you a domain controller in the same site that the code is running from.
I think the first thing to check is that you have your sites and subnets configured correctly. Run Active Directory Sites and Services, and make sure that subnets and domain controllers are assigned to the correct sites.
This MSDN page (and the Technet article in Peter's answer) says that you must be searching by the DNS name for the DC Locator to attempt to find a DC in the current site. I don't know if the Name property of the Domain class is the DNS domain name.
I have to assume that DomainController.FindOne is a wrapper for DsGetDcName. At that link, you can find how to turn on tracing for that function. You can use this if you still have problems, or maybe you should just PInvoke this function.
Here is a code sample that has no hard coding of DCs. Comments and criticism are welcome.
/// <summary>
/// For best results ensure all hosts are pingable, and turned on.
/// </summary>
/// <returns>An ordered list of DCs with the PDCE first</returns>
static LinkedList<DomainController> GetNearbyDCs()
{
LinkedList<DomainController> preferredDCs = new LinkedList<DomainController>();
List<string> TestedDCs = new List<string>();
using (var mysite = ActiveDirectorySite.GetComputerSite())
{
using (var currentDomain = Domain.GetCurrentDomain())
{
DirectoryContext dctx = new DirectoryContext(DirectoryContextType.Domain, currentDomain.Name);
var listOfDCs = DomainController.FindAll(dctx, mysite.Name);
foreach (DomainController item in listOfDCs)
{
Console.WriteLine(item.Name );
if (IsConnected(item.IPAddress))
{
// Enumerating "Roles" will cause the object to bind to the server
ActiveDirectoryRoleCollection rollColl = item.Roles;
if (rollColl.Count > 0)
{
foreach (ActiveDirectoryRole roleItem in rollColl)
{
if (!TestedDCs.Contains(item.Name))
{
TestedDCs.Add(item.Name);
if (roleItem == ActiveDirectoryRole.PdcRole)
{
preferredDCs.AddFirst(item);
break;
}
else
{
if (preferredDCs.Count > 0)
{
var tmp = preferredDCs.First;
preferredDCs.AddBefore(tmp, item);
}
else
{
preferredDCs.AddFirst(item);
}
break;
}
}
}
}
else
{
// The DC exists but has no roles
TestedDCs.Add(item.Name);
if (preferredDCs.Count > 0)
{
var tmp = preferredDCs.First;
preferredDCs.AddBefore(tmp, item);
}
else
{
preferredDCs.AddFirst(item);
}
}
}
else
{
preferredDCs.AddLast(item);
}
}
}
}
return preferredDCs;
}
static bool IsConnected(string hostToPing)
{
string pingurl = string.Format("{0}", hostToPing);
string host = pingurl;
bool result = false;
Ping p = new Ping();
try
{
PingReply reply = p.Send(host, 3000);
if (reply.Status == IPStatus.Success)
return true;
}
catch { }
return result;
}
Here's my approach using powershell but I'm sure it's a simple implementation in c#, etc. If DHCP is setup correctly, the Primary DNS server in your subnet should be the closest Domain Controller. So the following code should grab the first DNS IP and resolve it to the hostname of the closest DC. This doesn't require RSAT or credentials and contains no specific properties of the current domain.
$NetItems = #(Get-WmiObject -Class Win32_NetworkAdapterConfiguration -Filter "IPEnabled = 'True'" -ComputerName $env:COMPUTERNAME)
foreach ($objItem in $NetItems)
{
if ($objItem.{DNSServerSearchOrder}.Count -ge 1)
{
$PrimaryDNS = $objItem.DNSServerSearchOrder[0]
$domain = $objItem.DNSDomain
break
}
}
[System.Net.Dns]::GetHostbyAddress($PrimaryDNS).hostname -replace ".$($domain)",""

How to get a user's client IP address in ASP.NET?

