I want to get the last seen of user and save it to my sql database in mvc5 . I got the last seen in controller with code like this:
users.userlast=DateTime.Now;
and saved to my database in this format "2015-08-06 12:12:13.443". I want to get datetime only format day,month,year, hour and minute.
I can't use something like this,
var dateTime = DateTime.ParseExact("12/02/21 10:56:09", "yy/MM/dd HH:mm", CultureInfo.InvariantCulture);
var text = dateTime.ToString("MMM. dd, yyyy HH:mm");
It did not work because my last seen column is a datetime type not string. What should i do?
Thanks.
Edit:
Like whatsup App., i want to see only hour and minute, not seconds as last seen.
You say that you are storing as a datetime type, in which case the you shouldn't need to convert a string to a DateTime. In fact you shouldn't need to do any parsing.
When you query the database you should get a DateTime, on which you can call the ToString() you want.
to get datetime in format day, month, year, hour and minute only (without seconds, milliseconds), create a new DateTime value before save:
var dt = DateTime.Now;
users.userlast = dt.Date.AddHours(dt.Hour).AddMinutes(dt.Minute);
You don't have to worry about the format you save in the database. When you want to represent it in your specific format you can ToString it accordingly.
I want to get datetime only format day,month,year, hour and minute.
string text = dateTime.ToString("yyyy-MM-dd HH:mm",
CultureInfo.InvariantCulture);
CultureInfo.InvariantCulture is to use your specified culture regardless of the user's current culture.
You can use InvariantCulture because your user must be in a culture that uses a dot instead of a colon:
DateTime.ToString("yyyy-MM-dd HH:mm", CultureInfo.InvariantCulture);
Just do like that
var formattedDateTime = yourLastSeenDateTime.ToString("MMM. dd, yyyy HH:mm", CultureInfo.InvariantCulture);
EDIT: Try this as you mentioned in comments
DateTime dbDate = yourLastSeenDateTime;
DateTime newDateTime = new DateTime(dbDate.Year, dbDate.Month, dbDate.Day, dbDate.Hour, dbDate.Minute, 0);
Related
I am taking selected date from telerik date picker and want to take that selected date and current system time by 24 hours format and want date like this:
For Ex: Current Date = dd/mm/yy HH:Minutes:Seconds
21/1/2016 14:48:21
This is my code:
DateTime dt = DateTime.ParseExact(Datepicker1.SelectedDate.Value.ToShortDateString(), "dd/MM/yyyy", CultureInfo.InvariantCulture);//Error:String was not recognized as a valid DateTime.
Datepicker1.SelectedDate.Value= {1/21/2016 12:00:00 AM}
Datepicker1.SelectedDate.Value.ToShortDateString()=1/21/2016
Error:String was not recognized as a valid DateTime on Datetime.ParseExact.
Change your format in the ParseExact from
"dd/MM/yyyy"
to
"M/d/yyyy" or "M/d/yyyy h:m:s tt" //the first one use .ToShortDateString(), the second one for 1/21/2016 12:00:00 AM
The first one only takes care for case like 21/12/1997
The second one takes care 12/21/1997, 2/21/1997, 12/2/1997, and 2/1/1997 in addition to take care of time info
Also, note that you may consider to have multiple formats (just in case): "d/M/yyyy H:m:s", "d/M/yyyy h:m:s tt" to take care of the case where day and month are swapped and when you have AM/PM.
MSDN link.
#yourDateTime.FormattedReviewDate.ToString("MMM dd,yyyy")
You might even just add a simple property to dateTime for the formatted display:
public string FormattedReviewDate
{
get { return ReviewDate.ToString("MMM dd,yyyy"); }
}
Note: Give your needed format
You don't need to parse anything.
Your Datepicker1.SelectedDate.Value is already DateTime, just assign this value to your dt variable.
DateTime dt = Datepicker1.SelectedDate.Value;
If you want to get it's string representation based on your format, just use ToString method with proper format.
string formattedDate = dt.ToString("dd/M/yyyy HH:mm:ss", CultureInfo.InvariantCulture);
which returns 21/1/2016 14:48:21 as a string.
Also if you want 1/21/2016 as a string, just change your format to M/dd/yyyy like;
string formattedDate = dt.ToString("M/dd/yyyy", CultureInfo.InvariantCulture);
i have a text-box in a detailview and the value of the text-box is a Date but it only shows the Month and Year and it is like this:November 2013 so i want to take this value and convert like this: 20131101. So as you can see, i would like the format to be YYYYMMDD but the day should always be 01 which is the first of the month. So how can i go from this November 2013 to this 20131101? here is my code and i know i have to convert from string to date first:
string myDate = ((TextBox)DetailView1.FindControl("InputDate")).Text.ToString();
Convert it:
TextBox txtInputDate = (TextBox)DetailView1.FindControl("InputDate");
DateTime dt = DateTime.ParseExact(txtInputDate.Text, "MMMM yyyy", CultureInfo.InvariantCulture);
then convert it to string again:
txtInputDate.Text = dt.ToString("yyyyMMdd", CultureInfo.InvariantCulture);
C# is pretty good at parsing stringy dates, you could lean on the build it parsing:
string myDateString = ((TextBox)DetailView1.FindControl("InputDate")).Text.ToString();
DateTime myDate;
if (DateTime.TryParse(myDateString, out myDate)) {
// myDate now contains a proper .NET date.
}
Now you have a proper DateTime, you can output it in any format you like.