We have Request.UserHostAddress to get the IP address in ASP.NET, but this is usually the user's ISP's IP address, not exactly the user's machine IP address who for example clicked a link. How can I get the real IP Address?
For example, in a Stack Overflow user profile it is: "Last account activity: 4 hours ago from 86.123.127.8", but my machine IP address is a bit different. How does Stack Overflow get this address?
In some web systems there is an IP address check for some purposes. For example, with a certain IP address, for every 24 hours can the user just have only 5 clicks on download links? This IP address should be unique, not for an ISP that has a huge range of clients or Internet users.
Did I understand well?
Often you will want to know the IP address of someone visiting your website. While ASP.NET has several ways to do this one of the best ways we've seen is by using the "HTTP_X_FORWARDED_FOR" of the ServerVariables collection.
Here's why...
Sometimes your visitors are behind either a proxy server or a router and the standard Request.UserHostAddress only captures the IP address of the proxy server or router. When this is the case the user's IP address is then stored in the server variable ("HTTP_X_FORWARDED_FOR").
So what we want to do is first check "HTTP_X_FORWARDED_FOR" and if that is empty we then simply return ServerVariables("REMOTE_ADDR").
While this method is not foolproof, it can lead to better results. Below is the ASP.NET code in VB.NET, taken from James Crowley's blog post "Gotcha: HTTP_X_FORWARDED_FOR returns multiple IP addresses"
C#
protected string GetIPAddress()
{
System.Web.HttpContext context = System.Web.HttpContext.Current;
string ipAddress = context.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrEmpty(ipAddress))
{
string[] addresses = ipAddress.Split(',');
if (addresses.Length != 0)
{
return addresses[0];
}
}
return context.Request.ServerVariables["REMOTE_ADDR"];
}
VB.NET
Public Shared Function GetIPAddress() As String
Dim context As System.Web.HttpContext = System.Web.HttpContext.Current
Dim sIPAddress As String = context.Request.ServerVariables("HTTP_X_FORWARDED_FOR")
If String.IsNullOrEmpty(sIPAddress) Then
Return context.Request.ServerVariables("REMOTE_ADDR")
Else
Dim ipArray As String() = sIPAddress.Split(New [Char]() {","c})
Return ipArray(0)
End If
End Function
As others have said you can't do what you are asking. If you describe the problem you are trying to solve maybe someone can help?
E.g.
are you trying to uniquely identify your users?
Could you use a cookie, or the session ID perhaps instead of the IP address?
Edit The address you see on the server shouldn't be the ISP's address, as you say that would be a huge range. The address for a home user on broadband will be the address at their router, so every device inside the house will appear on the outside to be the same, but the router uses NAT to ensure that traffic is routed to each device correctly. For users accessing from an office environment the address may well be the same for all users. Sites that use IP address for ID run the risk of getting it very wrong - the examples you give are good ones and they often fail. For example my office is in the UK, the breakout point (where I "appear" to be on the internet) is in another country where our main IT facility is, so from my office my IP address appears to be not in the UK. For this reason I can't access UK only web content, such as the BBC iPlayer). At any given time there would be hundreds, or even thousands, of people at my company who appear to be accessing the web from the same IP address.
When you are writing server code you can never be sure what the IP address you see is referring to. Some users like it this way. Some people deliberately use a proxy or VPN to further confound you.
When you say your machine address is different to the IP address shown on StackOverflow, how are you finding out your machine address? If you are just looking locally using ipconfig or something like that I would expect it to be different for the reasons I outlined above. If you want to double check what the outside world thinks have a look at whatismyipaddress.com/.
This Wikipedia link on NAT will provide you some background on this.
UPDATE:
Thanks to Bruno Lopes. If several ip addresses could come then need to use this method:
private string GetUserIP()
{
string ipList = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrEmpty(ipList))
{
return ipList.Split(',')[0];
}
return Request.ServerVariables["REMOTE_ADDR"];
}
If is c# see this way, is very simple
string clientIp = (Request.ServerVariables["HTTP_X_FORWARDED_FOR"] ??
Request.ServerVariables["REMOTE_ADDR"]).Split(',')[0].Trim();
What else do you consider the user IP address? If you want the IP address of the network adapter, I'm afraid there's no possible way to do it in a Web app. If your user is behind NAT or other stuff, you can't get the IP either.
Update: While there are Web sites that use IP to limit the user (like rapidshare), they don't work correctly in NAT environments.
I think I should share my experience with you all. Well I see in some situations REMOTE_ADDR will NOT get you what you are looking for. For instance, if you have a Load Balancer behind the scene and if you are trying to get the Client's IP then you will be in trouble. I checked it with my IP masking software plus I also checked with my colleagues being in different continents. So here is my solution.
When I want to know the IP of a client, I try to pick every possible evidence so I could determine if they are unique:
Here I found another sever-var that could help you all if you want to get exact IP of the client side. so I am using : HTTP_X_CLUSTER_CLIENT_IP
HTTP_X_CLUSTER_CLIENT_IP always gets you the exact IP of the client. In any case if its not giving you the value, you should then look for HTTP_X_FORWARDED_FOR as it is the second best candidate to get you the client IP and then the REMOTE_ADDR var which may or may not return you the IP but to me having all these three is what I find the best thing to monitor them.
I hope this helps some guys.
You can use:
System.Net.Dns.GetHostEntry(System.Net.Dns.GetHostName()).AddressList.GetValue(0).ToString();
All of the responses so far take into account the non-standardized, but very common, X-Forwarded-For header. There is a standardized Forwarded header which is a little more difficult to parse out. Some examples are as follows:
Forwarded: for="_gazonk"
Forwarded: For="[2001:db8:cafe::17]:4711"
Forwarded: for=192.0.2.60;proto=http;by=203.0.113.43
Forwarded: for=192.0.2.43, for=198.51.100.17
I have written a class that takes both of these headers into account when determining a client's IP address.
using System;
using System.Web;
namespace Util
{
public static class IP
{
public static string GetIPAddress()
{
return GetIPAddress(new HttpRequestWrapper(HttpContext.Current.Request));
}
internal static string GetIPAddress(HttpRequestBase request)
{
// handle standardized 'Forwarded' header
string forwarded = request.Headers["Forwarded"];
if (!String.IsNullOrEmpty(forwarded))
{
foreach (string segment in forwarded.Split(',')[0].Split(';'))
{
string[] pair = segment.Trim().Split('=');
if (pair.Length == 2 && pair[0].Equals("for", StringComparison.OrdinalIgnoreCase))
{
string ip = pair[1].Trim('"');
// IPv6 addresses are always enclosed in square brackets
int left = ip.IndexOf('['), right = ip.IndexOf(']');
if (left == 0 && right > 0)
{
return ip.Substring(1, right - 1);
}
// strip port of IPv4 addresses
int colon = ip.IndexOf(':');
if (colon != -1)
{
return ip.Substring(0, colon);
}
// this will return IPv4, "unknown", and obfuscated addresses
return ip;
}
}
}
// handle non-standardized 'X-Forwarded-For' header
string xForwardedFor = request.Headers["X-Forwarded-For"];
if (!String.IsNullOrEmpty(xForwardedFor))
{
return xForwardedFor.Split(',')[0];
}
return request.UserHostAddress;
}
}
}
Below are some unit tests that I used to validate my solution:
using System.Collections.Specialized;
using System.Web;
using Microsoft.VisualStudio.TestTools.UnitTesting;
namespace UtilTests
{
[TestClass]
public class IPTests
{
[TestMethod]
public void TestForwardedObfuscated()
{
var request = new HttpRequestMock("for=\"_gazonk\"");
Assert.AreEqual("_gazonk", Util.IP.GetIPAddress(request));
}
[TestMethod]
public void TestForwardedIPv6()
{
var request = new HttpRequestMock("For=\"[2001:db8:cafe::17]:4711\"");
Assert.AreEqual("2001:db8:cafe::17", Util.IP.GetIPAddress(request));
}
[TestMethod]
public void TestForwardedIPv4()
{
var request = new HttpRequestMock("for=192.0.2.60;proto=http;by=203.0.113.43");
Assert.AreEqual("192.0.2.60", Util.IP.GetIPAddress(request));
}
[TestMethod]
public void TestForwardedIPv4WithPort()
{
var request = new HttpRequestMock("for=192.0.2.60:443;proto=http;by=203.0.113.43");
Assert.AreEqual("192.0.2.60", Util.IP.GetIPAddress(request));
}
[TestMethod]