DateTime test = DateTime.Parse("November 2013");
Console.WriteLine(test.ToString("yyyyMMdd"));
Use the DateTime.ParseExact() method, like this:
var theParsedDate = DateTime.ParseExact(myDate, "MMMM yyyy",
CultureInfo.InvariantCulture);
Now you can use the parsed date however you wish, convert it to string, send it to database, etc.
i have textbox that accepts time format like this 12:40 PM but would like to convert it into time format like this 12:40:00 basically without the PM or AM. Here is what i have so far:
string StartTime = ((TextBox)TestDV.FindControl("txtBST")).Text.ToString();
thanks
One option would be to parse into a DateTime and then back to a string:
string s = "12:40 PM";
DateTime dt = DateTime.Parse(s);
string s2 = dt.ToString("HH:mm:ss"); // 12:40:00
Be aware, however, that most operations work better with a DateTime versus a string representation of a DateTime.
First you should parse it to a DateTime, then format it. It sounds like your input format is something like hh:mm tt and your output format is HH:mm:ss. So, you'd have:
string input = "12:40 PM"
DateTime dateTime = DateTime.ParseExact(input, "hh:mm tt",
CultureInfo.InvariantCulture);
string output = dateTime.ToString("HH:mm:ss", CultureInfo.InvariantCulture);
Note that:
I've used DateTime.ParseExact which will throw an exception if the parsing fails; you may want to use DateTime.TryParseExact (it depends on your situation)
I've used the invariant culture for both operations here. I don't know whether or not that's correct for your scenario.
I've used hh:mm, but you might want h:mm... would you expect "1 PM" or "01 PM"?
You don't parse seconds, so that part will always be 0... is that okay?
Since you are bringing it in as a string this is actually kind of easy.
string StartTime = ((TextBox)TestDV.FindControl("txtBST")).Text.ToString();
DateTime dt = new DateTime();
try { dt = Convert.ToDateTime(StartTime); }
catch(FormatException) { dt = Convert.ToDateTime("12:00 AM"); }
StartTime = dt.ToString("HH:mm");
So you bring in your string, and convert it to a date. if the input is not a valid date, this will default it to 00:00. Either way, it gives you a string and a DateTime object to work with depending on what else you need to do. Both represent the same value, but the string will be in 24-Hour format.
Cheers!!
I have a datetime column in database.
DateTime end_date = DateTime.ParseExact("2013-Jan-31", "yyyy-MM-dd", CultureInfo.InvariantCulture);
Why isn't this working?
This is not working because MM would mean January to be 01. If this is the format of the date you're trying to parse, try the format "yyyy-MMM-dd".
Hope this helps
Try like this;
DateTime a = DateTime.ParseExact("2013-Jan-31", "yyyy-MMM-dd", System.Globalization.CultureInfo.InvariantCulture);
Console.WriteLine (a);
Output:
31.01.2013
Look at from MSDN Custom Date and Time Format Strings
To use such a name of the month you need to take "MMM" so it will be
myObject.end_date = DateTime.ParseExact("2013-Jan-31", "yyyy-MMM-dd", System.Globalization.CultureInfo.InvariantCulture);
MM represents a two-digit numerical month (such as "01").
MMM represents the abbreviated month (such as "Jan").
Which means that you need
myObject.end_date = DateTime.ParseExact("2013-Jan-31", "yyyy-MMM-dd", System.Globalization.CultureInfo.InvariantCulture);
See http://msdn.microsoft.com/en-us/library/8kb3ddd4.aspx for a list of string format specifiers.
If I have a timestamp in the form: yyyy-mm-dd hh:mm:ss:mmm
How can I just extract the date from the timestamp?
For instance, if a timestamp reads: "2010-05-18 08:36:52:236" what is the best way to just get 2010-05-18 from it.
What I'm trying to do is isolate the date portion of the timestamp, define a custom time for it to create a new time stamp. Is there a more efficient way to define the time of the timestamp without first taking out the date, and then adding a new time?
DateTime.Parse("2010-05-18 08:36:52:236").ToString("yyyy-MM-dd");
You should use the DateTime type:
DateTime original = DateTime.Parse(str);
DateTime modified = original.Date + new TimeSpan(13, 15, 00);
string str = modified.ToString("yyyy-MM-dd HH:mm:ss:fff");
Your format is non-standard, so you'll need to call ParseExact instead of Parse:
DateTime original = DateTime.ParseExact(str, "yyyy-MM-dd HH:mm:ss:fff", CultureInfo.InvariantCulture);
You could use substring:
"2010-05-18 08:36:52:236".Substring(0, 10);
Or use ParseExact:
DateTime.ParseExact("2010-05-18 08:36:52:236",
"yyyy-MM-dd HH:mm:ss:fff",
CultureInfo.InvariantCulture)
.ToString("yyyy-MM-dd");
DateTime date;
if (DateTime.TryParse(dateString, out date))
{
date = date.Date; // Get's the date-only component.
// Do something cool.
}
else
{
// Flip out because you didn't get a real date.
}
Get the .Date member on the DateTime
DateTime date = DateTime.Now;
DateTime midnightDate = date.Date;
use it like this:
var x = DateTime.Now.Date; //will give you midnight today
x.AddDays(1).AddTicks(-1); //use these method calls to modify the date to whats needed.
The best (and fastest) way to do this is to convert the date to an integer as the time part is stored in the decimal part.
Try this:
select convert(datetime,convert(int, #yourdate))
So you convert it to an integer and then back to a data and voila, time part is gone.
Of course subtracting this result from the original value will give you the time part only.