public void TestForwardedMultiple()
{
var request = new HttpRequestMock("for=192.0.2.43, for=198.51.100.17");
Assert.AreEqual("192.0.2.43", Util.IP.GetIPAddress(request));
}
}
public class HttpRequestMock : HttpRequestBase
{
private NameValueCollection headers = new NameValueCollection();
public HttpRequestMock(string forwarded)
{
headers["Forwarded"] = forwarded;
}
public override NameValueCollection Headers
{
get { return this.headers; }
}
}
}
IP addresses are part of the Network layer in the "seven-layer stack". The Network layer can do whatever it wants to do with the IP address. That's what happens with a proxy server, NAT, relay, or whatever.
The Application layer should not depend on the IP address in any way. In particular, an IP Address is not meant to be an identifier of anything other than the idenfitier of one end of a network connection. As soon as a connection is closed, you should expect the IP address (of the same user) to change.
If you are using CloudFlare,
you can try this Extension Method:
public static class IPhelper
{
public static string GetIPAddress(this HttpRequest Request)
{
if (Request.Headers["CF-CONNECTING-IP"] != null) return Request.Headers["CF-CONNECTING-IP"].ToString();
if (Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null) return Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
return Request.UserHostAddress;
}
}
then
string IPAddress = Request.GetIPAddress();
string IP = HttpContext.Current.Request.Params["HTTP_CLIENT_IP"] ?? HttpContext.Current.Request.UserHostAddress;
What you can do is store the router IP of your user and also the forwarded IP and try to make it reliable using both the IPs [External Public and Internal Private]. But again after some days client may be assigned new internal IP from router but it will be more reliable.
Combining the answers from #Tony and #mangokun, I have created the following extension method:
public static class RequestExtensions
{
public static string GetIPAddress(this HttpRequest Request)
{
if (Request.Headers["CF-CONNECTING-IP"] != null) return Request.Headers["CF-CONNECTING-IP"].ToString();
if (Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
string ipAddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrEmpty(ipAddress))
{
string[] addresses = ipAddress.Split(',');
if (addresses.Length != 0)
{
return addresses[0];
}
}
}
return Request.UserHostAddress;
}
}
public static class Utility
{
public static string GetClientIP(this System.Web.UI.Page page)
{
string _ipList = page.Request.Headers["CF-CONNECTING-IP"].ToString();
if (!string.IsNullOrWhiteSpace(_ipList))
{
return _ipList.Split(',')[0].Trim();
}
else
{
_ipList = page.Request.ServerVariables["HTTP_X_CLUSTER_CLIENT_IP"];
if (!string.IsNullOrWhiteSpace(_ipList))
{
return _ipList.Split(',')[0].Trim();
}
else
{
_ipList = page.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrWhiteSpace(_ipList))
{
return _ipList.Split(',')[0].Trim();
}
else
{
return page.Request.ServerVariables["REMOTE_ADDR"].ToString().Trim();
}
}
}
}
}
Use;
string _ip = this.GetClientIP();
use in ashx file
public string getIP(HttpContext c)
{
string ips = c.Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (!string.IsNullOrEmpty(ips))
{
return ips.Split(',')[0];
}
return c.Request.ServerVariables["REMOTE_ADDR"];
}
In NuGet package install Microsoft.AspNetCore.HttpOverrides
Then try:
public class ClientDeviceInfo
{
private readonly IHttpContextAccessor httpAccessor;
public ClientDeviceInfo(IHttpContextAccessor httpAccessor)
{
this.httpAccessor = httpAccessor;
}
public string GetClientLocalIpAddress()
{
return httpAccessor.HttpContext.Connection.LocalIpAddress.ToString();
}
public string GetClientRemoteIpAddress()
{
return httpAccessor.HttpContext.Connection.RemoteIpAddress.ToString();
}
public string GetClientLocalPort()
{
return httpAccessor.HttpContext.Connection.LocalPort.ToString();
}
public string GetClientRemotePort()
{
return httpAccessor.HttpContext.Connection.RemotePort.ToString();
}
}
Its easy.Try it:
var remoteIpAddress = Request.HttpContext.Connection.RemoteIpAddress;
just it :))
use this
Dns.GetHostEntry(Dns.GetHostName())
Hello guys Most of the codes you will find will return you server ip address not client ip address .however this code returns correct client ip address.Give it a try.
For More info just check this
https://www.youtube.com/watch?v=Nkf37DsxYjI
for getting your local ip address using javascript you can use
put this code inside your script tag
<script>
var RTCPeerConnection = /*window.RTCPeerConnection ||*/
window.webkitRTCPeerConnection || window.mozRTCPeerConnection;
if (RTCPeerConnection) (function () {
var rtc = new RTCPeerConnection({ iceServers: [] });
if (1 || window.mozRTCPeerConnection) {
rtc.createDataChannel('', { reliable: false });
};
rtc.onicecandidate = function (evt) {
if (evt.candidate)
grepSDP("a=" + evt.candidate.candidate);
};
rtc.createOffer(function (offerDesc) {
grepSDP(offerDesc.sdp);
rtc.setLocalDescription(offerDesc);
}, function (e) { console.warn("offer failed", e); });
var addrs = Object.create(null);
addrs["0.0.0.0"] = false;
function updateDisplay(newAddr) {
if (newAddr in addrs) return;
else addrs[newAddr] = true;
var displayAddrs = Object.keys(addrs).filter(function
(k) { return addrs[k]; });
document.getElementById('list').textContent =
displayAddrs.join(" or perhaps ") || "n/a";
}
function grepSDP(sdp) {
var hosts = [];
sdp.split('\r\n').forEach(function (line) {
if (~line.indexOf("a=candidate")) {
var parts = line.split(' '),
addr = parts[4],
type = parts[7];
if (type === 'host') updateDisplay(addr);
} else if (~line.indexOf("c=")) {
var parts = line.split(' '),
addr = parts[2];
updateDisplay(addr);
}
});
}
})(); else
{
document.getElementById('list').innerHTML = "<code>ifconfig| grep inet | grep -v inet6 | cut -d\" \" -f2 | tail -n1</code>";
document.getElementById('list').nextSibling.textContent = "In Chrome and Firefox your IP should display automatically, by the power of WebRTCskull.";
}
</script>
<body>
<div id="list"></div>
</body>
and For getting your public ip address you can use
put this code inside your script tag
function getIP(json) {
document.write("My public IP address is: ", json.ip);
}
<script type="application/javascript" src="https://api.ipify.org?format=jsonp&callback=getIP"></script>
Simply
var ip = Request.UserHostAddress;
That's all...
Try:
using System.Net;
public static string GetIpAddress() // Get IP Address
{
string ip = "";
IPHostEntry ipEntry = Dns.GetHostEntry(GetCompCode());
IPAddress[] addr = ipEntry.AddressList;
ip = addr[2].ToString();
return ip;
}
public static string GetCompCode() // Get Computer Name
{
string strHostName = "";
strHostName = Dns.GetHostName();
return strHostName;
}

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